I have a table that holds date
ID Dates
1 2014-01-20
2 2014-01-21
...
100 2014-05-20
101 2014-06-01 --Missing a few dates
102 2014-06-02
...
201 2014-10-31
202 2014-12-05 --Missing a few dates
...
349 2015-04-29
350 2015-04-30
I want to find the available date range by year between a from and to date, for example
#StartDate: 2014/04/06
#EndDate: 2015/04/05
The expected result is
Year StartRange EndRange
2014 2014-04-06 2014-05-20
2014 2014-06-01 2014-10-31
2014 2014-12-05 2014-12-31
2015 2015-01-01 2015-04-05
I am trying to find the available date ranges from the Dates column. Lets take the first row in the expected result 2014-04-06 to 2014-05-20 which says I have continuous dates from the 6th April to 20th May then there is a break (I do not have dates from 2014-05-21 to 2014-05-30)
The dates 2014-04-06 (in the first row) and 2015-04-05 (in the last row) are included in the expected result as it is the start and end date (parameter to the query) and I have those dates in the [Dates] column of my table
Thanks
This is an "Islands and Gaps" type of problem. Here is one way to do it:
;
WITH
cteDays As (SELECT *, DATEDIFF(dd,0,Dates) As DayNo From YourTable)
, cteDifs As
(
SELECT *,
DayNo-(ROW_NUMBER() OVER(ORDER BY Dates, ID)) As Dif
FROM cteDays
)
SELECT
Year(Dates) As [Year],
MIN(Dates) As StartRange,
MAX(Dates) As EndRange
FROM cteDifs
GROUP BY Year(Dates), Dif
ORDER BY [Year], StartRange
Related
I have a table of EMPLOYEES that contains information about the DATE and WORKTIME per that day. Fx:
ID | DATE | WORKTIME |
----------------------------------------
1 | 1-Sep-2014 | 4 |
2 | 2-Sep-2014 | 6 |
1 | 3-Sep-2014 | 5.5 |
1 | 4-Sep-2014 | 7 |
2 | 4-Sep-2014 | 4 |
1 | 9-Sep-2014 | 8 |
and so on.
Question: How can I create a query that would allow me to calculate amount of time worked per week (HOURS_PERWEEK). I understand that I need a summation of WORKTIME together with grouping considering both, ID and week, but so far my trials as well as googling didnt yield any results. Any ideas on this? Thank you in advance!
edit:
Got a solution of
select id, sum (worktime), trunc(date, 'IW') week
from employees
group by id, TRUNC(date, 'IW');
But will need somehow to connect that particular output with DATE table by updating a newly created column such as WEEKLY_TIME. Any hints on that?
You can find the start of the ISO week, which will always be a Monday, using TRUNC("DATE", 'IW').
So if, in the query, you GROUP BY the id and the start of the week TRUNC("DATE", 'IW') then you can SELECT the id and aggregate to find the SUM the WORKTIME column for each id.
Since this appears to be a homework question and you haven't attempted a query, I'll leave it at this to point you in the correct direction and you can complete the query.
Update
Now I need to create another column (lets call it WEEKLY_TIME) and populate it with values from the current output, so that Sep 1,3,4 (for ID=1) would all contain value 16.5, specifying that on that day (that is within the certain week) that person worked 16.5 in total. And for ID=2 it would then be a value of 10 for both Sep 2 and 4.
