<healthcare>
<plans>
<plan1>
<planid>100</planid>
<planname>medical</planname>
<desc>medical</desc>
<offerprice>500</offerprice>
<area>texas</area>
</plan1>
<plan2>
<planid>101</planid>
<planname>dental</planname>
<desc>dental</desc>
<offerprice>1000</offerprice>
<area>texas</area>
</plan2>
</plans>
</healthcare>
<splitter evaluator="xpath" expression="/healthcare/plans" doc:name="Splitter"/>
<transformer ref="domToXml" doc:name="Transformer Reference"/>
<logger level="INFO" doc:name="Logger" message=" plans detils...#[message.payload]" />
i have input xml data as above. I want to replace offerprice value from the above xml data . I tried various ways. anyone can shed the light for my requirement in mule
in my requiremnet , hit external api based on the result value , I need to change the offerprice value in the input xml .
anyone help is highly valuable.I need this immediately in my work .please shed light
You can use XSLT to transform the XML file to another XML file (with or without the same schema). Here's a small example of how it would look in mule . . .
http://marcotello.com/mule-esb/using-the-xslt-transformer-in-mule-esb/
There are also a lot of resources for learning how to create XSLT files online / through google.
There are many ways to do it.
You can use Mule XSLT in your flow, which will change the value of offerprice from input xml and you will be getting the required Xml as output with the value you want.
Another way is to use Groovy, with XmlSlurper to parse your input Xml, replace the value, and rebuild the XML you want.
reference :- XML Mapping in Mule
and
Mule: Enriching an XML with additional information from DB
also refer
http://www.ibm.com/developerworks/library/j-pg05199/index.html
Hope this help
Related
How to split xml file into multiple files based on a tag in xml file using mule
In xml we have <EOF> data based on <EOF> we need to chunk the xml.
You can do something similar to:
<splitter expression="#[xpath('//EOF')]" />
That would generate many messages one for each EOF tag in your XML. Depending on the structure you may need to fix the Xpath expression to be more precise.
Use splitter component in Mule
http://www.mulesoft.org/documentation/display/current/Splitter+Flow+Control+Reference
I have a flow that calls a MS SQL stored procedure which returns a value. The output that i get from the DB is {resultset1=[{id=30}]} i would like to store the value of id to flow variable
couldn't find a successful way to do this, Could somebody please help me in this
I'am using mule server 3.4.0 EE
Thank you in Advance
First place a json-to-object-transformer and then try the following :-
<json:json-to-object-transformer returnClass="java.util.HashMap" />
<set-variable variableName="id" value="#[payload.resultset1[0].id]" doc:name="Variable"/>
We are having an xml request that is very huge which contains nearly 10000 xml elements as shown below
<root>
<message></message>
<message></message>
<message></message>
.....
.....
.....
.....
<message></message>
<message></message>
<message></message>
</root>
In mule we are using xpath extractor in for-each processor, which is taking huge amount of time.
Is there a way where we can process huge xml files faster in mule ?
<foreach doc:name="Foreach" batchSize="1" collection="#[xpath://message]">
<!-- stuff -->
</foreach>
Also changing batchSize didn't help.
Is there any other processing way which makes it faster?
we can achieve this by following few best practices in mule
use sax parser instead of DOM for loading the xml
divide the file into chunks and process the chunks parellelly
if you are storing the data in several variables do not store the
complete xml which may cause the memory leak
remove variables at the end of each mule flow
if unnecessary
I'm using Mule ESB CE 3.4. I have a requirement where I'm reading the configuration information from database and using it as the file name for the file outbound endpoint. Here is an example code (the code may not work as I have only given an outline)
<file:connector name="File-Data" autoDelete="false" streaming="true" validateConnections="true" doc:name="File" />
.....
<!-- Gets the configuration from database using a transformer. The transformer populates the configuration entries in a POJO and puts that in a session. -->
<custom-transformer class="com.test.DbGetConfigsTransformer" doc:name="Get Integration Configs"/>
....<!-- some code to process data -->
<logger message="$$$: #[sessionVars['currentFeed'].getFilePattern()]" doc:name="Set JSON File Name" /> -->
<file:outbound-endpoint path="/temp" outputPattern="#[sessionVars['currentFeed'].getFilePattern()]" responseTimeout="10000" mimeType="text/plain" connector-ref="File-Data" doc:name="Save File"/>
The above code throws the following error:
1. The filename, directory name, or volume label syntax is incorrect (java.io.IOException)
java.io.WinNTFileSystem:-2 (null)
2. Unable to create a canonical file for /temp/Test_User_#[function:datestamp:YYYYMMddhhmmss.sss] (org.mule.api.MuleRuntimeException)
org.mule.util.FileUtils:354 (http://www.mulesoft.org/docs/site/current3/apidocs/org/mule/api/MuleRuntimeException.html)
3. Failed to route event via endpoint: DefaultOutboundEndpoint{endpointUri=file:///temp, connector=FileConnector
In the database table, the field name is called FilePattern and it has the value 'Test_User_#[function:datestamp:YYYYMMddhhmmss.sss]. If I hardcode the value or move this value to the mule configuration file
file.name=Test_User_#[function:datestamp:YYYYMMddhhmmss.sss]
and use the configuration property syntax (for e.g. ${file.name} in the 'outputpattern'), it works. But if I read the same from db and use it, it is not working and throwing the error. The logger displays as (which is read from the db)
$$$: Test_#[function:datestamp:YYYYMMddhhmmss.sss]
Any help is much appreciated.
If your datestamp format does not vary, you should just store the environment prefix in your db and use something like:
outputPattern="#[sessionVars['prefix']+server.dateTime.format('YYYYMMddhhmmss.sss')]"
If you need to use your current database values, you can use basic Java string methods to find the correct substrings. For example:
#[sessionVars['currentFeed'].getFilePattern().substring(0,sessionVars['currentFeed'].getFilePattern().indexOf('function')-2)+server.dateTime.format('YYYYMMddhhmmss.sss')]
If you use different datestamp formats, you can find that part as well using similar String methods. However, I still suggest you come up with an implementation that only stores the environment prefix in the db.
I have a requirement where I run xPath evaluator against xml payload in mule flow. This xPath evaluator can return single or multiple values. I need to store these values in flow variable and use somewhere later in the flow. Can someone help me implementing this changes?
Appreciate your help on this.
Thanks
For extracting values from an XML document, use the XPath extractor.
<mulexml:xpath-extractor-transformer expression="/a:my/b:xpath/text()"/>
You can also use Mule Expression Language to create dynamic XPath expressions:
<expression-transformer mimeType="text/xml" evaluator="xpath" expression="//school/day[#date= #[function:datestamp:yyyy-MM-dd] ]/name
"/>
However this can get somewhat messy for complicated expressions, so I have created my own dynamic XPath transformer:
<dx:dxpath expression="/b:team[name = $teamName]/b:player[b:name = $playerName]/b:goals/text()">
<dx:variable key="playerName" value="#[header:invocation:playerName]"/>
<dx:variable key="teamName" value="#[header:invocation:teamName]"/>
<!-- unlimited number of variables -->
</dx:dxpath>
which is somewhat more easy on the eyes.
Then Wrap your flow with an ericher:
<enricher target="#[variable:myData]">
<processor-chain>
<!-- your flow here -->
</processor-chain>
</enricher>