I'm trying to run an SQL query involving converting one datatype to another.
SELECT
convert(char(12),name) as NAME
FROM
people
WHERE
convert(char(12),place) = 'Chicago'
This works. However, I'm not sure how to alter the query to use wildcard characters. I imagine it would be something like the following (which does not work in its current state) -
SELECT
convert(char(12),name) as NAME
FROM
people
WHERE
convert(char(12),place) = '%Chicago%'
Please help.
If you want to use wildcard characters, you need to use LIKE:
select convert(char(12),name) as NAME
from people
where convert(char(12),place) LIKE '%Chicago%'
Related
The records I am querying for are kept in 2 different formats. Each person has at least 1 record of their email in the format John.Doe#abc.com. Some people have a second record in which their email is DoeJ#abc.com.
How can I query for the records in which the email is formatted like John.Doe#abc.com?
I attempted to do it with the following SQL Statement but I it returns an empty result:
Select * from email where regexp_like(emailaddress, '. (#)')
The end product will be used in a join with a few other Queries, so selecting distinct values is not an option here. The environment is an Oracle DB, and because this will be done through multiple joins, the more efficient it is the better. Does anyone have any ideas what I am doing wrong, or other ways to accomplish this?
Thank you,
Joshua
You can use REGEXP_LIKE:
Select * from email where regexp_like(emailaddress, '\S*\.\S*\#\S*\.\S*')
Use "\S*" to match all non-whitespace characters
Or just a regular LIKE:
Select * from email where emailaddress LIKE '%.%#%.%'
Not sure what characters are included in the % placeholder in Oracle, so you should test it out.
The REGEXP one will give you tighter control over the pattern matching.
Let me know if it works.
How about using like?
where emailaddress like '%.%#%'
The first format seems distinguished by having a period before the ampersand.
I am trying to count the names which has "non-western" characters in my table.
I am using the following but it does not work:
select count(id)
from table
where name != cast(name as varchar(1000))
Is there any other solutions?
Have you tried using regular expression with the exclusion (^). (Thank you Tyron and Damien for pointing out my error and provide the solution to it).
select count(id) from table
where name LIKE ('%[^0-9abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ]%')
Check this link https://msdn.microsoft.com/en-us/library/ms179859.aspx
(Below is the content copied from the link)
[^] Any single character not within the specified range ([^a-f]) or set ([^abcdef]). WHERE au_lname LIKE 'de[^l]%' all author last names starting with de and where the following letter is not l.
I do not know if DVT solution did not work for me because I am trying it on Redshift or not.
Anyway I manipulated his solution to be accepted with redshift logic and it works as following:
select count(*)
from table
where ( name !~* '([A-Z].*)' )
for more details
I need to find the '&' in a string.
SELECT * FROM TABLE WHERE FIELD LIKE ..&...
Things we have tried :
SELECT * FROM TABLE WHERE FIELD LIKE '&&&'
SELECT * FROM TABLE WHERE FIELD LIKE '&\&&'
SELECT * FROM TABLE WHERE FIELD LIKE '&|&&' escape '|'
SELECT * FROM TABLE WHERE FIELD LIKE '&[&]&'
None of these give any results in SQLServer.
Well some give all rows, some give none.
Similar questions that didn't work or were not specific enough.
Find the % character in a LIKE query
How to detect if a string contains special characters?
some old reference Server 2000
http://web.archive.org/web/20150519072547/http://sqlserver2000.databases.aspfaq.com:80/how-do-i-search-for-special-characters-e-g-in-sql-server.html
& isn't a wildcard in SQL, therefore no escaping is needed.
Use % around the value your looking for.
SELECT * FROM TABLE WHERE FIELD LIKE '%&%'
Your statement contains no wildcards, thus is equivalent to WHERE FIELD = '&'.
& isn't a special character in SQL so it doesn't need to be escaped. Just write
WHERE FIELD LIKE '%&%'
to search for entries that contain & somewhere in the field
Be aware though, that this will result in a full table scan as the server can't use any indexes. Had you typed WHERE FIELD LIKE '&%' the server could do a range seek to find all entries starting with &.
