I need to select the last 12 months. As you can see on the picture, May occurs two times.
But I only want it to occur once. And it needs to be the newest one.
Plus, the table should stay in this structure, with the latest month on the bottom.
And this is the query:
SELECT Monat2,
Monat,
CASE WHEN NPLAY_IND = '4P'
THEN 'QuadruplePlay'
WHEN NPLAY_IND = '3P'
THEN 'TriplePlay'
WHEN NPLAY_IND = '2P'
THEN 'DoublePlay'
WHEN NPLAY_IND = '1P'
THEN 'SinglePlay'
END AS Series,
Anzahl as Cnt
FROM T_Play_n
where NPLAY_IND != '0P'
order by Series asc ,Monat
This is the new query
SELECT sub.Monat2,sub.Monat,
CASE WHEN NPLAY_IND = '4P'
THEN 'QuadruplePlay'
WHEN NPLAY_IND = '3P'
THEN 'TriplePlay'
WHEN NPLAY_IND = '2P'
THEN 'DoublePlay'
WHEN NPLAY_IND = '1P'
THEN 'SinglePlay'
END
AS Series, Anzahl as Cnt FROM (SELECT ROW_NUMBER () OVER (PARTITION BY Monat2 ORDER BY Monat DESC)rn,
Monat2,
Monat,
Anzahl,
NPLAY_IND
FROM T_Play_n)sub
where sub.rn = 1
It does only show the months once but it doesn't do that for every Series.
So with every Play it should have 12 months.
In Oracle and SQL-Server you can use ROW_NUMBER.
name = month name and num = month number:
SELECT sub.name, sub.num
FROM (SELECT ROW_NUMBER () OVER (PARTITION BY name ORDER BY num DESC) rn,
name,
num
FROM tab) sub
WHERE sub.rn = 1
ORDER BY num DESC;
WITH R(N) AS
(
SELECT 0
UNION ALL
SELECT N+1
FROM R
WHERE N < 12
)
SELECT LEFT(DATENAME(MONTH,DATEADD(MONTH,-N,GETDATE())),3) AS [month]
FROM R
The With R(N) is a Common Table Expression.The R is the name of the result set (or table) that you are generating. And the N is the month number.
In SQL Server you can do It in following:
SELECT DateMonth, DateWithMonth -- Specify columns to select
FROM Tbl -- Source table
WHERE CAST(CAST(DateWithMonth AS INT) * 100 + 1 AS VARCHAR(20)) >= DATEADD(MONTH, -12,GETDATE()) -- Condition to return data for last 12 months
GROUP BY DateMonth, DateWithMonth -- Uniqueness
ORDER BY DateWithMonth -- Sorting to get latest records on the bottom
So it sounds like you want to select rows that contain the last occurrence of months. Something like this should work:
select * from [table_name]
where id in (select max(id) from [table_name] group by [month_column])
The last select in the brackets will get a list of id's for the last occurrence of each month. If the year+month column you have shown is not in descending order already, you might want to max this column instead.
You can use something like this(the table dbo.Nums contains int values from 0 to 11)
SELECT DATEADD(MONTH, DATEDIFF(MONTH, '19991201', CURRENT_TIMESTAMP) + n - 12, '19991201'),
DATENAME(MONTH,DateAdd(Month, DATEDIFF(month, '19991201', CURRENT_TIMESTAMP) + n - 12, '19991201'))
FROM dbo.Nums
I suggest to use a group by for the month name, and a max function for the numeric component. If is not numeric, use to_number().
Related
I have a table which has a timestamp and inCycle status of a machine. I'm using two CTE's and doing an INNER JOIN on row number so I can easily compare the timestamp of one row to the next. I have the DATEDIFF working and now I need to look at the inCycle status. Basically, if the inCycleThis and inCycleNext both = 1, I need to add it to an InCycle total.
Similarly (Shown table will make this clear):
incycleThis/next = 0,1 = not in cycle
incycleThis/next = 0,0 = not in cycle
incycleThis/next = 1,1 = in cycle
If I was doing this client side, this would be pretty simple. I need to do this in a stored procedure though due to there being a lot of records. I'd love to use an 'IF' in the SELECT section, but it seems that's not how it works.
