I need to remove the + - values records mean to say
I need only Blue colored two records from the output windows.
Hope its clear what exactly I want.
User5 | -15
User6 | -10
The idea is to get rows whose second column, in my case it's Val, is are cancelled out. You can do it by getting the absolute value and assign a row number grouped by absolute value and the value itself. Those row number that does not have a match should be the result.
WITH SampleData(UserID, Val) AS(
SELECT 'User1', -10 UNION ALL
SELECT 'User2', 10 UNION ALL
SELECT 'User3', -15 UNION ALL
SELECT 'User4', -10 UNION ALL
SELECT 'User5', -15 UNION ALL
SELECT 'User6', -10 UNION ALL
SELECT 'User7', 10 UNION ALL
SELECT 'User8', 15
)
,Numbered AS(
SELECT
UserID,
Val,
BaseVal = ABS(Val),
RN = ROW_NUMBER() OVER(PARTITION BY ABS(Val), Val ORDER BY UserId)
FROM SampleData
)
SELECT
n1.UserID,
n1.Val
FROM Numbered n1
LEFT JOIN Numbered n2
ON n2.BaseVal = n1.BaseVal
AND n2.RN = n1.rn
AND n2.UserID <> n1.UserID
WHERE n2.UserID IS NULL
ORDER BY n1.UserID
Appears that you want rows where the total does not equal 0?
select
userName,
userValue
from
yourTable
where
userName in (
select userName from yourTable
group by userName
having sum (userValue) <> 0
)
Related
I have this query
select *
from dbo.EventLogs
where EntityID = 60181615
and EventTypeID in (1, 2, 3, 4, 5)
and NewValue = 'Received'
If 2 and 4 does not exist with NewValue 'Received' it shows this
current results
What I want
Ideally you should maintain somewhere a table containing all possible EventTypeID values. Sans that, we can use a CTE in place along with a left join:
WITH EventTypes AS (
SELECT 1 AS ID UNION ALL
SELECT 2 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5
)
SELECT et.ID AS EventTypeId, el.*
FROM EventTypes et
LEFT JOIN dbo.EventLogs el
ON el.EntityID = 60181615 AND
el.NewValue = 'Received'
WHERE
et.ID IN (1,2,3,4,5);
i want to find the minimum missing number of a column named (s_no) and the table named (test_table) in oracle and I write the following code..
select
min_s_no-1+level missing_number
from (
select min(s_no) min_s_no, max(s_no) max_s_no
from test_table
) connect by level <= max_s_no-min_s_no+1
minus
select s_no from test_table
;
it gives me all the missing number as a result. But I want to select the minimum
number. Can any one help me please.
thanks in advance.
Using analytical function LEAD you can get the number from the next row in ascending order. Comparing of this value with with the original number increased by 1 you get the missing values (if two numbers do not match).
To get the first missing value in ascending order is the same selecting the MIN value:
select
num,
lead(num) over (order by num) num_lead,
case when num + 1 != lead(num) over (order by num) then num + 1 end as missing_num
from test_data
order by num;
NUM NUM_LEAD MISSING_NUM
---------- ---------- -----------
4 5
5 6
6 9 7
9 10
10 13 11
13
-- first missing number = MIN missing number
select min(missing_num)
from (
select
case when num + 1 != lead(num) over (order by num) then num + 1 end as missing_num
from test_data
);
MIN(MISSING_NUM)
----------------
7
ADDENDUM
A good practice in writing SQL is to consider edge cases - here a table that contains a complete interval without holes. The first missing value will be the successor of the last number.
select nvl(min(missing_num),max(num)+1) first_missing_value
from (
select
num,
case when num + 1 != lead(num) over (order by num) then num + 1 end as missing_num
from test_data
);
A complete table return no MISSING_NUM, so the original query return NULL. Using the NVL the expected result is provided.
