I have two table
Table_1:
id pa_name
1 A
2 B
3 C
Table_2:
id breakfast lunch dinner day day_des
1 Yes Yes No 1 des1
1 No No Yes 2 des2
1 Yes No Yes 3 des3
2 Yes Yes Yes 1 des11
2 Yes No No 2 des22
2 No Yes No 3 des33
I want the result like that
id pa_name breakfast lunch dinner day_des
1 A 2 1 2 des1
2 B 2 2 1 des11
I am using SQL Server 2008
This will give you the values in Comma seperated format
;WITH CTE AS
(
SELECT t1.id, t1.pa_name,
SUM(CASE WHEN breakfast = 'YES' then 1 end) as breakfast,
SUM(CASE WHEN lunch = 'YES' THEN 1 END) AS lunch,
SUM(CASE WHEN dinner= 'YES' THEN 1 END) AS dinner
FROM Table_1 AS t1
JOIN Table_2 AS t2 ON t1.id = t2.id
GROUP BY t1.id, t1.pa_name
)
SELECT *,
SUBSTRING(
(SELECT ', ' + day_des
FROM TABLE_2 T2
WHERE CTE.id=id
FOR XML PATH('')),2,200000) day_des
FROM CTE
SQL FIDDLE
Combine a JOIN with GROUP BY:
select t1.id, t1.pa_name,
SUM(case when breakfast = 'YES' then 1 end) as breakfast,
SUM(case when lunch = 'YES' then 1 end) as lunch,
SUM(case when dinner= 'YES' then 1 end) as dinner,
MIN(day_des)
from Table_1 as t1 join Table_2 as t2 on t1.id = t2.id
group by t1.id, t1.pa_name
But I'm a bit concerned about the recent edit, how is day_des supposed to be picked if there are different values? My choice was MIN value.
Related
Here is a subset of my table:
id
date
value
1
01/01/2022
5
1
02/02/2022
0
1
03/01/2022
0
1
04/02/2022
10
2
01/04/2022
5
2
02/04/2022
3
2
03/04/2022
0
2
04/04/2022
10
Where there are 0s in the value field, i would like to replace them with the non-zero value that occurs after the sequence of 0s are over, partitioned by id.
I have tried to use LAG but im really struggling as it takes the value above the current value in the table.
Any help will be appreciated.
Transformed table to look like
id
date
value
1
01/01/2022
5
1
02/02/2022
10
1
03/01/2022
10
1
04/02/2022
10
2
01/04/2022
5
2
02/04/2022
3
2
03/04/2022
10
2
04/04/2022
10
you can use cross apply;
select T1.id, T1.date, CASE WHEN T1.value = 0 THEN X.value ELSE T1.value END value from TestTable T1
OUTER APPLY (SELECT TOP 1 * FROM TestTable T2
WHERE T1.id = T2.id AND T2.date > T1.date
AND T2.value > 0
ORDER BY T2.date) X
sqlfiddle
Assuming by replace them you mean to update the table, simplest way would be a correlated subquery:
update t set value = (
select top(1) value
from t t2
where t2.id = t.id
and t2.value > 0
and t2.date > t.date
order by t2.date
)
where t.value = 0;
We group every 0 with the first value after it that's not 0 and then we use max() over() to replace the 0s in the group.
select id
,date
,max(value) over(partition by id, grp) as value
from
(
select *
,count(case when value != 0 then 1 end) over(partition by id order by date desc) as grp
from t
) t
order by id, date
id
date
value
1
2022-01-01
5
1
2022-02-02
10
1
2022-03-01
10
1
2022-04-02
10
2
2022-01-04
5
2
2022-02-04
3
2
2022-03-04
10
2
2022-04-04
10
Fiddle
You can do it using outer apply:
select
d.id, d.date_,
case when d.value != 0 then d.value else nz.value end as value
from data d
outer apply (
select min(value) as value
from data dd
where dd.id = d.id
and dd.date_ > d.date_
and dd.value <> 0
) nz
You can test on this db<>fiddle
|id|last|
|2 |NULL|
|2 |2018|
|3 |NULL|
|3 |NULL|
|4 |2011|
|4 |2013|
This is what my current table looks like. A new 'status' column is to be created for each 'id' that must have the below 3 values.
