I am trying to get the results:
Quote = 12345
Total Assets = 14
Total Ordered = 22
When I run the queries separately I get the correct results, but when I put the two queries together my results are off (this is because the tables b and c do not represent each other)
my table summaries are as follows:
Select a.Quote, SUM(b.Quantity) As 'Total Assets'
FROM a
INNER JOIN b ON b.aId = a.Id
GROUP By a.Quote
Result: 12345 : 14
Select a.Quote, SUM(c.Quantity) As 'Total Ordered'
FROM a
INNER JOIN c on c.aId = a.Id
GROUP By a.Quote
Result: 12345 : 22
However, when I put them together:
Select a.Quote, SUM(b.Quantity)As 'Total Assets',SUM(c.Quantity) As 'Total Ordered'
FROM a
INNER JOIN b on b.Aid = a.Id
INNER JOIN c on c.Aid = a.Id
GROUP BY a.Quote
Result 12345 : 56 : 308
I played with the group by but was never able to get the proper result. Any thoughts?
So far the solution I came up with is
With abc AS
(
Select a.Quote, SUM(b.Quantity) As 'Total Assets'
FROM a
INNER JOIN b ON b.aId = a.Id
GROUP By a.Quote
)
SELECT abc.* , SUM(c.Quantity) As ' Total Ordered'
FROM abc
INNER JOIN c ON c.aid = a.Id
GROUP BY (all in abc)
It doesn't seem like the best way to get the results though..
Maybe use Left JOIN. The INNER JOIN will repeat rows of b and c. Also, try to see the result of:
Select a.Quote, b.Quantity As 'Total Assets', c.Quantity As 'Total Ordered'
FROM a
INNER JOIN b on b.Aid = b.Id
INNER JOIN c on c.Aid = c.Id
GROUP BY a.Quote
And check if it's the right results that are computed. Then compare it against:
Select a.Quote, b.Quantity As 'Total Assets', c.Quantity As 'Total Ordered'
FROM a
LEFT JOIN b on b.Aid = b.Id
LEFT JOIN c on c.Aid = c.Id
GROUP BY a.Quote
Related
I'm making a query to get the stages of a case. So Now I have three cases with 3 stages (the last stage inserted in the table user_case_stage).
SELECT DISTINCT ON (c.id)
c.id,
f.name
FROM schema.user a
JOIN schema.intern_user b ON a.id = b."userId"
JOIN schema.user_case c ON b.id = c."internUserId"
JOIN schema.user_case_stage d ON c.id = d."userCaseId"
JOIN schema.stage f ON d."stageId" = f.id
WHERE b.id = 1
ORDER BY c.id,d."createdAt" DESC
Result:
caseId stageName
1 "Pasive"
6 "Closed"
7 "Closed"
But I want something to count by stageName like this:
total stageName
1 "Pasive"
2 "Closed"
assumed your logic is correct , since you didn't provide any information, here is how you can do it:
SELECT
f.name
, count(distinct c.id) total
FROM schema.user a
JOIN schema.intern_user b ON a.id = b."userId"
JOIN schema.user_case c ON b.id = c."internUserId"
JOIN schema.user_case_stage d ON c.id = d."userCaseId"
JOIN schema.stage f ON d."stageId" = f.id
WHERE b.id = 1
group by f.name
I have a problem with this query
SELECT DISTINCT(oth.book) FROM book_meta_keywords oth,
(SELECT bmk.meta_keyword AS metaKeyword, bmk.book AS book FROM books b
INNER JOIN customers_books cvb ON cvb.book = b.id
INNER JOIN book_meta_keywords bmk ON bmk.book = b.id
WHERE cvb.customer = 1 ) AS allCustomerPurchasedBooksMeta
INNER JOIN books b ON b.id = oth.book
WHERE oth.meta_keyword = allCustomerPurchasedBooksMeta.metaKeyword AND oth.book != allCustomerPurchasedBooksMeta.book AND b.status = 'GOOD'
I am getting below error for this query.
