I have 3 columns
Order_ID
Activation_Date
Order_Received_Date
So, if i distinctly count all the order_IDs on Order_Received_Date, I will get "Number of Orders" Similarly, if i distinctly count all the order_IDs on Activation_Date, I will get "Number of Activations"
What i want is two columns called "# Orders" and "# Activations"
Appreciate any inputs, thanks
I use union all for this type of calculation. The following is standard SQL so it should work in any database:
select thedate, sum(r) as numorders, sum(a) as numactivations
from (select activation_date as thedate, 1 as a, 0 as r from table t
union all
select order_received_date, 0, 1 from table t
) t
group by thedate
order by thedate;
If I understand you correctly, I guess the below query might help you solve this issue:
SELECT
OrderID,
ActivationDate,
OrderReceivedDate,
COUNT(OrderID) OVER (),
COUNT(ActivationDate) OVER ()
FROM
(
SELECT 1 AS OrderID, '2014-01-01' AS ActivationDate, '2013-12-15' AS OrderReceivedDate UNION
SELECT 2 AS OrderID, NULL AS ActivationDate, '2013-12-19' AS OrderReceivedDate UNION
SELECT 3 AS OrderID, '2014-03-01' AS ActivationDate, '2013-12-17' AS OrderReceivedDate UNION
SELECT 4 AS OrderID, '2014-04-01' AS ActivationDate, '2013-12-03' AS OrderReceivedDate
) t
I wish this helps you...
Related
I posted a question similar to this, and got an answer, but the answer isn't configurable - my fault I should have been more clear, so I'll try again.
I have a table where TABLENAME has the following information - OrderDate, OrderNumber, CustomerID, ProductSKU, ProductName exist. This table has lines for invoices. So an order will have a data line for every item in the order.
I want to know, which customers have ordered the same item, more than once, where the order is within 90 of any other order of that same product by that customer, after a specific date. Same product in the same order number do not count. The catch is that I want "more than once" to be configurable, so if I need to see 3 or more, or 4 or more I can adjust AND I want to see the counts. Here's the query I have so far, which I think gives me the items and the counts - but not the 90 day thing:
EDITED: I don't think the former version gave me the right counts
SELECT customerid, productsku, productname, count(distinct ordernumber) FROM tablename
WHERE orderdate >'2017-11-01'
GROUP BY customerid, productsku, productname
HAVING COUNT(distinct ordernumber) > 2
Try doing this. it'll go back 90 days
declare #date date = '2017-11-01'
SELECT customerid, productsku, productname, count(distinct ordernumber) FROM tablename
WHERE orderdate >= dateadd(DD,-90,#date) and orderdate <= #date
GROUP BY customerid, productsku, productname
HAVING COUNT(distinct ordernumber) > 1
yes that is what I was doing in the first query. so this might be a really crappy way of doing it but without seeing any data it was kind of tough. this query shows gives you the order dates as well. hope it helps
WITH DupsWithin90Days (customerid,productsku,productname,orderdate,num)
as
(
select customerid,productsku,productname,orderdate ,count(*) num from (
SELECT X.customerid, X.productsku, X.productname,X.ORDERDATE,ROW_NUMBER() OVER (partition by x.customerid,x.orderdate order by x.orderdate) rownum
FROM
(
SELECT T1.customerid, T1.productsku, T1.productname,T1.ORDERDATE
FROM TABLENAME1 T1
) X
JOIN
(
SELECT T2.customerid, T2.productsku, T2.productname,T2.ORDERDATE
FROM
TABLENAME1 T2
) Y
ON X.customerid = Y.customerid AND X.orderdate >= dateadd(DD,-90,Y.orderdate)
) dup
where rownum > 1
group by customerid,productsku,productname,orderdate
)
select customerid,productsku,productname,orderdate
from DupsWithin90Days
order by customerid ,orderdate desc
I have written queries to get the total qty of each month in 2016. Then I added another row called Total to sum up the total qty in 2016. But the ordermonth in the result turned out to be in a mess.
So, the question is is there any way to put the ordermonth in the right order? Both ASC and DESC are OK. Thanks in advance.
