I have a user form where user selects From_date & To_date to search between those days, there is no way to restrict the user not to enter more than 20 days, this must be done in the store procedure.
How can I return the results after adding 20 days to the From_date. The date format is '2015-05-29-06.44.03.956380'
Your date contains fractional seconds, so it's a TIMESTAMP not a DATE datatype. Dont worry about the TIMESTAMP format, because Oracle store it internally always as a number then it is formatted depending to your session settigs, you can use + operator to add days to any datetime datatypes (DATE, TIMESTAMP, TIMESTAMP WITH TIME ZONE, and TIMESTAMP WITH LOCAL TIME ZONE):
select * from my_table where date_field between From_date and From_date+20
Related
I have seperate date and time columns in my table. Date as mm/dd/yyyy, time as hh:mm but i can change the format. I want to list data between 2 date/time. How can I do that?
select * from testtable where date >= '01/10/2022' AND date <= '01/10/2023' AND time >= '13:45' AND time <= '15:50'
I wrote it but of course it doesn't work like what i expected.
The best fix and really the only one you want here would be to start storing your timestamps in a sortable ISO format yyyy-mm-dd hh:ii:ss. Then, use this query:
SELECT *
FROM testtable
WHERE date BETWEEN '2022-01-10 13:45:00' AND '2023-01-10 15:50:00';
The thing to realize here is that SQLite does not actually have a date column type. Rather, you always store your dates/timestamps as text, and therefore it is crucial to use an ISO sortable format as shown above.
If your target is sqlite, it lacks complex timestamp types. But you have another option here. You can store that as unix timestamp, it is an integer representing the number of seconds offset from the epoch which is 1970-01-01 00:00:00 UTC. The table format would then be:
CREATE TABLE testtable (
date INTEGER
);
You can the use the unixepoch function to translate a string representation to that unix timestamp format. To insert a new date, you would use:
INSERT INTO testtable (date) VALUES (unixepoch('2023-01-11T11:30:00+01:00'))
Finding a matching row is now as easy to compare integers together. You can convert the datetime representation to unix timestamp at the application level, most programming environments provide such time utility functions/library. Or can still use the unixepoch function from sqlite for your where clause.
SELECT * FROM testtable
WHERE date >= unixepoch('2022-10-01T13:45:00Z')
AND date <= unixepoch('2023-10-01T15:50:00Z')
The final Z indicates an UTC time zone but you can adjust that with another +HH:00 extenstion instead which reflect the offset from utc of your datetime representation.
I have a Oracle SQL statement where I have to get the current timestamp as one of the columns. But I dont require the Timezone which CURRENT_TIMESTAMP gives or the AM/PM given by LOCALTIMESTAMP.
I require the current timestamp in 24hr format without the timezone.
Is it possible to get that in Oracle SQL?
It seems you're mixing 2 concepts here: "datatype" and "date format mask".
data type: LOCALTIMESTAMP returns datatype TIMESTAMP and CURRENT_TIMESTAMP returns datatype TIMESTAMP WITH TIME ZONE. TIMESTAMP is similar to DATE but has a higher precision. As usual... checking the docs is worth it.
date format mask: determines how you display the date information. Americans can't read 24 hour format, the rest of the world is confused by AM/PM. Fortunately, you can decide how you want to display the date as explained in the oracle docs.
If you just want to return the current date in 24 hour format you could do something like:
SELECT
TO_CHAR(SYSDATE,'DD-MON-YYYY HH24:MI:SS') as mydate,
<other columns>
FROM
<table_name>
If you need the date to be more precise and you require fractional seconds then you can use SYSTIMESTAMP instead of DATE with a format mask 'DD-MON-YYYY HH24:MI:SS.FF9'
I have a temp table.
It has last_update column in 2/10/2018 6:01:50 PM datetime format.
How can I write THE BEST QUERY to display all information that's updated on 02-Oct-2018 day?
You can use trunc function
select *
from tab
where trunc(last_update) = date'2018-10-02'
It is preferable to avoid TRUNC especially if you have an index on the column last_update.
A simple where condition should be better and may be better performant.
WHERE last_update >= date '2018-10-02' AND
last_update < date '2018-10-02' + 1
Use trunc function for getting the same day:
trunc(last_update) = trunc(to_date('02-Oct-2018', 'DD-MONTH-YYYY'))
The TRUNC (date) function returns date with the time portion of the day truncated to the unit specified by the format model fmt. The value returned is always of datatype DATE, even if you specify a different datetime datatype for date. If you omit fmt, then date is truncated to the nearest day.
You can also use format DD-MON-YYYY
I need to write a select query that gets data in between EPOCH(datetime)-3600 AND EPOCH(datetime).
select all incidents modified in specific date range between EPOCH(datetime)-3600 AND EPOCH(datetime)
So my query is:
SELECT *
FROM TABLENAME
WHERE COLUMN_NAME BETWEEN COLUMNNAME-3600 AND COLUMNNAME
Will this query get the data from 1 hour ago to the current time, in Unix TimeStamp format?
Given a column (COLUMN_NAME) where data is stored as a unix timestamp (eg number of seconds elapsed since January 1st, 1970), you are looking to filter records based on a DATE passed as parameter.
My understanding is that you need a way to convert a unix timestamp to a date. There is no such built-in function in Oracle, however you are allowed to add a number to a date, where the number represents the number of days to add.
Try :
SELECT *
FROM TABLENAME
WHERE
TO_DATE('01/01/1970', 'dd/mm/yyyy') + COLUMN_NAME/60/60/24 -- convert unix timestamp to date
BETWEEN :mydate - 3600 AND :mydate
;
Replace both :mydate with the actual DATE for which you want the search to be performed.
I need to substract 2 timestamps in the given format:
16/01/17 07:01:06,165000000
16/01/17 07:01:06,244000000
I want to express the result with 2 decimal values but somewhere in the CAST process I am loosing precision. My atempt by now goes this way:
select
id,
trunc((CAST(MAX(T.TIMESTAMP) AS DATE) - CAST(MIN(T.TIMESTAMP) AS DATE))*24*60*60,2) as result
from table T
group by id;
But I get id_1 '0' as a result for the two timestamps above even after I set the truncate decimals at 2.
Is there a way that I can obtain the 0.XX aa a result of the substraction?
It's because you are casting the timestamp to date.
Use to_timestamp to convert your string into timestamp.
Try this:
with your_table(tstamp) as (
select '16/01/17 07:01:06,165000000' from dual union all
select '16/01/17 07:01:06,244000000' from dual
),
your_table_casted as (
select to_timestamp(tstamp,'dd/mm/yy hh24:mi:ss,ff') tstamp from your_table
)
select trunc(sysdate + (max(tstamp) - min(tstamp)) * 86400 - sysdate, 2) diff
from your_table_casted;
The difference between two timestamps is INTERVAL DAY TO SECOND.
To convert it into seconds, use the above trick.
DATE—This datatype stores a date and a time, resolved to the second. It does not include the time zone. DATE is the oldest and most commonly used datatype for working with dates in Oracle applications.
TIMESTAMP—Time stamps are similar to dates, but with these two key distinctions: you can store and manipulate times resolved to the nearest billionth of a second (9 decimal places of precision), and you can associate a time zone with a time stamp, and Oracle Database will take that time zone into account when manipulating the time stamp.
The result of a substraction of two timestamps is an INTERVAL:
INTERVAL—Whereas DATE and TIMESTAMP record a specific point in time, INTERVAL records and computes a time duration. You can specify an interval in terms of years and months, or days and seconds.
You can find more information here