how i can result like this ?
in my mind i can query = >
select id, count(no1, no2, no3) where no1='B',no2='B',no3='B'
thank's very much.
Use Case Statement
select id,
case when no1='B' then 1 else 0 END +
case when no2='B' then 1 else 0 END +
case when no3='B' then 1 else 0 END As Count_All
From yourtable
Use Case When statements with Count aggregate. Lastly, Group them with id:
Select id,
count(case when no1='B' then 1 END) +
count(case when no2='B' then 1 END) +
count(case when no3='B' then 1 END) AS count_all
From yourtable
Group by id
Related
I need help How can I merge the column into a single column, here is my code, is this method is correct. I want to get the count of the selected row in the table for the columns.
SELECT
CAT_MGR,
SUM ( case when CAT_MGR = 'A' THEN 1 else 0 end ) AS DESIGN,
sum (case when CAT_MGR = 'b' THEN 1 else 0 END) AS DESIGN,
sum (case when CAT_MGR = 'c' THEN 1 else 0 END) AS DESIGN
from Table_A
GROUP BY
CAT_MGR
Can you guys help me I'm a beginner at SQL.
Thank you in advance
If you want just one row in the resultset, then remove the group by clause. Then, if you want to count the three cat mgr together, you can use in:
select
sum(case when cat_mgr = 'a' then 1 else 0 end ) as design_a,
sum(case when cat_mgr = 'b' then 1 else 0 end ) as design_b,
sum(case when cat_mgr = 'c' then 1 else 0 end ) as design_c,
sum(case when cat_mgr in ('a', 'b', 'c') then 1 else 0 end ) as design
from Table_a
You just need to make addion like below in order to get one column "Design"
SELECT
CAT_MGR,
SUM (case when CAT_MGR = 'A' THEN 1 else 0 end )
+ sum (case when CAT_MGR = 'b' THEN 1 else 0 END)
+ sum (case when CAT_MGR = 'c' THEN 1 else 0 END)
AS DESIGN
from TJD_CORE_CATPB_TB
GROUP BY
CAT_MGR
I would like to query with the result of
How can I achieve it?
This is how you can select the values without grouping:
select name, case when ket = 'dalam proses' then 1 else 0 end dalam_proses, 'selesai' then 1 else 0 end selesai
from yourtable;
Let's use it as a subquery:
select name, sum(dalam_proses) as dalam_proses, sum(selesai) as selesai
from (
select name, case when ket = 'dalam proses' then 1 else 0 end dalam_proses, 'selesai' then 1 else 0 end selesai
from yourtable
} t
group by name;
You can do it by using subquery, like this :
select
name,
distinct(name) ,
count(select ket from my_table where ket = 'dalam proses' ) as 'dalam proses',
count(select ket from my_table where ket = 'selesai' ) as 'selesai'
from my_table
group by name;
Use case expressions to do conditional aggregation:
select name,
sum(case when ket = 'dalam proses' then 1 else 0 end) as dalam_proses,
sum(case when ket = 'selesai' then 1 else 0 end) as selesai
from tablename
group by name
I have two queries and I want to get the maximum value of the two of them.
