Finding unique characters from a table field for all rows - sql

How to find the number of distinct character used in the field having multiple rows.
For example, if there are two rows having data like abcd and eaafg* then distinct character used are abcdefg*.

Try this one -
INSERT INTO #temp (txt)
VALUES ('abcd3'), ('abcdefg*')
SELECT disword = (
SELECT DISTINCT dt.ch
FROM (
SELECT ch = SUBSTRING(t.mtxt, n.number + 1, 1)
FROM [master].dbo.spt_values n
CROSS JOIN (
SELECT mtxt = (
SELECT txt
FROM #temp
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
) t
WHERE [type] = N'p'
AND number <= LEN(mtxt) - 1
) dt
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
Example (edited):
SET NOCOUNT ON;
DECLARE #temp TABLE (txt VARCHAR(8000))
INSERT INTO #temp (txt)
VALUES ('abcd'), ('abcdefg*'), (REPLICATE('-', 8000)), (REPLICATE('+', 8000))
DECLARE #t TABLE (i BIGINT)
DECLARE
#i BIGINT = 1
, #l BIGINT = (
SELECT SUM(LEN(txt))
FROM #temp
)
WHILE (#i <= #l) BEGIN
INSERT INTO #t (i)
VALUES (#i), (#i+1), (#i+2), (#i+3), (#i+4), (#i+5), (#i+6), (#i+7), (#i+8), (#i+9)
SELECT #i += 10
END
SELECT disword = (
SELECT DISTINCT dt.ch
FROM (
SELECT ch = SUBSTRING(t.mtxt, n.i, 1)
FROM #t n
CROSS JOIN (
SELECT mtxt = (
SELECT txt
FROM #temp
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
) t
) dt
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
Have a look a t this solution -
SELECT
dt.ch
, cnt = COUNT(1)
FROM (
SELECT ch = SUBSTRING(t.mtxt, n.i, 1)
FROM #t n
CROSS JOIN (
SELECT mtxt = (
SELECT txt
FROM #temp
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)')
) t
) dt
WHERE dt.ch != ''
GROUP BY dt.ch
ORDER BY cnt DESC

Here are questions that may refer to what you are asking:
How do I get distinct characters of string column in mssql?
and
SQL: how to get all the distinct characters in a column, across all rows

With tallys:
DECLARE #t TABLE (s NVARCHAR(MAX))
INSERT INTO #t
VALUES ('abcd'), ('abcdefg*')
;WITH tally AS(SELECT ROW_NUMBER() OVER(ORDER BY (SELECT 1)) i
FROM (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) t1(n)
CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) t2(n))
SELECT
( SELECT DISTINCT sb
FROM tally
CROSS APPLY ( SELECT SUBSTRING(s, i, 1) sb FROM #t ) ca
WHERE sb <> ''
FOR XML PATH(N'') , TYPE , ROOT).value(N'root[1]', N'NVARCHAR(MAX)')

