Replace values in a file conditional on their value - awk

Question

I have a file full of numbers that range 10.00-10.66, 20.67-21.33, 30.67-31.33 and 40.34-42.00.
Example input:
10.21 21.12 10.50 30.80
30.91 31.12 31.00 10.30
21.21 20.99 20.90 31.20
41.71 41.72 10.10 41.80
I want to convert the file such that:
10.00-10.20 = 0|0:[DOSE]
10.21-10.66 = .|.:[DOSE]
20.90-21.10 = 1|0:[DOSE]
20.67-20.89 = .|.:[DOSE]
21.11-21.33 = .|.:[DOSE]
30.90-31.10 = 0|1:[DOSE]
30.67-30.89 = .|.:[DOSE]
31.11-31.33 = .|.:[DOSE]
41.80-42.00 = 1|1:[DOSE]
41.34-41.79 = .|.:[DOSE]
Example output:
.|.:10.21 .|.:21.12 .|.:10.50 .|.:30.80
0|1:30.91 .|.:31.12 0|1:31.00 .|.:10.30
.|.:21.21 1|0:20.99 1|0:20.90 .|.:31.20
.|.:41.71 .|.:41.72 0|0:10.10 1|1:41.80
I can think of a way to do this in R, but the actual file is roughly 1000*5000000 elements in size, and I don't think R can cope!
Is there a way to conditionally replace all elements in a file dependant on their value with an in-line text editor like sed or awk? Alternative programs are welcome!

Answer 1

A simple way to do this in awk would be like this:
{
for (i=1;i<=NF;++i) {
if ($i>=10&&$i<=10.2) $i="0|0:"$i
else if ($i>=10.21&&$i<=10.66) $i=".|.:"$i
# etc.
}
print
}
That is, loop through each field of each record and add the strings you want depending on the value of the field. You can put the script in a file and run it like awk -f script.awk input_file