I'm hoping to find a solution for this to automate a report I have. Basically what I'm trying to accomplish here is grabbing a date (first day of previous month, two years ago through last day of previous month current year).
So the date span if running this month would look like this: between 4/1/2013 and 3/31/2015
I have found code to get the date two years ago but I'm not able to also incorporate the month functions... Any help is very much appreciated!
For year I'm using this:
SELECT CONVERT(VARCHAR(25),DATEADD(year,-2,GETDATE()),101)
First day of previous month 2 years ago:
SELECT CONVERT(DATE,dateadd(day, -1, dateadd(day, 1 - day(GETDATE()), GETDATE())))
Last day of last month:
SELECT CONVERT(DATE,DATEADD(month, DATEDIFF(month, 0, DATEADD(year,-2,GETDATE())), 0))
Then just do whatever logic you need with them
Your where clause can look something like this:
where date >= cast(dateadd(year, -2,
dateadd(month, -1, getdate() - day(getdate()) + 1)
) as date) and
date < cast(getdate() - day(getdate()) + 1 as date)
This makes use of the handy convenience that subtracting/adding a number to a datetime is the same as adding a date. The start date says: get the first day of the month, then subtract one month, then subtract two years. This could have been done as dateadd(month, -25, . . .), but I think separating the logic is clearer.
This gives you two dates you are looking for:
SELECT
CAST((DATEADD(yy, -2, DATEADD(d, -1 * DATEPART(dd, getdate()) + 1 , GETDATE() ))) as date) as yourTwoYearsAgoDate,
CAST((DATEADD(d, -1 * DATEPART(dd, GETDATE()), GETDATE())) as date) as yourEndOfLastMonthDate
Given a reference date (e.g. "today"),
declare #today date = '23 April 2015'
The 1st of the month is computed by subtracting 1 less than the day number of the current month:
select first_of_current_month = dateadd(day,1-day(#today),#today)
The last day of the previous month is day 0 of the current month, so to get the last day of the previous month, just subtract the current day number:
select last_of_previous_month = dateadd(day,-day(#today),#today)
Moving two years back is easy:
select two_years_back = dateadd(year,-2, #today )
Putting it all together, this should do you:
declare #today date = '23 April 2015'
select *
first_day_of_current_month = dateadd(day,1-day(#today),#today),
last_day_of_previous_month = dateadd(day, -day(#today),#today) ,
date_from = dateadd(year,-2, dateadd(day,1-day(#today),#today) ) ,
date_thru = dateadd(day, -day(#today),#today)
yielding the expected results:
first_day_of_current_month: 2015-04-01
last_day_of_previous_month: 2015-03-31
date_from : 2013-04-01
date_thru : 2015-03-31
So you should be able to say something like this:
select *
from foo t
where t.transaction_date between dateadd(year,-2, dateadd(day,1-day(#today),#today) )
and dateadd(day, -day(#today),#today)
If you have to deal with datetime values rather than date, its easier to not use between and say something like this:
declare #today date = current_timestamp -- get the current date without a time component
select *
from foo t
where t.transaction_date >= dateadd(year,-2, dateadd(day,1-day(#today),#today) )
and t.transaction_date < dateadd(year, 0, dateadd(day, -day(#today),#today)
[superfluous addition of 0 years added for clarity]
Related
i need help on my little problem.
SELECT FORMAT(ServiceDate, 'dd-MM-yyy") AS ServiceDate
FROM Services
WHERE Day(ServiceDate) BETWEEN '1' AND Day(getdate() -2)
AND Month(ServiceDate) =
CASE
WHEN Day(getdate()) <=2
THEN Month(getdate() -1
ELSE Month(getdate())
END
AND Year(ServiceDate) = Year(getdate())
Now the problem is the first and the second of the Month.
The query don't use the last month. It shows the actual month.
I hope its clear what i need.
if we have the 01-06-2016 and i need minus 2, so the query must give me back to the day 30-05-2016
big THX
the output for today with this query
output query
Assuming you are using sql-server, you need to use DATEADD(Day, -2, GETDATE()) for subtracting 2 days from current date.
I think I understand the logic now:
If the current day is the 1st of the month, get all the records from the start of previous month, until 2 days before it ends.
If the current day is the 2nd of the month, get all the records from the start of the previous month until one day before it ends.
If the current day is the 3rd of the month or higher, get all the records from the beginning of the current month until 2 days ago.
Since you are using the FORMAT() function that was introduced in 2012 version, you can also use the EOMONTH() function that was introduced in the same version.