For this, if I understand correctly, you appear to not want to use aggregation functions and want to use the analytic version of the function:
select id,
"DATE",
trunc("DATE", 'IW') week,
worktime,
sum (worktime) OVER (PARTITION BY id, trunc("DATE", 'IW'))
AS weekly_time
from employees;
Which, for the sample data:
CREATE TABLE employees (ID, "DATE", WORKTIME) AS
SELECT 1, DATE '2014-09-01', 4 FROM DUAL UNION ALL
SELECT 2, DATE '2014-09-02', 6 FROM DUAL UNION ALL
SELECT 1, DATE '2014-09-03', 5.5 FROM DUAL UNION ALL
SELECT 1, DATE '2014-09-04', 7 FROM DUAL UNION ALL
SELECT 2, DATE '2014-09-04', 4 FROM DUAL UNION ALL
SELECT 1, DATE '2014-09-09', 8 FROM DUAL;
Outputs:
ID
DATE
WEEK
WORKTIME
WEEKLY_TIME
1
2014-09-01 00:00:00
2014-09-01 00:00:00
4
16.5
1
2014-09-03 00:00:00
2014-09-01 00:00:00
5.5
16.5
1
2014-09-04 00:00:00
2014-09-01 00:00:00
7
16.5
1
2014-09-09 00:00:00
2014-09-08 00:00:00
8
8
2
2014-09-04 00:00:00
2014-09-01 00:00:00
4
10
2
2014-09-02 00:00:00
2014-09-01 00:00:00
6
10
db<>fiddle here
edit: answer submitted without noticing "Oracle" tag. Otherwise, question answered here: Oracle SQL - Sum and group data by week
Select employee_Id,
DATEPART(week, workday) as [Week],
sum (worktime) as [Weekly Hours]
from WORK
group by employee_id, DATEPART(week, workday)
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=238b229156a383fa3c466b6c3c2dee1e
I'm trying to display a result set based on a min date value and today's date but can't seem to make it work. It's essentially a date sensitive price list.
Example Data
ID Title Value ExpireDate
1 Fred 10 2019-03-01
2 Barney 15 2019-03-01
3 Fred2 20 2019-06-01
4 Barney2 25 2019-06-01
5 Fred3 30 2019-07-01
6 Barney3 55 2019-07-01
Required Results:
Display records based on minimum date > GetDate()
3 Fred2 20 2019-06-01
4 Barney2 25 2019-06-01
Any assistance would be great - thank you.
Use where clause to filter all future rows and row_number() to find the first row per group:
SELECT *
FROM (
SELECT *, ROW_NUMBER() OVER (PARTITION BY Title ORDER BY ExpireDate) AS rn
FROM t
WHERE ExpireDate >= CAST(CURRENT_TIMESTAMP AS DATE)
) AS x
WHERE rn = 1
Based on your revised question, you can simply do this:
SELECT TOP 1 WITH TIES *
FROM t
WHERE ExpireDate >= CAST(CURRENT_TIMESTAMP AS DATE)
ORDER BY ExpireDate
I'm trying to identify a consecutive sequence in dates, per person, as well as sum amount for that sequence. My records table looks like this:
person start_date end_date amount
1 2015-09-10 2015-09-11 500
1 2015-09-11 2015-09-12 100
1 2015-09-13 2015-09-14 200
1 2015-10-05 2015-10-07 2000
2 2015-10-05 2015-10-05 300
2 2015-10-06 2015-10-06 1000
3 2015-04-23 2015-04-23 900
The resulting query should be this:
person sequence_start_date sequence_end_date amount
1 2015-09-10 2015-09-14 800
1 2015-10-05 2015-10-07 2000
2 2015-10-05 2015-10-06 1400
3 2015-04-23 2015-04-23 900
Below, I can use LAG and LEAD to identify the sequence start_date and end_date, but I don't have a way to aggregate the amount. I'm assuming the answer will involve some sort of ROW_NUMBER() window function that will partition by sequence, I just can't figure out how to make the sequence identifiable to the function.
SELECT
person
,COALESCE(sequence_start_date, LAG(sequence_start_date, 1) OVER (ORDER BY person, start_date)) AS "sequence_start_date"
,COALESCE(sequence_end_date, LEAD(sequence_end_date, 1) OVER (ORDER BY person, start_date)) AS "sequence_end_date"
FROM
(
SELECT
person
,start_date
,end_date
,CASE WHEN LAG(end_date, 1) OVER (PARTITION BY person ORDER BY start_date) + interval '1 day' = start_date
THEN NULL
ELSE start_date
END AS "sequence_start_date"
,CASE WHEN LEAD(start_date, 1) OVER (PARTITION BY person ORDER BY start_date) - interval '1 day' = end_date
THEN NULL
ELSE end_date
END AS "sequence_end_date"
,amount
FROM records
) sq
Even your updated (sub)query still isn't quite right for the data you've presented, which is inconsistent about whether the start date of the second and subsequent rows in a sequence should be equal to their previous rows' end date or one day later. The query can be updated pretty easily to accommodate both, if that's needed.