Related

How to get first character beside underscore for a given string

input:
string
'abc_def_ghk_lmn'
output:
dgl
You can try this (or even create a function):
DECLARE #str varchar(250) = 'abc_def_ghk_lmn'
DECLARE #result varchar(250)='';
WHILE(charindex('_',#str)!=0)
BEGIN
DECLARE #position int = charindex('_',#str)
SET #result += substring(#str,#position+1,1)
SET #str = substring(#str,#position+1,len(#str))
END
SELECT #result
You can use a recursive CTE:
IF OBJECT_ID('tempdb..#t') is not null drop table #t
SELECT * into #t from (values (N'abc_def_ghk_lmn'), (N'a_f_k_n'), (null), ('____'), ('asasas'), ('a_sasas'), ('asas_')) T(val);
;WITH CTE AS
(
SELECT
Cast(SUBSTRING(T.val, CHARINDEX('_',T.val,1) + 1, 1) as nvarchar(4000)) FC
,CHARINDEX('_', T.val, 1) CI
,val
,0 [level]
from #t T
where CHARINDEX('_', T.val, 1) > 0
union all
SELECT
Cast(T.FC + SUBSTRING(T.val, CHARINDEX('_',T.val,T.CI+1) + 1, 1) as nvarchar(4000)) FC
,CHARINDEX('_', T.val, T.CI+1) CI
,val
,t.[level] + 1
from CTE T
where CHARINDEX('_',T.val,T.CI+1) > 0
)
, Res AS
(
SELECT
*
,ROW_NUMBER() OVER (Partition by val order by [level] desc) RN
from CTE
)
SELECT * from Res where RN = 1
This uses Jeff Moden's DelimitedSplit8K Function. Firstly because i don't know what version of SQL Server you are using, and secondly, the inbuilt function STRING_SPLIT (available in SQL Server 2016 onwards) doesn't include an Item Number value (thus how does one exclude the first result?):
SELECT (SELECT LEFT(Item, 1)
FROM DelimitedSplit8K ('abc_def_ghk_lmn','_') DS
WHERE DS.ItemNumber > 1
FOR XML PATH(''));
Edit:
Example with a dataset:
WITH VTE AS(
SELECT *
FROM (VALUES ('asdgsad_sdfh_sadfh'),('_ashdf+ashd'),('jsda_sdkhfsdjf_654_asdfkhasd_567465413_kasbgdjkasdj')) V(S))
SELECT (SELECT LEFT(Item, 1)
FROM DelimitedSplit8K (S,'_') DS
WHERE DS.ItemNumber > 1
FOR XML PATH('')) AS FirstCharacters
FROM VTE;
Try this:
DECLARE #String VARCHAR(50)= 'abc_def_ghk_lmn',#Result VARCHAR(10)=''
WHILE CHARINDEX('_',#String)>0
BEGIN
SELECT #Result=#Result + SUBSTRING(#String,CHARINDEX('_',#String)+1,1)
SELECT #String=RIGHT(#String,LEN(#String)- CHARINDEX('_',#String))
END
SELECT #Result FinalResult
OUTPUT:
FinalResult
dgl
Please try this -...Always use SET BASED Approach
SOLUTION
DECLARE #x AS XML=''
DECLARE # AS VARCHAR(1000) = 'abc_def_ghk_lmn_'
SET #x = CAST('<A>'+ REPLACE(#,'_','</A><A>')+ '</A>' AS XML)
;WITH CTE AS
(
SELECT t.value('.', 'VARCHAR(10)') Value FROM #x.nodes('/A') AS x(t)
)
,CTE1 AS
(
SELECT * , ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) rnk FROM CTE
)
,CTE2 AS
(
SELECT SUBSTRING(Value,1,1) v , rnk FROM CTE1
)
SELECT CASE WHEN LEFT(#,1) <> '_' THEN MAX(SUBSTRING(u,2,LEN(u))) ELSE MAX(u) END finalstr from (
SELECT
(
SELECT '' + v
FROM CTE2 a
FOR XML PATH('')
)u
FROM CTE2 )x
OUTPUT
finalstr
---------------
dgl
(1 row affected)
Try this below
DECLARE #str TAble(String varchar(250))
INSERT INTO #str
SELECT 'abc_def_ghk_lmn_opq_rst_uvw_xyz'
SELECT STUFF((SELECT ''+LEFT(String,1) FROM
(
SELECT Split.a.value('.','Varchar(1000)') As String,
ROW_NUMBER()OVER(ORDER BY (SELECT 1)) AS Id FROM
(
SELECT CASt('<S>'+REPLACE(String,'_','</S><S>')+'</S>' AS XML )AS String
FROM #str
)as A
CROSS APPLY String.nodes ('S') AS Split(a)
)dt
WHERE dt.Id <>1
FOR XML PATH ('')),1,0,'') AS ExpectedColumn
Result
ExpectedColumn
--------------
dglorux
Use LEFT to get the left part and INSTR to find underscore and finally get your string:
SELECT LEFT(FIELD_1, CHARINDEX('_', FIELD_1) - 2) AS [ANY_ALIAS]
FROM TABLE_1;
EDIT: Now is MSSQL... ;D