1 - If Similar id and only one NULL value
2 - If Similar id and no NULL value
0 - If Similar id and both NULL value
EXAMPLE: Id 2 will get 1, id 3 will be assigned 0 and id 4 will get 2. There can be only 2 similar ids in the id table (there are no 3 values of 2 or 4)
I could find the similar id, but having difficulties writing the cases
select id
from table
group by id
having count(id) = 2
We can determine the status values by using aggregation:
WITH cte AS (
SELECT id,
CASE WHEN COUNT(*) > 1 AND COUNT(CASE WHEN last IS NULL THEN 1 END) = 1
THEN 1
WHEN COUNT(*) > 1 AND COUNT(CASE WHEN last IS NULL THEN 1 END) = 0
THEN 2
WHEN COUNT(*) > 1 AND COUNT(CASE WHEN last IS NULL THEN 1 END) = COUNT(*)
THEN 0 ELSE -1 END AS status
FROM yourTable
GROUP BY id
)
SELECT t1.*, t2.status
FROM yourTable t1
INNER JOIN cte t2
ON t1.id = t2.id;
Note that I assign a status value of -1 to any id which does not meet one of the three criteria. This would include any id which only appears once, among other edge cases.
You can do it this way
select a.id, last,
case
when exists(select 1 from _table b where a.id = b.id and coalesce(b.last,0) <> coalesce(a.last,0) and (a.last is null or b.last is null))
then 1
when exists(select 1 from _table b where a.id = b.id
and coalesce(b.last,0) <> coalesce(a.last,0))
and not exists(select 1 from _table b where a.id = b.id
and b.last is null)
then 2
when exists(select 1 from _table b where a.id = b.id )
and exists(select 1 from _table b where a.id = b.id and b.last is null and a.last is null having count(*) =
(select count(*) from _table b where a.id = b.id))
then 0
end as status
from _table a
Output:
id last status
2 NULL 1
2 2018 1
3 NULL 0
3 NULL 0
4 2011 2
4 2013 2
If you want one row per id:
select id,
(case count(*) filter (value is null)
when 1 then 1
when 0 then 2
when 2 then 3
end) as status
from t
group by id;
If you want this as a column on the original data, use window functions:
select t.*,
(case count(*) filter (value is null) over (partition by id)
when 1 then 1
when 0 then 2
when 2 then 3
end) as status
from t;
i have 2 tables :
table1(id, name)
1233 AAA
3424 BBB
4345 CCC
4342 DDD
1243 RRR
3453 GGG
table2(id,date,status)
1233 01/07/19 1
3424 01/07/19 1
4342 01/07/19 2
1243 01/07/19 1
4342 01/07/19 1
4345 02/07/19 2
1243 02/07/19 1
1233 02/07/19 1
4345 03/07/19 1
4342 03/07/19 2
1233 03/07/19 1
4342 04/07/19 2
4345 04/07/19 2
4342 04/07/19 1
1243 04/07/19 2
15 ROW
i have tried this code
SELECT rn.id, name, NVL(cnt, 0) jum
FROM table1 rn
LEFT JOIN (SELECT id, COUNT(id) AS cnt
FROM VIEW_AKTIFITAS
WHERE extract(year from date)=2019
AND extract(month from date)=7
GROUP BY id,extract(month from date) n ON n.id= rn.id
i want to get this result
how to count the status entry in table 2
RESULT
ID COUNT_STATUS_1 COUNT_STATUS_2 TOTAL_COUNT
1233 2 0 2
3424 2 0 2
4345 1 2 3
4342 2 3 5
1243 2 1 3
3453 0 0 0
please help me to solve this problem.. thanks
Left join table2 to table1 and then use conditional aggregation to get the different counts for the two status.
