Method:
- (void)serverResponse:(NSData *)data
{
NSString *response = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
NSLog(#"%#", response);
NSLog(#"%i", [response isEqualToString:#"1"]);
}
Log:
2015-03-15 06:26:53.716 appName[687:60b] 1
2015-03-15 06:26:53.718 appName[687:60b] 0
This doesn't seem to make any sense. I'm guessing the problem has something to do with the encoding, but I'm not sure what. Any help is appreciated.
When comparing strings, NSString does not take encoding into account.
Your problem is simple: The response contains 28 spaces after the "1".
Two possible solutions:
BOOL integerValueEquality = [response integerValue] == 1;
or
NSString *trimmedString = [response stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
BOOL stringEquality = [trimmedString isEqualToString:#"1"];
Related
I want to extract the phone number from a NSString.
For ex: In the string Nandu # +91-(123)-456-7890, I want to extract +91-(123)-456-7890.
I have tried code like,
NSString *myString = #"Nandu # +91-(123)-456-7890";
NSString *myRegex = #"\\d{2}+\\d{3}-\\d{3}-\\d{4}";
NSRange range = [myString rangeOfString:myRegex options:NSRegularExpressionSearch];
NSString *phoneNumber = nil;
if (range.location != NSNotFound) {
phoneNumber = [myString substringWithRange:range];
NSLog(#"%#", phoneNumber);
} else {
NSLog(#"No phone number found");
}
how can I get phone number with +91 also.
You can use this Regex pattern
(\+\d{2}-\(\d{3}\)-\d{3}-\d{4})
https://regexr.com/3qcsi
Using NSCharacterSet you can get your output. see below code and let me know if you have any query then.
NSString *originalString = #"Nandu # +91-(123)-456-7890";
NSString *cleanedString = [[originalString componentsSeparatedByCharactersInSet:[[NSCharacterSet characterSetWithCharactersInString:#"0123456789-+()"] invertedSet]] componentsJoinedByString:#""];
NSLog(#"%#", cleanedString); //+91-(123)-456-7890
You can use componentsSeparatedByString
NSString *originalString = #"Nandu # +91-(123)-456-7890";
NSArray *arrayWithTwoStrings = [originalString componentsSeparatedByString:#"+"];
NSString *mobileNumberstring = [NSString stringWithFormat:#"+%#",[arrayWithTwoStrings objectAtIndex:1]];
NSLog (#"%#",mobileNumberstring);
The following code works perfectly to convert the NSData that I got from a URL/JSON file to a NSString, EXCEPTION MADE by the cases that data contains line breaks!
What's wrong with my code?
My Code:
NSError *errorColetar = nil;
NSURL *aColetarUrl = [[NSURL alloc]initWithString:#"http://marcosdegni.com.br/petsistema/teste/aColetar3.php"];
NSString *aColetarString = [NSString stringWithContentsOfURL:aColetarUrl encoding:NSUTF8StringEncoding error:&errorColetar];
NSLog(#"NSString: %#", aColetarString);
if (!errorColetar) {
NSData *aColetarData = [aColetarString dataUsingEncoding:NSUTF8StringEncoding];
self.arrayAColetar = [NSJSONSerialization JSONObjectWithData:aColetarData options:kNilOptions error:nil];
}
NSLog(#"arrayAColetar %#", self.arrayAColetar);
Log Results:
**NSString**: [{"id_atendimento":"2","observacoes":"ABC-Enter-->
DEF-Enter-->
GFH-END"},{"id_atendimento":"1","observacoes":"123Enter-->
345Enter-->
678End"}]
**arrayAColetar** (null)
As you can see my bottom line is an empty array :(
Thanks in advance!
By checking the error message hidden under 'error:nil' I found a "Unescaped control character around character" issue and implemented the code below from Unescaped control characters in NSJSONSerialization
and got a new 'cleaned' string.
