Makefile variable not set from grep output - variables

I am trying to set the variable COGLINE to be the output of my grep line (which is searching my config.json file for the regExthe "cogs"). When I execute the grep line it correctly outputs the proper line number, but when I echo the variable it comes up blank.
COGLINE = $(grep -n \"cogs\" ~/Desktop/Repos/pronghorn/config.json | cut -f1 -d:)
all:
grep -n \"cogs\" ~/Desktop/Repos/pronghorn/config.json | cut -f1 -d:
echo $(COGLINE)
Here is the output:
GlennMBP:test glenn$ make all
grep -n \"cogs\" ~/Desktop/Repos/pronghorn/config.json | cut -f1 -d:
2
echo
You can see that the line number is properly found as "2", but the variable comes up blank as if it were not set. What am I doing wrong?

grep is not a make function. That COGLINE = line is a make assignment.
You either need to use
COGLINE := $(shell grep -n \"cogs\" ~/Desktop/Repos/pronghorn/config.json | cut -f1 -d:)
if you want that run at make parse time and want it in a make variable.
Or
all:
COGLINE=$$(grep -n \"cogs\" ~/Desktop/Repos/pronghorn/config.json | cut -f1 -d:); \
echo "$${COGLINE}"
to run it at all recipe execution time and have it in a shell variable.
There are middle grounds as well but those are the two basic ideas.

Related

ksh cmd one-liner to grep for several PIDs at once

I got a bunch of processes that I need to check CPU affinity for, so I got this one liner:
for i in `ps -Fae | grep proc_name| awk '{print $2}'`; do taskset -acp $i;done
but I have a problem, taskset shows all the child processes' pid too so I get a massive line of numbers along with their cpu affinity.
I want to pipe the above line into an egrep 'pid1|pid2' so I can filter out all the child processes.
I tried to this:
for i in `ps -Fae | grep proc_name| awk '{print $2}'`; do taskset -acp $i;done | xargs egrep 'ps -Fae | grep proc_name| awk '{print $2}''
but my ksh shell didn't like the awk brackets at all.
So I have two questions:
can taskset be changed to show only parent pid?
how do I write the last bit where I egrep only the parent pid?
Filter inside the loop:
for i in $(ps -Fae | grep proc_name| grep -v grep | awk '{print $2}'); do
taskset -acp "$i" | grep "$i"
done
It sounds like you're asking for this syntax if it were bash (see https://mywiki.wooledge.org/BashFAQ/001, I'm not sure what the equivalent robust read loop syntax is for ksh):
while IFS= read -r i; do
taskset -acp "$i"
done < <(ps -Fae | awk '/proc_name/{print $2}') |
grep -E 'pid1|pid2'
but that's pretty fragile, e.g. if pid1 appeared as a substring of some other pid. If you edit your question to provide concise, testable sample input (i.e. the output of ps -Fae and the associated output of taskset) plus the expected output then we can be of more help.

bash script variables weird results when using cp

If I use cp inside a bash script the copied file will have weird charachters around the destination filename.
The destination name comes from the results of an operation, it's put inside a variable, and echoing the variable shows normal output.
The objective is to name a file after a string.
#!/bin/bash
newname=`cat outputfile | grep 'hostname ' | sed 's/hostname //g'
newecho=`echo $newname`
echo $newecho
cp outputfile "$newecho"
If I launch the script the echo looks ok
$ ./rename.sh
mo-swc-56001
However the file is named differently
~$ ls
'mo-swc-56001'$'\r'
As you can see the file contains extra charachters which the echo does not show.
Edit: the newline of the file is like this
# file outputfile
outputfile: ASCII text, with CRLF, CR line terminators
I tried in every possible way to get rid of the ^M charachter but this is an example of the hundreds of attempts
# cat outputfile | grep 'hostname ' | sed 's/hostname //g' | cat -v
mo-swc-56001^M
# cat outputfile | grep 'hostname ' | sed 's/hostname //g' | cat -v | sed 's/\r//g' | cat -v
mo-swc-56001^M
This newline will stay there. Any ideas?
Edit: crazy, the only way is to perform a dos2unix on the output...
Looks like your outputfile has \r characters in it, so you could add logic there to remove them and give it a try then.
#!/bin/bash
##remove control M first from outputfile by tr command.
tr -d '\r' < outputfile > temp && mv temp outputfile
newname=$(sed 's/hostname //g' outputfile)
newecho=`echo $newname`
echo $newecho
cp outputfile "$newecho"
The only way was to use dos2unix

