I have the following table:
CUST_PRODUCT_DTL
Cust_ID Product_ID QTY
1 10 5
2 10 2
3 10 5
1 11 5
2 12 1
How can I get Total Distinct CUST_ID, TOTAL DISTINCT PRODUCT_ID from the above table in Oracle 11 G
The below one doesn't work
SELECT SUM(COUNT(DISTINCT cust_id)), product_id
FROM CUST_PRODUCT_DTL
WHERE
GROUP BY product_id , cust_id
The desired result I am looking at is
Total Unique Cust_id: 3
Total Unique Product_id:3
sum is not involved, nor do you need the group by. Your desired output contains only one row. You just want two count distincts:
select count(distinct cust_id) as total_distinct_cust_id,
count(distinct product_id) as total_distinct_prod_id
from cust_product_dtl
Related
I have a table like this:
id | invoice_id | product_id | quantity | total
1 5 10 2 100
2 5 10 1 50
3 5 11 1 200
4 5 11 1 200
I want to combine the rows having same product_id in an invoice by adding their quantities and total values to one of the rows and then delete the other rows in the table. So the output should be like this
id | invoice_id | product_id | quantity | total
1 5 10 3 150
3 5 11 2 400
How can I do this? I was thinking of using an sql function that returns a list of id's having the same invoice and product and then using aggregate functions on quantity and price. Are there any simpler ways to do this?
First, you need an UPDATE statement that updates for each invoice_id, product_id combination the row with the min id with the totals of quantity and total:
UPDATE tablename t
SET quantity = s.quantity,
total = s.total
FROM (
SELECT MIN(id) id, SUM(quantity) quantity, SUM(total) total
FROM tablename
GROUP BY invoice_id, product_id
) s
WHERE s.id = t.id;
Then a DELETE statement to delete all the other ids:
DELETE FROM tablename t1
WHERE t1.id > (
SELECT MIN(t2.id)
FROM tablename t2
WHERE t2.invoice_id = t1.invoice_id AND t2.product_id = t1.product_id
);
See the demo.
This looks like an aggregation query:
select min(id) as id, invoice_id, product_id,
sum(quantity) as quantity, sum(total) as total
from t
group by invoice_id, product_id;
I am trying to get a count of records of data that spans over three tables. I have a table of products, a table of groups and a table showing which groups a product is in. As below:
Product
Product_ID
Product_Name
1
A Product
2
Another Product
Group
Group_ID
Group_Name
10
Group A
20
Group B
30
Group C
40
Group D
Product Grouping
Product_ID
Group_ID
1
10
1
20
1
30
2
20
2
40
3
50
I am trying to write a query that will, given the condition of group ids of say for example (10,20,30), it will return product 1. And if I give group ids of say (20), it will return product 1 and product 2
I have tried:
select * from product_grouping
where group_id = 10 and group_id = 20 and group_id = 30
Use aggregation and having:
select pg.group_id
from product_grouping pg
where pg.group_id in (10, 20 30)
group by product_id
having count(*) = 3;
If the product groupings can be duplicated, use having count(distinct pg.group_id) = 3.
I have a list of transactions where the ID's are repeated and I have the quantity of items being bought. I need to count the number of times that a particular number of items were purchased at once.
Row
ItmNBR
TQTY
1
123
5
2
123
5
3
123
5
3
456
25
4
456
19
I need to produce an out put like this...
ItmNBR
QTY
Occurance
123
5
3
123
19
1
123
25
1
I can get the first two columns of my result but when I attempt to counting over a partition I end up counting getting repeating numbers since I'm only looking up 9 items I just count the number of rows in which the Cnt is the same.
TOT_IVO_ITM_QTY
Count(*) OVER (PARTITION BY QTY) AS CNT
FROM dataset
WHERE YEAR(bus_dt) = 2021
AND ITM_NBR IN (12639,12940,12949,12955,13485,13666,43950,631343,1103731)
AND QTY BETWEEN 5 AND 25
ORDER BY ITM_NBR
,QTY
GROUP BY ITM_NBR, TOT_IVO_ITM_QTY```
I think you just want group by:
select ItmNBR, QTY, count(*)
from t
group by ItmNBR, QTY
order by count(*) desc;
This assumes that you want the count by item and quantity, which seems to be the gist of the question.
I'm trying to create a running total based on groups of records. My data looks like the below
Country | Genre | Month | Amt
A X 1 5
A X 2 3
B X 1 8
B Y 1 10
A X 1 12
I'd like to do a running sum on Amt grouped by unique occurences of Genre and Month for each Country. So my desired output is
Country | Genre | Month | Amt | RunAmt
A X 1 5 5
A X 2 3 3
B X 1 8 8
B Y 1 10 10
A X 1 12 17
Since Genre = X and Month = 1 has occurred previously for country A.
My attempt has been sum(amt) over (partition by country, genre, month order by month rows between unbounded preceding and current row) but it seems to do a running sum over every row not for unique occurences by country. Any help would be appreciated.
Try this
SELECT *,
Sum(amt)
OVER(
partition BY country, genre, month
ORDER BY amt) as RunAmt
FROM ( VALUES ('A','X',1,5),
('A','X',2,3),
('B','X',1,8),
('B','Y',1,10),
('A','X',1,12) )tc(Country, Genre, Month, Amt)
Try this..
select *,
sum(amt) over
(
partition by country, Genre, month order by amt
) as RunAmt
from TableName
Here is the SQLFiddle for you that I tried.
I have a SQL data scructure like this.
Table 1
http://pbrd.co/1x6TAl3
Table 2
http://pbrd.co/1x6TIRw
I'm trying to count the number of times each item_num has been sold based on the item_qty value in the second table.
Each item_num can appear multiple times in the second table.
I need a way to add the total item_qty for each associated item_num and output it to show how many times an item has been sold.
The correct output ordering by total quantity sold in descending order should look like this.
item_num: 4 7 6
qty_sold: 11 5 4
Try this:
SELECT
a.item_num
, SUM(b.item_qty) as "qty_sold"
FROM
Table1 a
LEFT JOIN
Table2 b
ON a.item_num = b.item_num
GROUP BY
a.item_num
ORDER BY
qty_sold DESC
SELECT A.Item_num , A.Item_name , sum(B.Item_Qty) from Table1 as A inner join Table2 as B
on A.Item_num=B.Item_num
group by A.Item_num , A.Item_name
result:
item_num item_name Item_qty
1 A 1
2 B 1
4 D 11
6 F 4
7 G 5