- (NSString *)stringByRemovingControlCharacters: (NSString *)inputString {
NSCharacterSet *controlChars = [NSCharacterSet controlCharacterSet];
NSRange range = [inputString rangeOfCharacterFromSet:controlChars];
if (range.location != NSNotFound) {
NSMutableString *mutable = [NSMutableString stringWithString:inputString];
while (range.location != NSNotFound) {
[mutable deleteCharactersInRange:range];
range = [mutable rangeOfCharacterFromSet:controlChars];
}
return mutable;
}
return inputString;
}
I need to parse a string like [abc]000, and what I want to get is an array containing abc and 000. Is there an easy way to do it?
I'm using code like this:
NSString *sampleString = #"[abc]000";
NSArray *sampleParts = [sampleString componentsSeparatedByString:#"]"];
NSString *firstPart = [[[sampleParts objectAtIndex:0] componentsSeparatedByString:#"["] lastObject];
NSString *lastPart = [sampleParts lastObject];
But it's inefficient and didn't check whether the string is in a format like [**]**.
For this simple pattern, can just parse yourself like:
NSString *s = #"[abc]000";
NSString *firstPart = nil;
NSString *lastPart = nil;
if ([s characterAtIndex: 0] == '[') {
NSUInteger i = [s rangeOfString:#"]"].location;
if (i != NSNotFound) {
firstPart = [s substringWithRange:NSMakeRange(1, i - 1)];
lastPart = [s substringFromIndex:i + 1];
}
}
Or you could learn to use the NSScanner class.
As always, there are lots of ways to do this.
OPTION 1
If these are fixed length strings (each part is always three characters) then you can simply get the substrings directly:
NSString *sampleString = #"[abc]000";
NSString *left = [sampleString substringWithRange:NSMakeRange(1, 3)];
NSString *right = [sampleString substringWithRange:NSMakeRange(5, 3)];
NSArray *parts = #[ left, right ];
NSLog(#"%#", parts);
OPTION 1 (shortened)
NSArray *parts = #[ [sampleString substringWithRange:NSMakeRange(1, 3)],
[sampleString substringWithRange:NSMakeRange(5, 3)] ];
NSLog(#"%#", parts);
OPTION 2
If they aren't always three characters, then you can use NSScanner:
NSString *sampleString = #"[abc]000";
NSScanner *scanner = [NSScanner scannerWithString:sampleString];
// Skip the first character if we know that it will always start with the '['.
// If we can not make this assumption, then we would scan for the bracket instead.
scanner.scanLocation = 1;
NSString *left, *right;
// Save the characters until the right bracket into a string which we store in left.
[scanner scanUpToString:#"]" intoString:&left];
// Skip the right bracket
scanner.scanLocation++;
// Scan to the end (You can use any string for the scanUpToString that doesn't actually exist...
[scanner scanUpToString:#"\0" intoString:&right];
NSArray *parts = #[ left, right ];
NSLog(#"%#", parts);
RESULTS (for all options)
2013-05-10 00:25:02.031 Testing App[41906:11f03] (
abc,
000
)
NOTE
All of these assume well-formed strings, so you should include your own error checking.
try like this ,
NSString *sampleString = #"[abc]000";
NSString *pNRegex = #"\\[[a-z]{3}\\][0-9]{3}";
NSPredicate *PNTest = [NSPredicate predicateWithFormat:#"SELF MATCHES %#", pNRegex];
BOOL check=[PNTest evaluateWithObject:sampleString ];
NSLog(#"success:%i",check);
if success comes as 1 then you can perform the action for separating string into array.
I am working on an iOS application and I have a basic problem. I have spent many hours to resolve it but I haven't had any success.
I have some JSON like this : {"htmlCode":"<thead><tr><td class=/"/"><p>Protected.....
SBJsonParser *jsonParser = [[[SBJsonParser alloc]init]autorelease];
NSDictionary *results = [jsonParser objectWithString:jsonTableData];
NSLog(#" result %#",results);
result (null)
My problem is the :/"/" - how I can replace it with \"\"?
i would like to do something like this :
jsonTableData = [jsonTableData stringByReplacingOccurrencesOfString:#"/"/"" withString:#"\"\""];
You can replace characters in string like this!
