Delete duplicate values from concatenated string - sql

I have the following table:
Object Field Values
------------------------------------
1 1 A;A;A;B;A;A
2 1 A;B;C;C
2 2 X
3 1 X;Y;Z
3 2 V;V;V;V;V;V;V;V;V;V;V
How can I select from this table only the unique values from the concatenated values? So:
Object Field Values
---------------------
1 1 A;B
2 1 A;B;C
2 2 X
3 1 X;Y;Z
3 2 V
In any scripting language, I would loop through the values from Values, explode on ; and loop through that array with some logic filtering out duplicates. However, I need to do this only using SQL (Server 2008).
Can anybody tell me if and how this can be done?
Any help is greatly appreciated :-)

To do this first create a split function. This is the one I use but if you search the internet (or even SO) for "SQL Server Split Function" you will find a number of alternatives if you don't like this:
ALTER FUNCTION [dbo].[Split](#StringToSplit NVARCHAR(MAX), #Delimiter NCHAR(1))
RETURNS TABLE
AS
RETURN
(
SELECT ID = ROW_NUMBER() OVER(ORDER BY n.Number),
Position = Number,
Value = SUBSTRING(#StringToSplit, Number, CHARINDEX(#Delimiter, #StringToSplit + #Delimiter, Number) - Number)
FROM ( SELECT TOP (LEN(#StringToSplit) + 1) Number = ROW_NUMBER() OVER(ORDER BY a.object_id)
FROM sys.all_objects a
CROSS JOIN sys.all_objects b
) n
WHERE SUBSTRING(#Delimiter + #StringToSplit + #Delimiter, n.Number, 1) = #Delimiter
);
Then you can split your field, So running:
SELECT t.Object, t.Field, s.Value
FROM T
CROSS APPLY dbo.Split(t.[Values], ';') AS s
Will turn this:
Object Field Values
------------------------------------
1 1 A;A;A;B;A;A
into:
Object Field Values
------------------------------------
1 1 A
1 1 A
1 1 A
1 1 B
1 1 A
1 1 A
Then you can apply the DISTINCT Operator:
SELECT DISTINCT t.Object, t.Field, s.Value
FROM T
CROSS APPLY dbo.Split(t.[Values], ';') AS s;
To give:
Object Field Values
------------------------------------
1 1 A
1 1 B
Then you can concatenate your rows back into a single column giving a final query:
SELECT t.Object, t.Field, [Values] = STUFF(x.value('.', 'NVARCHAR(MAX)'), 1, 1, '')
FROM T
CROSS APPLY
( SELECT DISTINCT ';' + s.Value
FROM dbo.Split(t.[Values], ';') AS s
FOR XML PATH(''), TYPE
) AS s (x)
SQL Fiddle appears to be down, but once you have the Split function created the below is a full working example:
CREATE TABLE #T (Object INT, Field INT, [Values] VARCHAR(MAX));
INSERT #T
VALUES
(1, 1, 'A;A;A;B;A;A'),
(2, 1, 'A;B;C;C'),
(2, 2, 'X'),
(3, 1, 'X;Y;Z'),
(3, 2, 'V;V;V;V;V;V;V;V;V;V;V');
SELECT t.Object, t.Field, [Values] = STUFF(x.value('.', 'NVARCHAR(MAX)'), 1, 1, '')
FROM #T AS T
CROSS APPLY
( SELECT DISTINCT ';' + s.Value
FROM dbo.Split(t.[Values], ';') AS s
FOR XML PATH(''), TYPE
) AS s (x);
EDIT
Based on your comment that you can't create tables or modify the DDL, I thought I would account for the situation where you can't create a function either. You can expand the above split function out into your query, so you don't actually need to create a function:
CREATE TABLE #T (Object INT, Field INT, [Values] VARCHAR(MAX));
INSERT #T
VALUES
(1, 1, 'A;A;A;B;A;A'),
(2, 1, 'A;B;C;C'),
(2, 2, 'X'),
(3, 1, 'X;Y;Z'),
(3, 2, 'V;V;V;V;V;V;V;V;V;V;V');
SELECT t.Object,
t.Field,
[Values] = STUFF(x.value('.', 'NVARCHAR(MAX)'), 1, 1, '')
FROM #T AS T
CROSS APPLY
( SELECT DISTINCT ';' + SUBSTRING(t.[Values], Number, CHARINDEX(';', t.[Values] + ';', Number) - Number)
FROM ( SELECT TOP (LEN(t.[Values]) + 1) Number = ROW_NUMBER() OVER(ORDER BY a.object_id)
FROM sys.all_objects a
CROSS JOIN sys.all_objects b
) n
WHERE SUBSTRING(';' + t.[Values] + ';', n.Number, 1) = ';'
FOR XML PATH(''), TYPE
) AS s (x);

