I have this in my table
TempTable
Id Date
1 1-15-2010
2 2-14-2010
3 3-14-2010
4 4-15-2010
i would like to change every record so that they have all same day, that is the 15th
like this
TempTable
Id Date
1 1-15-2010
2 2-15-2010 <--change to 15
3 3-15-2010 <--change to 15
4 4-15-2010
what if i like on the 30th?
the records should be
TempTable
Id Date
1 1-30-2010
2 2-28-2010 <--change to 28 because feb has 28 days only
3 3-30-2010 <--change to 30
4 4-30-2010
thanks
You can play some fun tricks with DATEADD/DATEDIFF:
create table T (
ID int not null,
DT date not null
)
insert into T (ID,DT)
select 1,'20100115' union all
select 2,'20100214' union all
select 3,'20100314' union all
select 4,'20100415'
SELECT ID,DATEADD(month,DATEDIFF(month,'20100101',DT),'20100115')
from T
SELECT ID,DATEADD(month,DATEDIFF(month,'20100101',DT),'20100130')
from T
Results:
ID
----------- -----------------------
1 2010-01-15 00:00:00.000
2 2010-02-15 00:00:00.000
3 2010-03-15 00:00:00.000
4 2010-04-15 00:00:00.000
ID
----------- -----------------------
1 2010-01-30 00:00:00.000
2 2010-02-28 00:00:00.000
3 2010-03-30 00:00:00.000
4 2010-04-30 00:00:00.000
Basically, in the DATEADD/DATEDIFF, you specify the same component to both (i.e. month). Then, the second date constant (i.e. '20100130') specifies the "offset" you wish to apply from the first date (i.e. '20100101'), which will "overwrite" the portion of the date your not keeping. My usual example is when wishing to remove the time portion from a datetime value:
SELECT DATEADD(day,DATEDIFF(day,'20010101',<date column>),'20100101')
You can also try something like
UPDATE TempTable
SET [Date] = DATEADD(dd,15-day([Date]), DATEDIFF(dd,0,[Date]))
We have a function that calculates the first day of a month, so I just addepted it to calculate the 15 instead...
Related
I have a table of EMPLOYEES that contains information about the DATE and WORKTIME per that day. Fx:
ID | DATE | WORKTIME |
----------------------------------------
1 | 1-Sep-2014 | 4 |
2 | 2-Sep-2014 | 6 |
1 | 3-Sep-2014 | 5.5 |
1 | 4-Sep-2014 | 7 |
2 | 4-Sep-2014 | 4 |
1 | 9-Sep-2014 | 8 |
and so on.
Question: How can I create a query that would allow me to calculate amount of time worked per week (HOURS_PERWEEK). I understand that I need a summation of WORKTIME together with grouping considering both, ID and week, but so far my trials as well as googling didnt yield any results. Any ideas on this? Thank you in advance!
edit:
Got a solution of
select id, sum (worktime), trunc(date, 'IW') week
from employees
group by id, TRUNC(date, 'IW');
But will need somehow to connect that particular output with DATE table by updating a newly created column such as WEEKLY_TIME. Any hints on that?
You can find the start of the ISO week, which will always be a Monday, using TRUNC("DATE", 'IW').
So if, in the query, you GROUP BY the id and the start of the week TRUNC("DATE", 'IW') then you can SELECT the id and aggregate to find the SUM the WORKTIME column for each id.
Since this appears to be a homework question and you haven't attempted a query, I'll leave it at this to point you in the correct direction and you can complete the query.
Update
Now I need to create another column (lets call it WEEKLY_TIME) and populate it with values from the current output, so that Sep 1,3,4 (for ID=1) would all contain value 16.5, specifying that on that day (that is within the certain week) that person worked 16.5 in total. And for ID=2 it would then be a value of 10 for both Sep 2 and 4.
