AVG of Cells Next to Cells used in Another Formula - vba

Question

I am new to asking questions here so I hope I get this correct. I am helping my dad with a spreadsheet and I'm having issues with figuring out how to do one formula. Dont know if it can be done with a formula or if it has to be done with macros.
This is a scoring sheet with multiple matches. For each match there is a total score and the cell next to the score is an X count (number of bulleyes). In the same row (column K) I calculate the top 6 total scores and average them:
=AVERAGE(LARGE((N15,Q15,T15,W15,Z15,AC15,AF15,AI15,AL15,AO15,AR15,AU15,AX15,BA15,BD15,BG15,BJ15),{1,2,3,4,5,6}))
Now I need to take the AVG of the X counts that are next to the total scores that are used in the formula above and put solution in column L.
For example, if the cells that are used for AVG score in that row are:
N15,Q15,T15,W15,Z15,AC15
then the cells that would need to be used for the X count AVG would be:
O15,R15,U15,X15,AA15,AD15
This result would be put into L15
Please help. If any clarification is needed just let me know.
Screen Shot:

Answer 1

Please try the following formula:
=SUMPRODUCT(O15:BM15,
--(MOD(COLUMN(N15:BL15)-COLUMN($N15),3)=0),
--(N15:BL15+O15:BM15/10^3+COLUMN(N15:BL15)/10^6>=
LARGE(N15:BL15+O15:BM15/10^3+COLUMN(N15:BL15)/10^6,6))
)/6
How does it work?
SUMPRODUCT has 3 parameters - first is the array to sum, next 2 parameters return an array of 0 and 1 to choose only interesting elements of the first array.
MOD(COLUMN(N15:BL15)-COLUMN($N15),3)=0)
This part is included to avoid listing every single cell. If the score is in every third column of the input range, we can calculate column number relative to first column, and function MOD(column,3) returns: {1,0,0,1,0,0...}. So only every third column of input array will be included in sum.
(N15:BL15+O15:BM15/10^3+COLUMN(N15:BL15)/10^6>=
LARGE(N15:BL15+O15:BM15/10^3+COLUMN(N15:BL15)/10^6,6)
This part is to decide which 6 of the scores should be included in the final sum. The trickiest part is to decide what to do with ties. My approach is to take:
if two scores are the same, take the one with higher number of bulleyes
if it is still tied, take the one from first columns
This means that instead of N15 value we calculate:
N15+O15/10^3+COLUMN(N15)/10^6
With your sample data it evaluates to: 566.017014. First three decimal places is the number of bulleyes, next 3 is column number.
You can use the same formula to calculate average of top 6 scores by changing the first parameter:
=SUMPRODUCT(N15:BL15,
--(MOD(COLUMN(N15:BL15)-COLUMN($N15),3)=0),
--(N15:BL15+O15:BM15/10^3+COLUMN(N15:BL15)/10^6>=
LARGE(N15:BL15+O15:BM15/10^3+COLUMN(N15:BL15)/10^6,6))
)/6

Answer 2

You can try this not so elegant solution:
=SUMPRODUCT(INDEX(N15:BK15,MATCH(LARGE((N15,Q15,T15,W15,Z15,AC15,AF15,AI15,AL15,AO15,AR15,AU15,AX15,BA15,BD15,BG15,BJ15),{1,2,3,4,5,6}),N15:BK15,0)+1))/6
Entered as array formula by Ctr+Shift+Enter in Cell L15:M15 (2 cells) which should look like this:
{=SUMPRODUCT(INDEX(N15:BK15,MATCH(LARGE((N15,Q15,T15,W15,Z15,AC15,AF15,AI15,AL15,AO15,AR15,AU15,AX15,BA15,BD15,BG15,BJ15),{1,2,3,4,5,6}),N15:BK15,0)+1))/6}
with added braces.
The number 6 is the equates to the number of top scores you want returned.
Now, why 2 cells (L15:M15). I cannot make SUMPRODUCT evaluate the resulting array from the INDEX so we have to enter it at 2 cells. I don't think that would be a problem since in your screen shot, Column M is not used.
Note: If the range evaluated have less than 6 items, it will error out. Also good point by user3964075. It may or may not be able to deal with ties.