Gurus,
I have a table which has log of all customer's shopping details as below. shopmode is a master table id.
ShopDate CustomerId ShoppingMode
1/1/2011 a 0
1/1/2011 a 0
1/1/2011 a 1
1/1/2011 b 0
2/1/2011 a 0
2/1/2011 b 1
3/1/2011 a 1
3/1/2011 b 0
3/1/2011 c 0
I am trying to comeup with query for requirements
(date is in dd/mm/yyyy)
Show one record per customer on shopdate,customerid,shopmode
1/1/2011 a 0
1/1/2011 a 1
1/1/2011 b 0
on a given date range(1/1/2011- 3/1/2011), need most recent shop date having unique value of customerid + shopmode
3/1/2011 a 1
3/1/2011 b 0
3/1/2011 c 0
2/1/2011 b 1
2/1/2011 a 0
on a given date range(1/1/2011-3/1/2011), the most recent by shopdate for customerid
3/1/2011 a 1
3/1/2011 b 0
3/1/2011 c 0
Need your help..
SELECT Max(shopdate),customerid, shopmode
FROM Table
with this result I will be joining shoppingdetail table to show data. Am tring to create a table variable or CTE show that I can join with other table.
1: just group by or select distinct
with cte1 as (
select ShopDate, CustomerId, ShoppingMode
from table
group by ShopDate, CustomerId, ShoppingMode)
select * from cte1;
2: First, find number of shopping types per day and customer. Then over those with one shopping type, just get the maximum date.
with cte2 as (
select ShopDate, CustomerId, max(ShoppingMode),
count(distinct ShoppingMode) as cnt
from table
where ShopDate between start_date and end_date
group by ShopDate, CustomerId
)
select max(ShopDate)as ShopDate, CustomerId, ShoppingMode
from cte2
where cnt = 1
group by Customer_id;
3: Just select all customers, rank them, and select what you want:
with cust as (
select
CustomerId,
row_number() over (partition by customerId order by ShopDate desc) as rnk
from table
where ShopDate between start_date and end_date
)
select * from cust where rnk = 1
Try this:
SELECT *
FROM (SELECT ShopDate,
CustomerId,
ShoppingMode,
ROW_NUMBER ()
OVER (PARTITION BY ShopDate, CustomerId, ShoppingMode
ORDER BY ShopDate, CustomerId, ShoppingMode)
rn
FROM yourtable where shopdate >= '01jan2011' AND shopdate <= '03jan2011')
WHERE rn = 1;
Related
I have a Order shipment table like below -
Order_ID
shipment_id
pkg_weight
1
101
5
1
101
5
1
101
5
1
102
3
1
102
3
I want the output table to look like below -
Order_ID
Distinct_shipment_id
total_pkg_weight
1
2
8
select
order_id
, count(distinct(shipment_id)
, avg(pkg_weight) over (partition by shipment_id)
from table1
group by order_id
but getting the below error -
column "pkg_weight" must appear in the GROUP BY clause or be used in
an aggregate function
Please help
Use a distinct select first, then aggregate:
SELECT Order_ID,
COUNT(DISTINCT shipment_id) AS Distinct_shipment_id,
SUM(pkg_weight) AS total_pkg_weight
FROM
(
SELECT DISTINCT Order_ID, shipment_id, pkg_weight
FROM table1
) t
GROUP BY Order_ID;
I have the following sales table that displays the customer ID, their name, the order amount, and the order date.
ID
Name
Order
Date
1
A
25
11/10/2006
1
A
10
5/25/2010
1
A
10
6/18/2018
2
B
20
3/31/2008
2
B
15
11/15/2010
3
C
35
1/1/2019
3
C
20
4/12/2007
3
C
10
3/20/2010
3
C
5
10/19/2012
4
D
15
12/12/2013
4
D
15
2/18/2010
5
E
25
12/11/2006
6
F
10
5/1/2016
I am trying to group the data so that for each customer it would only show me their most recent order and the amount, as per below:
ID
Name
Order
Date
1
A
10
6/18/2018
2
B
15
11/15/2010
3
C
35
1/1/2019
4
D
15
12/12/2013
5
E
25
12/11/2006
6
F
10
5/1/2016
So far I've only been able to group by ID and Name, because adding the Order column would also group by that column as well.
