I want to combine 2 table into 1 table as example below
Table1
100
200
300
Table2
A B C
D E F
G H I
OutputTable
100 A B C
100 D E F
100 G H I
200 A B C
200 D E F
200 G H I
300 A B C
300 D E F
300 G H I
Thank you.
If you already have the new table then:
insert into new_table (field1,field2,field3,field4)
select
a.field1
,b.field2
,b.field3
,b.field4
from a
cross join b
If you do not have the table:
select
a.field1
,b.field2
,b.field3
,b.field4
into new_table
from a
cross join b
Use Cross Join which will create a Cartesian product of two tables
SELECT a.*,b.*
FROM table1 a
CROSS JOIN table2 b
or Use Cross Apply
SELECT a.*,b.*
FROM table1 a
CROSS Apply table2 b
Related
I have the table 'Table01' which contains the keys that should be mandatory:
id
1
2
3
4
And I also have the table 'Table02' which contains the records to be filtered:
id
customer
weight
1
a
100
2
a
300
3
a
200
4
a
45
1
b
20
2
b
100
3
b
17
1
c
80
4
c
90
2
d
30
3
d
30
4
d
50
So I want to identify which are the mandatory id's that the table 'Table02' does not have, and in turn identify which is the 'customer' of each id's that the table 'Table02' does not have.
The resulting table should look like this:
customer
id
b
4
c
2
c
3
d
1
What I have tried so far is a 'rigth join'.
proc sql;
create table table03 as
select
b.id
from table02 a
right join table01 b
on a.id=b.id
where a.id is null;
run;
But that query is not identifying all the id's that should be mandatory.
I hope someone can help me, thank you very much.
here is one way:
select cl.customerid , a.id
from
Table1 a
cross join
( select customerid
from table2
group by customerid
) cl
where not exists ( select 1 from table2 b
where b.customerid = cl.customerid
and b.id = a.id
)
You can use an EXCEPT between two sub-selects. The first creates a matrix of all possibilities, and the except table is a selection of the extant customers.
Example:
data ids;
do id = 1 to 4; output; end;
run;
data have;
input id customer $ weight;
datalines;
1 a 100
2 a 300
3 a 200
4 a 45
1 b 20
2 b 100
3 b 17
1 c 80
4 c 90
2 d 30
3 d 30
4 d 50
run;
proc sql;
create table want(label='Customers missing some ids') as
select matrix.*
from
(select distinct have.customer, ids.id from have, ids) as matrix
except
(select customer, id from have)
;
quit;
If you are doing it in SQL server. Something like #eshirvana above posted, but also you can use with cte:
;with cte as
(
SELECT t1.id, t2.Customer
FROM Table01 t1
cross join (select distinct customer from Table02)
)
SELECT a.customer, a.id FROM cte a
LEFT JOIN Table02 b
ON a.id=b.id AND a.customer=b.customer
where b.id is null
If I have 3 tables A, B and C I understand how to use left join to join them like this:
SELECT *
FROM A LEFT JOIN
B
ON A.col = B.col LEFT JOIN
C
on B.col = C.col
So A to B then B to C
How would I do this:
SELECT *
FROM A LEFT JOIN
B
ON A.col = B.col LEFT JOIN
C
on A.col = C.col
So A to B and then A to C
Would really appreciate any help
I don't see anything wrong with what you're trying to accomplish.
A simple example is at: http://sqlfiddle.com/#!9/6dbbe2/2
There are three tables (A, B, and C):
Table A
id name
1 Alice
2 Bob
3 Carol
4 Don
5 Edith
Table B
id id_A pet
1 5 Tex
2 4 Socks
3 2 Rex
4 1 Percy
5 1 Quinlan
Table C
id id_A hobby
1 1 acting
2 2 boxing
3 4 dancing
4 5 eating
Tables B and C relate to Table A through the id_A foreign key.
A query like you have:
SELECT * FROM A LEFT JOIN B
ON A.id = B.id_a LEFT JOIN C
ON A.id = C.id_a;
works just fine.
Suppose I have a table A as a 'dictionary':
A type code name
1 a x
1 b y
2 a z
2 b t
I want to translate the following table B in to names:
B c1 c2
a a
a b
b b
Where B.c1 is the code of A.type=1 and B.c2 is the code of A.type=2.
The expected result is
x z
x t
y t
If there is only one column in B needs to be translated, it is easy.
SELECT A.name
FROM A, B
WHERE A.type = 1
AND B.c1=A.code
Using joins;
select a1.type,b.c1,a2.type,b.c2 from b
left outer join a as a1 on b.c1= a1.code and a1.type=1
left outer join a as a2 on b.c2= a2.code and a2.type=2
SQL Server 2008
Table A looks like:
A_ID v1 v2 v3
---------------------------
1 d e f
1 a b c
1 a b d
2 d a b
2 e f g
3 d e f
3 e f g
3 d a b
and Table B is similar:
B_ID v1 v2 v3
---------------------------
Q a b c
Q b a c
Q a b d
R d e f
R a b c
R d e f
P e f g
P d a b
What I need back from these two tables are the (A_ID, B_ID) pairs, if any, where each row of Table B where B_ID = any one value has one matching row in Table A where A_ID = any one value. In other words, I need to the complete matching set in A for each full set of triples in B--no super sets or subsets. The value of B_ID and A_ID is immaterial.
I thought partitioning would be the way to go, since I already have the column that naturally partitions A and B, and I also thought I could pre-select which paritions where JOINed by ensuring only partitions with matching numbers of rows would be attempting. I haven't been able to do either--partitioning both tables was easy, but I see no way to tell the join to only act on the partitions.
In this example, (2,P) would be returned because all rows in Set P match all rows in Set 2. Result (1, R) would NOT be returned because all rows of Set R are not matched by all rows of Set 1, etc.
Using symetric difference:
SELECT DISTINCT a1.A_ID, b1.B_ID
FROM A a1,B b1
WHERE NOT EXISTS (
(SELECT v1,v2,v3
FROM A WHERE A.A_ID = a1.A_ID
EXCEPT
SELECT v1,v2,v3
FROM B WHERE B.B_ID = b1.B_ID
)
UNION ALL
(
SELECT v1,v2,v3
FROM B WHERE B.B_ID = b1.B_ID
EXCEPT
SELECT v1,v2,v3
FROM A WHERE A.A_ID = a1.A_ID)
);
LiveDemo
I have 2 tables joined with inner join with a column
Now rows would have
A B
C D
E G
P Q
Z F
This row I need to compare with Master Relation Table
Column1 Column2
A B
D C
E F
So based on the above condition I need to show records in a report
A B Do Not Show
C D Do Not Show
E G Show
P Q Show
Z F Show
You can do it this using LEFT JOIN:
SELECT T1.Col1,T1.Col2,
CASE WHEN T2.Column1 IS NOT NULL THEN 'Do Not Show' ELSE 'Show' END AS Result
FROM Table1 T1 LEFT JOIN
Table2 T2 ON
(T1.Col1=T2.Column1 AND T1.Col2=T2.Column2)
OR (T1.Col1=T2.Column2 AND T1.Col2=T2.Column1)
Result:
Col1 Col2 Result
---------------------------
A B Do Not Show
C D Do Not Show
E G Show
P Q Show
Z F Show
Sample result in SQL Fiddle