I am trying to query a database to obtain rows that matches 4 conditions.
The code I'm using is the following:
$result = db_query("SELECT * FROM transportesgeneral WHERE CiudadOrigen LIKE '$origen%' AND DepartamentoOrigen LIKE '$origendep' AND DepartamentoDestino LIKE '$destinodep' AND CiudadDestino LIKE '$destino%'");
But it is not working; Nevertheless, when I try it using only 3 conditions; ie:
$result = db_query("SELECT * FROM transportesgeneral WHERE CiudadOrigen LIKE '$origen%' AND DepartamentoOrigen LIKE '$origendep' AND DepartamentoDestino LIKE '$destinodep'");
It does work. Any idea what I'm doing wrong? Or is it not possible at all?
Thank you so much for your clarification smozgur.
Apparently this was the problem:
I was trying to query the database by using the word that contained a tittle "Petén" so I changed the database info and replaced that word to the same one without the tittle "Peten" and it worked.
Now, im not sure why it does not accept the tittle but that was the problem.
If you have any ideas on how I can use the tittle, I would appreciate that very much.
Related
I assume this could be some setting issue. When I used something like below, I got no result
where name = 'hello-world-new'
However, if I changed it to below, I got result (because indeed there is data)
where name like 'hello-world%'
Does anyone know where to check/change the setting?
Thanks!
I have a list of Products with a field called 'Title' and I have been trying to get a list of initial letters with not much luck. The closes I have is the following that dosn't work as 'Distinct' fails to work.
atoz = Product.objects.all().only('title').extra(select={'letter': "UPPER(SUBSTR(title,1,1))"}).distinct('letter')
I must be going wrong somewhere,
I hope someone can help.
You can get it in python after the queryset got in, which is trivial:
products = Project.objects.values_list('title', flat=True).distinct()
atoz = set([i[0] for i in products])
If you are using mysql, I found another answer useful, albeit using sql(django execute sql directly):
SELECT DISTINCT LEFT(title, 1) FROM product;
The best answer I could come up with, which isn't 100% ideal as it requires post processing is this.
atoz = sorted(set(Product.objects.all().extra(select={'letter': "UPPER(SUBSTR(title,1,1))"}).values_list('letter', flat=True)))
I am attempting to pull data from mysql database using codeigniter and ignited datatables. I have no troubles pulling the join query with a single where clause, but when I try to add a WHERE x OR y, I can't seem to get it working. Here is the basic code that works fine:
$table = 'test_base';
$table2 = 'lab';
$this->datatables->select('test_base.idlab');
$this->datatables->from($table);
$this->datatables->join($table2, 'test_base.idlab = lab.idlab');
$this->datatables->where('lab.idaccount',$idaccount);
If I wanted to put multiple conditions in the query, I see from the manual that I can put multiple conditions in an array, but this seems to only do an AND, not an OR statement.
I then see that I may be able to create my own sql query using the following:
$this->datatables->where('column != "string"');
So, I tried this:
$this->datatables->where("`lab`.`idaccount`= $idaccount OR `lab`.`idlab` = 0");
SELECT `test_base`.`idlab`
FROM (`test_base`)
JOIN `lab` ON `test_base`.`idlab` = `lab`.`idlab`
WHERE `lab`.`idaccount`=` 124 OR `lab`.`idlab` = 0
ORDER BY `idtest` asc
The issue is that there is an extra (`) in the WHERE `lab`.`idaccount` = `<-here and I'm not sure how to get rid of it.
As #Ehecatl suggests, I got it working by entering the full query into the (). There were no examples on the CodeIgniter website or anywhere else I could find. Still new to CodeIgniter so maybe this will also help others.
Resolution is to put the query string in the $this->datatables->where(); and removing all the single quotes.
$this->datatables->where("lab.idaccount = $idaccount OR lab.idlab = 0");
Is it possible to use a wildcard in a SQL LIKE statement within a ColdFusion cfscript query?
An example that doesn't work:
local.q = new Query();
local.q.setDatasource(variables.dsn);
local.q.addParam(name='lastname', value='%' & arguments.lastname, cfsqltype="cf_sql_varchar");
local.qString = 'SELECT name FROM users WHERE lastname LIKE :lastname';
local.q.setSQL(local.qString);
local.result = local.q.execute().getResult();
I also tried these, which didn't work:
local.qString = 'SELECT name FROM users WHERE lastname LIKE %:lastname';
local.qString = "SELECT name FROM users WHERE lastname LIKE '%:lastname'";
UPDATE:
I am using MS SQL Server 2008.
The query works fine within SQL Server Mgmt Studio... I think it has something to do with how to format the query within cfscript tags?
Yes, it is possible. You're setting it in the param, which is correct. I'm not sure why it's not working with you.