For this, if I understand correctly, you appear to not want to use aggregation functions and want to use the analytic version of the function:
select id,
"DATE",
trunc("DATE", 'IW') week,
worktime,
sum (worktime) OVER (PARTITION BY id, trunc("DATE", 'IW'))
AS weekly_time
from employees;
Which, for the sample data:
CREATE TABLE employees (ID, "DATE", WORKTIME) AS
SELECT 1, DATE '2014-09-01', 4 FROM DUAL UNION ALL
SELECT 2, DATE '2014-09-02', 6 FROM DUAL UNION ALL
SELECT 1, DATE '2014-09-03', 5.5 FROM DUAL UNION ALL
SELECT 1, DATE '2014-09-04', 7 FROM DUAL UNION ALL
SELECT 2, DATE '2014-09-04', 4 FROM DUAL UNION ALL
SELECT 1, DATE '2014-09-09', 8 FROM DUAL;
Outputs:
ID
DATE
WEEK
WORKTIME
WEEKLY_TIME
1
2014-09-01 00:00:00
2014-09-01 00:00:00
4
16.5
1
2014-09-03 00:00:00
2014-09-01 00:00:00
5.5
16.5
1
2014-09-04 00:00:00
2014-09-01 00:00:00
7
16.5
1
2014-09-09 00:00:00
2014-09-08 00:00:00
8
8
2
2014-09-04 00:00:00
2014-09-01 00:00:00
4
10
2
2014-09-02 00:00:00
2014-09-01 00:00:00
6
10
db<>fiddle here
edit: answer submitted without noticing "Oracle" tag. Otherwise, question answered here: Oracle SQL - Sum and group data by week
Select employee_Id,
DATEPART(week, workday) as [Week],
sum (worktime) as [Weekly Hours]
from WORK
group by employee_id, DATEPART(week, workday)
https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=238b229156a383fa3c466b6c3c2dee1e
I have a table like the below:
ID, MachineID Customer TimeStamp Counter type
1 A ABC 2017-10-25 3:08PM 1952 1
2 A ABC 2017-10-25 3:00PM 1940 1
3 A ABC 2017-10-25 12:05PM 1920 1
4 A ABC 2017-10-25 9:00AM 1900 1
5 B BCD 2017-10-25 3:11PM 1452 1
6 B BCD 2017-10-25 3:10PM 1440 1
7 B BCD 2017-10-25 12:15PM 1420 1
8 B BCD 2017-10-25 9:30AM 1400 1
9 A ABC 2017-10-23 3:08PM 1900 1
10 A ABC 2017-10-23 3:00PM 1840 1
11 A ABC 2017-10-23 12:05PM 1820 1
12 A ABC 2017-10-23 9:00AM 1800 1
13 B BCD 2017-10-23 3:11PM 1399 1
14 B BCD 2017-10-23 3:10PM 1340 1
15 B BCD 2017-10-23 12:15PM 1320 1
16 B BCD 2017-10-23 9:30AM 1300 1
The counter value increases whenever there is a click. I am trying to calculate number of clicks for each day by taking maximum counter value at the end of day and subtract the previous day maximum counter value and so on.
How do I do this in SQL server. Have to repeat this for each customer and Machine
Try this. I am using LAG function in order to achieve this. You can use where clause to filter out specific date you want :
Create table #counter(ID int, timeStamp datetime, Counter int, type int)
insert into #counter values
(1, '20171024 3:08PM' ,1952, 1),
(1, '20171025 3:00PM' ,1964, 1)
Select iq.*, (iq."counter" - iq.yesterday_counter) as today_count
from
(select id,
cast("timestamp" as date) as today_date,
"counter",
LAG("counter") over (order by cast("timestamp" as date)) yesterday_counter
from #counter
) iq
output:
id today_date counter yesterday_counter today_count
----------- ---------- ----------- ----------------- -----------
1 2017-10-24 1952 NULL NULL
1 2017-10-25 1964 1952 12
A SQL query to get the max counter for each day is:
SELECT CAST(timeStamp as date) AS [dateval]
,MAX(Counter) AS [maxCounter]
FROM YOURDATASET
GROUP BY CAST(timeStamp as date)
This is converting the datetime to date- cutting out the time, then taking the max(Counter).
One method to get the difference is to save the result in a temp datastructure, then query it to get the difference.
The question is whether your previous date is exactly the previous day, or if you're skipping days between counts, or taking the weekend off, etc. In that case you have to select the greatest previous date to the date being examined.
ex.
DECLARE #temp TABLE (dateval date, maxCounter int)
INSERT INTO #temp(dateval, maxCounter)
SELECT CAST(timeStamp as date) AS [dateval]
,MAX(Counter)
FROM YOURDATASET
GROUP BY CAST(timeStamp as date)
SELECT T.dateval
,T.dateval
-
(SELECT maxCounter
FROM #temp T2
WHERE T2.dateVal = (SELECT MAX(dateVal)
FROM #temp T3
WHERE T3.dateVal < T1.dateVal
)
) AS [Difference]
FROM #temp T
ORDER BY T.dateval
I have a created_date (timestamp) on 1 of my tables, that also has the duration column of a project, and I need to join with another table that only has first_day_of_month column that has the first day of each month, and other relevant information.