SELECT t1.id,
count(CASE
WHEN t2.status = 1 THEN
1
END) count_status_1,
count(CASE
WHEN t2.status = 2 THEN
1
END) count_status_2,
count(t2.status) total_count
FROM table1 t1
LEFT JOIN table2 t2
ON t2.id = t1.id;
In Oracle 11.1 and higher, you can use the PIVOT operator to do the aggregation. Something like this:
select id, name, count_status_1, count_status_2,
count_status_1 + count_status_2 as total_count
from (select t1.id, t1.name, t2.status from table1 t1 left join table2 t2
on t1.id = t2.id)
pivot (count(*) for status in (1 as count_status_1, 2 as count_status_2))
order by id -- if needed
;
Based on your sample code, you seem to want:
SELECT rn.id, rn.name, NVL(cnt, 0) jum,
SUM(CASE WHEN a.status = 1 THEN 1 ELSE 0 END) as status_1,
SUM(CASE WHEN a.status = 1 THEN 1 ELSE 0 END) as status_2,
COUNT(a.status) as total
FROM table1 rn LEFT JOIN
VIEW_AKTIFITAS a
ON a.id = rn.id AND
a.date >= DATE '2019-07-01' AND
a.date < DATE '2019-08-01'
GROUP BY rn.id, rn.name;
You do not need a subquery for the LEFT JOIN. The date comparisons are better done using direct date comparisons. Oracle allows you to use ISO-standard date formats with the DATE keyword.
this is my final code
SELECT t1.nip, t1.nama_pegawai,
count(CASE
WHEN t2.status = 1
and t2.tahun=2019
and t2.bulan=7
THEN
1
END) count_status_1,
count(CASE
WHEN t2.status = 2
and t2.tahun=2019
and t2.bulan=7
THEN
1
END) count_status_2,
count(CASE
WHEN t2.tahun=2019
and t2.bulan=7
THEN 1 END
) total_count
FROM VIEW_PEGAWAI t1
LEFT JOIN VIEW_AKTIFITAS t2
ON t2.nip = t1.nip
where t1.opd_id=14
and T1.JENIS_PEG<>3
group by t1.nip,t1.nama_pegawai
I have two tables as below. Caseid from first table is referenced in second table along with accidents. What I am trying to get total different accidents for a case type. Below two tables I documented sample data and expected result.
Table case:
caseId CaseType
1 AB
2 AB
3 AB
4 CD
5 CD
6 DE
Table CaseAccidents:
AccidentId caseID AccidentRating
1 1 High
2 1 High
3 1 Medium
4 1 LOW
5 2 High
6 2 Medium
7 2 LOW
8 5 High
9 5 High
10 5 Medium
11 5 LOW
Result should look like:
CaseType TotalHIghrating TotalMediumRating TotalLOWRating
AB 3 2 2
CD 2 1 1
DE 0 0 0
To get the sum of every rating, you can Use a SUM(CASE WHEN) clause, adding 1 by every record that match the rating.
In your question, you have pointed out that you want to see all distinct CaseType, you can get it by using a RIGHT JOIN, this will include all records of case table.
select case.CaseType,
sum(case when caseAccidents.AccidentRating = 'High' then 1 else 0 end) as TotalHighRating,
sum(case when caseAccidents.AccidentRating = 'Medium' then 1 else 0 end) as TotalMediumRating,
sum(case when caseAccidents.AccidentRating = 'LOW' then 1 else 0 end) as TotalLowRating
from caseAccidents
right join case on case.caseId = caseAccidents.caseID
group by case.CaseType;
+----------+-----------------+-------------------+----------------+
| CaseType | TotalHighRating | TotalMediumRating | TotalLowRating |
+----------+-----------------+-------------------+----------------+
| AB | 3 | 2 | 2 |
+----------+-----------------+-------------------+----------------+
| CD | 2 | 1 | 1 |
+----------+-----------------+-------------------+----------------+
| DE | 0 | 0 | 0 |
+----------+-----------------+-------------------+----------------+
Check it: http://rextester.com/MCGJA9193
Have you use case in a select clause before?