How to group a table, at the same time saving all column values in each group to a single column as comma-separated values

Please see the following SQL code.
Declare #LookUp table (id int,val varchar(12))
insert into #LookUp values (1,'A'),(1,'D'),(1,'X'),(2,'B'),(2,'F')
Declare #summary table (id int,val varchar(2000))
------------------------------
Declare #value varchar(30)
Declare #start int = 1, #end int = (Select count(Distinct id) from #LookUp)
While #start <= #end
Begin
Set #value = ''
Select #value = #value + '|' + val From #LookUp Where id = #start
Insert into #summary
Select #start,Right(#value,Len(#value)-1)
Set #start = #start + 1
End
Select * From #summary
With the following query, I am grouping based on Id, and making the values with in a group, as comma-separated values.
Input:
Output:
I have done this using a loop, which is not performing very well when it comes to large amount of data.
Can we do this avoiding a loop?
Note: Assume that #lookup.id is continuous.
INSERT #summary(id, val)
SELECT
t.id,
STUFF((
select '|' + [val]
from #LookUp t1
where t1.id = t.id
for xml path(''), type
).value('.', 'varchar(max)'), 1, 1, '') [values]
FROM #LookUp t
GROUP BY t.id
Try this..
Declare #LookUp table (id int,val varchar(12))
insert into #LookUp values (1,'A'),(1,'D'),(1,'X'),(2,'B'),(2,'F')
select
id,
val =
stuff((
select
'| ' + t2.val
from #LookUp t2
where
t2.id = t1.id
group by t2.val
for xml path(''), type).value('.', 'varchar(max)'
), 1, 2, '')
from #LookUp t1
GROUP BY t1.id
Declare #LookUp table (id int,val varchar(12))
insert into #LookUp values (1,'A'),(1,'D'),(1,'X'),(2,'B'),(2,'F');
WITH A AS
(
SELECT DISTINCT id
FROM #LookUp
)
SELECT
A.id,
STUFF
(
(
SELECT ',' + val
FROM #LookUp B
WHERE B.id = A.id
FOR XML PATH('')
),
1, 1, ''
) AS val
FROM A
Declare #LookUp table (id int,val varchar(12))
insert into #LookUp values (1,'A'),(1,'D'),(1,'X'),(2,'B'),(2,'F')
SELECT DISTINCT a.id, stuff((select '|' + val
from #LookUp c
where c.id = a.id
for xml path('')),1,1,'') as vall
FROM #LookUp a
I'll add a solution based on a recursive common table expression. With small modifications it should work in DB2 too (you have to change the row_number() function to rownumber() and how the concatenation works in the second list (use || instead of the concat function).
DECLARE #LookUp TABLE (id int, val varchar(12))
INSERT INTO #LookUp VALUES (1,'A'),(1,'D'),(1,'X'),(2,'B'),(2,'F')
;WITH
list1(rn, id, val) AS
(
SELECT row_number() OVER (PARTITION BY id ORDER BY id), id, val
FROM #LookUp
),
list2 (id, val, idx) AS
(
SELECT id, val, 1
FROM list1
WHERE rn = 1
UNION ALL
SELECT
list2.id,
CAST(CONCAT(list2.val, ' | ', list1.val) AS varchar(12)),
list2.idx + 1
FROM list2
JOIN list1 ON list2.id = list1.id
WHERE list2.idx + 1 = list1.rn
)
SELECT l2.id, l2.val
FROM list2 l2
JOIN (SELECT id, MAX(rn) maxid FROM list1 GROUP BY id) a
ON l2.id = a.id AND l2.idx = a.maxid
ORDER BY l2.id
This outputs:
id val
1 A | D | X
2 B | F