Table 1
id project_id created_date duration
1 12345 01/01/2015 10
2 12345 20/10/2015 11
3 12345 10/04/2016 13
4 12345 10/08/2016 15
Table 2
project_id month_start_date
12345 01/01/2015
12345 01/02/2015
12345 01/03/2015
12345 01/04/2015
...
12345 01/08/2016
Expected result
project_id month_start_date duration
12345 01/01/2015 10
12345 01/02/2015 10
...
12345 01/10/2015 11
12345 01/11/2015 11
...
12345 01/04/2016 13
12345 01/05/2016 13
12345 01/06/2016 13
...
12345 01/08/2016 15
I want to be able to present the data listed in my second table historically. So, basically I want the query to return the same duration related to the month_start_date, so that values will repeat until another dateadd(month,datediff(month,0,created_date),0) = first_day_of_month is met... and so forth.
This is my query:
select table2.project_name,
table2.month_start_date,
table1.duration,
table1.created_date
from table1 left outer join table2
on table1.project_id=table2.project_id
where dateadd(month,datediff(month,0,table1.created_date),0)<=table2.month_start_date
group by table2.project_name,table2.month_start_date,table1.duration,table1.created_date
order by table2.month_start_date asc
but I get repeated records on this:
Result I'm getting
project_id month_start_date duration
12345 01/01/2015 10
12345 01/02/2015 10
...
12345 01/10/2015 10
12345 01/10/2015 11
...
12345 01/04/2016 10
12345 01/04/2016 11
12345 01/04/2016 13
...
12345 01/08/2016 10
12345 01/08/2016 11
12345 01/08/2016 13
12345 01/08/2016 15
Can anyone help?
Thank you!
I'd use CROSS/OUTER APPLY operator.
Here is one possible variant. For each row in your calendar table Table2 (for each month) the inner correlated subquery inside the CROSS APPLY finds one row from Table1. It will be the row with the same project_id and the first row with created_date before the month_start_date plus 1 month.
SELECT
Table2.project_id
,Table2.month_start_date
,Durations.duration
FROM
Table2
CROSS APPLY
(
SELECT TOP(1) Table1.duration
FROM Table1
WHERE
Table1.project_id = Table2.project_id
AND Table1.created_date < DATEADD(month, 1, Table2.month_start_date)
ORDER BY Table1.created_date DESC
) AS Durations
;
Make sure that Table1 has index on (project_id, created_date) include (duration). Otherwise, performance would be poor.
This post is really similar to my question:
SQL Server : how many days each item was in each state
but I dont have the column Revision to see wich is the previous state, and also I want to get the full time of a status, I b
....
I'm want to get how long one item has been in one status in general, my table look like this:
ID DATE STATUS
3D56B7B1-FCB3-4897-BAEB-004796E0DC8D 2016-04-05 11:30:00.000 1
3D56B7B1-FCB3-4897-BAEB-004796E0DC8D 2016-04-08 11:30:00.000 13
274C5DA9-9C38-4A54-A697-009933BB7B7F 2016-04-29 08:00:00.000 5
274C5DA9-9C38-4A54-A697-009933BB7B7F 2016-05-04 08:00:00.000 4
A70A66DC-9D9E-49BE-93CF-00F9E3E06CE2 2016-04-14 07:50:00.000 1
A70A66DC-9D9E-49BE-93CF-00F9E3E06CE2 2016-04-21 14:00:00.000 2
A70A66DC-9D9E-49BE-93CF-00F9E3E06CE2 2016-04-23 12:15:00.000 3
A70A66DC-9D9E-49BE-93CF-00F9E3E06CE2 2016-04-23 16:15:00.000 1
BF122AE1-CB39-4967-8F37-012DC55E92A7 2016-04-05 10:30:00.000 1
BF122AE1-CB39-4967-8F37-012DC55E92A7 2016-04-20 17:00:00.000 5
I want to get this
Column 1 : ID Column 2 : Status Column 3 : Time with the status
Column 3 : Time with the status
= NextDate - PreviosDate + 1
if is the last Status, is count as 1
if is more than one Status on the same day, I get the Last one (u can say that only mather the last Status of the day)
by ID, Status must be unique
I should look like this:
ID STATUS TIME
3D56B7B1-FCB3-4897-BAEB-004796E0DC8D 1 3
3D56B7B1-FCB3-4897-BAEB-004796E0DC8D 13 1
274C5DA9-9C38-4A54-A697-009933BB7B7F 5 5
274C5DA9-9C38-4A54-A697-009933BB7B7F 4 1
A70A66DC-9D9E-49BE-93CF-00F9E3E06CE2 1 8
A70A66DC-9D9E-49BE-93CF-00F9E3E06CE2 2 2
BF122AE1-CB39-4967-8F37-012DC55E92A7 1 15
BF122AE1-CB39-4967-8F37-012DC55E92A 5 1
Thanks to #ConradFrix comments, this is how works ..