select C.CaseType,
sum(case when CA.AccidentRating = 'High' then 1 else 0 end)
from Case C join CaseAccidents CA on C.CaseId = CA.CaseId
group by C.CaseType
Please see this. Sample query of the table and also that result
create table #case(caseid int,casetype varchar(5))
insert into #case (caseid,casetype)
select 1,'AB' union all
select 2,'AB' union all
select 3,'AB' union all
select 4,'CD' union all
select 5,'CD' union all
select 6,'DE'
create table #CaseAccidents(AccidentId int, CaseId int,AccidentRating varchar(10))
insert into #CaseAccidents(AccidentId, CaseId, AccidentRating)
select 1,1,'High' union all
select 2,1,'High' union all
select 3,1,'Medium' union all
select 4,1,'Low' union all
select 5,2,'High' union all
select 6,2,'Medium' union all
select 7,2,'Low' union all
select 8,5,'High' union all
select 9,5,'High' union all
select 10,5,'Medium' union all
select 11,5,'Low'
My script
select c.casetype,
sum(case when ca.AccidentRating='High' then 1 else 0 end) as TotalHighRating,
sum(case when ca.AccidentRating='Medium' then 1 else 0 end) as TotalMediumRating,
sum(case when ca.AccidentRating='Low' then 1 else 0 end) as TotalLowRating
from #case c
Left join #CaseAccidents ca
on c.Caseid=ca.Caseid
group by c.casetype
Hope This could help!
Another approach using Pivot operator
SELECT casetype,
[High],
[Medium],
[Low]
FROM (SELECT c.casetype,
AccidentRating
FROM case c
LEFT JOIN CaseAccidents ca
ON ca.CaseId = c.caseid)a
PIVOT (Count(AccidentRating)
FOR AccidentRating IN ([High],
[Medium],
[Low]) ) p
Try This code once.
select casetype,
sum(case when ca.AccidentRating='High' then 1 else 0 end ) as TotalHIghrating,
sum(case when ca.AccidentRating='Medium' then 1 else 0 end ) as TotalMediumRating ,
sum(case when ca.AccidentRating='Low' then 1 else 0 end ) as TotalLOWRating
from #case c
left join #CaseAccidents ca on c.caseid=ca.CaseId
group by casetype
Consider tables
Table1
id, name
1 xyz
2 abc
3 pqr
Table2
id title
1 Mg1
2 Mg2
3 SG1
Table3
Tb1_id tb2_id count
1 1 3
1 2 3
1 3 4
2 2 1
3 2 2
3 3 2
I want to do query to give result like
id title
1 MG1
2 MG2
3 Two or More Title
MG1 has higher preference if MG1 and count >= 1 then it is given as MG1 title , for others corresponding title is used and for count > 1 as two or more
I think this is what you are going for:
select t3.Tb1_id as id,
case
when mg1cnt.count >= 1 then 'MG1'
when cnt.count = 1 then upper(t2.title)
else 'Two or More Titles'
end as title
from (
select Tb1_id, count(*) as count
from Table3
group by Tb1_id
) cnt
inner join (
select Tb1_id, isnull(SUM(case when t2.title='mg1' then 1 end), 0) as count
from Table3 t3
inner join Table2 t2 on t3.tb2_id = t2.id
group by Tb1_id
) as mg1cnt on cnt.Tb1_id = mg1cnt.Tb1_id
inner join Table3 t3 on cnt.Tb1_id = t3.Tb1_id
inner join Table2 t2 on t3.tb2_id = t2.id
group by t3.Tb1_id,
case
when mg1cnt.count >= 1 then 'MG1'
when cnt.count = 1 then upper(t2.title)
else 'Two or More Titles'
end