I have a SQL data scructure like this.
Table 1
http://pbrd.co/1x6TAl3
Table 2
http://pbrd.co/1x6TIRw
I'm trying to count the number of times each item_num has been sold based on the item_qty value in the second table.
Each item_num can appear multiple times in the second table.
I need a way to add the total item_qty for each associated item_num and output it to show how many times an item has been sold.
The correct output ordering by total quantity sold in descending order should look like this.
item_num: 4 7 6
qty_sold: 11 5 4
Try this:
SELECT
a.item_num
, SUM(b.item_qty) as "qty_sold"
FROM
Table1 a
LEFT JOIN
Table2 b
ON a.item_num = b.item_num
GROUP BY
a.item_num
ORDER BY
qty_sold DESC
SELECT A.Item_num , A.Item_name , sum(B.Item_Qty) from Table1 as A inner join Table2 as B
on A.Item_num=B.Item_num
group by A.Item_num , A.Item_name
result:
item_num item_name Item_qty
1 A 1
2 B 1
4 D 11
6 F 4
7 G 5
Related
I'm trying to merge the values of two rows based on the value of another row in a different column. Below is my based table
Customer ID
Property ID
Bookings per customer
Cancellations per customer
A
1
0
1
B
2
10
1
C
3
100
1
C
4
100
1
D
5
20
1
Here is the SQL query I used
select customer_id, property_id, bookings_per_customer, cancellations_per_customer
from table
And this is what I want to see. Any ideas the query to get this would be? We use presto SQL
Thanks!
Customer ID
Property ID
Bookings per customer
Cancellations per customer
A
1
0
1
B
2
10
1
C
3 , 4
100
1
D
5
20
1
We can try:
SELECT
customer_id,
ARRAY_JOIN(ARRAY_AGG(property_id), ',') AS properties,
bookings_per_customer,
cancellations_per_customer
FROM yourTable
GROUP BY
customer_id,
bookings_per_customer,
cancellations_per_customer;
This is my parent table acc_detial -
ACC_DETIAL example -
acc_id
1
2
3
Now i have 3 tables:
ORDER
EMAIL
REPORT
Each table contains 100 rows and acc_id are ForeignKey from ACC_DETIAL.
In ORDER table I have a columns ACC_ID and QUANTITY. I want the count of ACC_ID and sum of QUANTITY.
ORDER table example:
acc_id
quantity
date
1
2
2022/01/22
2
5
2022/01/23
1
10
2022/01/25
3
1
2022/01/25
In EMAIL table I have a column name ACC_ID and I want count of ACC_ID.
EMAIL table example:
acc_id
mail
date
1
5
2022/01/22
2
10
2022/01/22
1
7
2022/01/23
1
7
2022/01/24
2
10
2022/01/25
In REPORT table I have a columns ACC_ID and TYPE and I want the count of ACC_ID and TYPE. Note that TYPE column has only two, possible values:
postive
negative
I want count of each, i.e. count of postive and count of negative in TYPE column.
REPORT table example:
acc_id
type
date
1
positive
2022/01/22
2
negative
2022/01/22
1
negative
2022/01/23
2
postitive
2022/01/26
2
postitive
2022/01/27
I need to take this in a single i need answer as raw query or sqlalchemy. Is it possible or not? Do I need to write separate query to get each table result ?
Result -
result based on above examplec -
acc_id
total_Order_acc_id
total_Order_quantity
total_Email_acc_id
total_Report_acc_id
total_postitive_report
total_negative_report
1
2
12
3
2
1
1
2
1
5
2
3
2
1
3
1
1
Null
Null
Null
Null
You need to aggregate then join as the following:
SELECT ADL.acc_id,
ORD.ord_cnt AS total_Order_acc_id,
ORD.tot_quantity AS total_Order_quantity,
EML.eml_cnt AS total_Email_acc_id,
RPT.rpt_cnt AS total_Report_acc_id,
RPT.pcnt AS total_postitive_report,
RPT.ncnt AS total_negative_report
FROM ACC_DETIAL ADL LEFT JOIN
(
SELECT acc_id,
SUM(quantity) AS tot_quantity,
COUNT(*) AS ord_cnt
FROM ORDERS
GROUP BY acc_id
) ORD
ON ADL.acc_id = ORD.acc_id
LEFT JOIN
(
SELECT acc_id, COUNT(*) AS eml_cnt
FROM EMAIL
GROUP BY acc_id
) EML
ON ADL.acc_id = EML.acc_id
LEFT JOIN
(
SELECT acc_id,
COUNT(*) AS rpt_cnt,
COUNT(*) FILTER (WHERE type='positive') AS pcnt,
COUNT(*) FILTER (WHERE type='negative') AS ncnt
FROM REPORT
GROUP BY acc_id
) RPT
ON ADL.acc_id = RPT.acc_id
See demo
Sample :
Select
`order`.`acc_id`,
report_email_select.`type`,
report_email_select.report_count,
report_email_select.email_count,
SUM(`quantity`) as quantity_sum
FROM
`order`
Left JOIN(
Select
report_select.`acc_id`,
report_select.`type`,
report_select.report_count,
COUNT(*) as email_count
from
(
SELECT
report.`acc_id`,
report.`type`,
COUNT(*) as report_count
FROM
`report`
WHERE
1
GROUP BY
report.`acc_id`,
report.`type`
) AS report_select
INNER JOIN email ON email.acc_id = report_select.acc_id
GROUP BY
report_select.`acc_id`,
report_select.`type`
) AS report_email_select ON `order`.acc_id = report_email_select.acc_id
GROUP BY
`order`.`acc_id`,
report_email_select.`type`;
I have a product table:
productid product
1 A-110
2 B-110
3 C-400
4 D-401
And orderditems table:
orderitemid productid qty
1 1 10
2 2 10
3 3 10
4 3 10
5 4 10
I can group by based on product as:
select productid, sum(qty)
from ordereditems
group by productid
Which gives:
1 10
2 10
3 20
4 10
However for this query productid 1 & 2 , 3 & 4 are the same.
