Laravel Display a record details while grouped by year or month - sql

Question

I just moved to the laravel framework and am starting to migrate some legacy sites and I have hit a problem with SQL or blade - dunno which.
I have to display a load of rows 'sports classes' which are grouped by year and then month. each needs to show attendance etc.
I am unsure which way to proceed.
I am able to display all rows and sort by date - easy squeezy
I am able to groupBy year AND month - fiddly but sorted it.
These are all displayed in an accordian.
Click the month - the individual rows drop down - you get the idea
I can get a number of rows per month/year
What I am unable to figure out is how to actually display the rows.
The groupBy is this:
$LinkClasses = DB::table('classes_lists')
->select('id, class, teacher, size')
->select(DB::raw('YEAR(date) AS year, MONTH(date) AS month, MONTHNAME(date) AS month_name, COUNT(*) post_count'))
->groupBy('year')
->groupBy('month')
->orderBy('year', 'desc')
->orderBy('month', 'desc')
->orderBy('id', 'desc')

Answer 1

If the code you provided is within your controller, then you can append ->get() after your last ->orderBy(). This will return a Collection. You can then do whatever you want with the Collection (http://laravel.com/api/master/Illuminate/Support/Collection.html), including conversion to an array using ->toArray(), but I think it would be best to utilize the Eloquent ORM if possible.
Anyway, once you have it in the format you want, just pass it to the view like so:
return view('your.view', compact('LinkClasses'));
Then, inside the your.view blade template, you can access this by using the following:
#foreach ($LinkClasses as $currentRow)
<tr>
<td>{{ $currentRow['id'] }}</td>
<td>{{ $currentRow['class'] }}</td>
<td> ... </td>
</tr>
#endforeach
Best guess I can offer without seeing the blade template to get a better idea of what you're doing. Hope that helps!
UPDATE BASED ON OP FEEDBACK:
Since you are only receiving a single record, it seems as though the issue lies in your query. I suggest you simplify your query to fetch all records and then do your sorting within an array. Something like this in your controller:
$allClasses = DB::table('classes_lists')->all();
foreach ($allClasses as $currentClass) {
$yearMonth = date('Y-m', $currentClass['date']);
$classesByYearMonth[$yearMonth][] = $currentClass;
}
ksort($classesByYearMonth);
/* now you have an array of all classes sorted by year-month like this:
// $classesByYearMonth[2014-01] = array(
// [0] => array(1, 'class name', 'teacher name', 23),
// [1] => array(2, 'another class', 'different teacher', 25),
// ...
// );
//
// $classesByYearMonth[2014-02] = ...
*/
return view('your.view', compact('classesByYearMonth'));
Then, inside your blade template:
#foreach ($classesByYearMonth as $yearMonth => $classListArray)
Found {{ sizeof($classListArray) }} classes for {{ $yearMonth }}
#foreach ($classListArray as $currentClass)
<div>
<div>ID: {{ $currentClass['id'] }}</div>
<div>Class: {{ $currentClass['class'] }}</div>
<div>Teacher: {{ $currentClass['teacher'] }}</div>
<div>Size: {{ $currentClass['size'] }}</div>
</div>
#endforeach
#endforeach
I will leave it to you to fix the formatting to make your accordion work. But hopefully that will get you on the right path.

Answer 2

DNoe - thank you so much.
Your reply put me on exactly the right track.
I had to mod some bits due to laravel ambiguities and add the strtotime but the logic was all there.
foreach ($allClasses as $currentClass) {
$ym = $currentClass['date'];
$yearMonth = date("Y-m",strtotime($ym));
$classesByYearMonth[$yearMonth][] = $currentClass;
}
krsort($classesByYearMonth);
return View::make('classes.index', compact('classesByYearMonth'));
The css is simple from here.
I owe you some beers. And thanks for helping me take my head from my butt!
Send me a pm and i would be very very happy to forward beer donation :o
Great work and thank you again. :)

Answer 3

Also, part of the problem was that the results were throwing an stdObject rather than an array.
Being able to compare your code with my own has enabled me to create a dbquery with multiple joins from which meaningfull data is selected and then converted to an array.
$classes = DB::table('table2')
->join('table1', 'table2.id', '=', 'table1.id2' )
->join('table3', 'table1.id3', '=', 'table3.id' )
->orderBy('classes_lists.date','DESC')
->get(array('table1.id', 'teacher', 'date', 'size', 'students', 'fname', 'classname', 'table1.notes'));
$cfr = count($classes);
foreach($classes as $object)
{
$arrays[] = (array) $object;
}
foreach ($arrays as $currentClass){
$ym = $currentClass['date'];
$yearMonth = date("Y-m",strtotime($ym));
$clazByYearMonth[$yearMonth][] = $currentClass;
}
krsort($clazByYearMonth);
This was the output into blade:
Not formatted :
#foreach ($clazByYearMonth as $yearMonth => $classListArray)
Found {{ sizeof($classListArray) }} classes for {{ $yearMonth }}
#foreach ($classListArray as $currentClass)
<div>
date: {{ $currentClass['date'] }} | class: {{ $currentClass['classname'] }} | Size: {{ $currentClass['size'] }} Teacher: {{ $currentClass['fname'] }} |
</div>
#endforeach
#endforeach