SELECT
ID,
Name,
MAX(Date) 'Most recent date'
FROM Table
GROUP BY Customer, Customer
How can I also add the order amount for each Customer?
SELECT ID, Name, Order, Date FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY Name ORDER BY Date DESC) AS sn
FROM your_table_name
) A WHERE sn = 1;
You could use a subqoery for max date
SELECT
ID,
Name,
MAX(Date) 'Most recent date'
FROM Table
GROUP BY Customer, Customer
select a.ID, a.Name, b.max_date
from Table a
inner join (
select name, max(Date) max_date
from Table
group by name
) b on a. name = b.name and a.date = b.max_date
You can use this query to get the expected result:
SELECT S.*
FROM Sales S
CROSS APPLY
(
SELECT ID, Max(Date) MaxDate
FROM Sales
GROUP BY ID
)T
WHERE S.ID = T.ID
AND S.Date = T.MaxDate
ORDER BY S.ID
I'm trying to obtain rolling number of unique values in a window.
Here's how my table looks like:
SELECT
user_id
, order_date
, product
FROM example_table
WHERE user_id = 1
ORDER BY order_date ASC
user_id
order_date
product
1
2021-01-01
A
1
2021-01-01
B
1
2021-01-04
A
1
2021-01-07
C
1
2021-01-09
C
1
2021-01-20
A
Here's what I'm trying to achieve:
user_id
order_date
product
cum_dist_count
1
2021-01-01
A
1
1
2021-01-02
B
2
1
2021-01-04
A
2
1
2021-01-07
C
3
1
2021-01-09
C
3
1
2021-01-20
A
3
In other words, I want to be able to see how many unique items a customer has bough so far, and be able to see that for particular date (so for the example above: on 2021-01-04 they have bought 2 unique items and for 2021-01-07 that number was 3).
I've tried grouping by selecting user_id and product, and min(order_date) in a CTE, then doing ROW_NUMBER over user_id and product in that CTE and that worked partially - I'm able to seethe dates the countof unique products has changed (so for this example: 2021-01-01, 2021-01-02 and 2021-01-07, but then I loose the rows "between" which I still want to be able to access.
with cte as (
SELECT
user_id
, product
, min(order_date) as first_order
FROM example_table
GROUP BY 1,2
ORDER BY order_date ASC
)
SELECT
user_id
, first_order
, product
, ROW_NUMBER() OVER (PARTITION BY user_id, product ORDER BY first_order) AS number_of_unique_products
WHERE user_id = 1
With the above, I would get:
user_id
order_date
product
cum_dist_count
1
2021-01-01
A
1
1
2021-01-02
B
2
1
2021-01-07
C
3
The DB is in BigQuery StandardSQL.
Any help is much appreciated!
For each item, you can record the earliest date it appears. Then add those up:
select et.* except (seqnum),
countif(seqnum = 1) over (partition by user_id order by order_date) as running_distinct_count
from (select et.*,
row_number() over (partition by user_id, product order by order_date) as seqnum
from example_table et
) et
Below is for BigQuery
select * except(cum_products),
(select count(distinct product) from t.cum_products product) as cum_dist_count
from (
select *,
array_agg(product) over prev_rows as cum_products
from example_table
window prev_rows as (partition by user_id order by order_date)
) t
if applied to sample data in your question
with example_table as (
select 1 user_id, '2021-01-01' order_date, 'A' product union all
select 1, '2021-01-02', 'B' union all
select 1, '2021-01-04', 'A' union all
select 1, '2021-01-07', 'C' union all
select 1, '2021-01-09', 'C' union all
select 1, '2021-01-20', 'A'
)
output is
I am trying to write a SQL statement that will return a set of Distinct set of CompanyNames from a table based on the most recent SaleDate withing a specified date range from another table.
T01 = Account
T02 = TransHeader
The fields of importance are:
T01.ID, T01.CompanyName
T02.AccountID, T02.SaleDate
T01.ID = T02.AccountID
What I want to return is the Max SaleDate for each CompanyName without any duplicate CompanyNames and only the Max(SaleDate) as LastSale. I will be using a Where Clause to limit the SaleDate range.
