Simple utility to get a file for use.
Using openfiledialog I am trying to get the full path EG: File = text1.txt and it is located in c:\temp. So the full path is C:\temp\text1.txt.
But all I can get is the file name. I've searched I've hunted, I'e tried for a couple of hours and nothing works.
Here is code with comments...
'open the openfile dialog so the user can search for a file
Dim openFileDialog1 As New OpenFileDialog()
'set the root to the z drive
openFileDialog1.InitialDirectory = "Z:\"
'make sure the root goes back to where the user started
openFileDialog1.RestoreDirectory = True
'show the dialog
openFileDialog1.ShowDialog()
'check there is something to work with... the user did not exit before selecting a file etc.
If openFileDialog1.FileName.Length = 0 Then
'if the user selected a file set the value of the replacefile text box
Else
TB_ReplacementFile.Text = System.IO.Path.GetFullPath(openFileDialog1.FileName)
End If
All I get is the file name...
The MSDN documentation and numerous posts all over the place say all you need is openfiledialog.FileName. However this did not work for me, can't tell you why. What DID work is to use this:
TB_ReplacementFile.Text = System.IO.Path.GetFullPath(openFileDialog1.FileName)
This works great, I get what I need. I cannot explain why I have to do this. Not sure how I can be the problem, but that must be the problem right?!
Hopefully this helps someone.
The FileName Property returns the full path.
The file name includes both the file path and the extension. If no files are selected, this method returns an empty string ("").
If (openFileDialog1.ShowDialog = Windows.Forms.DialogResult.OK) Then
TB_ReplacementFile.Text = openFileDialog1.FileName
End If
Not 100% sure if this would resolve the issue you're having, or if it's simply just another way to handle it, but I prefer to check the DialogResult. I.E:
Dim openFileDialog1 As New OpenFileDialog()
openFileDialog1.InitialDirectory = "Z:\"
openFileDialog1.RestoreDirectory = True
If openFileDialog1.ShowDialog = System.Windows.Forms.DialogResult.Ok Then
Console.WriteLine(openFileDialog1.fileName)
End If
this worked to get the directory or path
dim sDir as String = System.IO.Path.GetDirectoryName(openfiledialog1.FileName.ToString)
Related
I am writing a small program in which user will select set of file (mostly .CSV) files and my program will search through them and find required data.
It's working for up to 300 files, but after that its not working. It's giving me an error:
InvalidOperationExceprion was Unhandaled
Too Many files are selected. Select Fewer files and try again.
What should i do?
Like Eric Walker said, open file dialog works with 1,000's and 1,000's of files, there is no reason why it would stop at 300.
The best way to loop though files/folders to get info is to use the .GetFiles() method
Dim OFD As New FolderBrowserDialog
If OFD.ShowDialog = DialogResult.OK Then
For Each f In Directory.GetFiles(OFD.SelectedPath)
If Path.GetExtension(f) = ".txt" Path.GetExtension(f) = ".csv" Then
Dim reader As String() = File.ReadAllLines(f)
For each line as String in reader
DoSomethingAwesome(line)
Next
End If
Next
End If
This will cycle through every file in a certain Directory.
Now if you would like to cycle through every file in a file dialog, then you would use this.
Dim OFD As New OpenFileDialog()
OFD.Multiselect = True
If OFD.ShowDialog = DialogResult.OK Then
For Each f In OFD.FileNames
If Path.GetExtension(f) = ".txt" Path.GetExtension(f) = ".csv" Then
Dim reader As String() = File.ReadAllLines(f)
For Each line As String In reader
DoSomethingAwesome(line)
Next
End If
Next
End If
Give one of these a try depending on your preference.
As a side note, for future posts - please post your attempted code or more details on what you are trying to accomplish and where you are having trouble. Frankly, Im surprised you weren't downvoted (very surprised, people on SO can be ruthless). Just a friendly tip.
Ok, so my code look like the following.
Dim file As System.IO.StreamWriter
file = My.Computer.FileSystem.OpenTextFileWriter("E:/Med/Dra.txt", False)
file.WriteLine(NameBasic)
file.WriteLine(LastBasic)
file.WriteLine(PhoneBasic)
file.Close();
All those are variables that I have set for text boxes. This is OnbuttonClick(...
Now for my onload I take the info out of the notepad, Here is the code,
Dim read As System.IO.StreamReader
read = My.Computer.FileSystem.OpenTextFileReader("E:/Med/Dra.txt")
lblNameBasic.Text = read.ReadLine
lblLastBasic.Text = read.ReadLine
lblPhoneBasic.Text = read.ReadLine
read.Close();
I have placed the notepad(txt file) inside a flashdrive folder named med
I got the saving info to work and load, so I took the flashdrive to another computer, I got this nasty error, talking about the System.IO and all this other stuff.
