I am trying to select records that appear more than once and are part of a specific department plus other departments.
So far the query that I have is this:
SELECT employeeCode, employeeName
FROM
Employees
WHERE
Department <> 'Technology'
AND employeeCode IN (SELECT employeeCode
FROM Employees
GROUP BY employeeCode HAVING COUNT(*) > 1)
The problem is that I want to select employees which are part of the Technology department, but they also participate in other departments.
So, they must be from the Technology department, but they could also be from the Household department. In the database it could look like:
1 | A1 | Alex | Technology
2 | A2 | Thor | Household
3 | A3 | John | Cars
4 | A3 | John | Technology
5 | A4 | Kim | Technology
6 | A4 | Kim | Video Games
So basically the query should return:
A3 | John |
A4 | Kim |
I think it's a small part that I am missing but..
Any ideas on how to filter/sort it so that it always uses the technology and the other departments?
Btw, I tried searching but I couldn't find a problem like mine..
If you want employees that could be in the technology department and another department:
select e.employeeCode, e.employeeName
from employees e
group by e.employeeCode, e.employeeName
having sum(case when e.department = 'Technology' then 1 else 0 end) > 0 and
count(*) > 1;
This assumes no duplicates in the table. If it can have duplicates, then use count(distinct department) > 1 rather than count(*) > 1.
Try this:
SELECT E.employeeCode, E.employeeName
FROM Employees E
INNER JOIN (SELECT DISTINCT E1.employeeCode, E1.employeeName
FROM Employees E
WHERE E.Department = 'Technology'
) AS A ON E.employeeCode = A.employeeCode AND E.employeeName = A.employeeName
GROUP BY E.employeeCode, E.employeeName
HAVING COUNT(*) > 1;
You can use EXISTS with correlated sub-query joining on the same table with different condition.
SELECT e1.employeeCode, e1.employeeName
FROM Employees e1
WHERE e1.Department = 'Technology'
AND EXISTS (SELECT * FROM Employees e2
WHERE e1.employeeCode = e2.employeeCode
AND e2.Department <> 'Technology')
This will work for your case:
SELECT a.employeeCode, a.employeeName
FROM Employees a, Employees b
WHERE
a.Department = 'Technology'
AND
b.Department <> 'Technology'
AND
a.employeeCode = b.employeeCode
AND
a.employeeID <> b.employeeID
Related
This question already has answers here:
Get top 1 row of each group
(19 answers)
Closed 4 months ago.
We have 2 Tables Employees and Department.
We want to show the maximum salary from each department and their corresponding employee name from the employee table and the department name from the department table.
Employee Table
EmpId | EmpName |salary |DeptId
101 shubh1 1000 1
101 shubh2 4000 1
102 shubh3 3000 2
102 shubh4 5000 2
103 shubh5 12000 3
103 shubh6 1000 3
104 shubh7 1400 4
104 shubh8 1000 4
Department Table
DeptId | DeptName
1 ComputerScience
2 Mechanical
3 Aeronautics
4 Civil
I tried doing it but was getting error
SELECT DeptName FROM Department where deptid IN(select MAX(salary),empname,deptid
FROM Employee
GROUP By Employee.deptid)
Error
Token error: 'Column 'Employee.EmpName' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.' on server 4e0652f832fd executing on line 1 (code: 8120, state: 1, class: 16)
Can someone please help me.
select salary
,EmpName
,DeptName
from (
select e.salary
,e.EmpName
,d.DeptName
,rank() over(partition by e.DeptId order by e.salary desc) as rnk
from Employee e join Department d on d.DeptId = e.DeptId
) t
where rnk = 1
salary
EmpName
DeptName
4000
shubh2
ComputerScience
5000
shubh4
Mechanical
12000
shubh5
Aeronautics
1400
shubh7
Civil
Fiddle
Now that I know it's MS SQL Server, technically; we could use cross or outer Apply; it's a table value function not a join per say... but this will depend on the version of SQL Server; and if you want data if it doesn't exist in another
I find this the "Best" Design pattern to use for this type of query.