The query I've written:
WITH CTE AS(
SELECT CONVERT(CHAR(10), MONTH(orderdate)) AS ordermonth, SUM(qty) AS qty
FROM dbo.orders
WHERE YEAR(orderdate) = 2016
GROUP BY MONTH(orderdate)
)
SELECT * FROM CTE
UNION
SELECT 'Total', SUM(qty)
FROM dbo.orders
WHERE YEAR(orderdate) = 2016;
Current result:
ordermonth qty
1 4134
10 6454
11 9780
12 4000
2 5548
3 6970
4 3543
5 3309
6 4251
7 4997
8 6134
9 6926
Total 66046
First, you can do what you want without UNION. Something like this:
select coalesce(cast(month(orderdate) as varchar(255)), 'Total') as mon . . .
from . . .
group by grouping sets (month(orderdate), ())
order by month(orderdate)
No CTE, that's the entire query.
You can put into subquery and try like below:
select * from (
--your query including cte and union
) a
order by case when a.[Month] = 'Total' then 9999 else convert(int,a.[Month]) end
You can sort it by yyyymm, that is the best way even when you'll have more than one year, i.e.
order by orderyear * 100 + ordermonth
Or you can just add '0' for getting the right order like this:
order by right('0' + cast(ordermonth as varchar(2)), 2)
I found an easy way to solve this issue, that is, replacing UNION with UNION ALL.
WITH CTE AS(
SELECT CONVERT(CHAR(10), MONTH(orderdate)) AS ordermonth, SUM(qty) AS qty
FROM dbo.orders
WHERE YEAR(orderdate) = 2016
GROUP BY MONTH(orderdate)
)
SELECT * FROM CTE
UNION ALL
SELECT 'Total', SUM(qty)
FROM dbo.orders
WHERE YEAR(orderdate) = 2016;
Is there a safe way to not have to group by a field when using an aggregate in another field? Here is my example
SELECT
C.CustomerName
,D.INDUSTRY_CODE
,CASE WHEN D.INDUSTRY_CODE IN ('003','004','005','006','007','008','009','010','017','029')
THEN 'PM'
WHEN UPPER(CustomerName) = 'ULINE INC'
THEN 'ULINE'
ELSE 'DR'
END AS BU
,ISNULL((SELECT SUM(GrossAmount)
where CONVERT(date,convert(char(8),InvoiceDateID )) between DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) - 1, 0) and DATEADD(year, -1, GETDATE())),0) [PREVIOUS YEAR GROSS]
FROM factMargins A
LEFT OUTER JOIN dimDate B ON A.InvoiceDateID = B.DateId
LEFT OUTER JOIN dimCustomer C ON A.CustomerID = C.CustomerId
LEFT OUTER JOIN CRCDATA.DBO.CU10 D ON D.CUST_NUMB = C.CustomerNumber
GROUP BY
C.CustomerName,D.INDUSTRY_CODE
,A.InvoiceDateID
order by CustomerName
before grouping I was only getting 984 rows but after grouping by the A.InvoiceDateId field I am getting over 11k rows. The rows blow up since there are multiple invoices per customer. Min and Max wont work since then it will pull data incorrectly. Would it be best to let my application (crystal) get rid of the extra lines? Usually I like to have my base data be as close as possible to how the report will layout if possible.
Try moving the reference to InvoiceDateID to within an aggregate function, rather than within a selected subquery's WHERE clause.
In Oracle, here's an example:
with TheData as (
select 'A' customerID, 25 AMOUNT , trunc(sysdate) THEDATE from dual union
select 'B' customerID, 35 AMOUNT , trunc(sysdate-1) THEDATE from dual union
select 'A' customerID, 45 AMOUNT , trunc(sysdate-2) THEDATE from dual union
select 'A' customerID, 11000 AMOUNT , trunc(sysdate-3) THEDATE from dual union
select 'B' customerID, 12000 AMOUNT , trunc(sysdate-4) THEDATE from dual union
select 'A' customerID, 15000 AMOUNT , trunc(sysdate-5) THEDATE from dual)
select
CustomerID,
sum(amount) as "AllRevenue"
sum(case when thedate<sysdate-3 then amount else 0 end) as "OlderRevenue",
from thedata
group by customerID;
Output:
CustomerID | AllRevenue | OlderRevenue
A | 26070 | 26000
B | 12035 | 12000
This says:
For each customerID
I want the sum of all amounts
and I want the sum of amounts earlier than 3 days ago
I am trying to solve a problem using SQL query and need some expert's advice.
I have below transaction table.
-- UserID, ProductId, TransactionDate
-- 1 , 2 , 2014-01-01
-- 1 , 3 , 2014-01-05
-- 2 , 2 , 2014-01-02
-- 2 , 3 , 2014-05-07
.
.
.
What I am trying to achieve is to find all user who purchased more than one product WITHIN 30 DAYS .