I did the following and it worked.
var qryArgsCol = {};
qryArgsCol.datasource = variables.datasource;
qryArgsCol.SQL = "
SELECT ID
FROM Users
WHERE LastName LIKE :searchStringParam
";
var qryGetID = new query(argumentCollection=qryArgsCol);
qryGetID.addParam(name="searchStringParam", value="%" & searchString, cfsqltype="cf_sql_varchar");
qryGetIDResult = qryGetID.execute().getResult();
There's a response here from Adam Cameron, which was apparently deleted by an overzealous mod.
Rather than repeat what he says, I've just copied and pasted (with emphasis added to the key parts):
Just to clarify that the syntax you tried in your first example does work. That is the correct approach here. To clarify / explain:
The <cfquery> version of the example you have would be along the lines of:
<cfqueryparam value="%foo">
So in the function version, the param would be ? or :paramName and the value of the param would continue to be "%foo".
The % is part of the param value, not the SQL string.
So given that "doesn't work" for you, it would help if you posted the error, or whatever it is that causes you to think it's not working (what your expectation is, and what the actual results are). Then we can deal with the actual cause of your problem, which is not what you think it is, I think.
Does the query work fine as a <cfquery>?
Depending on the dbms used, that single and double quotes may be interpreted when the sql statement is run. What dbms are you using? Your statement now doesn't select for the value in the variable, but for any user whose lastname is "lastname". It should be something like:
lastname like '%#lastname#'
Just remember that you ultimately need to see what CF gives the DB server. In this instance, you can try this mockup to get close and find the same error in SSMS by messing with the quotes/value in the param declaration:
declare #param1 varchar(max) = '%Eisenlohr';
SELECT name FROM users WHERE lastname LIKE #param1
I just ran into the same problem as the original poster where it "wasn't working" and I didn't get any results from the query of queries.
The problem for me is that the wildcard search is case-sensitive.
local.q = new Query();
local.q.setDatasource(variables.dsn);
local.q.addParam(name='lastname', value='%' & LCase(arguments.lastname), cfsqltype="cf_sql_varchar");
local.qString = 'SELECT name FROM users WHERE LOWER(lastname) LIKE :lastname';
local.q.setSQL(local.qString);
local.result = local.q.execute().getResult();
So what I did was made sure the incoming argument was lower case and made sure the comparing field in the SQL was lower case as well and it worked.
Use like this.
local.q = new Query();
local.q.setDatasource(variables.dsn);
local.q.addParam(name="lastname", cfsqltype="cf_sql_varchar",value='%ARGUMENTS.lastname' );
local.qString = 'SELECT name FROM users WHERE lastname LIKE :lastname';
local.q.setSQL(local.qString);
local.result = local.q.execute().getResult();
I would suggest using the CFQuery tag instead of attempting to run queries within CFScript. Unless you REALLY know what you are doing. I say this because the CFQuery tag has some built-in functionality that not only makes building queries easier for you but may also protect you from unforeseen attacks (the SQL injection type). For example, when using CFQuery it will automatically escape single-quotes for you so that inserting things like 'well isn't that a mess' will not blow up on you. You also have the benefit of being able to use the CFQueryParam tag to further battle against SQL injection attacks. While you may be able to use the CFQueryParam functionality within CFScript it is not as straight forward (at least not for me).
See this blog post from Ben Nadel talking about some of this.
So in CFQuery tags your query would look something like this:
<cfquery name="myQuery" datasource="#variables.dsn#">
SELECT name
FROM users
WHERE lastname LIKE <cfqueryparam cfsqltype="cf_sql_varchar" value="%:#arguments.lastname#" maxlength="256" />
</cfquery>
I'm having a strange issue when using the Where clause in Rails. I imagine it has something to do with my OR operator syntax. Here is my query:
Cookie.where("ID = ? OR ID = ? OR ID = ? OR ID = ?", chocolate.to_s, sugar.to_s, peanut_butter.to_s, oatmeal.to_s)
When I attempt to execute the query my application just hangs endlessly. However, If I submit a query that looks like this:
Cookie.where("ID = ?", chocolate.to_s)
I get the expected result. Any help with the proper format to this where clause would be greatly appreciated. Thanks.
UPDATE
I went into the rails console and did as you suggested. This was the result:
SELECT \"TBLCookies\".* FROM \"TBLCookies\" WHERE (ID in ('4','3','2','1'))
This seems correct. I opened up SQL Developer, pasted this query in, and ran it. I got the expected result. So everything seems to be fine there. However, when I try to run the query in the rails console I get nothing back. The console just hangs indefinitely. Any insight into what could be going wrong would be great.
Why not do this
Cookie.where("ID in (?)",[chocolate, sugar, peanut_butter, oatmeal].collect(&:to_s))