If you have a lot of data and can't add any more constraints, you should consider using SQL Server's full-text search to create and use and FTS index, with predicates like CONTAINS or FREETEXT
How to retrieve a column containing special characters including alphabets in SQL Query. i have a column like this 'abc%def'. i want to retrieve '%' based columns from that table.
Please help me in this regard.
Is abc%def the column name? or column value? Not sure what you are asking but if you mean your column name contains special character then you can escape them which would be different based on specific RDBMS you are using
SQL Server use []
select [abc%def] from tab
MySQL use backquote
select `abc%def` from tab
EDIT:
Try like below to fetch column value containing % character (Checked, it works in Ingres as well)
select * from tab where col like '%%%'
Others suggest that like '%%%' works in Ingres. So this is something special in Ingres. It does not work in other dbms.
In standard SQL you would have to declare an escape character. I think this should work in Ingres, too.
select * from mytable where str like '%!%%' escape '!';
I have the following SQL query:
SELECT Phrases.*
FROM Phrases
WHERE (((Phrases.phrase) Like "*ing aids*")
AND ((Phrases.phrase) Not Like "*getting*")
AND ((Phrases.phrase) Not Like "*contracting*"))
AND ((Phrases.phrase) Not Like "*preventing*"); //(etc.)
Now, if I were using RegEx, I might bunch all the Nots into one big (getting|contracting|preventing), but I'm not sure how to do this in SQL.
Is there a way to render this query more legibly/elegantly?
Just by removing redundant stuff and using a consistent naming convention your SQL looks way cooler:
SELECT *
FROM phrases
WHERE phrase LIKE '%ing aids%'
AND phrase NOT LIKE '%getting%'
AND phrase NOT LIKE '%contracting%'
AND phrase NOT LIKE '%preventing%'
You talk about regular expressions. Some DBMS do have it: MySQL, Oracle... However, the choice of either syntax should take into account the execution plan of the query: "how quick it is" rather than "how nice it looks".
With MySQL, you're able to use regular expression where-clause parameters:
SELECT something FROM table WHERE column REGEXP 'regexp'
So if that's what you're using, you could write a regular expression string that is possibly a bit more compact that your 4 like criteria. It may not be as easy to see what the query is doing for other people, however.
It looks like SQL Server offers a similar feature.
Sinec it sounds like you're building this as you go to mine your data, here's something that you could consider:
CREATE TABLE Includes (phrase VARCHAR(50) NOT NULL)
CREATE TABLE Excludes (phrase VARCHAR(50) NOT NULL)
INSERT INTO Includes VALUES ('%ing aids%')
INSERT INTO Excludes VALUES ('%getting%')
INSERT INTO Excludes VALUES ('%contracting%')
INSERT INTO Excludes VALUES ('%preventing%')
SELECT
*
FROM
Phrases P
WHERE
EXISTS (SELECT * FROM Includes I WHERE P.phrase LIKE I.phrase) AND
NOT EXISTS (SELECT * FROM Excludes E WHERE P.phrase LIKE E.phrase)
You are then always just running the same query and you can simply change what's in the Includes and Excludes tables to refine your searches.
Depending on what SQL server you are using, it may support REGEX itself. For example, google searches show that SQL Server, Oracle, and mysql all support regex.
You could push all your negative criteria into a short circuiting CASE expression (works Sql Server, not sure about MSAccess).
SELECT *
FROM phrases
WHERE phrase LIKE '%ing aids%'
AND CASE
WHEN phrase LIKE '%getting%' THEN 2
WHEN phrase LIKE '%contracting%' THEN 2
WHEN phrase LIKE '%preventing%' THEN 2
ELSE 1
END = 1
On the "more efficient" side, you need to find some criteria that allows you to avoid reading the entire Phrases column. Double sided wildcard criteria is bad. Right sided wildcard criteria is good.