Here is a standalone solution:
DECLARE #t table(Object int, Field int, [Values] varchar(max))
INSERT #t values
(1, 1, 'A;A;A;B;A;A'),
(2, 1, 'A;B;C;C'),
(3, 1, 'X'),
(4, 1, 'X;Y;Z'),
(5, 1, 'V;V;V;V;V;V;V;V;V;V;V')
SELECT t.Object, t.Field, x.[NewValues]
FROM #t t
CROSS APPLY
(
SELECT STUFF((
SELECT distinct ';'+t.c.value('.', 'VARCHAR(2000)') value
FROM (
SELECT x = CAST('<t>' +
REPLACE([Values], ';', '</t><t>') + '</t>' AS XML)
) a
CROSS APPLY x.nodes('/t') t(c)
for xml path(''), type
).value('.', 'varchar(max)'), 1, 1, '') [NewValues]
) x
Result:
Object Field NewValues
1 1 A;B
2 1 A;B;C
3 1 X
4 1 X;Y;Z
5 1 V
According to #GarethD's comment this may perform slow.
Test data:
create table #t(Object int identity(1,1), Field int, [Values] varchar(max))
INSERT #t values
(1, 'A;A;A;B;A;A'),(1, 'A;B;C;C'), (1, 'X'), (1, 'X;Y;Z'),(1, 'V;V;V;V;V;V;V;V;V;V;V')
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
insert #t select field, [values] from #t union all select field, [values] from #t union all select field, [values] from #t
Performance testing my script:
SELECT t.Object, t.Field, x.[NewValues]
FROM #t t
CROSS APPLY
(
SELECT STUFF((
SELECT distinct ';'+t.c.value('.', 'VARCHAR(2000)') value
FROM (
SELECT x = CAST('<t>' +
REPLACE([Values], ';', '</t><t>') + '</t>' AS XML)
) a
CROSS APPLY x.nodes('/t') t(c)
for xml path(''), type
).value('.', 'varchar(max)'), 1, 1, '') [NewValues]
) x
Result less than 1 sec.
Performance testing Garath script
(had to edit testdata to get all rows. Identical rows were considered as 1 row):
WITH CTE AS
( SELECT DISTINCT t.Object, t.Field, s.Value
FROM #T AS T
CROSS APPLY
( SELECT ID = ROW_NUMBER() OVER(ORDER BY n.Number),
Position = Number,
Value = SUBSTRING(t.[Values], Number, CHARINDEX(';', t.[Values] + ';', Number) - Number)
FROM ( SELECT TOP (LEN(t.[Values]) + 1) Number = ROW_NUMBER() OVER(ORDER BY a.object_id)
FROM sys.all_objects a
CROSS JOIN sys.all_objects b
) n
WHERE SUBSTRING(';' + t.[Values] + ';', n.Number, 1) = ';'
) AS s
)
SELECT Object,
Field,
[Values] = STUFF((SELECT ';' + Value
FROM CTE AS T2
WHERE T2.Object = T.Object
AND T2.Field = T.Field
FOR XML PATH(''), TYPE
).value('.', 'VARCHAR(MAX)'), 1, 1, '')
FROM CTE AS T
GROUP BY Object, Field;
Result 6 seconds
If any row has null in values this script will also crash.