using sed to add a backslash in front of a variable

I have a variable and that variable only needs a '\' in front of it.
I would say that the sed command is the ideal tool for it?
I tried using single quotes, double quotes, multiple variables, combination of variables, ...
I don't get an error returned but the end result is not showing what I need it do be
FOLDER=$(echo `cat file.XML | grep "Value" | cut -d \" -f2`)
echo $FOLDER
sed -i "s#"$FOLDER"#"\\$FOLDER"#g" ./file.XML
echo $FOLDER
After execution, I get
$ ./script.sh
b4c17422-1365-4fbe-bccd-04e0d7dbb295
b4c17422-1365-4fbe-bccd-04e0d7dbb295
Eventually I need to have a result like
$ ./script.sh
b4c17422-1365-4fbe-bccd-04e0d7dbb295
\b4c17422-1365-4fbe-bccd-04e0d7dbb295
Fixed thanks to the input of Cyrus and Ed Morton.
FOLDER=$(echo `cat file.XML | grep "Value" | cut -d \" -f2`)
NEW_FOLDER="\\$FOLDER"
sed -i "s#$FOLDER#\\$NEW_FOLDER#g" ./file.XML

Dereferencing variables in awk

Why doesn't this work?
x=5
$ ls -l | awk '{print $(($x))}'
should print field 5 of ls -l command, right?
The only ways you should pass in the value of shell variable to awk are the following
$ x=5
$ ls -l | awk -v x="$x" '{print $x}'
$ ls -l | awk '{print $x}' x="$x"
The main difference between these two methods is that by using -v the value of x is set in the BEGIN block whilst the second method the value would not be set. All other methods with quoting tricks or escaping should not be used unless you like headaches.
However you don't want to being parsing ls at all, the command you really want is:
stat --printf="%s\n" *
Assuming the fifth column of your ls is the same as mine, this will display all the file sizes in the current directory.
You could access the shell variable something similar to these;
The first way is not suggested!
x=5
ls -l | awk '{print $'$x'}'
or assigning the value x to the variable shellVar, before execution of the program begins
x=5
ls -l | awk -v shellVar="$x" '{print $shellVar}'
or using an array containing the values of the current environment
export x=5
ls -l | awk '{print $ENVIRON["x"]}'
That's a shell variable, which is not expanded by the shell in single quotes. The reason we put awk scripts in single quotes is precisely to prevent the shell from interpreting things meant for awk's benefit and screwing things up, but sometimes you want the shell to interpret part of it.
For something like this, I prefer to pass the value in as an awk variable:
ls -l | awk -v "x=$x" '{print $x}'
but you could do any number of other ways. For instance, this:
ls -l | awk '{print $'$x'}'
which should really be this:
ls -l | awk '{print $'"$x"'}'
alternatively, this:
ls -l | awk "{print \$$x}"
Try this :
ls -l | awk '{print $'$x'}'

How do you change a variable in a KSH if or case statement?

Does anyone know how to set a variable with global scope in a KSH if, case, or loop statement?
I am trying to run the following code but the script only echo's "H" instead of the actual value seen in the input file.
CFG_DIR=${WORK_DIR}/cfg
CFG_FILE=${CFG_DIR}/$1
NAME=$(echo $CFG_FILE | cut -f1 -d\.)
UPPER_BUS_NETWORK="H"
cat ${CFG_FILE} | grep -v ^\# |
while read CLINE
do
PROPERTY=$(echo $CLINE | cut -f1 -d\=)
VALUE=$(echo $CLINE | cut -f2 -d\=)
if [ ${PROPERTY} = "UpperBusService" ]; then
UPPER_BUS_SERVICE="${VALUE}"
fi
if [ ${PROPERTY} = "UpperBusNetwork" ]; then
UPPER_BUS_NETWORK="${VALUE}"
fi
done
echo ${UPPER_BUS_NETWORK}
Are you sure you're running that in ksh? Which version? Ksh93 doesn't set up a subshell in a while loop. Bash, dash, ash and pdksh do, though. I'm not sure about ksh88.
Compare
$ bash -c 'a=111; echo foo | while read bar; do echo $a; a=222; echo $a; done; echo "after: $a"'
111
222
after: 111
to
ksh -c 'a=111; echo foo | while read bar; do echo $a; a=222; echo $a; done; echo "after: $a"'
111
222
after: 222
Zsh gives the same result as ksh93.
Unfortunately, pdksh doesn't support process substitution and ksh93 does, but not when redirected into the done of a while loop, so the usual solution which works in Bash is not available. This is what it would look like:
# Bash (or Zsh)
while read ...
do
...
done < <(command)
Using a temporary file may be the only solution:
command > tmpfile
while read
do
...
done < tmpfile
Some additional notes:
Instead of cat ${CFG_FILE} | grep -v ^\# do grep -v ^\# "${CFG_FILE}"
Usually, you should use read -r so backslashes are handled literally
Instead of NAME=$(echo $CFG_FILE | cut -f1 -d\.) you should be able to do something like NAME=${CFG_FILE%%.*} and VALUE=${#*=}; VALUE=${VALUE%%=*}
Variables should usually be quoted on output, for example in each of your echo statements and your cat command
I recommend the habit of using lowercase or mixed case variable names to avoid conflict with shell variables (though none are present in your posted code)