ERROR: invalid reference to FROM-clause entry for table "oth"
LINE 6: INNER JOIN books b ON b.id = oth.book
^
HINT: There is an entry for table "oth", but it cannot be referenced from this part of the query.
, Time: 0.002000s
But if I run the below query it works
SELECT DISTINCT(oth.book) FROM book_meta_keywords oth,
(SELECT bmk.meta_keyword AS metaKeyword, bmk.book AS book FROM books b
INNER JOIN customers_books cvb ON cvb.book = b.id
INNER JOIN book_meta_keywords bmk ON bmk.book = b.id
WHERE cvb.customer = 1 ) AS allCustomerPurchasedBooksMeta
WHERE oth.meta_keyword = allCustomerPurchasedBooksMeta.metaKeyword AND oth.book != allCustomerPurchasedBooksMeta.book
Can anyone help me why... query is basically trying to get similar books based on purchased books based on their meta keywords.
thanks.
This is your FROM clause:
FROM
book_meta_keywords oth,
(SELECT ... FROM ... WHERE ...) AS allCustomerPurchasedBooksMeta
INNER JOIN books b ON b.id = oth.book
You are mixing explicit and implicit joins (the latter is denoted by the comma). Don't. They have different prescendence rules and the query planner ends up evaluating the the second condiiton before oth was seen.
As for how to solve this: assuming that the logic is indeed what you want, that's a lateral join:
FROM
book_meta_keywords oth
CROSS JOIN LATERAL (SELECT ... FROM ... WHERE ...) AS allCustomerPurchasedBooksMeta
INNER JOIN books b ON b.id = oth.book
I suspect, however, that your query could be further simplified. You might want to ask another question for this, explaning the purpose of the query and providing a minimum reproducible example.
You are missing join
SELECT DISTINCT oth.book FROM book_meta_keywords oth join
(SELECT bmk.meta_keyword AS metaKeyword, bmk.book AS book FROM books b
INNER JOIN customers_books cvb ON cvb.book = b.id
INNER JOIN book_meta_keywords bmk ON bmk.book = b.id
WHERE cvb.customer = 1 ) AS allCustomerPurchasedBooksMeta
on oth.meta_keyword = allCustomerPurchasedBooksMeta.metaKeyword and
oth.book != allCustomerPurchasedBooksMeta.book
INNER JOIN books b ON b.id = oth.book
WHERE b.status = 'GOOD'
Well it can work :
SELECT DISTINCT oth.book
FROM book_meta_keywords oth
INNER JOIN books b ON b.id = oth.book
, (SELECT bmk.meta_keyword AS metaKeyword, bmk.book AS book
FROM books b
INNER JOIN customers_books cvb ON cvb.book = b.id
INNER JOIN book_meta_keywords bmk ON bmk.book = b.id
WHERE cvb.customer = 1 ) AS allCustomerPurchasedBooksMeta
WHERE oth.meta_keyword = allCustomerPurchasedBooksMeta.metaKeyword
AND oth.book != allCustomerPurchasedBooksMeta.book
AND b.status = 'GOOD'
But does this do what you need...
I'm working on another SQL query, trying to group a collection of records while doing a count and joining tables. See below for goal, current query, and attached scripts for building and populating tables.
Show all customers who have checked more books than DVDs. Display
customer name, total book checkouts and total DVD checkouts. Sort
results by customer first name and last name.
