Draw an ellipse sqrt-based function - vb.net

I'm trying to make a function in Lua or VB based code to
draw / plot an ellipse and also a filled ellipse.
I don't have much knowledge about this math and I can use some help.
I googled everything there is to google about drawing ellipses with code but I can't find a good simple working example that i can code into my Lua / VB code.
here are a few websites i visited but couldn't make the code work or couldn't convert the code to Lua or VB properly...
https://sites.google.com/site/ruslancray/lab/projects/bresenhamscircleellipsedrawingalgorithm/bresenham-s-circle-ellipse-drawing-algorithm
http://groups.csail.mit.edu/graphics/classes/6.837/F98/Lecture6/circle.html
http://www.blitzbasic.com/codearcs/codearcs.php?code=2817
http://hackipedia.org/Algorithms/Graphics/pdf/A%20Fast%20Bresenham%20Type%20Algorithm%20For%20Drawing%20Ellipses%20by%20John%20Kennedy.pdf
https://scratch.mit.edu/projects/49873666/
http://www.sourcecodesworld.com/source/show.asp?ScriptID=112
How do I draw an ellipse with arbitrary orientation pixel by pixel?
Can anyone help me make code that can draw an ellipse and a filled ellipse?
here is some code I tried to convert to Lua from here:
https://gist.github.com/Wollw/3291916
this code has some problems (missing pixels) and I think it's not converted properly but I don't know how to do it otherwise.
function plotEllipseRect(x0, y0, x1, y1)
-- values of diameter
a = math.abs(x1-x0)
b = math.abs(y1-y0)
b1 = 2.5
-- error increment
dx = 4*(1-a)*b*b
dy = 4*(b1+1)*a*a
-- error of 1.step
err = dx+dy+b1*a*a
-- e2 = 0
if (x0 > x1) then -- if called with swapped points
x0 = x1
x1 = x1 + a
end
if (y0 > y1) then -- .. exchange them
y0 = y1
end
-- starting pixel
y0 = y0 + (b+1)/2
y1 = y0-b1
a = a * 8*a
b1 = 8*b*b
repeat
dot(x1, y0) -- I. Quadrant
dot(x0, y0) -- II. Quadrant
dot(x0, y1) -- III. Quadrant
dot(x1, y1) -- IV. Quadrant
e2 = 2*err
if (e2 <= dy) then -- y step
y0 = y0 + 1
y1 = y1 - 1
dy = dy + a
err = err + dy
end
if (e2 >= dx or 2*err > dy) then -- x step
x0 = x0 + 1
x1 = x1 - 1
dx = dx + b1
err = err + dx
end
until (x0 >= x1)
while (y0-y1 < b) do -- too early stop of flat ellipses a=1
dot(x0-1, y0) -- -> finish tip of ellipse
y0 = y0 + 1
dot(x1+1, y0)
dot(x0-1, y1)
y1 = y1 - 1
dot(x1+1, y1)
end
end
[EDIT:]
I almost got it for the filled one!
see the comments in this code below to know what the problem is...
I use EGSL to test this Lua code:
http://www.egsl.retrogamecoding.org//pages/downloads.php
function DrawEllipse(xc,yc,w,h)
local w2 = w * w
local h2 = h * h
local fw2 = 4 * w2
local fh2 = 4 * h2
xc = xc + w
yc = yc + h
local x = 0
local y = h
local s = 2 * h2 + w2 * (1 - h)
while h2 * x <= w2 * y do
dot(xc + x, yc + y)
dot(xc - x, yc + y)
dot(xc + x, yc - y)
dot(xc - x, yc - y)
redraw()
inkey()
color(int(rnd()*255),int(rnd()*255),int(rnd()*255)) --random color to see changes
if s >= 0 then
s = s + fw2 * (1 - y)
y = y - 1
color(255,0,255)
line(xc + x, yc + y, xc - x, yc + y)
line(xc + x, yc - y, xc - x, yc - y)
end
s = s + h2 * ((4 * x) + 6)
x = x + 1
end
x = w
y = 0
s = 2 * w2 + h2 * (1 - w)
line(xc + x, yc + y, xc - x, yc + y) --to prevent the first line to be drawn twice
redraw()
inkey()
s = s + w2 * ((4 * y) + 6)
y = y + 1
while w2 * y < h2 * (x-2) do
line(xc + x, yc + y, xc - x, yc + y)
redraw()
inkey()
color(int(rnd()*255),int(rnd()*255),int(rnd()*255))
line(xc + x, yc - y, xc - x, yc - y)
redraw()
inkey()
color(int(rnd()*255),int(rnd()*255),int(rnd()*255))
if s >= 0 then
s = s + fh2 * (1 - x)
x = x - 1
end
s = s + w2 * ((4 * y) + 6)
y = y + 1
end
dot(xc + x, yc + y)
dot(xc - x, yc + y)
redraw()
inkey()
color(int(rnd()*255),int(rnd()*255),int(rnd()*255))
dot(xc + x, yc - y)
dot(xc - x, yc - y)
redraw()
inkey()
end
openwindow (70,70,32,"Resize Window")
color(255,255,0)
DrawEllipse(10,10,20,20) --works perfect!
inkey()
cls()
DrawEllipse(10,10,10,20) --problems with last 2 horizontal lines between the pixels!
inkey()
cls()
DrawEllipse(10,10,20,10) --works perfect to!
closewindow()