Delete duplicate values from concatenated string

I have the following table:
Object Field Values
------------------------------------
1 1 A;A;A;B;A;A
2 1 A;B;C;C
2 2 X
3 1 X;Y;Z
3 2 V;V;V;V;V;V;V;V;V;V;V
How can I select from this table only the unique values from the concatenated values? So:
Object Field Values
---------------------
1 1 A;B
2 1 A;B;C
2 2 X
3 1 X;Y;Z
3 2 V
In any scripting language, I would loop through the values from Values, explode on ; and loop through that array with some logic filtering out duplicates. However, I need to do this only using SQL (Server 2008).
Can anybody tell me if and how this can be done?
Any help is greatly appreciated :-)
To do this first create a split function. This is the one I use but if you search the internet (or even SO) for "SQL Server Split Function" you will find a number of alternatives if you don't like this:
ALTER FUNCTION [dbo].[Split](#StringToSplit NVARCHAR(MAX), #Delimiter NCHAR(1))
RETURNS TABLE
AS
RETURN
(
SELECT ID = ROW_NUMBER() OVER(ORDER BY n.Number),
Position = Number,
Value = SUBSTRING(#StringToSplit, Number, CHARINDEX(#Delimiter, #StringToSplit + #Delimiter, Number) - Number)
FROM ( SELECT TOP (LEN(#StringToSplit) + 1) Number = ROW_NUMBER() OVER(ORDER BY a.object_id)
FROM sys.all_objects a
CROSS JOIN sys.all_objects b
) n
WHERE SUBSTRING(#Delimiter + #StringToSplit + #Delimiter, n.Number, 1) = #Delimiter
);
Then you can split your field, So running:
SELECT t.Object, t.Field, s.Value
FROM T
CROSS APPLY dbo.Split(t.[Values], ';') AS s
Will turn this:
Object Field Values
------------------------------------
1 1 A;A;A;B;A;A
into:
Object Field Values
------------------------------------
1 1 A
1 1 A
1 1 A
1 1 B
1 1 A
1 1 A
Then you can apply the DISTINCT Operator:
SELECT DISTINCT t.Object, t.Field, s.Value
FROM T
CROSS APPLY dbo.Split(t.[Values], ';') AS s;
To give:
Object Field Values
------------------------------------
1 1 A
1 1 B
Then you can concatenate your rows back into a single column giving a final query:
SELECT t.Object, t.Field, [Values] = STUFF(x.value('.', 'NVARCHAR(MAX)'), 1, 1, '')
FROM T
CROSS APPLY
( SELECT DISTINCT ';' + s.Value
FROM dbo.Split(t.[Values], ';') AS s
FOR XML PATH(''), TYPE
) AS s (x)
SQL Fiddle appears to be down, but once you have the Split function created the below is a full working example:
CREATE TABLE #T (Object INT, Field INT, [Values] VARCHAR(MAX));
INSERT #T
VALUES
(1, 1, 'A;A;A;B;A;A'),
(2, 1, 'A;B;C;C'),
(2, 2, 'X'),
(3, 1, 'X;Y;Z'),
(3, 2, 'V;V;V;V;V;V;V;V;V;V;V');
SELECT t.Object, t.Field, [Values] = STUFF(x.value('.', 'NVARCHAR(MAX)'), 1, 1, '')
FROM #T AS T
CROSS APPLY
( SELECT DISTINCT ';' + s.Value
FROM dbo.Split(t.[Values], ';') AS s
FOR XML PATH(''), TYPE
) AS s (x);
EDIT
Based on your comment that you can't create tables or modify the DDL, I thought I would account for the situation where you can't create a function either. You can expand the above split function out into your query, so you don't actually need to create a function:
CREATE TABLE #T (Object INT, Field INT, [Values] VARCHAR(MAX));
INSERT #T
VALUES
(1, 1, 'A;A;A;B;A;A'),
(2, 1, 'A;B;C;C'),
(2, 2, 'X'),
(3, 1, 'X;Y;Z'),
(3, 2, 'V;V;V;V;V;V;V;V;V;V;V');
SELECT t.Object,
t.Field,
[Values] = STUFF(x.value('.', 'NVARCHAR(MAX)'), 1, 1, '')
FROM #T AS T
CROSS APPLY
( SELECT DISTINCT ';' + SUBSTRING(t.[Values], Number, CHARINDEX(';', t.[Values] + ';', Number) - Number)
