Use trait from submodule with same name as struct - module

Question

Trying to compile the following Rust code
mod traits {
pub trait Dog {
fn bark(&self) {
println!("Bow");
}
}
}
struct Dog;
impl traits::Dog for Dog {}
fn main() {
let dog = Dog;
dog.bark();
}
gives the error message
error[E0599]: no method named `bark` found for type `Dog` in the current scope
--> src/main.rs:15:9
|
9 | struct Dog;
| ----------- method `bark` not found for this
...
15 | dog.bark();
| ^^^^
|
= help: items from traits can only be used if the trait is in scope
help: the following trait is implemented but not in scope, perhaps add a `use` for it:
|
1 | use crate::traits::Dog;
|
If I add use crate::traits::Dog;, the error becomes:
error[E0255]: the name `Dog` is defined multiple times
--> src/main.rs:11:1
|
1 | use crate::traits::Dog;
| ------------------ previous import of the trait `Dog` here
...
11 | struct Dog;
| ^^^^^^^^^^^ `Dog` redefined here
|
= note: `Dog` must be defined only once in the type namespace of this module
If I rename trait Dog to trait DogTrait, everything works. How can I use a trait from a submodule that has the same name as a struct in my main module?

Answer 1

You could rename the trait when importing it to get the same result without renaming the trait globally:
use traits::Dog as DogTrait;
The compiler now even suggests this:
help: you can use `as` to change the binding name of the import
|
1 | use crate::traits::Dog as OtherDog;
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
documentation

Answer 2

If you don't wish to import both (or can't for whatever reason), you can use Fully Qualified Syntax (FQS) to use the trait's method directly:
fn main() {
let dog = Dog;
traits::Dog::bark(&dog);
}