WITH CTE
AS
(
SELECT
ID,
STATUS,
DATE,
LEAD(DATE, 1) over (partition by ID order by DATE) LEAD,
ISNULL(DATEDIFF(DAYOFYEAR, DATE,
LEAD(DATE, 1) over (partition by ID order by DATE)), 1) DIF_BY_LEAD
FROM TABLE_NAME
)
SELECT ID, STATUS, SUM(DIF_BY_LEAD) AS TIME_STATUS
FROM CTE GROUP BY ID, STATUS
ORDER BY ID, STATUS
Here is the table structure:
tblApplicants:
applicantID (index) | ApplyingForYear (nvarchar)
------------------------------------------------------
1 2013/14
11 2013/14
13 2013/14
12 2013/14
15 2013/14
21 2012/13
tblApplicantSchools_shadow:
id (index) | applicantID | updated (datetime) | statusID (int) | schoolID (int)
-----------------------------------------------------------------------------------------------------
1 11 2012-09-24 00:00:00.000 3 2
1 13 2012-10-24 00:00:00.000 4 2
2 15 2012-11-24 00:00:00.000 3 4
3 13 2012-03-24 00:00:00.000 4 3
4 12 2012-09-24 00:00:00.000 4 1
5 21 2012-11-03 00:00:00.000 5 2
6 11 2012-09-04 00:00:00.000 4 4
What I need to do is:
get all applicants, that have an ApplyingForYear of '2013/14' in tblApplicants
have a statusID of 4
I only want to count them once - even if they appear twice or more in tblApplicantschools_show
group the number of distinct applicants (as per the above) - by the updated date column (grouped by week)
So based on the sample data above, there should be 3 rows that come out, (because ApplicantID 13 appears twice and I only want him once).
This is how the result should look:
Datesubmitted TotalAppsPerWeek
-------------------------------------------------------
2012-10-24 00:00:00.000 1
2012-09-24 00:00:00.000 1
2012-09-04 00:00:00.000 1
This is what I have so far - but it results in 4 rows, not 3 :(
select
DATEADD(ww,(DATEDIFF(ww,0,[tblApplicantSchools_shadow].updated)),0) AS Datesubmitted,
count(DISTINCT [tblApplicantSchools_shadow].applicantID) as TotalAppsPerWeek
FROM tblApplicants
INNER JOIN tblApplicantSchools_shadow
ON tblApplicantS.ApplicantID = tblApplicantSchools_shadow.applicantID
WHERE
ApplyingForYear = '2013/14'
AND [tblApplicantSchools_shadow].statusID = 4
GROUP BY
DATEADD(ww, (DATEDIFF(ww, 0, [tblApplicantSchools_shadow].updated)), 0)
And here is a Fiddle: http://sqlfiddle.com/#!3/3aa61/42
From your title, I'm assuming the one row you want from each applicant is the one with the smallest id. You can select one row per applicant ID with the ROW_NUMBER() function:
;with latestApplication AS
(
SELECT DATEADD(ww,(DATEDIFF(ww,0,[tblApplicantSchools_shadow].updated)),0)
AS Datesubmitted,
[tblApplicantSchools_shadow].applicantID,
ROW_NUMBER() OVER (PARTITION BY [tblApplicantSchools_shadow].applicantID
ORDER BY [tblApplicantSchools_shadow].id)
AS rn
FROM tblApplicants
INNER JOIN tblApplicantSchools_shadow
ON tblApplicantS.ApplicantID = tblApplicantSchools_shadow.applicantID
WHERE ApplyingForYear = '2013/14'
AND [tblApplicantSchools_shadow].statusID = 4
)
select Datesubmitted, COUNT(1) AS TotalAppsPerWeek
FROM latestApplication
WHERE rn = 1
group by Datesubmitted
order by Datesubmitted DESC
http://sqlfiddle.com/#!3/3aa61/57