This function returns the date of the end of the month of the date it receives as an argument, and also have a useful optional second argument that specifies the numbers of months to add to the date passed to the function.
Using this function will allow you to write your query without using any functions on the ServiceDate column, thus enabling the use of any indexes defined on this column.
DECLARE #Now datetime = GETDATE()
SELECT FORMAT(ServiceDate, 'dd-MM-yyy') AS ServiceDate
FROM Services
WHERE (
DAY(#Now) <= 2
AND ServiceDate >= DATEADD(DAY, 1, EOMONTH(#Now, -2))
AND ServiceDate < DATEADD(DAY, -(DAY(#Now)-1), EOMONTH(#Now, -1))
)
OR
(
DAY(GETDATE()) > 2
AND ServiceDate >= DATEADD(DAY, 1, EOMONTH(#Now, -1))
AND ServiceDate < DATEADD(DAY, -2, #Now)
)
Compute enddate as 2 days before getdate() and select data in interval from enddate's first of month and enddate.
SELECT FORMAT(ServiceDate, 'dd-MM-yyy") AS ServiceDate
FROM Services
CROSS APPLY (SELECT enddate = DATEADD(D,-2,getdate()) x
WHERE ServiceDate BETWEEN DATEADD(MONTH,DATEDIFF(MONTH,0,x.enddate),0) AND x.enddate
I have a query (pasted below), and I would like to make it so that people don't need to update the completed date range. I would like for it to automatically just get results from last month. So if it is run in February, for example, it will give me results for all completed items that meet my criteria for January. Can anyone think of a way to do that?
select External_ID__c,
Ewrk_Tracking_Number__c,
PIF_Branch_Name,
Distribution_Branch_Name,
Transaction_Type__C,
submitter_date__c, Completed_Date__C,
COUNT(External_ID__c)
from Business_Solutions_D.dbo.Reporting_SalesForce_AspireBaseData
where PIF_Branch_Code = 977
and Completed_Date__C >= '2015-01-01'
and Completed_Date__C < '2015-02-01'
and Delete_Flag__C = 'FALSE'
group by External_ID__c,
Ewrk_Tracking_Number__c,
PIF_Branch_Name,
Distribution_Branch_Name,
Transaction_Type__C,
submitter_date__c,
Completed_Date__C
There is no "keyword" for last month. You have to put that in your predicates.
Here is an example of how to get some date values for this.
select dateadd(MONTH, datediff(MONTH, 0, GETDATE()), 0) as BeginningOfThisMonth
select dateadd(MONTH, datediff(MONTH, 0, GETDATE()) - 1, 0) as BeginningOfPreviousMonth
If you want to see a number of other date routines here is an excellent blog post with quite a few of them. http://www.sqlservercentral.com/blogs/lynnpettis/2009/03/25/some-common-date-routines/
If you mean the last month prior to this one, you can do it in two steps: first, find the first day of the current month
#firstDayOfThisMonth = DATEADD(day, DAY(GETDATE())-1, GETDATE())
then subtract one month:
#firstDayOfLastMonth = DATEADD(month, -1, #firstDayOfThisMonth)
Then your query would be:
and Completed_Date__C >= #firstDayOfLastMonth
and Completed_Date__C < #firstDayOfThisMonth
Another way would be to query where the difference (in months) between Completed_Date__C and the current date is 1:
and DATEDIFF(Completed_Date__C, GETDATE()) = 1
You can do this with date arithmetic. One trick to get the first date of the month is to subtract the current day of the month from the date and add one day. SQL Server allows you to do this with + and - instead of dateadd(), on a datetime value. Of course, you need to remove the time component as well (using cast( as date)).
The logic looks like this for the current month:
where Completed_Date__C >= cast(getdate() - day(getdate()) + 1 as date) and
Completed_Date__C < dateadd(month, 1, cast(getdate() - day(getdate()) + 1 as date))
And like this for the previous month:
where Completed_Date__C >= dateadd(month, -1, cast(getdate() - day(getdate()) + 1 as date)) and
Completed_Date__C < cast(getdate() - day(getdate()) + 1 as date)
This has the nice property that it is a sargeable as your original code, so it will take advantage of an index on the column, if appropriate.
You just need to have it do some date math to calculate it.
--Go to last day of prev month - 'Day' to account for varying month day counts
and Completed_Date__C >= GETDATE() - DATEPART(DAY, GETDATE()) - DATEPART(DAY, GETDATE() - DATEPART(DAY, GETDATE())) + 1
and Completed_Date__C < GETDATE() - DATEPART(DAY, GETDATE()) + 1
When you do additions on DateTimes + integer it assumes it day based addition.
