I'm trying to build a simple FTP uploader. How can I make it so the user can select a file to upload? See, what I want is to have a button (which I do) that a user can click, and it shows the OpenFileDialog (which I have), but then when they select a file, I want its path to be shown in a text box. How can I do that?
Try the following code
Dim dialog As New OpenFileDialog()
If DialogResult.OK = dialog.ShowDialog Then
TextBox1.Text = dialog.FileName
End If
One way is to convert the filename to a FileInfo which contains all sorts of information about the file including the path. This opens the dialog and displays the path of the selected file.
If OpenFileDialog1.ShowDialog() = System.Windows.Forms.DialogResult.OK Then
Dim fi As New System.IO.FileInfo(OpenFileDialog1.FileName)
TextBox1.Text = fi.DirectoryName
End If
You want to get the OpenFileDialog's property Filename property. See OpenFileDialog's class members here on MSDN.
Hope this helps
Add a OpenFileDialog And Add This Code
If YourOpenFileDialogName.ShowDialog = YourOpenFileDialogName.OK Then
textBox1.Text = YourOpenFileDialogName.FileName
End If
Related
I am writing a small program in which user will select set of file (mostly .CSV) files and my program will search through them and find required data.
It's working for up to 300 files, but after that its not working. It's giving me an error:
InvalidOperationExceprion was Unhandaled
Too Many files are selected. Select Fewer files and try again.
What should i do?
Like Eric Walker said, open file dialog works with 1,000's and 1,000's of files, there is no reason why it would stop at 300.
The best way to loop though files/folders to get info is to use the .GetFiles() method
Dim OFD As New FolderBrowserDialog
If OFD.ShowDialog = DialogResult.OK Then
For Each f In Directory.GetFiles(OFD.SelectedPath)
If Path.GetExtension(f) = ".txt" Path.GetExtension(f) = ".csv" Then
Dim reader As String() = File.ReadAllLines(f)
For each line as String in reader
DoSomethingAwesome(line)
Next
End If
Next
End If
This will cycle through every file in a certain Directory.
Now if you would like to cycle through every file in a file dialog, then you would use this.
Dim OFD As New OpenFileDialog()
OFD.Multiselect = True
If OFD.ShowDialog = DialogResult.OK Then
For Each f In OFD.FileNames
If Path.GetExtension(f) = ".txt" Path.GetExtension(f) = ".csv" Then
Dim reader As String() = File.ReadAllLines(f)
For Each line As String In reader
DoSomethingAwesome(line)
Next
End If
Next
End If
Give one of these a try depending on your preference.
As a side note, for future posts - please post your attempted code or more details on what you are trying to accomplish and where you are having trouble. Frankly, Im surprised you weren't downvoted (very surprised, people on SO can be ruthless). Just a friendly tip.
Simple utility to get a file for use.
Using openfiledialog I am trying to get the full path EG: File = text1.txt and it is located in c:\temp. So the full path is C:\temp\text1.txt.
But all I can get is the file name. I've searched I've hunted, I'e tried for a couple of hours and nothing works.
Here is code with comments...
'open the openfile dialog so the user can search for a file
Dim openFileDialog1 As New OpenFileDialog()
'set the root to the z drive
openFileDialog1.InitialDirectory = "Z:\"
'make sure the root goes back to where the user started
openFileDialog1.RestoreDirectory = True
'show the dialog
openFileDialog1.ShowDialog()
'check there is something to work with... the user did not exit before selecting a file etc.
If openFileDialog1.FileName.Length = 0 Then
'if the user selected a file set the value of the replacefile text box
Else
TB_ReplacementFile.Text = System.IO.Path.GetFullPath(openFileDialog1.FileName)
End If
All I get is the file name...
The MSDN documentation and numerous posts all over the place say all you need is openfiledialog.FileName. However this did not work for me, can't tell you why. What DID work is to use this:
TB_ReplacementFile.Text = System.IO.Path.GetFullPath(openFileDialog1.FileName)
This works great, I get what I need. I cannot explain why I have to do this. Not sure how I can be the problem, but that must be the problem right?!
Hopefully this helps someone.
The FileName Property returns the full path.
The file name includes both the file path and the extension. If no files are selected, this method returns an empty string ("").
If (openFileDialog1.ShowDialog = Windows.Forms.DialogResult.OK) Then
TB_ReplacementFile.Text = openFileDialog1.FileName
End If
Not 100% sure if this would resolve the issue you're having, or if it's simply just another way to handle it, but I prefer to check the DialogResult. I.E:
Dim openFileDialog1 As New OpenFileDialog()
openFileDialog1.InitialDirectory = "Z:\"
openFileDialog1.RestoreDirectory = True
If openFileDialog1.ShowDialog = System.Windows.Forms.DialogResult.Ok Then
Console.WriteLine(openFileDialog1.fileName)
End If
this worked to get the directory or path
dim sDir as String = System.IO.Path.GetDirectoryName(openfiledialog1.FileName.ToString)
I have a Webbrowser control in a form which displays a pdf file. I have to specify the URL as the file location on my computer.
eg.