I tried the following but it returns all the records for all SalesDates in the range. This results in the same company being listed multiple times.
Current MS-SQL Query
SELECT T01.CompanyName, T02.LastSale
FROM
(SELECT DISTINCT ID, IsActive, ClassTypeID, CompanyName FROM Account) T01
FULL OUTER JOIN
(SELECT DISTINCT AccountID, TransactionType, MAX(SaleDate) LastSale FROM TransHeader group by AccountID, TransactionType, SaleDate) T02
ON T01.ID = T02.AccountID
WHERE ( ( T01.IsActive = 1 )AND
( (Select Max(SaleDate)From TransHeader Where AccountID = T01.ID AND TransactionType in (1,6) AND SaleDate is NOT NULL)
BETWEEN '01/01/2016' AND '12/31/2018 23:59:00' AND (Select Max(SaleDate)From TransHeader Where AccountID = T01.ID AND TransactionType in (1,6) AND SaleDate is NOT NULL) IS NOT NULL
)
)
ORDER BY T01.CompanyName
I thought the FULL OUTER JOIN was the ticket but it did not work and I am stuck.
Sample data Account Table (T01)
ID CompanyName IsActive ClassTypeID
1 ABC123 1 1
2 CDE456 1 1
3 EFG789 1 1
4 Test123 0 1
5 Test456 1 1
6 Test789 0 1
Sample data Transheader table (T02)
AccountID TransactionType SaleDate
1 1 02/03/2012
2 1 03/04/2013
3 1 04/05/2014
4 1 05/06/2014
5 1 06/07/2014
6 1 07/08/2015
1 1 08/09/2016
1 1 01/15/2016
2 1 03/20/2017
2 1 03/21/2017
3 1 03/04/2017
3 1 04/05/2018
3 1 05/27/2018
4 1 06/01/2018
5 1 07/08/2018
5 1 08/01/2018
5 1 10/11/2018
6 1 11/30/2018
Desired Results
CompanyName LastSale (Notes note returned in the result)
ABC123 01/15/2016 (Max(SaleDate) LastSale for ID=1)
CDE456 03/21/2017 (Max(SaleDate) LastSale for ID=2)
EFG789 05/27/2018 (Max(SaleDate) LastSale for ID=3)
Testing456 10/11/2018 (Max(SaleDate) LastSale for ID=5)
ID=4 & ID=6 are note returned because IsActive = 0 for these records.
One option is to select the maximum date in the select clause.
select
a.*,
(
select max(th.saledate)
from transheader th
where th.accountid = a.id
and th.saledate >= '2016-01-01'
and th.saledate < '2019-01-01'
) as max_date
from account a
where a.isactive = 1
order by a.id;
If you only want to show transaction headers with sales dates in the given date range, then you can just inner join the maximum dates with the accounts. In order to do so, you must group your date aggregation per account:
select a.*, th.max_date
from account a
join
(
select accountid, max(saledate) as max_date
from transheader
and saledate >= '2016-01-01'
and saledate < '2019-01-01'
group by accountid
) th on th.accountid = a.id
where a.isactive = 1
order by a.id;
select CompanyName,MAX(SaleDate) SaleDate from Account a
inner join Transheader b on a.id = b.accountid
group by CompanyName
order by 1
I want to get a prior date for each row for each person (ID) in SQL Server 2008. I have several million rows. Example:
ID TransactionDate
1 01/01/2012
1 01/20/2012
1 01/22/2012
2 01/20/2012
2 01/23/2012
2 01/25/2012
Returns:
ID TransactionDate priorDate
1 01/01/2012 Null
1 01/20/2012 01/01/2012
1 01/22/2012 01/20/2012
2 01/20/2012 null
2 01/23/2012 01/20/2012
2 01/25/2012 01/23/2012
just use a self join CTE (left) with row_number:
WITH CTE AS (
SELECT ID, TransactionDate,
ROW_NUMBER() OVER ( PARTITION BY ID order by TransactionDate ) AS RowNumber
FROM table_name
)
SELECT a.ID,a.TransactionDate , aa.TransactionDate priorDate
FROM CTE a
LEFT OUTER JOIN CTE aa
ON a.RowNumber = aa.RowNumber + 1
And aa.ID=a.ID
SQLFIDDLE DEMO