How to group a table, at the same time saving all column values in each group to a single column as comma-separated values - sql

Please see the following SQL code.
Declare #LookUp table (id int,val varchar(12))
insert into #LookUp values (1,'A'),(1,'D'),(1,'X'),(2,'B'),(2,'F')
Declare #summary table (id int,val varchar(2000))
------------------------------
Declare #value varchar(30)
Declare #start int = 1, #end int = (Select count(Distinct id) from #LookUp)
While #start <= #end
Begin
Set #value = ''
Select #value = #value + '|' + val From #LookUp Where id = #start
Insert into #summary
Select #start,Right(#value,Len(#value)-1)
Set #start = #start + 1
End
Select * From #summary
With the following query, I am grouping based on Id, and making the values with in a group, as comma-separated values.
Input:
Output:
I have done this using a loop, which is not performing very well when it comes to large amount of data.
Can we do this avoiding a loop?
Note: Assume that #lookup.id is continuous.

INSERT #summary(id, val)
SELECT
t.id,
STUFF((
select '|' + [val]
from #LookUp t1
where t1.id = t.id
for xml path(''), type
).value('.', 'varchar(max)'), 1, 1, '') [values]
FROM #LookUp t
GROUP BY t.id

Try this..
Declare #LookUp table (id int,val varchar(12))
insert into #LookUp values (1,'A'),(1,'D'),(1,'X'),(2,'B'),(2,'F')
select
id,
val =
stuff((
select
'| ' + t2.val
from #LookUp t2
where
t2.id = t1.id
group by t2.val
for xml path(''), type).value('.', 'varchar(max)'
), 1, 2, '')
from #LookUp t1
GROUP BY t1.id

Declare #LookUp table (id int,val varchar(12))
insert into #LookUp values (1,'A'),(1,'D'),(1,'X'),(2,'B'),(2,'F');
WITH A AS
(
SELECT DISTINCT id
FROM #LookUp
)
SELECT
A.id,
STUFF
(
(
SELECT ',' + val
FROM #LookUp B
WHERE B.id = A.id
FOR XML PATH('')
),
1, 1, ''
) AS val
FROM A

Declare #LookUp table (id int,val varchar(12))
insert into #LookUp values (1,'A'),(1,'D'),(1,'X'),(2,'B'),(2,'F')
SELECT DISTINCT a.id, stuff((select '|' + val
from #LookUp c
where c.id = a.id
for xml path('')),1,1,'') as vall
FROM #LookUp a

I'll add a solution based on a recursive common table expression. With small modifications it should work in DB2 too (you have to change the row_number() function to rownumber() and how the concatenation works in the second list (use || instead of the concat function).
DECLARE #LookUp TABLE (id int, val varchar(12))
INSERT INTO #LookUp VALUES (1,'A'),(1,'D'),(1,'X'),(2,'B'),(2,'F')
;WITH
list1(rn, id, val) AS
(
SELECT row_number() OVER (PARTITION BY id ORDER BY id), id, val
FROM #LookUp
),
list2 (id, val, idx) AS
(
SELECT id, val, 1
FROM list1
WHERE rn = 1
UNION ALL
SELECT
list2.id,
CAST(CONCAT(list2.val, ' | ', list1.val) AS varchar(12)),
list2.idx + 1
FROM list2
JOIN list1 ON list2.id = list1.id
WHERE list2.idx + 1 = list1.rn
)
SELECT l2.id, l2.val
FROM list2 l2
JOIN (SELECT id, MAX(rn) maxid FROM list1 GROUP BY id) a
ON l2.id = a.id AND l2.idx = a.maxid
ORDER BY l2.id
This outputs:
id val
1 A | D | X
2 B | F