FROM ( SELECT TOP (LEN(t.[Values]) + 1) Number = ROW_NUMBER() OVER(ORDER BY a.object_id)
FROM sys.all_objects a
CROSS JOIN sys.all_objects b
) n
WHERE SUBSTRING(';' + t.[Values] + ';', n.Number, 1) = ';'
FOR XML PATH(''), TYPE
) AS s (x);
Here is a standalone solution:
DECLARE #t table(Object int, Field int, [Values] varchar(max))
INSERT #t values
(1, 1, 'A;A;A;B;A;A'),
(2, 1, 'A;B;C;C'),
(3, 1, 'X'),
(4, 1, 'X;Y;Z'),
(5, 1, 'V;V;V;V;V;V;V;V;V;V;V')
SELECT t.Object, t.Field, x.[NewValues]
FROM #t t
CROSS APPLY
(
SELECT STUFF((
SELECT distinct ';'+t.c.value('.', 'VARCHAR(2000)') value
FROM (
SELECT x = CAST('<t>' +
REPLACE([Values], ';', '</t><t>') + '</t>' AS XML)
) a
CROSS APPLY x.nodes('/t') t(c)
for xml path(''), type
).value('.', 'varchar(max)'), 1, 1, '') [NewValues]
) x
Result:
Object Field NewValues
1 1 A;B
2 1 A;B;C
3 1 X
4 1 X;Y;Z
5 1 V
According to #GarethD's comment this may perform slow.
Test data:
create table #t(Object int identity(1,1), Field int, [Values] varchar(max))
INSERT #t values
(1, 'A;A;A;B;A;A'),(1, 'A;B;C;C'), (1, 'X'), (1, 'X;Y;Z'),(1, 'V;V;V;V;V;V;V;V;V;V;V')
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
Performance testing my script:
SELECT t.Object, t.Field, x.[NewValues]
FROM #t t
CROSS APPLY
(
SELECT STUFF((
SELECT distinct ';'+t.c.value('.', 'VARCHAR(2000)') value
FROM (
SELECT x = CAST('<t>' +
REPLACE([Values], ';', '</t><t>') + '</t>' AS XML)
) a
CROSS APPLY x.nodes('/t') t(c)
for xml path(''), type
).value('.', 'varchar(max)'), 1, 1, '') [NewValues]
) x
Result less than 1 sec.
Performance testing Garath script
(had to edit testdata to get all rows. Identical rows were considered as 1 row):
WITH CTE AS
( SELECT DISTINCT t.Object, t.Field, s.Value
FROM #T AS T
CROSS APPLY
( SELECT ID = ROW_NUMBER() OVER(ORDER BY n.Number),
Position = Number,
Value = SUBSTRING(t.[Values], Number, CHARINDEX(';', t.[Values] + ';', Number) - Number)
FROM ( SELECT TOP (LEN(t.[Values]) + 1) Number = ROW_NUMBER() OVER(ORDER BY a.object_id)
FROM sys.all_objects a
CROSS JOIN sys.all_objects b
) n
WHERE SUBSTRING(';' + t.[Values] + ';', n.Number, 1) = ';'
) AS s
)
SELECT Object,
Field,
[Values] = STUFF((SELECT ';' + Value
FROM CTE AS T2
WHERE T2.Object = T.Object
AND T2.Field = T.Field
FOR XML PATH(''), TYPE
).value('.', 'VARCHAR(MAX)'), 1, 1, '')
FROM CTE AS T
GROUP BY Object, Field;
Result 6 seconds
If any row has null in values this script will also crash.
Just as a Scalar Value Function alternative without the CTE...
ALTER FUNCTION [SplitRemoveDupes] (
#String VARCHAR(MAX)
,#Delimiter VARCHAR(5)
)
RETURNS VARCHAR(MAX)
AS
BEGIN
DECLARE #SplitLength INT
DECLARE #DedupedValues VARCHAR(MAX)
DECLARE #SplittedValues TABLE
(
OccurenceId SMALLINT IDENTITY(1,1),
SplitValue VARCHAR(200)
)
WHILE LEN(#String) > 0
BEGIN
SELECT #SplitLength = (
CASE CHARINDEX(#Delimiter, #String)
WHEN 0
THEN LEN(#String)
ELSE CHARINDEX(#Delimiter, #String) - 1
END
)
INSERT INTO #SplittedValues
SELECT SUBSTRING(#String, 1, #SplitLength)
SELECT #String = (
CASE (LEN(#String) - #SplitLength)
WHEN 0
THEN ''
ELSE RIGHT(#String, LEN(#String) - #SplitLength - 1) END)
END
SET #DedupedValues=(SELECT DISTINCT STUFF((
SELECT DISTINCT (#Delimiter + SplitValue)
FROM #SplittedValues s
ORDER BY (#Delimiter + SplitValue)
FOR XML PATH('')
), 1, 1, '') AS a
FROM #SplittedValues ss)
RETURN #DedupedValues
END
Call it inline...
SELECT Object, Field, [dbo].[SplitRemoveDupes](Values,';') From Table

