select data having same id - sql

Question

id idtest result
1 1 2
1 2 1
1 3 2
2 1 2
2 2 1
2 3 1
3 1 1
3 2 2
3 3 1
Would like to get all the rows with the same IDs that matches the condition.
For example: get all the rows with the same id where (idTest=2 and result=1) and (idTest=3 and result=2)
result:
id idtest result
1 1 2
1 2 1
1 3 2
What would be the query???
Thanks!

Answer 1

Do you mean this?
SELECT * FROM table WHERE id = 1 and (result = 1 OR result = 2)
How about his:
SELECT *
FROM table WHERE (idTest = 2 OR idTest = 3) AND (result=1 OR result=2)

Answer 2

ID test res
1 1 2
1 2 1
1 3 2
2 1 1
2 2 2
2 3 2
3 1 1
3 2 2
3 3 1
Sorry. This would be my table. and Would like to get all the rows with the same IDs that matches the condition. For example: get all the rows with the same id where (test=2 and res=1) and (test=3 and res=2)
Result:
ID test res
1 1 2
1 2 1
1 3 2
What would be the query in order to get the three rows ?? Thanks!

Answer 3

You can use EXISTS:
SELECT id, idTest, result
FROM dbo.TableName t
WHERE EXISTS
(
SELECT 1 FROM dbo.TableName t2
WHERE t.id = t2.id
AND(
( t2.idTest=2 AND t2.result=1 )
OR
( t2.idTest=3 AND t2.result=2 )
)
)
Demo
Update: result is different:
id idTest result
1 1 2
1 2 1 <-- satisfies your condition
1 3 2 <-- satisfies your condition
2 1 2
2 2 1 <-- satisfies your condition
2 3 1
So either my understanding was incorrect or your expected result. I have also all ID=2 because the second id-2 row matches the condition.

Answer 4

You seem to want all rows for id's that have rows with that particular combination. What about:
with ids as (
select id
from mytable
where (idTest=2 and result=1) or (idTest=3 and result=2)
group by id
having count(id) = 2
)
select mytable.* from mytable
inner join ids
on ids.id = mytable.id
This gets a list of id's where both conditions apply, and then gets all rows for those id's.
SqlFiddle

Answer 5

SELECT *
FROM table t1
WHERE EXISTS (SELECT 1 FROM table WHERE id = t1.id AND idtest = 2 AND result = 1)
AND EXISTS (SELECT 1 FROM table WHERE id = t1.id AND idtest = 3 AND result = 2)
Just keep adding more AND EXISTS if you need more
Or you can use IN if it makes more sense to you
SELECT *
FROM table
WHERE id IN (SELECT id from table where idtest = 2 and result = 1)
AND id IN (SELECT id from table where idtest = 3 and result = 2)

Answer 6

do you need a method that treats the condition(s) in a generic way, like if they're values in another table? Or do you only need a way to pull results of two independent conditions?
If the latter, then this should work:
SELECT
id
FROM
(SELECT id
FROM tbl
WHERE idTest=2 AND RESULT=1) cond1 INNER JOIN
(SELECT id
FROM tbl
WHERE idTest=3 AND RESULT=2) cond2 ON
cond1.id = cond2.id
otherwise, if your conditions are generic and stored in a table, you'd need something like:
SELECT
id
FROM
(SELECT id
FROM tbl FULL OUTER JOIN conditions c
WHERE c.isUseMe = 1 AND c.SEQ = 1 AND idTest=c.idTestVal AND result=c.resultVal) cond1 INNER JOIN
(SELECT id
FROM tbl FULL OUTER JOIN conditions c
WHERE c.isUseMe = 1 AND c.SEQ = 2 AND idTest=c.idTestVal AND result=c.resultVal) cond2 ON
cond1.id = cond2.id
if the 4 values are passed in as parameters, you'd need something like:
SELECT
id
FROM
(SELECT id
FROM tbl
WHERE idTest=#idTestVal1 AND result=#resultVal1) cond1 INNER JOIN
(SELECT id
FROM tbl
WHERE idTest=#idTestVal2 AND result=#resultVal2) cond2 ON
cond1.id = cond2.id