The following VB works for me, based on the first link provided; the only difference between mine here and the code at your link is I move xc and yc over, since you cannot can't have negative x or y values for the pixels in a bitmap.
Public Shared Function DrawEllipse(ByVal xc As Integer, ByVal yc As Integer, ByVal w As Integer, ByVal h As Integer, ByVal doFill As Boolean) As Drawing.Bitmap
Dim w2 As Integer = w * w
Dim h2 As Integer = h * h
Dim fw2 As Integer = 4 * w2
Dim fh2 As Integer = 4 * h2
// cheat by moving xc and yc so that we can handle quadrants
xc = w
yc = h
Dim bm As New Drawing.Bitmap(w2, h2)
// first half
Dim x As Integer = 0
Dim y As Integer = h
Dim s As Integer = 2 * h2 + w2 * (1 - h)
While h2 * x <= w2 * y
If doFill Then
For i As Integer = -y To y
bm.SetPixel(xc + x, yc + i, Drawing.Color.Red)
bm.SetPixel(xc - x, yc + i, Drawing.Color.Red)
Next
Else
bm.SetPixel(xc + x, yc + y, Drawing.Color.Red)
bm.SetPixel(xc - x, yc + y, Drawing.Color.Red)
bm.SetPixel(xc + x, yc - y, Drawing.Color.Red)
bm.SetPixel(xc - x, yc - y, Drawing.Color.Red)
End If
If s >= 0 Then
s += fw2 * (1 - y)
y -= 1
End If
s += h2 * ((4 * x) + 6)
x += 1
End While
// second half
x = w
y = 0
s = 2 * w2 + h2 * (1 - w)
While w2 * y <= h2 * x
If doFill Then
For i As Integer = -x To x
bm.SetPixel(xc + i, yc + y, Drawing.Color.Red)
bm.SetPixel(xc + i, yc - y, Drawing.Color.Red)
Next
Else
bm.SetPixel(xc + x, yc + y, Drawing.Color.Red)
bm.SetPixel(xc - x, yc + y, Drawing.Color.Red)
bm.SetPixel(xc + x, yc - y, Drawing.Color.Red)
bm.SetPixel(xc - x, yc - y, Drawing.Color.Red)
End If
If s >= 0 Then
s += fh2 * (1 - x)
x -= 1
End If
s += w2 * ((4 * y) + 6)
y += 1
End While
Return bm
End Function
(Aside: I used // instead of ' for the comments... just for readability here. If you copy to Visual Studio you'll have to fix that)