SELECT C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME, COUNT(T.TRANSACTION_ID)
FROM customer C
INNER JOIN library_card LC ON C.CUSTOMER_ID = LC.CUSTOMER_ID
INNER JOIN transaction T ON LC.LIBRARY_CARD_ID = T.LIBRARY_CARD_ID
INNER JOIN physical_item P ON T.PHYSICAL_ITEM_ID = P.PHYSICAL_ITEM_ID
INNER JOIN catalog_item CT ON P.CATALOG_ITEM_ID = CT.CATALOG_ITEM_ID
GROUP BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME
ORDER BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME;
Run first: https://drive.google.com/open?id=1PYAZV4KIfZtxP4eQn35zsczySsxDM7ls
Run second: https://drive.google.com/open?id=1pAzWmJqvD3o3n6YJqVUM6TtxDafKGd3f
EDIT
With some help from Mr. Barbaros I've come up with the below query, which is closer. However, this query isn't returning any results for DVDs, which leads me to believe it's a join issue.
SELECT C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME, COUNT(CT1.TYPE) AS BOOK_COUNT, COUNT(CT2.TYPE) AS DVD_COUNT
FROM customer C
INNER JOIN library_card LC ON C.CUSTOMER_ID = LC.CUSTOMER_ID
INNER JOIN transaction T ON LC.LIBRARY_CARD_ID = T.LIBRARY_CARD_ID
INNER JOIN physical_item P ON T.PHYSICAL_ITEM_ID = P.PHYSICAL_ITEM_ID
INNER JOIN catalog_item CT1 ON P.CATALOG_ITEM_ID = CT1.CATALOG_ITEM_ID AND CT1.TYPE = 'BOOK'
LEFT OUTER JOIN catalog_item CT2 ON P.CATALOG_ITEM_ID = CT2.CATALOG_ITEM_ID AND CT2.TYPE = 'DVD'
GROUP BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME, CT1.TYPE, CT2.TYPE
ORDER BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME;
Use "conditional aggregates" (use a case expression inside the aggregate function)
SELECT
C.CUSTOMER_FIRSTNAME
, C.CUSTOMER_LASTNAME
, COUNT( CASE WHEN CT.TYPE = 'BOOK' THEN T.TRANSACTION_ID END ) books
, COUNT( CASE WHEN CT.TYPE = 'DVD' THEN T.TRANSACTION_ID END ) dvds
FROM customer C
INNER JOIN library_card LC ON C.CUSTOMER_ID = LC.CUSTOMER_ID
INNER JOIN transaction T ON LC.LIBRARY_CARD_ID = T.LIBRARY_CARD_ID
INNER JOIN physical_item P ON T.PHYSICAL_ITEM_ID = P.PHYSICAL_ITEM_ID
INNER JOIN catalog_item CT ON P.CATALOG_ITEM_ID = CT.CATALOG_ITEM_ID
GROUP BY
C.CUSTOMER_FIRSTNAME
, C.CUSTOMER_LASTNAME
HAVING
COUNT( CASE WHEN CT.TYPE = 'BOOK' THEN T.TRANSACTION_ID END )
> COUNT( CASE WHEN CT.TYPE = 'DVD' THEN T.TRANSACTION_ID END )
ORDER BY
C.CUSTOMER_FIRSTNAME
, C.CUSTOMER_LASTNAME
;
You can use catalog_item table twice( think of as seperate tables for books and dvds ), and compare by HAVING clause as :
SELECT C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME,
COUNT(CT1.CATALOG_ITEM_ID) as "Book Checkout",
COUNT(CT2.CATALOG_ITEM_ID) as "DVD Checkout"
FROM customer C
INNER JOIN library_card LC ON C.CUSTOMER_ID = LC.CUSTOMER_ID
INNER JOIN transaction T ON LC.LIBRARY_CARD_ID = T.LIBRARY_CARD_ID
INNER JOIN physical_item P ON T.PHYSICAL_ITEM_ID = P.PHYSICAL_ITEM_ID
LEFT JOIN catalog_item CT1 ON P.CATALOG_ITEM_ID = CT1.CATALOG_ITEM_ID AND CT1.TYPE = 'BOOK'
LEFT JOIN catalog_item CT2 ON P.CATALOG_ITEM_ID = CT2.CATALOG_ITEM_ID AND CT1.TYPE = 'DVD'
GROUP BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME
HAVING COUNT(CT1.CATALOG_ITEM_ID) > COUNT(CT2.CATALOG_ITEM_ID)
ORDER BY C.CUSTOMER_FIRSTNAME, C.CUSTOMER_LASTNAME;
CUSTOMER_FIRSTNAME CUSTOMER_LASTNAME Book Checkout DVD Checkout
------------------ ----------------- ------------- -------------
Deena Pilgrim 3 1
Emile Cross 5 2
Please try to remove ,CT1.TYPE, CT2.TYPE on your group by clause.