Meaning that I want to see:
1 + 2 20
3 + 4 30
Basically I want the query to understand that 1 & 2 are the same group and 3 & 4 are the same group.
How can i do that?
Edit:
Products 1 & 2 , 3 & 4 are not the same. However they are of the same family... What I want is to see how much we sell per family and not per product.
This is why the desired out put is:
1 + 2 20
3 + 4 30
A hacky version if you know that 1&2 are the same and 3&4 are the same, and those are the only things the same.
select
case
when productid in (1,2) then '1 + 2'
when productid in (3,4) then '3 + 4'
else productid
end as product_ids, sum(qty)
from ordereditems
group by
case
when productid in (1,2) then '1 + 2'
when productid in (3,4) then '3 + 4'
else productid
end
A better approach is to record in the database that two products are the same. Either by linking the duplicated products (2,4) to the product they're the same as (1,3) or by creating a new table family etc. and recording that products 1,2 are related to the same family.
family
familyid name
1 1+2
2 3+4
Extend product table
productid product familyid
1 A-110 1
2 B-110 1
3 C-400 2
4 D-401 2
then you can group on family
select f.name, sum(qty)
from ordereditems oi
inner join product p on oi.productid = p.productid
inner join family f on p.familyid = f.familyid
group by f.name
Pls add a GroupID/Category field to your table.
productid product GroupID
1 A-110 A
2 B-110 A
3 C-400 B
4 D-401 B
Then use the query
select GroupID, sum(qty) as Sold
from ordereditems
group by GroupID
This will represent as group sale as if you have more than 10 products in a group your productid will make complicity to understand.
If it works for you pls mark as helpful.. :)
I am trying to figure out this problem but, it's already taking me a few days and I cant seem to solve it.
The questions demands:
Display a list of products (show ProductID and ProductDescription as the first two columns), the number of times each product has been ordered (the third column), and the total quantity each product has been ordered over all orders (the forth column).
The Database:
**Product_T** **OrderLine_T**
ProductID ProductDescription ProductID OrderedQuantity
1 End Table 1 2
2 Coffe Table 2 2
3 Computer Desk 4 1
4 Entertainment Center 3 5
5 Writers Desk 3 3
6 8-Drawer Desk 6 2
7 Dining Table 8 2
8 Computer Desk 4 4
4 1
5 2
7 2
1 3
2 2
3 3
8 3
4 2
7 3
8 10
Just a JOIN and GROUP BY
SELECT p.ProductID,
p.ProductDescription,
COUNT(*) AS time_ordered,
SUM(o.OrderedQuantity) AS qty_ordered
FROM Product_T as p
LEFT JOIN OrderLine_T AS o
ON p.ProductID = o.ProductID
GROUP BY p.ProductID,
p.ProductDescription;
Try this:
SELECT t1.ProductID,
t1.ProductDescription,
COALESCE(t2.num_times_ordered, 0) AS num_times_ordered,
COALESCE(t2.total_quantity, 0) AS total_quantity
FROM Product_T t1
LEFT JOIN
(
SELECT ProductID,
COUNT(*) AS num_times_ordered,
SUM(OrderedQuantity) AS total_quantity
FROM OrderLine-T
GROUP BY ProductID
) t2
ON t1.ProductID = t2.ProductID
The answer given by #GurV is more concise than this and works for this particular problem, but in general you would need to use a subquery to obtain stats from the OrderLine-T table, assuming that you wanted to include non-aggregate columns from Product_T in your report.
I have the following table:
CUST_PRODUCT_DTL
Cust_ID Product_ID QTY
1 10 5
2 10 2
3 10 5
1 11 5
2 12 1
How can I get Total Distinct CUST_ID, TOTAL DISTINCT PRODUCT_ID from the above table in Oracle 11 G
The below one doesn't work
SELECT SUM(COUNT(DISTINCT cust_id)), product_id
FROM CUST_PRODUCT_DTL
WHERE
GROUP BY product_id , cust_id
The desired result I am looking at is
Total Unique Cust_id: 3
Total Unique Product_id:3
sum is not involved, nor do you need the group by. Your desired output contains only one row. You just want two count distincts:
select count(distinct cust_id) as total_distinct_cust_id,
count(distinct product_id) as total_distinct_prod_id
from cust_product_dtl