My query so far is like
select UserID, COUNT(distinct ProductID)
from tableA
GROUP BY UserID HAVING COUNT(distinct ProductID) > 1
I am not sure where to apply "WITH IN 30 DAYS" logic in the query .
The outcome should be :
1, 2
2, 1
Thanks in advance for your help.
Edit: Within 30 Days
SQL Fiddle
SELECT
a.UserID,
COUNT(DISTINCT ProductID)
FROM TableA a
INNER JOIN (
SELECT UserID, TransactionDate = MAX(TransactionDate)
FROM TableA
GROUP BY UserID
) AS t
ON t.UserID = a.UserID
AND a.TransactionDate >= DATEADD(DAY, -30, t.TransactionDate)
AND a.TransactionDate <= t.TransactionDate
GROUP BY a.UserID
You can use GROUP BY YEAR(TransactionDate), MONTH(TransactionDate)
SELECT
UserID,
COUNT(DISTINCT ProductID)
FROM TableA
GROUP BY
UserID, YEAR(TransactionDate), MONTH(TransactionDate)
HAVING
COUNT(DISTINCT ProductID) > 1
Just add a where clause.
SELECT UserID, COUNT(DISTINCT ProductID) cnt
FROM tableA
WHERE TransactionDate >= CAST(DATEADD(DAY,-30,GETDATE()) AS DATE)
GROUP BY UserID
HAVING COUNT(DISTINCT ProductID) > 1
This works because the where clause is performed BEFORE the Group By and Having. So first it filters out all transactions over 30 days old and then returns only people who bought two distinct products.
Query Processing Order:
http://blog.sqlauthority.com/2009/04/06/sql-server-logical-query-processing-phases-order-of-statement-execution/
I have a select statement and want to return all values only if at least one of them has a date with 60 days of difference from today.
The problem is that i have an outer apply which returns the column i want to compare to, and they come from different tables (one belongs to cash items, and the other to card items).
Considering I have the following:
OUTER APPLY (
SELECT COUNT(*) AS quantity, MIN(date) AS item_date
FROM dbo.get_cash_items(loans.id_cash) AS cash_item
HAVING loans.id_product_type = 1 --Cash
UNION
SELECT COUNT(*) AS quantity, MIN(date) AS item_date
FROM dbo.get_card_items(loans.id_card) AS card_item
HAVING loans.id_product_type = 2 --Card
) AS items
I want to return all the rows only when DATEDIFF(DAY, MIN(items.item_date), GETDATE()) >= 60, but I want them all even if only one matches this condition.
What would be the best approach to do this?
EDIT
To make it clearer, I'll explain the use case:
I need to show the items of every loan, only if the client is late for more than 60 days of the due date on any of it
I am also not sure, what do you expect, but how about that:
WITH items
AS (SELECT Count(*) AS quantity,
Min(date) AS item_date
FROM dbo.Get_cash_items(loans.id_cash) AS cash_item
HAVING loans.id_product_type = 1
UNION
SELECT Count(*) AS quantity,
Min(date) AS item_date
FROM dbo.Get_card_items(loans.id_card) AS card_item
HAVING loans.id_product_type = 2)
SELECT a.*
FROM items AS a,
(SELECT TOP 1 *
FROM items AS b
WHERE Datediff(day, b.item_date, Getdate()) >= 60) AS c
It's a sort of CROSS JOIN, where table C will have one or zero rows depending on that if the condition is met - it will than join to every row in other table.
Have you tried something like this?
SELECT a.quantity, a.item_date
FROM
(SELECT COUNT(*) AS quantity, MIN(date) AS item_date
FROM dbo.get_cash_items(loans.id_cash) AS cash_item
HAVING loans.id_product_type = 1
UNION
SELECT COUNT(*) AS quantity, MIN(date) AS item_date
FROM dbo.get_card_items(loans.id_card) AS card_item
HAVING loans.id_product_type = 2) a
WHERE DATEDIFF(day, a.item_date, GETDATE()) >= 60
Typically I do this using a CTE to select the key for the records I want to select and then join on that. Below is an attempt at an example:
with LateClients as
(
SELECT LoadId FROM Payment Where /*payment date later than 60 days*/
)
SELECT p.LoanId,
p.UserId
FROM Payment as p
INNER JOIN LateClients as LC
ON p.LoanId = lc.LoanId
OrderBy p.LoanId, p.UserId
I know it's a bit different from the code you posted, but this is a simplified example that should explain the concept. Good luck!