Ok, I managed to find a solution for the filled ellipse by checking
if the pixel from the second half is gonna be drawn in the x-range of the first half of the ellipse.
function drawellipse(xc, yc, w, h, dofill)
--trouble with the size, 1 pixel to large on x and y to...
w=w/2 --good solution for making it the right size?
h=h/2 --good solution for making it the right size?
local w2 = w * w
local h2 = h * h
local fw2 = 4 * w2
local fh2 = 4 * h2
-- cheat by moving xc and yc so that we can handle quadrants
xc = xc + w
yc = yc + h
-- first half
local x = 0
local y = h
local s = 2 * h2 + w2 * (1 - h)
while h2 * x <= w2 * y do
if dofill then
for i = -y , y do
color(0,255,0)
dot(xc + x, yc + i)
dot(xc - x, yc + i)
--redraw()inkey()
end
else
color(255,0,255)
dot(xc + x, yc + y)
dot(xc - x, yc + y)
dot(xc + x, yc - y)
dot(xc - x, yc - y)
--redraw()inkey()
end
if s >= 0 then
s =s+ fw2 * (1 - y)
y =y- 1
end
s =s+ h2 * ((4 * x) + 6)
x =x+ 1
end
color(255,0,255)
line(xc + x,0,xc - x,0)
test1 = xc + x
test2 = xc - x
print(test1 .. '/' .. test2)
redraw()inkey()
-- second half
x = w
y = 0
s = 2 * w2 + h2 * (1 - w)
while w2 * y <= h2 * x do
if dofill then
for i = -x , x do
if not(xc + i > test2 and xc + i < test1) then
color(255,255,0)
dot(xc + i, yc + y)
dot(xc + i, yc - y)
redraw()inkey()
end
end
else
color(0,255,255)
dot(xc + x, yc + y)
dot(xc - x, yc + y)
dot(xc + x, yc - y)
dot(xc - x, yc - y)
redraw()inkey()
end
if s >= 0 then
s =s+ fh2 * (1 - x)
x =x- 1
end
s =s+ w2 * ((4 * y) + 6)
y =y+ 1
end
end

In vb.net you have both Graphics.DrawEllipse and Graphics.DrawArc. In Lua you may be able to use Cairo which I know has a arc function.
If you where to make a ellipse in a GraphicsPath in .Net and where to reverse engineer how it is stored in memory, you would find out that it is stored as four bezier curves. I implemented my own graphics library in vb.net once, and that was how I did it. The best resource I found at the time where a implementation in Actionscript, that I unfortunately was unable to locate aswell as that graphics library I was talking about.
TLDR; You should have a look at bezier curves.

A completely different, and very simple take on this, although the ellipse doesn't seem as "pretty" as the other algorithms; this just uses the mathematical definition of an ellipse and, looping over x calculates the y coordinate given x, w, and h.
Public Shared Function DrawEllipse2(ByVal xc As Integer, ByVal yc As Integer, ByVal w As Integer, ByVal h As Integer, ByVal doFill As Boolean) As Drawing.Bitmap
Dim bm As New Drawing.Bitmap(w * w, h * h)
For x As Integer = xc - w To xc + w
Dim y As Integer = CInt((Math.Sqrt(1 - ((x * x) / (w * w)))) * h)
If doFill Then
For j As Integer = -y To y
bm.SetPixel(w + x, h + j, Drawing.Color.Red)
Next
Else
bm.SetPixel(w + x, h + y, Drawing.Color.Red)
bm.SetPixel(w + x, h - y, Drawing.Color.Red)
End If
Next
Return bm
End Function