What the engine does is for each record in department, it runs a query for the employees Finding those in that department returning the 1 record having the max salary. With top we could specify with ties to return more than one. but we would need to know how to handle Ties of salary. Use top 1 with ties or order the results so you get the "Top" result you want.
Demo: dbfddle.uk
SELECT Sub.empName, Sub.Salary, D.DeptName
FROM Department D
CROSS Apply (SELECT Top 1 *
--(SELECT TOP 1 with Ties * -- could use this if we ties
FROM Employee E
WHERE E.DeptID = D.DeptID
ORDER BY Salary Desc) Sub --add additional order by if we don't want ties.
The cross apply gives us:
+---------+--------+-----------------+
| empName | Salary | DeptName |
+---------+--------+-----------------+
| shubh2 | 4000 | ComputerScience |
| shubh4 | 5000 | Mechanical |
| shubh5 | 12000 | Aeronautics |
| shubh7 | 1400 | Civil |
+---------+--------+-----------------+
Before window functions, before cross Apply or lateral... We'd write an inline view
It would get us the max salary for each dept, we then join that back to our base tables to find the employee within each dept with max salary...
Demo: DbFiddle.uk
SELECT E.*, D.*
FROM Employee E
INNER JOIN Department D
on E.DeptID = D.DeptID
INNER JOIN (SELECT MAX(SALARY) maxSal , DeptID
FROM Employee
GROUP BY DeptID) Sub
on Sub.DeptID = E.DeptID
and Sub.MaxSal = E.Salary
One has to do a join to get the department info an the employee info. However, we can eliminate the join for salarymax by using exists and correlation instead.
Demo DbFiddle.uk
SELECT E.*, D.*
FROM Employee E
INNER JOIN Department D
on E.DeptID = D.DeptID
WHERE EXISTS (SELECT MAX(Sub.SALARY) maxSal , Sub.DeptID
FROM Employee Sub
WHERE sub.DeptID=E.DeptID --correlation 1
GROUP BY Sub.DeptID
HAVING E.Salary = max(Sub.Salary)) --correlation 2
We could eliminate the last join too I suppose:
Demo: Dbfiddle.uk
SELECT E.*, (SELECT DeptName from Department where E.DeptID = DeptID)
FROM Employee E
WHERE EXISTS (SELECT MAX(Sub.SALARY) maxSal , Sub.DeptID
FROM Employee Sub
WHERE sub.DeptID=E.DeptID --correlation 1
GROUP BY Sub.DeptID
HAVING E.Salary = max(Sub.Salary)) --correlation 2
The top 3 give us this result:
+-----+---------+--------+--------+--------+-----------------+
| id | empName | salary | deptID | DeptID | DeptName |
+-----+---------+--------+--------+--------+-----------------+
| 101 | shubh2 | 4000 | 1 | 1 | ComputerScience |
| 102 | shubh4 | 5000 | 2 | 2 | Mechanical |
| 103 | shubh5 | 12000 | 3 | 3 | Aeronautics |
| 104 | shubh7 | 1400 | 4 | 4 | Civil |
+-----+---------+--------+--------+--------+-----------------+
I got a customer table and each customer has 4 different employeeID (tranieeID,RepresenterID,CoridatorID and ManagerID) I want to get all these employees name rather then their ID in single row.
CustomerTable
|CustomerID|CustomerName|tranieeID|RepresenterID |CoridatorID |ManagerID
------------------------------------------------------------------------
01 Mr T 100 101 102 103
EmployeeTable
EmpID | EmpName
---------------
100 Mr A
101 Mr B
102 Mr C
103 Mr D
What I need
CustomerID | CustomerName | tranieeName | RepresenterName | CoridatorName | ManagerName
----------------------------------------------------------------------------------------
01 Mr T Mr A Mr B Mr C Mr D
I did inner join but I got 4 Rows, is there any way to get all these with a single row?
Thank you for your help!