The best way to find the gaps is to use analytic functiions lead or lag. An example with lag:
with test_data as (
select 1 num from dual union all
select 4 from dual union all
select 6 from dual union all
select 8 from dual union all
select 3 from dual union all
select 9 from dual union all
select 0 from dual
)
select min(gap) min_gap
from (
select num, lag(num) over (order by num)+1 gap
from test_data
)
where num != gap
;
MIN_GAP
------------------
2
More about how to find the gaps here
In Oracle 12.1 and above, MATCH_RECOGNIZE can do quick work of this kind of problems:
Edited. Initially I was picking the "next number" where a gap exists (in the example, the value 9). But that is not what the OP wants, he wants the first missing number (7 in this case). I edited to change the measures clause, to find the first missing number as requested. End Edit
with test_data (num) as (
select 4 from dual union all
select 5 from dual union all
select 6 from dual union all
select 9 from dual union all
select 10 from dual union all
select 13 from dual
)
-- end of test data; when you use the SQL query below,
-- replace test_data and num with your actual table and column names.
select result as num
from test_data
match_recognize (
order by num
measures last(b.num) + 1 as result
pattern ( ^ a b* c )
define b as num = prev(num) + 1,
c as num > prev(num) + 1
)
;
NUM
---
7
I have a table and i want to colum joint_no column. The column's values are like these
FW-1
FW-2
.
.
.
FW-13
FW-R1
FW-1A
When i ordered them i get this results
FW-1
FW-10
FW-11
FW-12
FW-13
FW-1A
.
.
FW-R1
I want to get this result after sql query
FW-1
FW-1A
FW-2
FW-3
..
FW-13
FW-R1
can anybody help me?
If you can do it, I'd advise you to renumber the values so that the 'logical' order sticks to the alphabetical order. F-1 will then be updated to F-01, or F-001.
If you cannot do it, add a field that will be populated with the 'ordered' form of your code. You 'll then be able to order by the F-001 column and still display the F-1 value
Otherwise ordering your records will rapidly become your nightmare.
Using Patindex to find the first numeric expression as first sort field, then extracting the numeric part as integer as second sortfield and using the whole string as third sort field you might get the desired result.
Declare #a Table (c varchar(50))
Insert Into #a
Select 'FW-1'
Union Select 'FW-10'
Union Select 'FW-11'
Union Select 'FW-12'
Union Select 'FW-13'
Union Select 'FW-1A'
Union Select 'FW-2'
Union Select 'FW-3'
Union Select 'FW-R1'
Union Select 'FW-A1'
;With CTE as
(Select 1 as ID
Union All
Select ID + 1 from CTE where ID < 100
)
Select * from
(
Select c
,PATINDEX('%[0-9]%',c) as s1
,(Select Cast(
(Select Case
When SUBSTRING(c, ID, 1) LIKE '[0-9]'
Then SUBSTRING(c, ID, 1)
Else ''
End
From (Select * from CTE) AS X(ID)
Where ID <= LEN(c)
For XML PATH(''))
as int)
)
as s2
from
#a
) x
order by
s1,s2,c
With the output:
FW-1 4 1 -1
FW-1A 4 1 -1A
FW-2 4 2 -2
FW-3 4 3 -3
FW-10 4 10 -10
FW-11 4 11 -11
FW-12 4 12 -12
FW-13 4 13 -13
FW-A1 5 1 A1
FW-R1 5 1 R1
If the leading part is not fixed (FW-) you might need to add one additional sort field
Declare #a Table (c varchar(50))
Insert Into #a
Select 'FW-1'
Union Select 'FW-10'
Union Select 'FW-11'
Union Select 'FW-12'
Union Select 'FW-13'
Union Select 'FW-1A'
Union Select 'FW-2'
Union Select 'FW-3'
Union Select 'FW-R1'
Union Select 'FW-A1'
Union Select 'AB-A1'
Union Select 'AB-11'
;With CTE as
(Select 1 as ID
Union All
Select ID + 1 from CTE where ID < 100
)
Select * from
(
Select c
,SubString(c,1,PATINDEX('%[0-9]%',c)-1) as S0
,PATINDEX('%[0-9]%',c) as s1
,(Select Cast(
(Select Case
When SUBSTRING(c, ID, 1) LIKE '[0-9]'
Then SUBSTRING(c, ID, 1)
Else ''
End
From (Select * from CTE) AS X(ID)
Where ID <= LEN(c)
For XML PATH(''))
as int)
)
as s2
from
#a
) x
order by
s0,s1,s2,c
I am using the following query :
select 8 Union Select 0 Union Select 15
to populate the these 3 number in a column. The result I get is:
0
8
15
But I want 8 to come first and then 0 and then 15, e.g.