Related

Visual basic function for intermittent antibiotic dosing

I am a beginner in VB. I wrote a little program to simulate dosing regimens of antibiotics using some exponential equations and pharmacokinetic data.
The problem I have is that I want to display on a graph the following mathematical function:
That simulates the concentration variation at different intervals of time:
Where:
b(t) is the concentration at time t that will be plotted as Y axis, t is time (plotted on the x-axis).
b(0) is the concentration at time 0 and it is a known variable.
u(t-a1) is a function that has the value u(t-a1)=b(o) if t=a1 or 0 if t<>a1
a1 is the time at which a next dose is given.
alpha is the elimination rate constant, a variable that is known.
What I have so far:
Dim y, x As Double
For x = 0 To 24 Step 1
For n As Double = 1 To 24 / tau
y = (1 - test_condition(n * tau, x)) * css * Math.Exp(-ke * x) + test_condition(n * tau, x) * css * Math.Exp(-ke * (x - n * tau))
Chart1.Series("Concentratie1").Points.AddXY(x, y)
Next
Next
The test_condition:
if x=tau then test_condition= 1 else 0
It is close but I don't get an exponential decay after a dose ... don't know how to make that happen.
This works!! for tau (dosing interval) every 4 hours. Can it be rearranged somehow because the tau (dosing interval) will vary (sometimes 4 hours, sometimes every 6 hours)?:
Dim y, x, y2, x2, y3, x3, y4, x4, x5, x6, y5, y6 As Double
For x = 0 To tau Step 1
y = exponential_decay(css, ke, x) + test_condition(tau, x) * (css - Val(mic))
Chart1.Series("Bolus 1").Points.AddXY(x, y)
Next
For x2 = tau To 2 * tau Step 1
y2 = exponential_decay(css, ke, x2 - tau) + test_condition(2 * tau, x2) * (css - Val(mic))
Chart1.Series("Bolus 2").Points.AddXY(x2, y2)
Next
For x3 = 2 * tau To 3 * tau Step 1
y3 = exponential_decay(css, ke, x3 - 2 * tau) + test_condition(3 * tau, x3) * (css - Val(mic))
Chart1.Series("Bolus 3").Points.AddXY(x3, y3)
Next
For x4 = 3 * tau To 4 * tau Step 1
y4 = exponential_decay(css, ke, x4 - 3 * tau) + test_condition(4 * tau, x4) * (css - Val(mic))
Chart1.Series("Bolus 4").Points.AddXY(x4, y4)
Next
For x5 = 4 * tau To 5 * tau Step 1
y5 = exponential_decay(css, ke, x5 - 4 * tau) + test_condition(5 * tau, x5) * (css - Val(mic))
Chart1.Series("Bolus 4").Points.AddXY(x5, y5)
Next
For x6 = 5 * tau To 32 Step 1
y6 = exponential_decay(css, ke, x6 - 5 * tau)
Chart1.Series("Bolus 4").Points.AddXY(x6, y6)
Next
End Sub
I managed to solve the problem:
this function f relates time (t) to dosing interval (tau)
Private Function f(ByVal t As Double, ByVal tau As Double)
Dim n As Integer
For n = 0 To 24 / tau
If t = n * tau Then
f = n * tau
ElseIf t < tau Then
f = 0
ElseIf t > n * tau And t < (n + 1) * tau Then
f = n * tau
ElseIf t >= (n + 1) * tau Then
f = n * tau
End If
Next
End Function
And this is what I draw on the chart:
For x = 0 To 36 Step 0.5
y = exponential_decay(css, ke, x - f(x, tau))
Chart1.Series("Intermitent Dosage").Points.AddXY(x, y)
Next

VB.NET spirograph program

I'm trying to create a a program that will draw hypotrochoids (spirograph). The program below compiles fine. But when I run it I only get a portion of the drawing.. I'm not sure what I'm doing wrong. I'm fairly new to VB.. Any help is appreciated. Thanks.
Here is the screenshot http://imgur.com/a/KxFWk
Public Class Form1
Private Sub Form1_Load(sender As System.Object, e As System.EventArgs) Handles MyBase.Load
End Sub
Private Sub PictureBox1_Paint(sender As Object, e As PaintEventArgs) Handles PictureBox1.Paint
Dim x As Integer
Dim y As Integer
Dim p As Integer
Dim x1 As Integer
Dim y1 As Integer
Dim x2 As Integer
Dim y2 As Integer
x = 75
y = 15
p = 15
x1 = (x + y) * Math.Cos(0) + p * Math.Cos(0)
y1 = (x + y) * Math.Sin(0) + p * Math.Sin(0)
For t = 0 To 500 Step 0.1
x2 = (x + y) * Math.Cos(t) + p * Math.Cos((x + y) * t / y)
y2 = (x + y) * Math.Sin(t) + p * Math.Sin((x + y) * t / y)
e.Graphics.DrawLine(Pens.Blue, x1, y1, x2, y2)
x1 = x2
y1 = y2
Next
End Sub
End Class
The results of the Sin and Cos calculations result in negative numbers where the parameter is greater than 90 for cos and greater than 180 for sin.
To see the whole image, you need to change the offset for x2 and y2 - see the code below. Alter the number 200 in each of the four lines to a value appropriate for your picturebox
x1 = 200 + CInt((x + y) * Math.Cos(0) + p * Math.Cos(0))
y1 = 200 + CInt((x + y) * Math.Sin(0) + p * Math.Sin(0))
For t As Double = 0 To 500 Step 0.1
x2 = 200 + CInt((x + y) * Math.Cos(t) + p * Math.Cos((x + y) * t / y))
y2 = 200 + CInt((x + y) * Math.Sin(t) + p * Math.Sin((x + y) * t / y))
e.Graphics.DrawLine(Pens.Blue, x1, y1, x2, y2)
x1 = x2
y1 = y2
Next

