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How can i write a code that i want to choose name and adress of a customer which customer_id is bigger than him. Thank you very much.
select c.name,a.adress,a.postcode_id from customer c left join Adress a on c.customer_id=a.customer_id where c.customer_id>11
SELECT cs.name,ad.adress
FROM Customer cs, Adress ad
WHERE cs.customer_id=ad.customer_id
AND cs.customer_id>11;
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Please, how do I SELECT, to get the result column?
columns
SELECT machine, software
FROM ms_tbl
INNER JOIN machine_tbl
ON machine_tbl.machine_id = ms_tbl.machine_id
INNER JOIN software_tbl
ON software_tbl.software_id = ms_tbl.software_id;
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oracle query is not working. Please specify what is wrong in this query?
(select hacker_id,challenge_id, max(score) as soc
from submissions
group by hacker_id,challenge_id
having max(score)>0) t2;
Please read #OldProgrammer comments. Anyway, I think this should work for you
select hacker_id,challenge_id, max(score) as soc
from submissions
group by hacker_id,challenge_id
having max(score)>0;
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Could anyone help me on the below please?
I have a field called F1.Images and I need to divide by 2 ONLY when my other field W1.Plex is Duplex else I need to retain the F1.Images count.
Thanks Satya
Sorted Brad.
Used Case/When logic. Here's the Answer:
Case
WHEN W1.Plex = 'Duplex' then (F1.images / 2)
Else F1.images
End AS Pages
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I have a Screen table which has name and display_name columns. I am trying to replace the word Lawfirm with Law Firm in name and display_name columns for all the records of Screen table.
My SQL experience is pretty premature, I am wondering is there a way to achieve this using a SQL script?
Yes, you can do this:
update screen
set display_name = replace(display_name, 'Lawfirm', 'Law Firm')
where display_name like '%Lawfirm%';
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My table name is SOFTSKILL. One of Columns is MakeID. The values in the column are,
000277755
000278143
000277738
000277051
i need to change 000 into 100, like
100277755
100278143
100277738
100277051
Anybody please help me how to do this..
UPDATE SOFTSKILL
SET MakeId = STUFF(MakeId,1,1,'1')
WHERE MakeId LIKE '000%'