8
0
15
How do I do this?
Use UNION ALL
E.g.
select 8 UNION ALL Select 0 UNION ALL Select 15
#SimonMartin's answer works for the exact data set you give, but be aware that if your data set contains duplicate values, the UNION ALL will produce different results than UNION.
The UNION operator removes duplicates, whereas the UNION ALL will preserve them (as well as their order, as noted in #SimonMartin's answer).
If you want to combine the functionality of your UNION operator with the ordering capabilities provided by UNION ALL, then you need to start with UNION ALL then filter out the duplicate values yourself:
-- baseline query + 1 duplicate record at the end
with query as
(
select 8 as Val
UNION ALL
Select 0 as Val
UNION ALL
Select 15 as Val
UNION ALL
Select 0 as Val
)
-- now add row numbers
, queryWithRowNumbers as
(
select row_number() over (order by (select 0)) as rn, Val
from query
)
-- finally, get rid of the duplicates
select Val from (
select Val, min(rn) as minRn
from querywithrownumbers
group by val
) q
order by minRn
This will give results of
8
0
15
whereas if you ONLY use UNION ALL you will end up with
8
0
15
0
I need to split 1 amount into 2 fields. I know the total sums of the resulting fields = the ratio to split the first row, but i need to round the resulting sums and only then compute the ratio for next row (so the total sum of the rounded values will be correct).
How can i write this algorithm in Oracle 10g PL/SQL? I need to test some migrated data. Here is what i came up with (so far):
with temp as (
select 1 id, 200 amount, 642 total_a from dual union all
select 2, 200, 642 from dual union all
select 3, 200, 642 from dual union all
select 4, 200, 642 from dual union all
select 5, 200, 642 from dual
)
select
temp2.*,
remaining_a / remaining_amount ratio,
round(amount * remaining_a / remaining_amount, 0) rounded_a,
round(amount - amount * remaining_a / remaining_amount, 0) rounded_b
from (
select
temp.id,
temp.amount,
sum(amount) over (
order by id
range between current row and unbounded following
) remaining_amount,
case when id=1 then total_a /* else ??? */ end remaining_a
from temp
) temp2
Update: If you can't see the image above, expected rounded_A values are:
1 128
2 129
3 128
4 129
5 128
Here is my suggestion. It is not getting exactly what you want . . . by my calculation the 129 doesn't come until the 3rd row.
The idea is to add more columns. For each row, calculate the estimated split. Then, keep track of the accumulative fraction. When the cum remainder exceeds an integer, then bump up the A amount by 1. Once you have the A amount, you can calculate the rest:
WITH temp AS (
SELECT 1 id, 200 amount, 642 total_a FROM dual UNION ALL
SELECT 2, 200, 642 FROM dual UNION ALL
SELECT 3, 200, 642 FROM dual UNION ALL
SELECT 4, 200, 642 FROM dual UNION ALL
SELECT 5, 200, 642 FROM dual
)
select temp3.*,
sum(estArem) over (order by id) as cumrem,
trunc(estA) + (case when trunc(sum(estArem) over (order by id)) > trunc(- estArem + sum(estArem) over (order by id))
then 1 else 0 end)
from (SELECT temp2.*,
trunc(Aratio*amount) as estA,
Aratio*amount - trunc(ARatio*amount) as estArem
FROM (SELECT temp.id, temp.amount,
sum(amount) over (ORDER BY id range BETWEEN CURRENT ROW AND unbounded following
) remaining_amount,
sum(amount) over (partition by null) as total_amount,
max(total_a) over (partition by null)as maxA,
(max(total_a) over (partition by null) /
sum(amount) over (partition by null)
) as ARatio
FROM temp
) temp2
) temp3
This isn't exactly a partitioning problem. This is an integer approximation problem.
If you are rounding the values rather than truncating them, then you need a slight tweak to the logic.
trunc(estA) + (case when trunc(sum(0.5+estArem) over (order by id)) > trunc(0.5 - estArem + sum(estArem) over (order by id))
This statement was originally just looking for the cumulative remainder passing over the integer threshhold. This should do rounding instead of truncation.