It then prompts me, would you like to continue with errors, or quit.
I click continue than all the saved data does not load. Am I doing something wrong here??
Also sorry for alot of questions today. (The .exe is in the flashdrive, med folder aswell).
First of all, your path is incorrect - E:/Med/Dra.txt should be E:\Med\Dra.txt. And here how you use open file dialog - this is just basis, you need to take care of error handling, etc.
Dim openFileDialog1 As New OpenFileDialog()
openFileDialog1.InitialDirectory = "c:\"
openFileDialog1.Filter = "txt files (*.txt)|*.txt"
openFileDialog1.RestoreDirectory = True
If openFileDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK Then
Dim read As System.IO.StreamReader = My.Computer.FileSystem.OpenTextFileReader(openFileDialog1.FileName)
End If
I think, main reason why you had errors is because incorrect path. You can also check if path exists
If Not File.Exists("E:\Med\Dra.txt") Then
MessageBox.Show("There is no such file")
Exit Sub
End If
' Code to open non existing file will be skipped
I have a Webbrowser control in a form which displays a pdf file. I have to specify the URL as the file location on my computer.
eg.
E:\Folder\Manual.pdf
Both the pdf file and the program are in the same folder.
How do I specify the URL so that when I move the folder onto another drive, it opens the same pdf file?
The location of your application is
Dim path as String = My.Application.Info.DirectoryPath
The you could use:
Dim pdffile as String = IO.Path.Combine(path, "pdffile.pdf")
WebBrowser1.Navigate(pdffile)
If I understand you correctly, then:
Dim myPdf As String =
IO.Path.Combine(IO.Directory.GetParent(Application.ExecutablePath).FullName, "myPdfFile.pdf")
Another way you could do it is by using something like the code below;
Private Sub FamilyLocateFile_Click(sender As Object, e As EventArgs) Handles FamilyLocateFile.Click
If LocateFamilyDialog.ShowDialog = DialogResult.OK Then
FamilyWMP.URL = LocateFamilyDialog.FileName
ElseIf LocateFamilyDialog.ShowDialog = DialogResult.Cancel Then
MsgBox(MsgBoxStyle.Critical, "Error!")
End If
End Sub
What this will do is play a file in a Windows Media Player ActiveX object. The file can be selected with an OpenFile Dialog, which in this case is called LocateFamilyDialog. You don't need the ElseIf part of the statement, but you will need to insert an open file dialog and a control that can display PDFs. I think it'll work with WebBrowsers, but I'm not sure.
I'm trying to build a simple FTP uploader. How can I make it so the user can select a file to upload? See, what I want is to have a button (which I do) that a user can click, and it shows the OpenFileDialog (which I have), but then when they select a file, I want its path to be shown in a text box. How can I do that?
Try the following code
Dim dialog As New OpenFileDialog()
If DialogResult.OK = dialog.ShowDialog Then
TextBox1.Text = dialog.FileName
End If
One way is to convert the filename to a FileInfo which contains all sorts of information about the file including the path. This opens the dialog and displays the path of the selected file.
If OpenFileDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK Then
Dim fi As New System.IO.FileInfo(OpenFileDialog1.FileName)
TextBox1.Text = fi.DirectoryName
End If
You want to get the OpenFileDialog's property Filename property. See OpenFileDialog's class members here on MSDN.
Hope this helps
Add a OpenFileDialog And Add This Code
If YourOpenFileDialogName.ShowDialog = YourOpenFileDialogName.OK Then
textBox1.Text = YourOpenFileDialogName.FileName
End If
I have a fairly straight forward peice of code that just tries to set the default saved directory for a standard .net save dialogue to a specific folder. If that folder doesn't exist, it sets it to the desktop.
This works fine for everyone but one user who is getting the following error:
Could not find special directory 'Desktop'
How is that even possible?
'Check if folder exists
If Not IO.Directory.Exists(strDirectory) Then
strDirectory = FileIO.SpecialDirectories.Desktop
If Not IO.Directory.Exists(strDirectory) Then
strDirectory = IO.Directory.GetCurrentDirectory
End If
End If
'Show save file dialogue.
Dim folderDlg As New Windows.Forms.FolderBrowserDialog
folderDlg.RootFolder = Environment.SpecialFolder.Desktop
folderDlg.SelectedPath = strDirectory
folderDlg.ShowNewFolderButton = True
How about:
strDirectory = _
Environment.GetFolderPath(Environment.SpecialFolder.Desktop).ToString()
I use GetFolderPath() to get "My Documents" and it works fine (I don't ever have to think about it).