Update table with values of another table (PostgreSQL) - sql

Question

I'm trying to update an table with data from another table (using PostgreSQL). My table is something like:
+-------------------+-------------------+-----------------------+
| id_location | user_location | social_sec_number |
+-------------------+-------------------+-----------------------+
| 00000000001 | Jason (null) | 812.539.037 |
+-------------------+-------------------+-----------------------+
| 00000000002 | Jennifer (null) | 066.307.382 |
+-------------------+-------------------+-----------------------+
| 00000000003 | Albert (null) | 560.732.535 |
+-------------------+-------------------+-----------------------+
And I want Into this:
+-------------------+---------------------------+-----------------------+
| id_location | user_location | social_sec_number |
+-------------------+---------------------------+-----------------------+
| 00000000001 | Jason (812.539.037) | 812.539.037 |
+-------------------+---------------------------+-----------------------+
| 00000000002 | Jennifer (066.307.382) | 066.307.382 |
+-------------------+---------------------------+-----------------------+
| 00000000003 | Albert (560.732.535) | 560.732.535 |
+-------------------+---------------------------+-----------------------+
Columns id_location and user_location are in the same table TableLocation, but social_sec_number are in another table.
My code trying update them (this code does not reflect what was shown in the examples of tables):
WITH tb_cpf
AS (
SELECT doc.nr_documento_identificacao
FROM core.tb_usuario_localizacao ul
INNER JOIN core.tb_localizacao l ON ul.id_localizacao = l.id_localizacao
INNER JOIN client.tb_pess_doc_identificacao doc ON ul.id_usuario = doc.id_pessoa
WHERE l.ds_localizacao ilike '%(null)%'
AND doc.cd_tp_documento_identificacao = 'CPF'
)
UPDATE core.tb_localizacao AS l
SET l.ds_localizacao = REPLACE(l.ds_localizacao, '(null)', tb_cpf)
WHERE l.id_localizacao IN (
SELECT l.id_localizacao
FROM core.tb_usuario_localizacao ul
INNER JOIN core.tb_localizacao l ON ul.id_localizacao = l.id_localizacao
INNER JOIN client.tb_pess_doc_identificacao doc ON ul.id_usuario = doc.id_pessoa
WHERE l.ds_localizacao ilike '%(null)%'
AND doc.cd_tp_documento_identificacao = 'CPF'
)
AND tb_pess_doc_identificacao.id_pessoa = tb_usuario_localizacao.id_usuario
AND tb_usuario_localizacao.id_localizacao = tb_localizacao.id_localizacao;
And I receive this ugly error:
ERROR: column "tb_cpf" does not exist
LINE 11: ... of l.ds_localizacao = REPLACE (l.ds_localization, '(null)', tb_cpf)
^
********** Error **********
ERROR: column "tb_cpf" does not exist
SQL state: 42703
Character: 433
That way, it is possible that each record with "null" is replaced by social security (for example) on every table?

Answer 1

You're misunderstanding with clause usage. Think of it like a view or like a subquery. It works exactly like a memory table. You have to expose all columns you're gonna use.
But, why are you complicating it so much? Why don't you do something as simple as this?
update mytable m1
set m1.mycolumn = replace( m1.mycolumn,
'(null)',
(
select mycolumn2
from mytable2 m2
where m2.id = m1.id
)
)
where m1.mycolumn like '%(null)'
Or, if you really want to use with (for performance issues):
with t1 as
(select t.id,
t.mycolumn
from mytable
)
update mytable2 t2
set t2.mycolumn = replace (t2.mycolumn, '(null)', t1.mycolumn)
where t2.id = t1.id
and t2.mycolumn like '%(null)'

Answer 2

The tb_cpf from the CTE works like any other relation in your main UPDATE statement. You are missing a column identifier, so if you add .nr_documento_identificacao to tb_cpf then the update should work:
WITH tp_cpf AS (
...
)
UPDATE core.tb_localizacao AS l
SET l.ds_localizacao = REPLACE(l.ds_localizacao, 'null', tb_cpf.nr_documento_identificacao)
WHERE ...