I have a query get_product:
select A.product_id,
A.name, A.description, A.type_id,
B.series_name
product_data A
inner join
series B
on A.series_raw_id = B.series_raw_id
where A.product_id = 503061
and A.registration_type_id = 4
order by B.series_name
and second query
select B.series_name,
A.TEMPACC_STATUS
FROM
ACCESS_FACT A
inner join
**get_product** B
on A.TEMPACC_PRODUCT_ID = B.product_id
where A.TEMPACC_DATE_ID between 6717 and 6808
and A.reason_id_total = 0
group by Series_name,
STATUS
In the second query we use data from first query (get_product is the first query). How do I get that table here?
You could use the WITH clause.
For example,
WITH get_product AS
(SELECT A.product_id,
A.name,
A.description,
A.type_id,
B.series_name product_data A
INNER JOIN series B
ON A.series_raw_id = B.series_raw_id
WHERE A.product_id = 503061
AND A.registration_type_id = 4
ORDER BY B.series_name
)
SELECT B.series_name,
A.TEMPACC_STATUS
FROM ACCESS_FACT A
INNER JOIN get_product B
ON A.TEMPACC_PRODUCT_ID = B.product_id
WHERE A.TEMPACC_DATE_ID BETWEEN 6717 AND 6808
AND A.reason_id_total = 0
GROUP BY Series_name,
STATUS;
Or, you could use an INLINE VIEW
SELECT B.series_name,
A.TEMPACC_STATUS
FROM ACCESS_FACT A
INNER JOIN
(SELECT A.product_id,
A.name,
A.description,
A.type_id,
B.series_name product_data A
INNER JOIN series B
ON A.series_raw_id = B.series_raw_id
WHERE A.product_id = 503061
AND A.registration_type_id = 4
ORDER BY B.series_name
) B ON A.TEMPACC_PRODUCT_ID = B.product_id
WHERE A.TEMPACC_DATE_ID BETWEEN 6717 AND 6808
AND A.reason_id_total = 0
GROUP BY Series_name,
STATUS;
I'm coming across an issue where when I write a query as so:
SELECT a.v, b.w, c.x, d.y, e.z
FROM a
JOIN b
on a.id = b.id
LEFT JOIN c
on a.id = c.id
LEFT JOIN d
on b.code=d.code
JOIN e
on a.n = e.n
WHERE
a.zone = 10
WITH (nolock)
I get several hundred results, but when I modify it to this:
SELECT a.v, b.w, c.x, d.y, e.z
FROM a
JOIN b
on a.id = b.id
LEFT JOIN c
on a.id = c.id AND c.n = 0
LEFT JOIN d
on b.code=d.code AND d.n = 0
JOIN e
on a.n = e.n
WHERE
a.zone = 10
WITH (nolock)
I get zero results.
From my understanding of SQL and left joins, I feel that getting any results with the first query means I should definitely get at least one result with the second, if only one where fields from c and d are null. Does PROGRESS implement outer joins in an unusual manner?
You might want to figure out what the c.n and d.n values are. Try something like this to figure out where your starting point is.
SELECT c.n, d.n, count(*)
FROM a
JOIN b
on a.id = b.id
LEFT JOIN c
on a.id = c.id
LEFT JOIN d
on b.code=d.code
JOIN e
on a.n = e.n
WHERE
a.zone = 10
group by c.n, d.n
Then you can adjust your query based on the result