Script that lists dates and week number of date:
DECLARE #initDate DATE = '2014-01-01';
DECLARE #endDate DATE = '2014-12-31';
WITH dates (date, week)
AS (SELECT #initDate date,
Datepart(ww, #initDate) week
UNION ALL
SELECT Dateadd(ww, 1, t.date),
Datepart(ww, t.date)
FROM dates t
WHERE t.date < #endDate)
SELECT dates.date,
dates.week
FROM dates
The first three rows are:
date: week number
---------- -----------
2014-01-01 1
2014-01-08 1
2014-01-15 2
..... ..
..... ..
I guess it should be 2 for the second row and 3 for the first, isn't it?
Is it some kind of bug in DATEPART? Even if something is depends on first day of the year, first row date differs from second on one week with any settings.
Could you clarify this, please?
It is because of Recursive CTE not because of Datepart.
In the Recursive part of CTE week is still holding the previous week not the new date that generated in recursive part
Try changing your query like this.
DECLARE #initDate DATE = '2014-01-01';
DECLARE #endDate DATE = '2014-12-31';
WITH dates (date, week)
AS (SELECT #initDate date,
Datepart(ww, #initDate) week
UNION ALL
SELECT Dateadd(ww, 1, t.date),
Datepart(ww, Dateadd(ww, 1, t.date))
FROM dates t
WHERE t.date < #endDate)
SELECT dates.date,
dates.week
FROM dates
This question already has answers here:
Get the records of last month in SQL server
(23 answers)
Closed 9 years ago.
How can I get last month date like
select * from table where date in ( last month )
I dont want the last 30 days
AND how can I get last month automatically
Assuming you want all items where the date is within the last month i.e. between today and 30/31 days ago:
Select *
From Table
Where Date Between DATEADD(m, -1, GETDATE()) and GETDATE()
You can use this
Select * from table where date between #startdate and #enddate
Or
SELECT * FROM DATE_SAMPLE WHERE
DATEPART(YEAR, SAMPLE_DATE) = '2013' AND
DATEPART(MONTH,SAMPLE_DATE) = '01' AND
DATEPART(DAY, SAMPLE_DATE) = '01'
Is it usefull for you?
select * from table
where month(date)=month(getdate())-1
Edit
if you mean last month from today. or previous month from a specific date then you need to do something like this
SELECT DATEPART(MONTH, DATEADD(MONTH, -1, [Date]))
Or to get records from previous month of the year you can do something like this
SELECT * FROM Table
WHERE MONTH(Date) = DATEPART(MONTH, DATEADD(MONTH, -1, [Date]))
AND YEAR(Date) = DATEPART(YEAR, DATEADD(MONTH, -1, [Date])) --<-- or pass year for which year you are checking
To make your aquery SARGable (Suggested by t-clausen.dk)
select * from table
where date >=dateadd(m, datediff(m, 0, current_timestamp)-1, 0)
and date < dateadd(m, datediff(m, 0, current_timestamp)-1, 0)
Read here more about sargable Queries when working with date/datetime datatypes.
You can try to use the between statement to get the specific dates:
Select * from table where date between '01-01-2014' and '14-01-2014'
Specifically MSSQL 2005.
Here's a solution that gives you the last second of the current month. You can extract the date part or modify it to return just the day. I tested this on SQL Server 2005.
select dateadd( s, -1, dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 ) );
To understand how it works we have to look at the dateadd() and datediff() functions.
DATEADD(datepart, number, date)
DATEDIFF(datepart, startdate, enddate)
If you run just the most inner call to datediff(), you get the current month number since timestamp 0.
select datediff(m, 0, getdate() );
1327
The next part adds that number of months plus 1 to the 0 timestamp, giving you the starting point of the next calendar month.
select dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 );
2010-09-01 00:00:00.000
Finally, the outer dateadd() just subtracts one second from the beginning timestamp of next month, giving you the last second of the current month.
select dateadd( s, -1, dateadd( mm, datediff( m, 0, getdate() ) + 1, 0 ) );
2010-08-31 23:59:59.000
This old answer (below) has a bug where it doesn't work on the last day of a month that has more days than the next month. I'm leaving it here as a warning to others.
Add one month to the current date, and then subtract the value returned by the DAY function applied to the current date using the functions DAY and DATEADD.
dateadd(day, -day(getdate()), dateadd(month, 1, getdate()))
SELECT DATEADD(M, DATEDIFF(M, '1990-01-01T00:00:00.000', CURRENT_TIMESTAMP), '1990-01-31T00:00:00.000')
Explanation:
General approach: use temporal functionality.