Related

Combine Multi Rows with COALESCE

Using SQL-Server 2012
I have the following Table:
Id Description
6192 Salzburg
6193 Salzburg
6194 Salzburg
6196 Innsbruck
6197 Innsbruck
6198 Innsbruck
6199 Innsbruck
6201 Bregenz
6202 Bregenz
6203 Bregenz
I want to Select each Distinct "Description" with all the Id's together in one string:
Description Ids
Salzburg '6192,6193,6194'
Innsbruck '6196,6197,6198'
I saw some similar code on this site [How to concatenate text from multiple rows into a single text string in SQL server?, but I couldn't figure it out yet for my purpose (don't want to use XML Path!). Here is what I have tried so far:
DECLARE #ids AS Nvarchar(MAX)
SELECT #ids = COALESCE(#ids + ',', '') + CAST(t.Id AS nvarchar(5))
FROM (SELECT tmp.Id FROM (SELECT id, [Description] FROM tblMasterPropValues WHERE IdCategory = 253 AND IsActive = 1) as tmp
WHERE [Description] = tmp.[Description]) AS t
SELECT #ids
--SELECT DISTINCT [Description], #ids AS IDs FROM tblMasterPropValues WHERE IdCategory = 253 AND IsActive = 1 AND Id IN (#ids)
I can't really get my head around it, and would appreciate any help on it.
You can try using STUFF() function
SELECT description, Ids = STUFF(
(SELECT ',' + Id
FROM tblMasterPropValues t1
WHERE t1.description = t2.description
FOR XML PATH (''))
, 1, 1, '') from tblMasterPropValues t2
group by description;
For that FOR XML PATH() is the right clause so, you can do :
SELECT DISTINCT v.description, STUFF(v1.ids, 1, 1, '''') + ''''
FROM tblMasterPropValues v CROSS APPLY
(SELECT ', '+ CAST(v1.Id AS VARCHAR(255))
FROM tblMasterPropValues v1
WHERE v1.description = v.description
FOR XML PATH('')
) v1(ids);
You can also make it by using recursive CTE
DECLARE #tblMasterPropValues TABLE (Id INT, Description VARCHAR(20))
INSERT INTO #tblMasterPropValues VALUES
(6192 , 'Salzburg'),
(6193 , 'Salzburg'),
(6194 , 'Salzburg'),
(6196 , 'Innsbruck'),
(6197 , 'Innsbruck'),
(6198 , 'Innsbruck'),
(6199 , 'Innsbruck'),
(6201 , 'Bregenz'),
(6202 , 'Bregenz'),
(6203 , 'Bregenz')
;WITH Tbl AS
(
SELECT
*,
ROW_NUMBER() OVER(PARTITION BY Description ORDER BY Id) AS RN,
COUNT(*) OVER(PARTITION BY Description) AS CNT
FROM #tblMasterPropValues
)
, Rcr AS (
SELECT *, CAST(Id AS varchar(max)) Ids
FROM Tbl WHERE RN = 1
UNION ALL
SELECT T.*, Rcr.Ids + ',' + CAST(T.Id AS VARCHAR(10)) Ids
FROM Rcr
INNER JOIN Tbl T ON T.RN = Rcr.RN + 1 and Rcr.Description = T.Description
)
SELECT RN, Description, Ids FROM Rcr
WHERE RN = CNT
Result:
Description Ids
-------------------- -----------------------
Salzburg 6192,6193,6194
Innsbruck 6196,6197,6198,6199
Bregenz 6201,6202,6203
Try this:
DECLARE #Table TABLE(ID INT, Description VARCHAR(25))
INSERT INTO #Table
VALUES (6192,'Salzburg' )
,(6193,'Salzburg' )
,(6194,'Salzburg' )
,(6196,'Innsbruck')
,(6197,'Innsbruck')
,(6198,'Innsbruck')
,(6199,'Innsbruck')
,(6201,'Bregenz' )
,(6202,'Bregenz' )
,(6203,'Bregenz' )
Query:
SELECT DISTINCT T2.Description,
SUBSTRING(
(
SELECT ','+CAST(T1.ID AS VARCHAR) AS [text()]
FROM #Table T1
WHERE T1.Description = T2.Description
ORDER BY T1.Description
FOR XML PATH ('')
), 2, 1000) [Ids]
FROM #Table T2
Result:
Description Ids
Bregenz 6201,6202,6203
Innsbruck 6196,6197,6198,6199
Salzburg 6192,6193,6194

create one row from two columns sql

How to create one row from two columns?
Example:
id description
------------------
1 one
2 two
3 three
In result:
1: one, 2: two, 3: three
I use follow statment:
select Id,
stuff((SELECT distinct ', ' + cast(Description as varchar(10))
FROM dbo.tbl t2
where t2.Id = t1.Id
FOR XML PATH('')),1,1,'')
from dbo.tbl t1
group by Id
But in result I have two columns. I need one such as string
You can try this query.
CREATE TABLE T (
id int,
description varchar(50)
);
INSERT INTO T VALUES (1,'one');
INSERT INTO T VALUES (2,'two');
INSERT INTO T VALUES (3,'three');
Query 1:
select
stuff((SELECT ', ' + CAST(t2.ID AS VARCHAR(5)) + ':'+ t2.description
FROM t t2
FOR XML PATH('')),1,1,'')
Results:
| |
|------------------------|
| 1:one, 2:two, 3:three |
i think you are asking for this
select stuff((SELECT ', ' + CAST(tbl.id AS varchar) + ':' + tbl.description
FROM tablename tbl FOR XML PATH('')), 1, 1, '') as Columnname
You were close..
declare #T TABLE (
id int,
description varchar(50)
);
INSERT INTO #T VALUES (1,'one');
INSERT INTO #T VALUES (2,'two');
INSERT INTO #T VALUES (3,'three');
select Id,
stuff((SELECT distinct ', ' + +cast(id as nvarchar) +':'+description
FROM #T t2
where t2.Id = t1.Id
FOR XML PATH('')),1,1,'')
from #T t1
group by Id
OR If you want all the ids in a sing row use the below query
select stuff((select ',' +cast(id as nvarchar) +':'+description
from #T for xml path('')),1,1,'')
select statement is like a for loop or an iterator and you you need a space to save you data and it's not possible with select only because in the moment select statement only access to a row not previous row and not next row so
please use a scaler-value function
create function test()
return
nvarchar(max)
as
begin
declare #s nvarchar(max)
select #s = concate(#s, id, description)
from yourTable
return #s
end