VBA CODE CORRECTION

I am using VBA for the first time. I started with a very basic code using Runga Kutta Method. I am not able to run it. Can I know where I am going wrong? Can you also post some solutions for this type of differential equation solvers?
Option Explicit
Dim K1 As Double
Dim K2 As Double
Dim K3 As Double
Dim K4 As Double
Dim y As Double
Dim x As Double
Dim dx As Double
Dim x0 As Integer
Dim y0 As Integer
Function f(x, y) As Double
f = 0.5 * x - 0.5 * y
End Function
Sub RK(x, y, dx)
Dim i As Integer
Dim ynew As Double
dx = 0.5
x0 = 0
y0 = 1
K1 = dx * f(x, y)
K2 = dx * f(x + dx / 2, y + K1 / 2)
K3 = dx * f(x + dx / 2, y + K2 / 2)
K4 = dx * f(x + dx, y + K3)
RK = y + ((K1 + 2 * (K2 + K3 + K4)) / 6)
For i = 0 To 6
ynew = RK(x, y, dx)
x = x + dx
y = ynew
Next i
For j = 1 To 6
Call RK(x, y, dx, ynew)
ActiveCell.Offset(i - 1, 1).Value = x
ActiveCell.Offset(i - 1, 2).Value = y
x = x + dx
y = ynew
Next
End Sub
You need to execute the RK procedure and give it the starting values of x, y and dx.
To do this from within the VBE (Visual Basic Editor) open the Immediate window. If it's not visible press Ctrl+G and it should appear at the bottom of the VBE.
In the Immediate window type something like RK 1, 3, 2 and the results will appear in the two columns to the right of the active cell and take up 6 rows.
If you want the procedure to execute on the press of a button, or when a value is updated you'll need to add an extra bit of code for that.
Edit:
Just noticed these lines - RK = y + ((K1 + 2 * (K2 + K3 + K4)) / 6) and ynew = RK(x, y, dx).
The RK procedure won't return a value and you can't set it as a value either.
This link may help explain it: http://what-when-how.com/excel-vba/vba-sub-and-function-procedures/

sqrt-based filled ellipse pixel drawing function

I'm trying to make a function in Lua or VB based code to draw / plot a filled ellipse.
I don't have much knowledge about this math and I can use some help.
I Googled everything there is to Google about drawing ellipses with code but I can't find a good simple working example in VB or Lua for a filled one.
On a previous post on this site I did get an answer about how to draw a normal ellipse but nothing came up for a filled one, that's why i make a new topic for a filled one.
Here are a few websites I visited but I can't find a way to make a filled ellipse without redrawing already drawed pixels...
https://sites.google.com/site/ruslancray/lab/projects/bresenhamscircleellipsedrawingalgorithm/bresenham-s-circle-ellipse-drawing-algorithm
http://groups.csail.mit.edu/graphics/classes/6.837/F98/Lecture6/circle.html
http://www.blitzbasic.com/codearcs/codearcs.php?code=2817
http://hackipedia.org/Algorithms/Graphics/pdf/A%20Fast%20Bresenham%20Type%20Algorithm%20For%20Drawing%20Ellipses%20by%20John%20Kennedy.pdf
https://scratch.mit.edu/projects/49873666/
http://www.sourcecodesworld.com/source/show.asp?ScriptID=112
Here is the code I have for a normal ellipse (thanks to "Johnny Strings" for the VB version):
function DrawEllipse(xc,yc,w,h)
local w2 = w * w
local h2 = h * h
local fw2 = 4 * w2
local fh2 = 4 * h2
xc = xc + w
yc = yc + h
local x = 0
local y = h
local s = 2 * h2 + w2 * (1 - h)
while h2 * x <= w2 * y do
dot(xc + x, yc + y)
dot(xc - x, yc + y)
dot(xc + x, yc - y)
dot(xc - x, yc - y)
redraw()inkey()
color(int(rnd()*255),int(rnd()*255),int(rnd()*255))
if s >= 0 then
s = s + fw2 * (1 - y)
y = y - 1
end
s = s + h2 * ((4 * x) + 6)
x = x + 1
end
x = w
y = 0
s = 2 * w2 + h2 * (1 - w)
while w2 * y <= h2 * x do
dot(xc + x, yc + y)
dot(xc - x, yc + y)
dot(xc + x, yc - y)
dot(xc - x, yc - y)
redraw()inkey()
color(int(rnd()*255),int(rnd()*255),int(rnd()*255))
if s >= 0 then
s = s + fh2 * (1 - x)
x = x - 1
end
s = s + w2 * ((4 * y) + 6)
y = y + 1
end
end
Here's what I came up with for my CPU renderer in the past. It's very efficient and very simple too.
It relies on the mathematical definition of the ellipse, so the ellipse is drawn centered at x,y and has the width and height defined from the center, not from the other side.
The draw point function draws a pixel at the x by y point specified.
local function drawaxisalignedellipse(x,y,w,h)
--n Defines the bounds of the horizontal lines which fill the ellipse.
local n=w
local w2=w*w
local h2=h*h
--draws the center horizontal line.
for i=x-w,x+w do
drawpoint(i,y)
end
for j=1,h do
--The current top and bottom rows.
local ra,rb=y+j,y-j
--This loop removes 1 from n until it is within the shape
while w2*(h2-j*j)<h2*n*n and n~=0 do n=n-1 end
--Draws horizontal line from -n to n across the ellipse
for i=x-n,x+n do
drawpoint(i,ra)
drawpoint(i,rb)
end
end
end