The result I'm looking for at the end is simply: InCycle = Xtime. Something like:
SUM(Diff_seconds if((InCycleThis = 1 AND InCycleNext = 1) OR (InCycleThis = 1 AND InCycleNext = 0))
This is what I have so far:
WITH History_CTE (DT, MID, FRO, IC, RowNum)
AS
(
SELECT DateAndTime
,MachineID
,FeedRateOverride
,InCycle
,ROW_NUMBER()OVER(ORDER BY MachineID, DateAndTime) AS "row number"
FROM History
WHERE DateAndTime >= '2020-11-15'
AND DateAndTime < '2020-11-16'
),
History2_CTE (DT2, MID2, FRO2, IC2, RowNum2)
AS
(
SELECT DateAndTime
,MachineID
,FeedRateOverride
,InCycle
,ROW_NUMBER()OVER(ORDER BY MachineID, DateAndTime) AS "row number"
FROM History
WHERE DateAndTime >= '2020-11-15'
AND DateAndTime < '2020-11-16'
)
SELECT DT as 'TimeStamp'
,DT2 as 'TimeStamp Next Row'
,MID
,FRO
,IC as 'InCycle this'
,IC2 as 'InCycle next'
,RowNum
,DATEDIFF(s, History2_CTE.DT2, History_CTE.DT) AS 'Diff_seconds'
FROM History_CTE
INNER JOIN
History2_CTE ON History_CTE.RowNum = History2_CTE.RowNum2 + 1
Consider adding a third CTE to first conditionally calculate your needed value. Then aggregate for final statement. Recall CTEs can reference previously defined CTEs. Be sure to always quailfy columns with table aliases in JOIN queries.
WITH
... first two ctes...
, sub AS (
SELECT h1.DT AS 'TimeStamp'
, h2.DT2 AS 'TimeStamp Next Row'
, h1.MID
, h1.FRO
, h1.IC AS 'InCycle this'
, h2.IC2 AS 'InCycle next'
, h1.RowNum
, DATEDIFF(s, h2.DT2, h1.DT) AS 'Diff_seconds'
, CASE
WHEN (h1.IC = 1 AND h2.IC2 = 1) OR (h1.IC= 1 AND h2.IC2 = 0)
THEN DATEDIFF(s, h2.DT2, h1.DT)
END AS 'IC_Diff_seconds'
FROM History_CTE h1
INNER JOIN History2_CTE h2
ON h1.RowNum = h2.RowNum2 + 1
)
SELECT SUM([Diff_seconds]) AS Diff_seconds_Total
, SUM([IC_Diff_seconds]) AS IC_Diff_seconds_Total
FROM sub
And if needing to add groupings, incorporate GROUP BY:
SELECT h1.MID
, h1.FRO
, SUM([Diff_seconds]) AS Diff_seconds_Total
, SUM([IC_Diff_seconds]) AS IC_Diff_seconds_Total
FROM sub
GROUP BY h1.MID
, h1.FRO
Even aggregate calculations by day:
SELECT CONVERT(date, [TimeStamp]) AS [Day]
, SUM([Diff_seconds]) AS Diff_seconds_Total
, SUM([IC_Diff_seconds]) AS IC_Diff_seconds_Total
FROM sub
GROUP BY CONVERT(date, [TimeStamp])
The result I'm looking for at the end is simply: InCycle = Xtime. Something like:
SUM(Diff_seconds if((InCycleThis = 1 AND InCycleNext = 1) OR (InCycleThis = 1 AND InCycleNext = 0))
As I understand your question, you just need to sum the difference betwen the timestamp of "in cycle" rows and the timestamp of the next row.
select machineid,
sum(datediff(s, dateandtime, lead_dateandtime)) as total_in_time
from (
select h.*,
lead(dateandtime) over(partition by machineid order by dateandtime) as lead_dateandtime
from history h
) h
where inclycle = 1
group by machineid
I have the following query which works great. I would simply like to label the output (see below) following the dummy variables I created; '7a-7p' '7p-7a'.
Select
count([SHIFT_Type]) as Count
FROM
(
Select
CASE WHEN Checkin_hour >= 7 and Checkin_hour < 19 then '7a-7p' else '7p-7a' END AS [SHIFT_Type]
FROM (
Select *,
CONVERT(VARCHAR(10),CHECKIN_DATE_TIME,111) as Checkin_date, DATEPART(Hour, CHECKIN_DATE_TIME) as Checkin_hour, DATEPART(DW, CHECKIN_DATE_TIME) as Day_of_Week, [Day] = DATENAME(WEEKDAY, CHECKIN_DATE_TIME),
Row_Number () Over (Partition BY Patient_Fin order BY Patient_Fin) as RowNumber
FROM COVID_TAT
WHERE (CHECKIN_DATE_TIME > #StartDate and CHECKIN_DATE_TIME < #EndDate) and PT_DISCH_DISPO not like '%Error%'
and PT_DISCH_DISPO not like '%no show%' and PT_DISCH_DISPO not like'%Left Without Treatment%' and DOCTORSEE_DATE_TIME not like 'null'
and TRACK_GROUP like '%ED Track%'
)sub
)sub
Group By [SHIFT_Type]
CURRENT OUTPUT
Count
1 64
2 39
DESIRED OUTPUT
Count
7a-7p 64
7p-7a 39
The "label" is already available in the intermediate subquery, and you use it as a
GROUP BY column in the outer query. Just add it to the SELECT clause:
SELECT [SHIFT_Type], count([SHIFT_Type]) as Count
FROM ...