E:\Folder\Manual.pdf
Both the pdf file and the program are in the same folder.
How do I specify the URL so that when I move the folder onto another drive, it opens the same pdf file?
The location of your application is
Dim path as String = My.Application.Info.DirectoryPath
The you could use:
Dim pdffile as String = IO.Path.Combine(path, "pdffile.pdf")
WebBrowser1.Navigate(pdffile)
If I understand you correctly, then:
Dim myPdf As String =
IO.Path.Combine(IO.Directory.GetParent(Application.ExecutablePath).FullName, "myPdfFile.pdf")
Another way you could do it is by using something like the code below;
Private Sub FamilyLocateFile_Click(sender As Object, e As EventArgs) Handles FamilyLocateFile.Click
If LocateFamilyDialog.ShowDialog = DialogResult.OK Then
FamilyWMP.URL = LocateFamilyDialog.FileName
ElseIf LocateFamilyDialog.ShowDialog = DialogResult.Cancel Then
MsgBox(MsgBoxStyle.Critical, "Error!")
End If
End Sub
What this will do is play a file in a Windows Media Player ActiveX object. The file can be selected with an OpenFile Dialog, which in this case is called LocateFamilyDialog. You don't need the ElseIf part of the statement, but you will need to insert an open file dialog and a control that can display PDFs. I think it'll work with WebBrowsers, but I'm not sure.
I have used the filter method of openFileDialogBox to allow multiple file types to be opened, but the user must select which file type they want using the dropdown. Only files with extensions matching the selected file type are visible.
How can I show all files with extensions that match any of my allowed file types? I don't want all files to be visible/openable, just the ones that I have designated.
Just specify what you want to allow... Just an example...
Dim dlg As New OpenFileDialog()
'Filter by Office Files
dlg.Filter = "Office Files|*.doc;*.xls;*.ppt"
dlg.ShowDialog()
A small snippet of how it works
Dim result As DialogResult = New DialogResult()
OpenFileDialog1.Filter = "Word Documents|*.doc;*.docx|PowerPoint Slides|*.ppt|Video Files|*.MP4|PDF Files|*.pdf"
OpenFileDialog1.InitialDirectory = "C:\"
OpenFileDialog1.FileName = ""
result = OpenFileDialog1.ShowDialog()
Good morning everyone,
I'm working on my finals project in visual basic and i want to implement a save file option.
Right now the application has 2 textboxes (not richtextbox) which are the input and output of information.
What i want to do is save only the content of the output textbox. I managed to get it to save something to file but when its opened it always turns out to be empty.
the code example of the save file button is below, i have a feeling its not saving the content because it is not specified, yet i have no idea how to specify to only save the content of the one textbox even with the many hours of forum / google searching ive done to try and figure out on my own.
Dim myStream As Stream
Dim nsavetxtoutput As New SaveFileDialog()
'|All files (*.*)|*.*
nsavetxtoutput.Filter = "txt files (*.txt)|*.text"
nsavetxtoutput.FilterIndex = 2
nsavetxtoutput.RestoreDirectory = True
If nsavetxtoutput.ShowDialog() = DialogResult.OK Then
myStream = nsavetxtoutput.OpenFile()
If (myStream IsNot Nothing) Then
' Code to write the stream goes here.
myStream.Close()
End If
End If
Any and all insight would be much appreciated!
Thank you guys!
The Program allowed to save only the contents of the textbox with this function - Thanks very much everyone who replied. it helped out allot!
Private Sub NOTEPAD_BUTTON(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles BTSave2Notepad.Click
Dim nsavetxtoutput As New SaveFileDialog()
nsavetxtoutput.Filter = "txt files (*.txt)|*.text"
nsavetxtoutput.FilterIndex = 2
nsavetxtoutput.RestoreDirectory = True
If nsavetxtoutput.ShowDialog() = DialogResult.OK Then
IO.File.WriteAllText(nsavetxtoutput.FileName, txtoutput.Text)
End If
End Sub
Try this:
If nsavetxtoutput.ShowDialog() = DialogResult.OK Then
IO.File.WriteAllText(nsavetxtoutput.FileName, TextBox2.Text)
End If
Where TextBox2 is your output TextBox.
More information at MSDN Documentation.
You can write to a file using File.WriteAllText method. It takes two parameters. The first is the path to the file, which you get from the SaveFileDialog. The second is the value you want to write to the file.
See the article on MSDN