Just as a Scalar Value Function alternative without the CTE...
ALTER FUNCTION [SplitRemoveDupes] (
#String VARCHAR(MAX)
,#Delimiter VARCHAR(5)
)
RETURNS VARCHAR(MAX)
AS
BEGIN
DECLARE #SplitLength INT
DECLARE #DedupedValues VARCHAR(MAX)
DECLARE #SplittedValues TABLE
(
OccurenceId SMALLINT IDENTITY(1,1),
SplitValue VARCHAR(200)
)
WHILE LEN(#String) > 0
BEGIN
SELECT #SplitLength = (
CASE CHARINDEX(#Delimiter, #String)
WHEN 0
THEN LEN(#String)
ELSE CHARINDEX(#Delimiter, #String) - 1
END
)
INSERT INTO #SplittedValues
SELECT SUBSTRING(#String, 1, #SplitLength)
SELECT #String = (
CASE (LEN(#String) - #SplitLength)
WHEN 0
THEN ''
ELSE RIGHT(#String, LEN(#String) - #SplitLength - 1) END)
END
SET #DedupedValues=(SELECT DISTINCT STUFF((
SELECT DISTINCT (#Delimiter + SplitValue)
FROM #SplittedValues s
ORDER BY (#Delimiter + SplitValue)
FOR XML PATH('')
), 1, 1, '') AS a
FROM #SplittedValues ss)
RETURN #DedupedValues
END
Call it inline...
SELECT Object, Field, [dbo].[SplitRemoveDupes](Values,';') From Table

Related

Semicolon seperated value to other column in sql server

i have a table with a column have value seperated by semi colon.
the concern is value in the column are not fixed. it starts from 1 and end upto 80 semicolon sepaeration.
i am trying to put each individual value to seperate column
SQL SERVER 2008 code
DECLARE #Table TABLE(
Val VARCHAR(50)
)
INSERT INTO #Table (Val) SELECT '2Xcalcium; kidney' union all SELECT '3XMagnessium; liver' union all SELECT '2-ECG;3XSODIUM;DIALYSIS'
SELECT *,
CAST(LEFT(Val,CHARINDEX(';',Val)-1) AS VARCHAR) FirstValue,
CAST(RIGHT(Val,LEN(Val) - CHARINDEX(';',Val)) AS VARCHAR) SecondValue
FROM #Table
I tried the above code but this is limited to 2 semicolon only. please share your expertise.
Try it like this:
DECLARE #Table TABLE(
Val VARCHAR(50)
)