SQL Query for Min and Max Values [duplicate]

This question already has answers here:
How to split a comma-separated value to columns
(38 answers)
Closed 8 years ago.
I have the following data in a table. The number of values in each row can vary and the number of rows could also vary.
The table has 1 column with csv formatted values. The values will always be numeric
Data
1,2
4
5,12, 10
6,7,8,9,10
15,17
I would like to end up with a temp table with the following
Data Lowest Highest
1,2 1 2
4 4 4
5,12, 10 5 12
6,7,8,9,10 6 10
15,17 15 17
Can anyone help with writing a sql query or function to achieve this
Instead of function, you can achieve by this
;WITH tmp
AS (SELECT A.rn,split.a.value('.', 'VARCHAR(100)') AS String
FROM (SELECT Row_number() OVER(ORDER BY (SELECT NULL)) AS RN,
Cast ('<M>' + Replace([data], ',', '</M><M>') + '</M>' AS XML) AS String
FROM table1) AS A
CROSS apply string.nodes ('/M') AS Split(a))
SELECT X.data,Tmp.lower,Tmp.higher
FROM (SELECT rn,Min(Cast(string AS INT)) AS Lower,Max(Cast(string AS INT)) AS Higher
FROM tmp
GROUP BY rn) Tmp
JOIN (SELECT Row_number() OVER(ORDER BY (SELECT NULL)) AS RN1,data
FROM table1) X
ON X.rn1 = Tmp.rn
FIDDLE DEMO
Output would be:
Data Lower Higher
1,2 1 2
4 4 4
5,12, 10 5 12
6,7,8,9,10 6 10
15,17 15 17
First create a user defined function to convert each row of 'DATA' column to a intermediate table as:
/****** Object: UserDefinedFunction [dbo].[CSVToTable]******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE FUNCTION [dbo].[CSVToTable] (#InStr VARCHAR(MAX))
RETURNS #TempTab TABLE
(id int not null)
AS
BEGIN
;-- Ensure input ends with comma
SET #InStr = REPLACE(#InStr + ',', ',,', ',')
DECLARE #SP INT
DECLARE #VALUE VARCHAR(1000)
WHILE PATINDEX('%,%', #INSTR ) <> 0
BEGIN
SELECT #SP = PATINDEX('%,%',#INSTR)
SELECT #VALUE = LEFT(#INSTR , #SP - 1)
SELECT #INSTR = STUFF(#INSTR, 1, #SP, '')
INSERT INTO #TempTab(id) VALUES (#VALUE)
END
RETURN
END
GO
Function is explained further here.
Then Using Cross Apply we can get the desired output as:
With CTE as
(
select
T.Data, Min(udf.Id) as [Lowest],Max(udf.Id) as [Highest]
from
Test T
CROSS APPLY dbo.CSVToTable(T.Data) udf
Group By Data
)
Select * from CTE
Sample Code here...
What a Cross Apply does is : it applies the right table expression to each row from the left table and produces a result table with the unified result sets.
Create table #temp1 (name varchar(100),value int )
Declare #len int
Select #len=(select max(LEN(name)-LEN(replace(name,',',''))) from table)
Declare #i int = 1
while (#i<=#len+1)
begin
insert into #temp1
select name,PARSENAME(REPLACE(name,',','.'),#i) from table t
set #i = #i+1
end
Select name,MIN(value) MINV,MAX(value) MAXV from #temp1 group by name
declare #Testdata table ( Data varchar(max))
insert #Testdata select '1,2'
insert #Testdata select '4'
insert #Testdata select '5,12, 10'
insert #Testdata select '6,7,8,9,10'
;with tmp( DataItem, Data, RN1) as (
select LEFT(Data, CHARINDEX(',',Data+',')-1),
STUFF(Data, 1, CHARINDEX(',',Data+','), ''),
ROW_NUMBER()OVER(ORDER BY (SELECT NULL))AS RN1
from #Testdata
union all
select LEFT(Data, CHARINDEX(',',Data+',')-1),
STUFF(Data, 1, CHARINDEX(',',Data+','), ''),RN1
from tmp
where Data > ''
)
Select x.data,t.Low,t.Up FROM
(Select RN1,MIN(Cast(DataItem AS INT)) As Low,
MAX(Cast(DataItem AS INT)) As Up
FROM tmp t GROUP BY t.RN1)t
JOIN (Select ROW_NUMBER()OVER(ORDER BY (SELECT NULL))AS RN,data from #Testdata)X
ON X.RN = t.RN1