GROUP BY [SHIFT_Type]
I have a table that has data like following.
attr |time
----------------|--------------------------
abc |2018-08-06 10:17:25.282546
def |2018-08-06 10:17:25.325676
pqr |2018-08-05 10:17:25.366823
abc |2018-08-06 10:17:25.407941
def |2018-08-05 10:17:25.449249
I want to group them and count by attr column row wise and also create additional columns in to show their counts per day and percentages as shown below.
attr |day1_count| day1_%| day2_count| day2_%
----------------|----------|-------|-----------|-------
abc |2 |66.6% | 0 | 0.0%
def |1 |33.3% | 1 | 50.0%
pqr |0 |0.0% | 1 | 50.0%
I'm able to display one count by using group by but unable to find out how to even seperate them to multiple columns. I tried to generate day1 percentage with
SELECT attr, count(attr), count(attr) / sum(sub.day1_count) * 100 as percentage from (
SELECT attr, count(*) as day1_count FROM my_table WHERE DATEPART(week, time) = DATEPART(day, GETDate()) GROUP BY attr) as sub
GROUP BY attr;
But this also is not giving me correct answer, I'm getting all zeroes for percentage and count as 1. Any help is appreciated. I'm trying to do this in Redshift which follows postgresql syntax.
Let's nail the logic before presenting:
with CTE1 as
(
select attr, DATEPART(day, time) as theday, count(*) as thecount
from MyTable
)
, CTE2 as
(
select theday, sum(thecount) as daytotal
from CTE1
group by theday
)
select t1.attr, t1.theday, t1.thecount, t1.thecount/t2.daytotal as percentofday
from CTE1 t1
inner join CTE2 t2
on t1.theday = t2.theday
From here you can pivot to create a day by day if you feel the need
I am trying to enhance the query #johnHC btw if you needs for 7days then you have to those days in case when
with CTE1 as
(
select attr, time::date as theday, count(*) as thecount
from t group by attr,time::date
)
, CTE2 as
(
select theday, sum(thecount) as daytotal
from CTE1
group by theday
)
,
CTE3 as
(
select t1.attr, EXTRACT(DOW FROM t1.theday) as day_nmbr,t1.theday, t1.thecount, t1.thecount/t2.daytotal as percentofday
from CTE1 t1
inner join CTE2 t2
on t1.theday = t2.theday
)
select CTE3.attr,
max(case when day_nmbr=0 then CTE3.thecount end) as day1Cnt,
max(case when day_nmbr=0 then percentofday end) as day1,
max(case when day_nmbr=1 then CTE3.thecount end) as day2Cnt,
max( case when day_nmbr=1 then percentofday end) day2
from CTE3 group by CTE3.attr
http://sqlfiddle.com/#!17/54ace/20
In case that you have only 2 days:
http://sqlfiddle.com/#!17/3bdad/3 (days descending as in your example from left to right)
http://sqlfiddle.com/#!17/3bdad/5 (days ascending)
The main idea is already mentioned in the other answers. Instead of joining the CTEs for calculating the values I am using window functions which is a bit shorter and more readable I think. The pivot is done the same way.
SELECT
attr,
COALESCE(max(count) FILTER (WHERE day_number = 0), 0) as day1_count, -- D
COALESCE(max(percent) FILTER (WHERE day_number = 0), 0) as day1_percent,
COALESCE(max(count) FILTER (WHERE day_number = 1), 0) as day2_count,
COALESCE(max(percent) FILTER (WHERE day_number = 1), 0) as day2_percent
/*
Add more days here
*/
FROM(
SELECT *, (count::float/count_per_day)::decimal(5, 2) as percent -- C
FROM (
SELECT DISTINCT
attr,
MAX(time::date) OVER () - time::date as day_number, -- B
count(*) OVER (partition by time::date, attr) as count, -- A
count(*) OVER (partition by time::date) as count_per_day
FROM test_table
)s
)s
GROUP BY attr
ORDER BY attr
A counting the rows per day and counting the rows per day AND attr
B for more readability I convert the date into numbers. Here I take the difference between current date of the row and the maximum date available in the table. So I get a counter from 0 (first day) up to n - 1 (last day)
C calculating the percentage and rounding
D pivot by filter the day numbers. The COALESCE avoids the NULL values and switched them into 0. To add more days you can multiply these columns.