INSERT INTO #Table (Val) SELECT '2Xcalcium; kidney' union all SELECT '3XMagnessium; liver' union all SELECT '2-ECG;3XSODIUM;DIALYSIS';
;WITH Splitted AS
(
SELECT *
,CAST('<x>' + REPLACE(Val,';','</x><x>') + '</x>' AS XML) ValuesAsXML
FROM #Table
)
SELECT *
,ValuesAsXML.value('x[1]','varchar(max)') AS FirstCol
,ValuesAsXML.value('x[2]','varchar(max)') AS SecondCol
,ValuesAsXML.value('x[3]','varchar(max)') AS ThirdCol
,ValuesAsXML.value('x[4]','varchar(max)') AS FourthCol
,ValuesAsXML.value('x[5]','varchar(max)') AS FifthCol
FROM Splitted
The result
Val FirstCol SecondCol ThirdCol FourthCol FifthCol
2Xcalcium; kidney 2Xcalcium kidney NULL NULL NULL
3XMagnessium; liver 3XMagnessium liver NULL NULL NULL
2-ECG;3XSODIUM;DIALYSIS 2-ECG 3XSODIUM DIALYSIS NULL NULL
Most of the link provided extract the element into rows.
If you prefer to use your existing logic and extract the individual element into separate column, you can use multiple cascaded CROSS APPLY.
SELECT t.Val,
v1.V as V1,
v2.V as V2,
v3.V as V3
FROM #Table t
cross apply
(
select V = LEFT(t.Val, CHARINDEX(';', t.Val + ';') - 1),
Val = STUFF(t.Val, 1, CHARINDEX(';', t.Val + ';'), '')
) v1
cross apply
(
select V = LEFT(v1.Val, CHARINDEX(';', v1.Val + ';') - 1),
Val = STUFF(v1.Val, 1, CHARINDEX(';', v1.Val + ';'), '')
) v2
cross apply
(
select V = LEFT(v2.Val, CHARINDEX(';', v2.Val + ';') - 1),
Val = STUFF(v2.Val, 1, CHARINDEX(';', v2.Val + ';'), '')
) v3
From your question ,it seems that you have data in below format..This can be done easily with numbers table..
declare #string varchar(max)
set #string='s,t,a,c,k'
select substring(','+#string+',',n+1,charindex(',',','+#string+',',n+1)-n-1)
from
numbers
where n<=len(#string)
and substring(','+#string+',',n,1)=','
Output:
s
t
a
c
k
Few more Gems:
https://dba.stackexchange.com/questions/11506/why-are-numbers-tables-invaluable
http://sqlperformance.com/2012/07/t-sql-queries/split-strings