In any case, you cannot use COALESCE as a window function. Aggregate functions may be used as window functions by providing an OVER clause, but not ordinary functions. There are nevertheless ways to apply window function to this task. Here's a way to identify the sequences in your data (as presented):
SELECT
person
,MAX(sequence_start_date)
OVER (
PARTITION BY person
ORDER BY start_date
ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW)
AS "sequence_start_date"
,MIN(sequence_end_date)
OVER (
PARTITION BY person
ORDER BY start_date
ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING)
AS "sequence_end_date"
,amount
FROM
(
SELECT
person
,start_date
,end_date
,CASE WHEN LAG(end_date, 1) OVER (PARTITION BY person ORDER BY start_date) + interval '1 day' >= start_date
THEN date '0001-01-01'
ELSE start_date
END AS "sequence_start_date"
,CASE WHEN LEAD(start_date, 1) OVER (PARTITION BY person ORDER BY start_date) - interval '1 day' <= end_date
THEN NULL
ELSE end_date
END AS "sequence_end_date"
,amount
FROM records
order by person, start_date
) sq_part
ORDER BY person, sequence_start_date
That relies on MAX() and MIN() instead of COALESCE(), and it applies window framing to get the appropriate scope for each of those within each partition. Results:
person sequence_start_date sequence_end_date amount
1 September, 10 2015 00:00:00 September, 12 2015 00:00:00 500
1 September, 10 2015 00:00:00 September, 12 2015 00:00:00 100
1 October, 05 2015 00:00:00 October, 07 2015 00:00:00 2000
2 October, 05 2015 00:00:00 October, 06 2015 00:00:00 300
2 October, 05 2015 00:00:00 October, 06 2015 00:00:00 1000
3 April, 23 2015 00:00:00 April, 23 2015 00:00:00 900
Do note that that does not require an exact match of end date with subsequent start date; all rows for each person that abut or overlap will be assigned to the same sequence. If (person, start_date) cannot be relied upon to be unique, however, then you probably need to order the partitions by end date as well.
And now you have a way to identify the sequences: they are characterized by the triple person, sequence_start_date, sequence_end_date. (Or actually, you need only the person and one of those dates for identification purposes, but read on.) You can wrap the above query as an inline view of an outer aggregate query to produce your desired result:
SELECT
person,
sequence_start_date,
sequence_end_date,
SUM(amount) AS "amount"
FROM ( <above query> ) sq
GROUP BY person, sequence_start_date, sequence_end_date
Of course you need both dates as grouping columns if you're going to select them.
Why not:
select a1.person, a1.sequence_start_date, a1.sequence_end_date,
sum(rx.amount)
as amount
from (EXISTING_QUERY) a1
left join records rx
on rx.person = a1.person
and rx.start_date >= a1.start_date
and rx.end_date <= a1.end_date
group by a1.person, a1.sequence_start_date, a1.sequence_end_date
I have to modify a big pricelist table so that there is only one valid price for every article.
Sometimes the sales employees insert new prices and forgot to change the old infinite validTo dates.
So I have to write a sql-query to change all validTo dates to the next validFrom date minus one day, when the validTo date has infinite validity (9999-12-31).
But I have no idea how can i reach this with only SQL (Oracle 12).
anr price validFrom validTo
1 447.1 2015-06-01 9999-12-31 <
1 447.2 2015-06-16 2015-06-16
1 447.3 2015-06-17 2015-06-17
1 447.4 2015-06-22 2015-06-22
1 447.5 2015-07-06 9999-12-31 <
1 395.0 2015-07-20 2015-07-20
1 447.6 2015-08-03 9999-12-31 <
1 447.7 2015-08-17 9999-12-31 <
1 447.8 2015-08-24 9999-12-31 <
1 395.0 2015-09-07 2015-09-07
1 450.9 2015-11-15 9999-12-31 < no change because it is the last entry
after updating the the table, the result should look like
anr price validFrom validTo
1 447.1 2015-06-01 2015-06-15 <
1 447.2 2015-06-16 2015-06-16
1 447.3 2015-06-17 2015-06-17
1 447.4 2015-06-22 2015-06-22
1 447.5 2015-07-06 2015-07-19 <
1 395.0 2015-07-20 2015-07-20
1 447.6 2015-08-03 2015-08-16 <
1 447.7 2015-08-17 2015-08-23 <
1 447.8 2015-08-24 2015-09-06 <
1 395.0 2015-09-07 2015-09-07
1 450.9 2015-11-15 9999-12-31 <
In order to update an end date you can simply select the minimum of all higher start dates.
update mytable upd
set enddate = coalesce(
(
select min(startdate) - 1
from mytable later
where later.startdate > upd.startdate
and later.anr = upd.anr -- same product
), date'9999-12-31') -- coalesce for the case there is no later record
where enddate = date'9999-12-31';
I have taken anr to be the product id. If it isn't then change the statement accordingly.
