I have a path (as a string) to a directory. In that directory, are a bunch of text files. I want to go to that directory open it, and go to each text file and read the data.
I've tried
f = io.open(path)
f:read("*a")
I get the error "nil Is a directory"
I've tried:
f = io.popen(path)
I get the error: "Permission denied"
Is it just me, but it seems to be a lot harder than it should be to do basic file io in lua?
A directory isn't a file. You can't just open it.
And yes, lua itself has (intentionally) limited functionality.
You can use luafilesystem or luaposix and similar modules to get more features in this area.
You can also use the following script to list the names of the files in a given directory (assuming Unix/Posix):
dirname = '.'
f = io.popen('ls ' .. dirname)
for name in f:lines() do print(name) end
Related
I'm relatively new to Netlogo and already struggling ;)
I have the following problem: I want my program to open a folder, check a file in that folder and afterwards remove that file from that folder. I figured the best way to do this is via a while loop, but I'm struggling to find the right syntax. Hope you all can help!
The command 'file-open' will open a file using the path provided (the string after file-open: e.g. file-open "C:\Documents\model-out.txt" will open a file titled model-out.txt in the Documents folder on the C drive.)
You can then use 'file-read' or 'file-write' to read or write to the file respectively.
The command 'file-close' will close the file, which then can be deleted with 'file-delete'.
You can also check if a file exists in a folder using the command if file-exists? "C:\Documents\model-out.txt", and if true, the file can be deleted using file-delete.
Also check the command 'set-current-directory'.
Best,
I have received a file from a customer. The file is said to be
SQL code (application/sql)
However, this has turned out to be wrong: nothing could open it. It turns out it was secretely a .zip file. By renaming it to '.zip' and manually extracting it I was able to get the files contained in it. I would like to do a similar process in python.
So far I've renamed the file:
file_name_zip = file_name.replace('.sql', '.zip')
os.rename(file_name, file_name_zip)
And I've tried extracting it:
zip_ref = zipfile.ZipFile(file_name_zip, 'r')
zip_ref.extractall(extracted_file)
However, this failed because
zipfile.BadZipFile: File is not a zip file
I've googled, and apparently this can sometimes be fixed using:
zip_file_name_2 = zip_file_name.replace('.zip', '2.zip')
os.system(f'zip -FF {zip_file_name} --out {zip_file_name_2}')
This required me to put in a bunch of settings, which I wasn't able to figure out. There must be a better way to go about this.
Does anybody know how to parse such an .sql file?
I am trying to make a program that will write data to a file for another program to be able to read the data from it. The problem is that I can't figure out a way to do this when the file i am reading and writing from is in another directory than both of my programs. I know there are other ways of doing this, but I just thought that it would be useful to know how to do it. Anyone that can help me?
You can use the full path, e.g
local f1 = io.open('D:/test/b.txt') -- Windows
local f2 = io.open('/test/b.txt') -- Unix
or use relative path, e.g
local f = io.open('../../test/b.txt')
In this example, the file is in the test directory of the parent directory (..) of parent directory.
I'm trying to load group of folders files in one time with when
i set
sourceURI = 'gs://ybbi/bi_landing_zone/files_to_load/app/reports/app_network_analytics_report/201409011*'
all the folders that i'm want to load start with 20140911
but i get the error:
ERROR: Invalid path: gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/
20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0 is one of these folders(don't know why it's print the all folder name of this specific folder)
in some other folder tree cases it's works, but in this specific folder tree it's return the same error .
i know that cloud storage don't have real folders and it's part of the name of the object, but you understand what i mean.
is it bug?
Without more information, what it looks like is that you have a object file called gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/ that is not a csv/json file. Some tools may create these dummy files in order to simulate directories. BigQuery requires all objects that match the input glob path to be importable files.
One solution would be to change the glob path to include a narrower set of files. You can pass multiple paths if that makes things easier. For example, you could pass
gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/*
and
gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_some_other_path/*
1) I have a folder called CCBuilds containing couple of files in this path: E:\Testing\Builds\CCBuilds.