how to write SQL query for this result?

I have so many long database so I used seq_no in commas separate using more than one sequence store in single column but now I want all sequence in a single column so I am confused how to create this sql result for this.
For example:
TABLE STRUCTURE
SR_NO IS INT ,
SEQ_NO IS VARCHAR(MAX)
SR_NO SEQ_NO
---------------------------------
1 1839073,
2 1850097,1850098,
3 1850099,1850100,1850110
I need to get this result:
SEQ_NO
--------------
1839073
1850097
1850098
1850099
1850100
1850110
Thanks!
declare #t table(Id int,seq varchar(100))
insert into #t (Id,seq) values (1,'1839073,'),(2,'1839073,1850098,'),(3,'1850099,1850100,1850110 ')
;With Cte as (
SELECT A.Id,
Split.a.value('.', 'VARCHAR(100)') AS Seq
FROM
(
SELECT Id,
CAST ('<M>' + REPLACE(seq, ',', '</M><M>') + '</M>' AS XML) AS Data
FROM #t
) AS A CROSS APPLY Data.nodes ('/M') AS Split(a) )
Select ID,Seq from Cte Where Seq > ''
Try splitting it with XML
SELECT SR_NO, t.c.value('.', 'VARCHAR(2000)') COL1
FROM (
SELECT SR_NO, x = CAST('<t>' +
REPLACE(SEQ_NO, ',', '</t><t>') + '</t>' AS XML)
FROM
(values(1,'1839073'),(2, '1850097,1850098'),
(3, '1850099,1850100,1850110')) y(SR_NO, SEQ_NO)
) a
CROSS APPLY x.nodes('/t') t(c)
Result:
SR_NO COL1
1 1839073
2 1850097
2 1850098
3 1850099
3 1850100
3 1850110
You can replace this with your table:
(values (1,'1839073'),(2, '1850097,1850098'),
(3, '1850099,1850100,1850110')) y(SR_NO, SEQ_NO)
This should do it: (Replace YourTableName with your table name)
;WITH CTE(NEW_SEQ_NO, SEQ_NO) as (
SELECT LEFT(SEQ_NO, CHARINDEX(',',SEQ_NO + ',') -1),
STUFF(SEQ_NO, 1, CHARINDEX(',',SEQ_NO + ','), '')
FROM YourTableName
WHERE SEQ_NO <> '' AND SEQ_NO IS NOT NULL
UNION all
SELECT LEFT(SEQ_NO, CHARINDEX(',',SEQ_NO + ',') -1),
STUFF(SEQ_NO, 1, CHARINDEX(',',SEQ_NO + ','), '')
FROM CTE
WHERE SEQ_NO <> '' AND SEQ_NO IS NOT NULL
)
SELECT NEW_SEQ_NO from CTE ORDER BY NEW_SEQ_NO
You can check this topic for more information:
Turning a Comma Separated string into individual rows
I have written the following query after referring Turning a Comma Separated string into individual rows
It will work for you
create table STRUCTURE(SR_NO int, SEQ_NO varchar(max))
insert STRUCTURE select 1, '1839073,'
insert STRUCTURE select 2, '1850097,1850098,'
insert STRUCTURE select 3, '1850099,1850100,1850110'
;with tmp(SR_NO, DataItem, SEQ_NO) as (
select SR_NO, LEFT(SEQ_NO, CHARINDEX(',',SEQ_NO+',')-1),
STUFF(SEQ_NO, 1, CHARINDEX(',',SEQ_NO+','), '')
from STRUCTURE
union all
select SR_NO, LEFT(SEQ_NO, CHARINDEX(',',SEQ_NO+',')-1),
STUFF(SEQ_NO, 1, CHARINDEX(',',SEQ_NO+','), '')
from tmp
where SEQ_NO > ''
)
Select DataItem as SEQ_NO from tmp order by SEQ_NO;