Finding unique characters from a table field for all rows

How to find the number of distinct character used in the field having multiple rows.
For example, if there are two rows having data like abcd and eaafg* then distinct character used are abcdefg*.
Try this one -
INSERT INTO #temp (txt)
VALUES ('abcd3'), ('abcdefg*')
SELECT disword = (
SELECT DISTINCT dt.ch
FROM (
SELECT ch = SUBSTRING(t.mtxt, n.number + 1, 1)
FROM [master].dbo.spt_values n
CROSS JOIN (
SELECT mtxt = (
SELECT txt
FROM #temp
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
) t
WHERE [type] = N'p'
AND number <= LEN(mtxt) - 1
) dt
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
Example (edited):
SET NOCOUNT ON;
DECLARE #temp TABLE (txt VARCHAR(8000))
INSERT INTO #temp (txt)
VALUES ('abcd'), ('abcdefg*'), (REPLICATE('-', 8000)), (REPLICATE('+', 8000))
DECLARE #t TABLE (i BIGINT)
DECLARE
#i BIGINT = 1
, #l BIGINT = (
SELECT SUM(LEN(txt))
FROM #temp
)
WHILE (#i <= #l) BEGIN
INSERT INTO #t (i)
VALUES (#i), (#i+1), (#i+2), (#i+3), (#i+4), (#i+5), (#i+6), (#i+7), (#i+8), (#i+9)
SELECT #i += 10
END
SELECT disword = (
SELECT DISTINCT dt.ch
FROM (
SELECT ch = SUBSTRING(t.mtxt, n.i, 1)
FROM #t n
CROSS JOIN (
SELECT mtxt = (
SELECT txt
FROM #temp
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
) t
) dt
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
Have a look a t this solution -
SELECT
dt.ch
, cnt = COUNT(1)
FROM (
SELECT ch = SUBSTRING(t.mtxt, n.i, 1)
FROM #t n
CROSS JOIN (
SELECT mtxt = (
SELECT txt
FROM #temp
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)')
) t
) dt
WHERE dt.ch != ''
GROUP BY dt.ch
ORDER BY cnt DESC
Here are questions that may refer to what you are asking:
How do I get distinct characters of string column in mssql?
and
SQL: how to get all the distinct characters in a column, across all rows
With tallys:
DECLARE #t TABLE (s NVARCHAR(MAX))
INSERT INTO #t
VALUES ('abcd'), ('abcdefg*')
;WITH tally AS(SELECT ROW_NUMBER() OVER(ORDER BY (SELECT 1)) i
FROM (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) t1(n)
CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) t2(n))
SELECT
( SELECT DISTINCT sb
FROM tally
CROSS APPLY ( SELECT SUBSTRING(s, i, 1) sb FROM #t ) ca
WHERE sb <> ''
FOR XML PATH(N'') , TYPE , ROOT).value(N'root[1]', N'NVARCHAR(MAX)')