NSString *str = #"<thead><tr><td class=/\"/\"><p>Protected";
NSLog(#"%#", str);
str = [str stringByReplacingOccurrencesOfString:#"/" withString:#"\\"];
NSLog(#"%#", str);
Given a string, I need to obtain a count of each word that appears in that string. To do so, I extracted the string into an array, by word, and searched that way, but I have the feeling that searching the string directly is more optimal. Below is the code that I originally wrote to solve the problem. I'm up for suggestions on better solutions though.
NSMutableDictionary *sets = [[NSMutableDictionary alloc] init];
NSString *paragraph = [[NSString alloc] initWithContentsOfFile:[[NSBundle mainBundle] pathForResource:#"text" ofType:#"txt"] encoding:NSUTF8StringEncoding error:NULL];
NSMutableArray *words = [[[paragraph lowercaseString] componentsSeparatedByString:#" "] mutableCopy];
while (words.count) {
NSMutableIndexSet *indexSet = [[NSMutableIndexSet alloc] init];
NSString *search = [words objectAtIndex:0];
for (unsigned i = 0; i < words.count; i++) {
if ([[words objectAtIndex:i] isEqualToString:search]) {
[indexSet addIndex:i];
}
}
[sets setObject:[NSNumber numberWithInt:indexSet.count] forKey:search];
[words removeObjectsAtIndexes:indexSet];
}
NSLog(#"%#", sets);
Example:
Starting string:
"This is a test. This is only a test."
Results:
"This" - 2
"is" - 2
"a" - 2
"test" - 2
"only" - 1
This is exactly what an NSCountedSet is for.
You need to break the string apart into words (which iOS is nice enough to give us a function for so that we don't have to worry about punctuation) and just add each of them to the counted set, which keeps track of the number of times each object appears in the set:
NSString *string = #"This is a test. This is only a test.";
NSCountedSet *countedSet = [NSCountedSet new];
[string enumerateSubstringsInRange:NSMakeRange(0, [string length])
options:NSStringEnumerationByWords | NSStringEnumerationLocalized
usingBlock:^(NSString *substring, NSRange substringRange, NSRange enclosingRange, BOOL *stop){
// This block is called once for each word in the string.
[countedSet addObject:substring];
// If you want to ignore case, so that "this" and "This"
// are counted the same, use this line instead to convert
// each word to lowercase first:
// [countedSet addObject:[substring lowercaseString]];
}];
NSLog(#"%#", countedSet);
// Results: 2012-11-13 14:01:10.567 Testing App[35767:fb03]
// <NSCountedSet: 0x885df70> (a [2], only [1], test [2], This [2], is [2])
If I had to guess, I would say NSRegularExpression for that. Like this:
NSUInteger numberOfMatches = [regex numberOfMatchesInString:string
options:0
range:NSMakeRange(0, [string length])];
That snippet was taken from here.
Edit 1.0:
Based on what Sir Till said:
NSString *string = #"This is a test, so it is a test";
NSMutableDictionary *dictionary = [NSMutableDictionary dictionary];
NSArray *arrayOfWords = [string componentsSeparatedByCharactersInSet:[NSCharacterSet whitespaceCharacterSet]];
for (NSString *word in arrayOfWords)
{
if ([dictionary objectForKey:word])
{
NSNumber *numberOfOccurences = [dictionary objectForKey:word];
NSNumber *increment = [NSNumber numberWithInt:(1 + [numberOfOccurences intValue])];
[dictionary setValue:increment forKey:word];
}
else
{
[dictionary setValue:[NSNumber numberWithInt:1] forKey:word];
}
}
You should be careful with:
Punctuation signs. (near other words)
UpperCase words vs lowerCase words.
I think that's really bad idea that you trying to search a words among the long paragraph with a loop. You should use a regular expression to do that! I know it's not easy at first time to learn it but it's really worth to know it! Take look at this case Use regular expression to find/replace substring in NSString