Split string and divide value

I got a table Test with columns A and B.
The A column contains different values in one entry, e.g. abc;def;ghi, all separated by ;. And the B column contains numeric values, but only one.
What I want is to seperate the values from column A into multiple rows.
So:
abc;def;ghi;jkl
-->
abc
def
ghi
jkl
In column B is one value, e.g. 20 and I want that value split to the amount of rows,
So the final result shut be:
abc 5
def 5
ghi 5
jkl 5
The issue is that the amount of values in column A must be variable.
First you need to create this function
REATE FUNCTION Split
(
#delimited nvarchar(max),
#delimiter nvarchar(100)
) RETURNS #t TABLE
(
-- Id column can be commented out, not required for sql splitting string
id int identity(1,1), -- I use this column for numbering splitted parts
val nvarchar(max),
origVal nvarchar(max)
)
AS
BEGIN
declare #xml xml
set #xml = N'<root><r>' + replace(#delimited,#delimiter,'</r><r>') + '</r></root>'
insert into #t(val,origval)
select
r.value('.','varchar(max)') as item, #delimited
from #xml.nodes('//root/r') as records(r)
RETURN
END
GO
then this query might help
Select x.Val, test.B / (len(test.A) - len(replace(Test.A, ';', '')) + 1) from Test
inner join dbo.Split(Test.A,';') x on x.origVal = Test.A
this part len(test.A) - len(replace(Test.A, ';', '')) will count the number of ; in string
Be aware this query might have some malfunctioning if there will be duplicate strings in A column, in this situation you need to pass the unique value (for example ID) to split function and return it in the result table, then join it by this value (ie. x.origVal = Test.A => x.origID = Test.ID)
You can use some tricks with CTE, STUFF and windows functions
DECLARE #t TABLE
(
ID INT ,
A NVARCHAR(MAX) ,
B INT
)
INSERT INTO #t
VALUES ( 1, 'a;b;c;d;', 20 ),
( 2, 'x;y;z;', 40 );
WITH cte ( ID, B, D, A )
AS ( SELECT ID ,
B ,
LEFT(A, CHARINDEX(';', A + ';') - 1) ,
STUFF(A, 1, CHARINDEX(';', A + ';'), '')
FROM #t
UNION ALL
SELECT ID ,
B ,
LEFT(A, CHARINDEX(';', A + ';') - 1) ,
STUFF(A, 1, CHARINDEX(';', A + ';'), '')
FROM cte
WHERE A > ''
)
SELECT ID ,
B ,
D,
CAST(B AS DECIMAL) / COUNT(*) OVER (PARTITION BY ID) AS Portion
FROM cte
Output:
ID B D Portion
1 20 a 5.00000000000
1 20 b 5.00000000000
1 20 c 5.00000000000
1 20 d 5.00000000000
2 40 x 13.33333333333
2 40 y 13.33333333333
2 40 z 13.33333333333
this an example how you can achieve required result
DECLARE #table AS TABLE
(
ColumnA VARCHAR(100) ,
ColumnB FLOAT
)
INSERT INTO #table
( ColumnA, ColumnB )
VALUES ( 'abc;def;ghi;jkl', 20 ),
( 'asf;ret;gsd;jas', 30 ),
( 'dfa;aef;gffhi;fjfkl', 40 );
WITH C AS ( SELECT n = 1
UNION ALL
SELECT n + 1
FROM C
WHERE n <= 100
),
SetForSplit
AS ( SELECT T.ColumnA ,
T.ColumnB ,
C.n ,
( CASE WHEN LEFT(SUBSTRING(T.ColumnA, n, 100), 1) = ';'
THEN SUBSTRING(T.ColumnA, n + 1, 100) + ';'
ELSE SUBSTRING(T.ColumnA, n, 100) + ';'
END ) AS SomeText
FROM #table AS T
JOIN C ON C.n <= LEN(T.ColumnA)
WHERE SUBSTRING(T.ColumnA, n, 1) = ';'
OR n = 1
)
SELECT ROW_NUMBER() OVER ( PARTITION BY columnA ORDER BY LEFT(SomeText,
CHARINDEX(';',
SomeText) - 1) ) AS RowN,
LEFT(SomeText, CHARINDEX(';', SomeText) - 1) AS ColA ,
ColumnB / COUNT(*) OVER ( PARTITION BY ColumnA ) AS ColB
FROM SetForSplit
ORDER BY ColumnA
This is full working exmaple:
DECLARE #DataSource TABLE
(
[A] VARCHAR(MAX)
,[B] INT
);
INSERT INTO #DataSource ([A], [B])
VALUES ('a;b;c;d', 20 ),
('x;y;z', 40 );
SELECT T.c.value('.', 'VARCHAR(100)')
,[B] / COUNT([B]) OVER (PARTITION BY [B])
FROM #DataSource
CROSS APPLY
(
SELECT CONVERT(XML, '<t>' + REPLACE([A], ';', '</t><t>') + '</t>')
) DS([Bxml])
CROSS APPLY [Bxml].nodes('/t') AS T(c)
and of couse you can ROUND the devision as you like.

