I am trying to make a program that will write data to a file for another program to be able to read the data from it. The problem is that I can't figure out a way to do this when the file i am reading and writing from is in another directory than both of my programs. I know there are other ways of doing this, but I just thought that it would be useful to know how to do it. Anyone that can help me?
You can use the full path, e.g
local f1 = io.open('D:/test/b.txt') -- Windows
local f2 = io.open('/test/b.txt') -- Unix
or use relative path, e.g
local f = io.open('../../test/b.txt')
In this example, the file is in the test directory of the parent directory (..) of parent directory.
Related
I want to create an alias, which will take file name, get its path and open it by gvim.
Something like this:
alias gg "gvim `which \`"
usage:
> gg some_file_in_remote_path
But I cannot make it work in csh.
Can someone help please
The command "which" gets a full path of of shell commands.
It does not find the full path of of every file you have in your system.
The command you are looking for is "find", although searching the entire file system could be time consuming. Perhaps install "locate" and use that instead of find. Even then you would have to decide in your script what to do when multiple files have the same name.
I'm relatively new to Netlogo and already struggling ;)
I have the following problem: I want my program to open a folder, check a file in that folder and afterwards remove that file from that folder. I figured the best way to do this is via a while loop, but I'm struggling to find the right syntax. Hope you all can help!
The command 'file-open' will open a file using the path provided (the string after file-open: e.g. file-open "C:\Documents\model-out.txt" will open a file titled model-out.txt in the Documents folder on the C drive.)
You can then use 'file-read' or 'file-write' to read or write to the file respectively.
The command 'file-close' will close the file, which then can be deleted with 'file-delete'.
You can also check if a file exists in a folder using the command if file-exists? "C:\Documents\model-out.txt", and if true, the file can be deleted using file-delete.
Also check the command 'set-current-directory'.
Best,
I'm trying to load group of folders files in one time with when
i set
sourceURI = 'gs://ybbi/bi_landing_zone/files_to_load/app/reports/app_network_analytics_report/201409011*'
all the folders that i'm want to load start with 20140911
but i get the error:
ERROR: Invalid path: gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/
20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0 is one of these folders(don't know why it's print the all folder name of this specific folder)
in some other folder tree cases it's works, but in this specific folder tree it's return the same error .
i know that cloud storage don't have real folders and it's part of the name of the object, but you understand what i mean.
is it bug?
Without more information, what it looks like is that you have a object file called gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/ that is not a csv/json file. Some tools may create these dummy files in order to simulate directories. BigQuery requires all objects that match the input glob path to be importable files.
One solution would be to change the glob path to include a narrower set of files. You can pass multiple paths if that makes things easier. For example, you could pass
gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_3bab8ec0_092a_43de_a157_db35d1555ea0/*
and
gs://ybbi/bi_landing_zone/files_to_load/apn/reports/appnexus_network_analytics_report/20140901191111_some_other_path/*
is it possible to load module from file with extension other than .lua?
require("grid.txt") results in:
module 'grid.txt' not found:
no field package.preload['grid.txt']
no file './grid/txt.lua'
no file '/usr/local/share/lua/5.1/grid/txt.lua'
no file '/usr/local/share/lua/5.1/grid/txt/init.lua'
no file '/usr/local/lib/lua/5.1/grid/txt.lua'
no file '/usr/local/lib/lua/5.1/grid/txt/init.lua'
no file './grid/txt.so'
no file '/usr/local/lib/lua/5.1/grid/txt.so'
no file '/usr/local/lib/lua/5.1/loadall.so'
no file './grid.so'
no file '/usr/local/lib/lua/5.1/grid.so'
no file '/usr/local/lib/lua/5.1/loadall.so'
I suspect that it's somehow possible to load the script into package.preaload['grid.txt'] (whatever that is) before calling require?
It depends on what you mean by load.
If you want to execute the code in a file named grid.txt in the current directory, then just do dofile"grid.txt". If grid.txt is in a different directory, give a path to it.