SELECT '1990-01-01T00:00:00.000', '1990-01-31T00:00:00.000'
These are DATETIME literals, being the first time granule on the first day and last day respectively of the same 31-day month. Which month is chosen is entirely arbitrary.
SELECT DATEDIFF(M, '1990-01-01T00:00:00.000', CURRENT_TIMESTAMP)
This is the difference in whole months between the first day of the reference month and the current timestamp. Let's call this #calc.
SELECT DATEADD(M, #calc, '1990-01-31T00:00:00.000')
This adds #calc month granules to the last day of the reference month, the result of which is the current timestamp 'rounded' to the last day of its month. Q.E. D.
Try this:
DATEADD (DAY, -1, DATEADD (MONTH, DATEDIFF (MONTH, 0, CURRENT_TIMESTAMP) + 1, 0)
They key points are if you can get first day of current month,Last Day of Last Month and Last Day of Current Month.
Below is the Step by Step way to write query:
In SQL Server Date Starts from 1901/01/01( Date 0) and up to now each month can be identified by a number. Month 12 is first month of 1902 means January. Month 1200 is January of 2001. Similarly each day can be assigned by unique number e.g Date 0 is 1901/01/01. Date 31 is 1901/02/01 as January of 1901 starts from 0.
To find out First day of Current Month(Current Date or a given date)
First we need to check how many months have passed since date 0(1901/01/01).
SELECT DATEDIFF(MM,0,GETDATE())
Add same number of month to date 0(1901/01/01)
SELECT DATEADD(MM, DATEDIFF(MM,0,GETDATE()),0)
Then we will get first day of current month(Current Date or a given date)
To get Last Day of Last Month
We need to subtract a second from first day of current month
SELECT DATEADD(SS,-1,DATEADD(MM, DATEDIFF(MM,0,GETDATE()),0))
To get Last Day of Current Month
To get first day of current month first we checked how many months have been passed since date 0(1901/01/01). If we add another month with the total months since date 0 and then add total months with date 0, we will get first day of next month.
SELECT DATEADD(MM, DATEDIFF(MM,0,GETDATE())+1,0)
If we get first day of next month then to get last day of current month, all we need to subtract a second.
SELECT DATEADD(SS,-1,DATEADD(MM, DATEDIFF(MM,0,GETDATE())+1,0))
Hope that would help.
Using SQL2005, you do not have access to a helpful function EOMONTH(), So you must calculate this yourself.
This simple function will works similar to EOMONTH
CREATE FUNCTION dbo.endofmonth(#date DATETIME= NULL)
RETURNS DATETIME
BEGIN
RETURN DATEADD(DD, -1, DATEADD(MM, +1, DATEADD(DD, 1 - DATEPART(DD, ISNULL(#date,GETDATE())), ISNULL(#date,GETDATE()))))
END
Query to perform:
SELECT dbo.endofmonth(DEFAULT) --Current month-end date
SELECT dbo.endofmonth('02/25/2012') --User-defined month-end date
Some links to possible answers:
http://www.extremeexperts.com/sql/Tips/DateTrick.aspx
http://www.devx.com/tips/Tip/14405
http://blog.sqlauthority.com/2007/08/18/sql-server-find-last-day-of-any-month-current-previous-next/
http://www.sqlservercurry.com/2008/03/find-last-day-of-month-in-sql-server.html
DECLARE
#Now datetime,
#Today datetime,
#ThisMonth datetime,
#NextMonth datetime,
#LastDayThisMonth datetime
SET #Now = getdate()
SET #Today = DateAdd(dd, DateDiff(dd, 0, #Now), 0)
SET #ThisMonth = DateAdd(mm, DateDiff(mm, 0, #Now), 0)
SET #NextMonth = DateAdd(mm, 1, #ThisMonth)
SET #LastDayThisMonth = DateAdd(dd, -1, #NextMonth)
Sometimes you really do need the last day of this month, but frequently what you really want is to describe the time interval of this month. This is the best way to describe the time interval of this month:
WHERE #ThisMonth <= someDate and someDate < #NextMonth
For completeness, in Oracle you'd do something like ...
select add_months(trunc(sysdate,'MM'),1) ...
or
select last_day(sysdate)+1 ...
DATEADD(dd, -1, DATEADD(mm, +1, DATEADD(dd, 1 - DATEPART(dd, #myDate), #myDate)))