Excel VBA compile error: Expected Sub, Function or Property

I am getting a compile error in Excel VBA which says Expected Sub, Function or Property. The function I am using is given below which is trying to copy the rate function in Excel.
Thanks for your help.
Function rate_m(nper As Double, pmt As Double, pv As Double, fv As Double, types As Double, guess As Double) As Variant
Dim y, y0, y1, x0, x1, f, i As Double
Dim FINANCIAL_MAX_ITERATIONS As Double
Dim FINANCIAL_PRECISION As Double
If IsNull(guess) Then guess = 0.01
If IsNull(fv) Then fv = 0
If IsNull(types) Then types = 0
FINANCIAL_MAX_ITERATIONS = 128 'Bet accuracy with 128
FINANCIAL_PRECISION = 0.0000001 '1.0e-8
y , y0, y1, x0, x1, f, i = 0
rate_m = guess
If Abs(rate_m) < FINANCIAL_PRECISION Then
y = pv * (1 + nper * rate_m) + pmt * (1 + rate_m * types) * nper + fv
Else
f = Exp(nper * Log(1 + rate_m))
y = pv * f + pmt * (1 / rate_m + types) * (f - 1) + fv
y0 = pv + pmt * nper + fv
y1 = pv * f + pmt * (1 / rate_m + types) * (f - 1) + fv
End If
'find root by Newton secant method
i , x0 = 0
x1 = rate_m
While Abs(y0 - y1) > FINANCIAL_PRECISION & i < FINANCIAL_MAX_ITERATIONS
rate_m = (y1 * x0 - y0 * x1) / (y1 - y0)
x0 = x1
x1 = rate_m
If Abs(rate_m) < FINANCIAL_PRECISION Then
y = pv * (1 + nper * rate_m) + pmt * (1 + rate_m * types) * nper + fv
Else
f = Exp(nper * Log(1 + rate_m))
y = pv * f + pmt * (1 / rate_m + types) * (f - 1) + fv
End If
y0 = y1
y1 = y
i = i + 1
Wend
End Function
A couple things...
First, you have to assign each variable individually...like this:
y = 0
y0 = 0
y1 = 0
x0 = 0
x1 = 0
f = 0
i = 0
Second, you probably want to DIM your variables all as Double. Unfortunately, this line:
Dim y, y0, y1, x0, x1, f, i As Double
Only declares i as a Double, all the others will be a Variant. You need to declare each one individually, like this:
Dim y As Double
Dim y0 As Double
Dim y1 As Double
Dim x0 As Double
Dim x1 As Double
Dim f As Double
Dim i As Double
Every IF ends with a End If (unless in a single line) and While...loop. You might want to take a look at VBA's syntax:
http://msdn.microsoft.com/en-us/library/office/ee814737(v=office.14).aspx
EDIT: You have to declare variable individually, instead of:
y , y0, y1, x0, x1, f, i = 0
you could do:
y = 0
y0 = 0
y1 = 0
x0 = 0
x1 = 0
f = 0
i = 0