If you want to use the path search that require performs, then add a template for .txt in package.path, with the correct path and then do require"grid". Note the absence of suffix: require loads modules identified by names, not by paths.
If you want require("grid.txt") to work should someone try that then yes, you'll need to manually loadfile and run the script and put whatever it returns (or whatever require is documented to return when the module doesn't return anything) into package.loaded["grid.txt"].
Alternatively, you could write your own loader just for entries like this which you set into package.preload["grid.txt"] which finds and loads/runs the file or, more generically, you could write yourself a loader function, insert it into package.loaders, and then let it do its job whenever it sees a "*.txt" module come its way.
First, this question relates to Oracle SQL Developer 3.2, not SQL*Plus or iSQL, etc. I've done a bunch of searching but haven't found a straight answer.
I have several collections of scripts that I'm trying to automate (and btw, my SQL experience is pretty basic and mostly MS-based). The trouble I'm having is executing them by a relative path. for example, assume this setup:
scripts/A/runAll.sql
| /A1.sql
| /A2.sql
|
/B/runAll.sql
/B1.sql
/B2.sql
I would like to have a file scripts/runEverything.sql something like this:
##/A/runAll.sql
##/B/runAll.sql
scripts/A/runAll.sql:
##/A1.sql
##/A2.sql
where "##", I gather, means relative path in SQL*Plus.
I've fooled around with making variables but without much luck. I have been able to do something similar using '&1' and passing in the root directory. I.e.:
scripts/runEverything.sql:
#'&1/A/runAll.sql' '&1/A'
#'&1/B/runAll.sql' '&1/B'
and call it by executing this:
#'c:/.../scripts/runEverything.sql' 'c:/.../scripts'
But the problem here has been that B/runAll.sql gets called with the path: c:/.../scripts/A/B.
So, is it possible with SQL Developer to make nested calls, and how?
This approach has two components:
-Set-up the active SQL Developer worksheet's folder as the default directory.
-Open a driver script, e.g. runAll.sql, (which then changes the default directory to the active working directory), and use relative paths within the runAll.sql script to call sibling scripts.
Set-up your scripts default folder. On the SQL Developer toolbar, Use this navigation:
Tools > Preferences
In the preference dialog box, navigate to Database > Worksheet > Select default path to look for scripts.
Enter the default path to look for scripts as the active working directory:
"${file.dir}"
Create a script file and place all scripts associated in it:
runAll.sql
A1.sql
A2.sql
The content of runAll.sql would include:
#A1.sql;
#A2.sql;
To test this approach, in SQL Developer, click on File and navigate and open the script\runAll.sql file.
Next, select all (on the worksheet), and execute.
Through the act of navigating and opening the runAll.sql worksheet, the default file folder becomes "script".
I don't have access to SQL Developer right now so i can't experiment with the relative paths, but with the substitution variables I believe the problem you're seeing is that the positional variables (i.e. &1) are redefined by each start or #. So after your first #runAll, the parent script sees the same &1 that the last child saw, which now includes the /A.
You can avoid that by defining your own variable in the master script:
define path=&1
#'&path/A/runAll.sql' '&path/A'
#'&path/B/runAll.sql' '&path/B'
As long as runAll.sql, and anything that runs, does not also (re-define) path this should work, and you just need to choose a unique name if there is the risk of a clash.
Again I can't verify this but I'm sure I've done exactly this in the past...
you need to provide the path of the file as String , give the patch in double quote it will work
**
For Example
#"C:\Users\Arpan Saini\Zions R2\Reports Statements and Notices\Patch\08312017_Patch_16.2.3.17\DB Scripts\snsp.sql";
**
Execution of Sql
#yourPath\yourFileName.sql
How to pass parameters in file
#A1.sql; (Parameter)
#A2.sql; (Parameter)
This is not absolute or relative path issue. It's the SQL interpreter issue, where by default it will look for files which are having .sql extention.
Please make sure to modify the file name to file_name.sql
Ex: if workspace is having file name called "A", then move the file from A to "A.sql"