How to perform a join in SQL Server without using tables

I have two lists and I want to see what the two lists DON'T have in common. For example:
List1:
'a','b','c','123'
List2:
'd','e','f','a','asd','c'
I want output to be:
'b','123','d','e','f','asd'
Something like this?
select * from ('a','b','c','123')
join ('d','e','f','a','asd','c')
on ???
Is there a pure SQL Server solution for this without using tables?
If you have control over the lists, I would just make them table variables:
DECLARE #a TABLE (str varchar(100))
INSERT INTO #a
VALUES
('a'),
('b')...
DECLARE #b table (str varchar(100))
INSERT INTO #b
VALUES
...
(SELECT str FROM #a
EXCEPT
SELECT str FROM #b)
UNION
(SELECT str FROM #b
EXCEPT
SELECT str FROM #a)
Given this function:
CREATE FUNCTION dbo.SplitStrings ( #List NVARCHAR(MAX) )
RETURNS TABLE
AS
RETURN ( SELECT Item FROM (
SELECT Item = x.i.value('(./text())[1]', 'nvarchar(max)')
FROM (
SELECT [XML] = CONVERT(XML, '<i>' + REPLACE(#List,',', '</i><i>')
+ '</i>').query('.')) AS a CROSS APPLY [XML].nodes('i') AS x(i)
) AS y WHERE Item IS NOT NULL);
GO
You can do it with a full outer join:
DECLARE
#list1 NVARCHAR(MAX) = N'a,b,c,123',
#list2 NVARCHAR(MAX) = N'd,e,f,a,asd,c',
#output NVARCHAR(MAX) = N'';
SELECT #output += N',' + COALESCE(l1.Item, l2.Item)
FROM dbo.SplitStrings(#list1) AS l1
FULL OUTER JOIN dbo.SplitStrings(#list2) AS l2
ON l1.Item = l2.Item
WHERE l1.Item IS NULL OR l2.Item IS NULL;
SELECT STUFF(#output, 1, 1, N'');
Or similar to #JNK's:
DECLARE
#list1 NVARCHAR(MAX) = N'a,b,c,123',
#list2 NVARCHAR(MAX) = N'd,e,f,a,asd,c',
#output NVARCHAR(MAX) = N'';
;WITH l1 AS (SELECT Item FROM dbo.SplitStrings(#list1)),
l2 AS (SELECT Item FROM dbo.SplitStrings(#list2))
SELECT #output += N',' + Item
FROM ( (SELECT Item FROM l1 EXCEPT SELECT Item FROM l2)
UNION
(SELECT Item FROM l2 EXCEPT SELECT Item FROM l1)) AS x;
SELECT STUFF(#output, 1, 1, N'');
And probably a variety of other ways too. If order matters, it's going to be a little more complex, but still possible.
There is no easy way to accomplish this. To filter the values from a list you need to have them as rows. So you would end up with something like:
SELECT col FROM (
SELECT 'a' as col
UNION
SELECT 'b'
UNION
SELECT 'c') t
WHERE col NOT IN ('a', 'b')
How about:
with
list1(j) as (select 'a' union select 'b'),
list2(j) as (select 'b' union select 'c')
select coalesce(list1.j, list2.j)
from list1 full join list2
on list1.j = list2.j
where (list1.j is null or list2.j is null)
I think you'll have to insert the values into 2 variable tables.
DECLARE #Table1 TABLE (Value VARCHAR(1))
DECLARE #Table2 TABLE (Value VARCHAR(1))
INSERT INTO #Table1 (Value) VALUES ('a')
INSERT INTO #Table1 (Value) VALUES ('b')
INSERT INTO #Table2 (Value) VALUES ('b')
INSERT INTO #Table2 (Value) VALUES ('c')
Then perform some set operations on the 2 tables.
DECLARE #TableUnion TABLE (Value VARCHAR(1))
DECLARE #TableIntersection TABLE (Value VARCHAR(1))
DECLARE #TableExcept TABLE (Value VARCHAR(1))
INSERT INTO #TableUnion
SELECT * FROM
((SELECT * FROM #Table1)
UNION
(SELECT * FROM #Table2)) U
INSERT INTO #TableIntersection
SELECT * FROM
((SELECT * FROM #Table1)
INTERSECT
(SELECT * FROM #Table2)) I
INSERT INTO #TableExcept
SELECT * FROM
((SELECT * FROM #TableUnion)
EXCEPT
(SELECT * FROM #TableIntersection)) E
The result set of the final select statement will contain 'a' and 'c'. Which can be concatenated into a single string as follows.
DECLARE #ExceptString VARCHAR(3)
SELECT #ExceptString =
CASE
WHEN #ExceptString IS NULL THEN Value
ELSE #ExceptString + ',' + Value
END
FROM #TableExcept

Help with TSQL join query

Based on below 2 tables
declare #t1 table
(
Id int,
Title varchar(100),
RelatedId int
)
insert into #t1 values(1,'A',2)
insert into #t1 values(1,'A',3)
declare #t2 table
(
Id int,
Title varchar(100)
)
insert into #t2 values
(2,'B'),
(3,'C')
I am trying to get the below output
Id Title RelatedItems
---------------------------------
1 A 2 (B), 3 (C)
I tried the following:
select t1.Id,t1.Title, cast(t2.Id as varchar) + ' (' + t2.Title + ')' from #t1 as t1
left outer join #t2 as t2
on t1.RelatedId=t2.Id
But that gives 2 different rows. I want just one row with the data combined in the third column (as shown above). Pls. suggest.
Use:
SELECT DISTINCT
b.id,
b.title,
STUFF((SELECT ','+ CAST(t2.id AS VARCHAR(100)) + ' ('+ t2.title +')'
FROM t2
JOIN t1 a ON a.relatedid = t2.id
WHERE a.id = b.id
FOR XML PATH('')), 1, 1, '')
FROM t1 b