MAX((SELECT COUNT(p.[ItemID]) FROM [dbo].[Table] p WHERE HasHuman=0),
(SELECT COUNT(p.[ItemID]) FROM [dbo].[Table] p WHERE HasHuman=1))
You can calculate both result in a single query and then apply TOP:
select top 1
HasHuman,
COUNT(p.[ItemID]) as cnt
from [dbo].[Table]
group by HasHuman
order by cnt desc
You could even do this in a single query:
SELECT
CASE WHEN SUM(CASE WHEN HasHuman=0 THEN 1 ELSE 0 END) >
SUM(CASE WHEN HasHuman=1 THEN 1 ELSE 0 END)
THEN SUM(CASE WHEN HasHuman=0 THEN 1 ELSE 0 END)
ELSE SUM(CASE WHEN HasHuman=1 THEN 1 ELSE 0 END) END
FROM [dbo].[Table]
WHERE ItemID IS NOT NULL -- you were not counting NULLs
SELECT MAX(RC)
FROM (SELECT COUNT(p.ItemID) AS RC FROM dbo.[Table]
WHERE HasHuman=0
UNION
SELECT COUNT(p.ItemID) AS RC FROM dbo.[Table]
WHERE HasHuman=1
) A
I'm after a CTE which I want to return two columns, one with the total number of 1's and one with the total number of 0's. Currently I can get it to return one column with the total number of 1's using:
WITH getOnesAndZerosCTE
AS (
SELECT COUNT([message]) AS TotalNo1s
FROM dbo.post
WHERE dbo.checkletters([message]) = 1
--SELECT COUNT([message]) AS TotalNo0s
--FROM dbo.post
--WHERE dbo.checkletters([message]) = 0
)
SELECT * FROM getOnesAndZerosCTE;
How do I have a second column called TotalNo0s in the same CTE which I have commented in there to show what I mean.
Using conditional aggregation:
WITH getOnesAndZerosCTE AS(
SELECT
TotalNo1s = SUM(CASE WHEN dbo.checkletters([message]) = 1 THEN 1 ELSE 0 END),
TotalNo0s = SUM(CASE WHEN dbo.checkletters([message]) = 0 THEN 1 ELSE 0 END)
FROM post
)
SELECT * FROM getOnesAndZerosCTE;
For using COUNT() directly just be aware that it counts any NON-NULL values. You can omit the ELSE condition which implicitly returns NULL if not stated
SELECT
COUNT(CASE WHEN dbo.checkletters([message]) = 1 THEN 1 END) TotalNo1s
, COUNT(CASE WHEN dbo.checkletters([message]) = 0 THEN 1 END) TotalNo0s
FROM post
or, explicitly state NULL
SELECT
COUNT(CASE WHEN dbo.checkletters([message]) = 1 THEN 1 ELSE NULL END) TotalNo1s
, COUNT(CASE WHEN dbo.checkletters([message]) = 0 THEN 1 ELSE NULL END) TotalNo0s
FROM post
You can do it without CTE
select count(message) total,
dbo.checkletters(message) strLength
from post
group by dbo.checkletters(message)
having dbo.checkletters(message) in (1, 2) //All the messages with length 1 or 2
I have the following SQL code:
SELECT EmployeeID,
SUM(CASE
WHEN Error1 = '0'
THEN 1
ELSE 0
END + CASE
WHEN Error2 = '0'
THEN 1
ELSE 0
END + CASE
WHEN Error3 = '0'
THEN 1
ELSE 0
END) AS TotalErrors
FROM SubmittedDocuments
GROUP BY EmployeeID
The statement should calculate the number of errors in the table for each employee. However, there is another column in the table SubmittedDocuments named "DocumentName". How could I write a statement that only counts errors for the first instance of each DocumentName? (Or only counts for the one with the lowest "SubmittedID", the unique identifier)
Sorry if anything in unclear, I will attempt to clear up any confusion in the comments.
I might have not got this right from your question, but I think this should work. If you could show some sample data and expected output then we can definitely have a sure answer.
SELECT EmployeeID
SUM(CASE WHEN DocIDErr > 1 THEN 0 ELSE 1 END)
FROM
(SELECT EmployeeID
, Error1
, ROW_NUMBER() OVER (PARTITION BY EmployeeID ORDER BY DocumentName) AS DocIDErr
FROM SubmittedDocuments) AS RS
GROUP BY EmployeeID
I don't think you want aggregation. I think you just want to select the first document for each name.
If so, this may be what you want:
select sd.*,
((case when error1 = '0' then 1 else 0 end) +
(case when error2 = '0' then 1 else 0 end) +
(case when error3 = '0' then 1 else 0 end)
) as numerrors
from (select sd.*,
row_number() over (partition by documentname order by submittedid) as seqnum
from SumittedDocuments sd
) sd
where seqnum = 1;