Edit: Made the day counter more flexible for more days; new SQL Fiddle
Basically, I see this as conditional aggregation. But you need to get an enumerator for the date for the pivoting. So:
SELECT attr,
COUNT(*) FILTER (WHERE day_number = 1) as day1_count,
COUNT(*) FILTER (WHERE day_number = 1) / cnt as day1_percent,
COUNT(*) FILTER (WHERE day_number = 2) as day2_count,
COUNT(*) FILTER (WHERE day_number = 2) / cnt as day2_percent
FROM (SELECT attr,
DENSE_RANK() OVER (ORDER BY time::date DESC) as day_number,
1.0 * COUNT(*) OVER (PARTITION BY attr) as cnt
FROM test_table
) s
GROUP BY attr, cnt
ORDER BY attr;
Here is a SQL Fiddle.
I have an order file, with order id and ship date. Orders can only be shipped monday - friday. This means there are no records selected for Saturday and Sunday.
I use the same order file to get all order dates, with date in the same format (yyyymmdd).
i want to select a count of all the records from the order file based on order date... and (i believe) full outer join (or maybe right join?) the date file... because i would like to see
20120330 293
20120331 0
20120401 0
20120402 920
20120403 430
20120404 827
etc...
however, my sql statement is still not returning a zero record for the 31st and 1st.
with DatesTable as (
select ohordt "Date" from kivalib.orhdrpf
where ohordt between 20120315 and 20120406
group by ohordt order by ohordt
)
SELECT ohscdt, count(OHTXN#) "Count"
FROM KIVALIB.ORHDRPF full outer join DatesTable dts on dts."Date" = ohordt
--/*order status = filled & order type = 1 & date between (some fill date range)*/
WHERE OHSTAT = 'F' AND OHTYP = 1 and ohscdt between 20120401 and 20120406
GROUP BY ohscdt ORDER BY ohscdt
any ideas what i'm doing wrong?
thanks!
It's because there is no data for those days, they do not show up as rows. You can use a recursive CTE to build a contiguous list of dates between two values that the query can join on:
It will look something like:
WITH dates (val) AS (
SELECT CAST('2012-04-01' AS DATE)
FROM SYSIBM.SYSDUMMY1
UNION ALL
SELECT Val + 1 DAYS
FROM dates
WHERE Val < CAST('2012-04-06' AS DATE)
)
SELECT d.val AS "Date", o.ohscdt, COALESCE(COUNT(o.ohtxn#), 0) AS "Count"
FROM dates AS d
LEFT JOIN KIVALIB.ORDHRPF AS o
ON o.ohordt = TO_CHAR(d.val, 'YYYYMMDD')
WHERE o.ohstat = 'F'
AND o.ohtyp = 1
Given data in a table with the following schema:
CREATE TABLE purchases (timestamp DATETIME, quantity INT)
I would like to find the point in time (i.e. the timestamp of the row) where the sum of the values in the quantity column passed a certain threshold value.
This is in MS SQL Server, and ideally I'd like to avoid using a cursor if possible.
SELECT timestamp, SUM(quantity)
FROM purchases
GROUP BY timestamp
HAVING SUM(quantity) > someValue
Or if it is a Running Sum
SELECT a1.timestamp
FROM purchases a1, purchases a2
WHERE a1.quantity >= a2.quantity or (a1.quantity=a2.quantity and a1.timestamp = a2.timestamp)
GROUP BY a1.timestamp, a1.quantity
having SUM(a2.quantity) >= someValue
ORDER BY a1.timestamp ASC
LIMIT 1
You could get the smallest timestamp where the sum of the previous values is larger than the threshold:
select min(timestamp)
from purchases p
where (
select sum(x.quantity)
from purchases x
where x.timestamp < p.timestamp
) > #threshold
However, this is not a very efficient query, so it might be better to use a cursor after all.
In SQL Server 2005+ you could try this:
;WITH numbered AS (
SELECT
timestamp,
quantity,
rownum = ROW_NUMBER() OVER (ORDER BY timestamp)
FROM purchases
),
recursive AS (
SELECT
timestamp,
quantity,
rownum,
runningsum = quantity,
passed = CASE WHEN n.quantity < #threshold THEN 0 ELSE 1 END
FROM numbered
UNION ALL
SELECT
n.timestamp,
n.quantity,
n.rownum,
runningsum = n.quantity + r.runningsum,
passed = CASE WHEN n.quantity + r.runningsum < #threshold THEN 0 ELSE 1 END
FROM numbered n
INNER JOIN recursive r ON n.rownum = r.rownum + 1
)
SELECT MIN(timestamp)
FROM recursive
WHERE passed = 1
Basically, same as #Guffa's solution, only makes use of CTEs to avoid the need of triangular join.