Oracle provides an analytic function LEAD that references the current-plus-n-th record given a sort criterion. This function may serve the purpose of selecting the proper date value in an update statement as follows ( let test_prices be the table name, ppk its PK ):
update test_prices p
set p.validTo = (
select ps.vtn
from (
select lead ( p1.validFrom, 1 ) over ( order by p1.validFrom ) - 1 vtn
, ppk
from test_prices p1
) ps
where ps.ppk = p.ppk
)
where to_char(p.validTo, 'YYYY') = '9999'
and p.validFrom != ( select max(validFrom) from test_prices )
;
UPDATE VALID_DATES v
SET validTo = (
SELECT validTo
FROM (
SELECT anr,
validFrom,
COALESCE(
LEAD( validFrom - 1, 1 ) OVER ( PARTITION BY anr ORDER BY validFrom ),
validTo
) AS validTo
FROM valid_dates
) u
WHERE v.anr = u.anr
AND v.validFrom = u.validFrom
)
WHERE validTo = DATE '9999-12-31';
There are two possibilities:
1. Explicit time spans
price validFrom validTo
90.99 2016-01-01 9999-12-31
80.00 2016-01-16 2016-01-17
The first price would be valid both before January 16 and after January 17, whereas the second price was only valid on two days in January.
It would then be a very bad idea to change the first validTo.
2. Implicit time spans
price validFrom
90.99 2016-01-01
80.00 2016-01-16
90.99 2016-01-18
This data represents the same as in the explicit time spans example. The first price is valid before January 16, then the second price is valid until January 17, and afterwards the next price (which equals the first price again) is valid. Here you don't need an EndDate, because it's implicit. Of course the first price is only valid until January 15, because from January 16 there is another price valid (record #2).
So: Either remove the EndDate column completely or let it untouched. Don't simply update it, as you have intended. If you updated your records to next date minus one, you would actually hold data redundantly, which might lead to problems later.
I have this in my table
TempTable
Id Date
1 1-15-2010
2 2-14-2010
3 3-14-2010
4 4-15-2010
i would like to change every record so that they have all same day, that is the 15th
like this
TempTable
Id Date
1 1-15-2010
2 2-15-2010 <--change to 15
3 3-15-2010 <--change to 15
4 4-15-2010
what if i like on the 30th?
the records should be
TempTable
Id Date
1 1-30-2010
2 2-28-2010 <--change to 28 because feb has 28 days only
3 3-30-2010 <--change to 30
4 4-30-2010
thanks
You can play some fun tricks with DATEADD/DATEDIFF:
create table T (
ID int not null,
DT date not null
)
insert into T (ID,DT)
select 1,'20100115' union all
select 2,'20100214' union all
select 3,'20100314' union all
select 4,'20100415'
SELECT ID,DATEADD(month,DATEDIFF(month,'20100101',DT),'20100115')
from T
SELECT ID,DATEADD(month,DATEDIFF(month,'20100101',DT),'20100130')
from T
Results:
ID
----------- -----------------------
1 2010-01-15 00:00:00.000
2 2010-02-15 00:00:00.000
3 2010-03-15 00:00:00.000
4 2010-04-15 00:00:00.000
ID
----------- -----------------------
1 2010-01-30 00:00:00.000
2 2010-02-28 00:00:00.000
3 2010-03-30 00:00:00.000
4 2010-04-30 00:00:00.000
Basically, in the DATEADD/DATEDIFF, you specify the same component to both (i.e. month). Then, the second date constant (i.e. '20100130') specifies the "offset" you wish to apply from the first date (i.e. '20100101'), which will "overwrite" the portion of the date your not keeping. My usual example is when wishing to remove the time portion from a datetime value:
SELECT DATEADD(day,DATEDIFF(day,'20010101',<date column>),'20100101')
You can also try something like
UPDATE TempTable
SET [Date] = DATEADD(dd,15-day([Date]), DATEDIFF(dd,0,[Date]))
We have a function that calculates the first day of a month, so I just addepted it to calculate the 15 instead...