Finding unique characters from a table field for all rows

How to find the number of distinct character used in the field having multiple rows.
For example, if there are two rows having data like abcd and eaafg* then distinct character used are abcdefg*.
Try this one -
INSERT INTO #temp (txt)
VALUES ('abcd3'), ('abcdefg*')
SELECT disword = (
SELECT DISTINCT dt.ch
FROM (
SELECT ch = SUBSTRING(t.mtxt, n.number + 1, 1)
FROM [master].dbo.spt_values n
CROSS JOIN (
SELECT mtxt = (
SELECT txt
FROM #temp
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
) t
WHERE [type] = N'p'
AND number <= LEN(mtxt) - 1
) dt
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
Example (edited):
SET NOCOUNT ON;
DECLARE #temp TABLE (txt VARCHAR(8000))
INSERT INTO #temp (txt)
VALUES ('abcd'), ('abcdefg*'), (REPLICATE('-', 8000)), (REPLICATE('+', 8000))
DECLARE #t TABLE (i BIGINT)
DECLARE
#i BIGINT = 1
, #l BIGINT = (
SELECT SUM(LEN(txt))
FROM #temp
)
WHILE (#i <= #l) BEGIN
INSERT INTO #t (i)
VALUES (#i), (#i+1), (#i+2), (#i+3), (#i+4), (#i+5), (#i+6), (#i+7), (#i+8), (#i+9)
SELECT #i += 10
END
SELECT disword = (
SELECT DISTINCT dt.ch
FROM (
SELECT ch = SUBSTRING(t.mtxt, n.i, 1)
FROM #t n
CROSS JOIN (
SELECT mtxt = (
SELECT txt
FROM #temp
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
) t
) dt
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)'
)
Have a look a t this solution -
SELECT
dt.ch
, cnt = COUNT(1)
FROM (
SELECT ch = SUBSTRING(t.mtxt, n.i, 1)
FROM #t n
CROSS JOIN (
SELECT mtxt = (
SELECT txt
FROM #temp
FOR XML PATH(N''), TYPE, ROOT).value(N'root[1]', N'NVARCHAR(MAX)')
) t
) dt
WHERE dt.ch != ''
GROUP BY dt.ch
ORDER BY cnt DESC
Here are questions that may refer to what you are asking:
How do I get distinct characters of string column in mssql?
and
SQL: how to get all the distinct characters in a column, across all rows
With tallys:
DECLARE #t TABLE (s NVARCHAR(MAX))
INSERT INTO #t
VALUES ('abcd'), ('abcdefg*')
;WITH tally AS(SELECT ROW_NUMBER() OVER(ORDER BY (SELECT 1)) i
FROM (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) t1(n)
CROSS JOIN (VALUES(0),(0),(0),(0),(0),(0),(0),(0),(0),(0)) t2(n))
SELECT
( SELECT DISTINCT sb
FROM tally
CROSS APPLY ( SELECT SUBSTRING(s, i, 1) sb FROM #t ) ca
WHERE sb <> ''
FOR XML PATH(N'') , TYPE , ROOT).value(N'root[1]', N'NVARCHAR(MAX)')

Duplicates without using While or Cursor in T-SQL

ID Name
1 A
1 B
1 C
2 X
2 Y
3 P
3 Q
3 R
These are the columns in a table. I want to get output like
ID Company
1 A,B,C
2 X, Y
3 P,Q,R
Restriction is that I cannot use WHILE or CURSOR. Please write a query for the same.
This query should do it - uses FOR XML PATH which is new in SQL Server 2005 - hope you are on 2005 or higher, you didn't clearly specify.....
SELECT
ID,
STUFF(CAST((SELECT ','+Name FROM dbo.YourTable t2
WHERE t2.ID = dbo.YourTable.ID
FOR XML PATH(''), TYPE) AS VARCHAR(MAX)), 1, 1, '') AS 'Company'
FROM
dbo.YourTable
GROUP BY
ID
Here's a solution using the CROSS APPLY method:
select id, sub.names
from (
select distinct id from YourTable
) a
cross apply (
select name + ', ' as [text()]
from YourTable b
where b.id = a.id
for xml path('')
) sub(names)
For 2005 version:
CREATE TABLE dbo.TEST([Type] INTEGER, [Name] NVARCHAR(100), [Qty] INTEGER)
GO
INSERT dbo.TEST VALUES(1, N'a', 5)
INSERT dbo.TEST VALUES(1, N'b', 6)
INSERT dbo.TEST VALUES(2, N'c', 44)
INSERT dbo.TEST VALUES(3, N'd', 1)
GO
select [Type],
[Description] = replace((select [Name] + ':' + cast([Qty] as varchar) as 'data()'
from TEST where [Type] = t.[Type] for xml path('')), ' ', ',')
from dbo.TEST t
group by [Type]
go
drop table dbo.TEST
You can group on the ID to get the unique values, then get the comma separated string for each using a for xml query:
select
a.ID,
substring((
select ', ' + Name
from Test1
where Test1.ID = a.ID
for xml path('')
), 3, 1000) as Company
from
TheTable a
group by
a.ID