2) I have written C# code (Process.Start) to Rar this folder and save it in E:\Testing\Builds\CCBuilds.rar using the following command
"C:\program files\winrar\rar.exe a E:\Testing\Builds\CCBuilds.rar E:\Testing\Builds\CCBuilds"
3) The problem is that, though the rar file gets created properly, when I unrar the file to CCBuilds2 folder (both through code using rar.exe x command or using Extract in context menu), the unrared folder contains the full path, ie. extracting E:\Testing\Builds\CCBuilds.rar ->
E:\Testing\Builds\CCBuilds2\Testing\Builds\CCBuilds\<<my files>>
Whereas I want it to be something like this: E:\Testing\Builds\CCBuilds2\CCBuilds\<<my files>>
How can I avoid this full path persistence while adding to rar / extracting back from it. Any help is appreciated.
Use the -ep1 switch.
More info:
-ep = Files are added to an archive without including the path information. Could result in multiple files existing in the archive
with same name.
-ep1 = Do not store the path entered at the command line in archive. Exclude base folder from names.
-ep2 = Expand paths to full. Store full file paths (except drive letter and leading backslash) when archiving.
(source: http://www.qa.downappz.com/questions/winrar-command-line-to-add-files-with-relative-path-only.html)
Just in case this helps: I am currently working on an MS Access Database project (customer relations management for a small company), and one of the tasks there is to zip docx-files to be sent to customers, with a certain password encryption used.
In the VBA procedure that triggers the zip-packaging of the docx-files, I call WinRAR as follows:
c:\Programme\WinRAR\winrar.exe a -afzip -ep -pThisIsThePassword "OutputFullName" "InputFullName"
-afzip says: "Create a zip file (as opposed to a rar file)
-ep says: Do not include the paths of the source file, i.e. put the file directly into the zip folder
A full list of such switches is available in the WinRAR Help, section "Command line".
x extracts it as E:\Testing\Builds\CCBuilds2\Testing\Builds\CCBuilds\, because you're using full path when declaring the source. Either use -ep1 or set the default working dir to E:\Testing\Builds.
Use of -ep1 is needed but it's a bit tricky.
If you use:
Winrar.exe a output.rar inputpath
Winrar.exe a E:\Testing\Builds\CCBuilds.rar E:\Testing\Builds\CCBuilds
it will include the input path declared:
E:\Testing\Builds\CCBuilds -> E:\Testing\Builds\CCBuilds.rar:
Testing\Builds\CCBuilds\file1
Testing\Builds\CCBuilds\file2
Testing\Builds\CCBuilds\folder1\file3
...
which will end up unpacked as you've mentioned:
E:\Testing\Builds\CCBuilds2\Testing\Builds\CCBuilds\
There are two ways of using -ep1.
If you want the simple path:
E:\Testing\Builds\CCBuilds\
to be extracted as:
E:\Testing\Builds\CCBuilds2\CCBuilds\file1
E:\Testing\Builds\CCBuilds2\CCBuilds\file2
E:\Testing\Builds\CCBuilds2\CCBuilds\path1\file3
...
use
Winrar.exe a -ep1 E:\Testing\Builds\CCBuilds.rar E:\Testing\Builds\CCBuilds
the files inside the archive will look like:
CCBuilds\file1
CCBuilds\file2
CCBuilds\folder1\file3
...
or you could use ep1 to just add the files and folder structure sans the base folder with the help of recursion and defining the base path as the inner path of the structure:
Winrar.exe a -ep1 -r E:\Testing\Builds\CCBuilds.rar E:\Testing\Builds\CCBuilds\*
The files:
E:\Testing\Builds\CCBuilds\file1
E:\Testing\Builds\CCBuilds\file2
E:\Testing\Builds\CCBuilds\folder1\file3
...
inside the archive will look like:
file1
file2
folder1\file3
...
when extracted will look like:
E:\Testing\Builds\CCBuilds2\file1
E:\Testing\Builds\CCBuilds2\file2
E:\Testing\Builds\CCBuilds2\folder1\file3
...
Anyway, these are two ways -ep1 can be used to exclude base path with or without the folder containing the files (the base folder / or base path).