SQL splitting a word in separate characters

I need to change an application and the first thing I need is to change a field in a database table.
In this table I now have 1 to 6 single characters, i.e. 'abcdef'
I need to change this to '[a][b][c][d][e][f]'
[edit] It is meant to stay in the same field. So before field = 'abcdef' and after field = '[a][b][c][d][e][f]'.
What would be a good way to do this?
rg.
Eric
You can split string to separate characters using following function:
create function ftStringCharacters
(
#str varchar(100)
)
returns table as
return
with v1(N) as (
select 1 union all select 1 union all select 1 union all select 1 union all select 1
union all
select 1 union all select 1 union all select 1 union all select 1 union all select 1
),
v2(N) as (select 1 from v1 a, v1 b),
v3(N) as (select top (isnull(datalength(#str), 0)) row_number() over (order by ##spid) from v2)
select N, substring(#str, N, 1) as C
from v3
GO
And then apply it as:
update t
set t.FieldName = p.FieldModified
from TableName t
cross apply (
select (select quotename(s.C)
from ftStringCharacters(t.FieldName) s
order by s.N
for xml path(''), type).value('text()[1]', 'varchar(20)')
) p(FieldModified)
SQLFiddle sample
DECLARE #text NVARCHAR(50)
SET #text = 'abcdef'
DECLARE #texttable TABLE (value NVARCHAR(1))
WHILE (len(#text) > 0)
BEGIN
INSERT INTO #texttable
SELECT substring(#text, 1, 1)
SET #text = stuff(#text, 1, 1, '')
END
select * from #texttable
Without using a function:
declare #t table(C varchar(18))
insert #t values('abc'), ('1234'), (' 1234a')
;with CTE as
(
select C, '[' + substring(c, a.n, 1) + ']' v, rn from
(select 1 n union all
select 2 union all
select 3 union all
select 4 union all
select 5 union all
select 6) a
cross apply
(select c, row_number() over (order by C) rn from #t group by c) b
where a.n <= len(C)
)
update t3
set C = t4.[value]
FROM #t t3
JOIN
(
select C,
(
select v
from CTE t1
where t1.rn = t2.rn
for xml path(''), type
).value('.', 'varchar(18)') [value]
from CTE t2
group by t2.rn, C
) t4
ON t3.C = t4.C
SELECT * FROM #t