JOIN should work. I would recommend LEFT JOIN in case any of the values are not filled in:
select c.*,
et.empname as traineeName,
er.empname as RepresenterName,
ec.empname as CoridatorIDName,
em.empname as ManagerName
from customertable c left join
employeetable et
on c.traineeID = et.empid left join
employeetable er
on c.RepresenterID = et.empid left join
employeetable ec
on c.CoridatorID = ec.empid left join
employeetable em
on c.ManagerID = em.empid
You could use a correlated subquery in each instance, such as
select c.CustomerId, CustomerName,
(select Empname from EmployeeTable e where e.EmpID=c.TranieeId) TraineeName,
(select Empname from EmployeeTable e where e.EmpID=c.RepresenterId) RepresenterName,
... etc
from CustomerTable c
I'm really new to this and this particular question has been bugging me for days. I do know there are similar questions to this but I kept wondering how it would be done in subqueries.
SALARY TABLE
[Emp_ID] [SalaryPM]
001 | 10,500
002 | 50,000
003 | 8,000
004 | 10,000
DEPT TABLE
[Emp_ID] [Dept_ID]
001 | A
002 | B
003 | C
004 | C
I want it to look like this
[Emp_ID] [Dept_ID] [SalaryPM]
001 | A | 10,000
002 | B | 50,000
004 | C | 10,000
What I have tried so far, but it only gives the highest salary of the employee##
SELECT * FROM DEPT
WHERE EMP_ID IN
(SELECT Emp_ID
FROM SALARY
WHERE SalaryPM = (SELECT MAX(SalaryPM)
FROM SALARY));
Would this qualify as a subquery solution?
select *
from (
select s.*, e.deptid,
rank() over(partition by e.dept order by s.salaries desc) rn
from employees e
inner join salaries s on s.id = e.id
) rn
where rn = 1
Note: your does not look good. The data you are showing suggests a 1-1 relationship between the two tables (wich I called employees and salaries): if so, both tables should be combined in a single table.
I would be good to know what do you mean by "using subqueries" ;)
here's another solution using subquery in the SELECT clause
SELECT
d.id,
d.deptid,
(
SELECT
MAX(s.salary)
FROM
my_salaries s
WHERE
s.id = d.id
) max_salary
FROM
my_departments d;
here's solution without joining tables (IMHO not joining tables is just overcomplicating things). Why 'not using join' is so important for you?
SELECT
sub.id,
MAX(sub.deptid),
MAX(sub.salary)
FROM
(
SELECT
d.id,
d.deptid,
NULL salary
FROM
my_departments d
UNION ALL
SELECT
s.id,
NULL deptid,
s.salary
FROM
my_salaries s
) sub
GROUP BY
sub.id
ORDER BY
sub.id;
I'm trying to display staff from the same department who earn more than their managers.
SELECT ID, NAME, DEPARTMENT, SALARY, JOB
FROM STAFF
WHERE SALARY > ANY (SELECT SALARY FROM STAFF WHERE JOB = 'Manager')
This doesn't seem to work, and I'm reallly not sure why.
Here's a peep at how the tables are formatted:
ID | NAME | DEPARTMENT | SALARY | JOB
20 | JOHN | 180 | 52000 | Manager
30 | KATY | 180 | 60000 | Analyst
The problem is that you need to correlate the subquery to match the same departement:
SELECT s1.ID, s1.NAME, s1.DEPARTMENT, s1.SALARY, s1.JOB
FROM SALARY s1
WHERE
s1.JOB <> 'MANAGER' AND
s1.SALARY > (SELECT s2.SALARY FROM SALARY s2
WHERE s2.DEPARTMENT = s1.DEPARTMENT AND s2.JOB = 'MANAGER');
This answer assumes that each department would have only one manager. If there could be more than one manager, then it would be safer to write the above using exists logic:
SELECT s1.ID, s1.NAME, s1.DEPARTMENT, s1.SALARY, s1.JOB
FROM SALARY s1
WHERE
s1.JOB <> 'MANAGER' AND
NOT EXISTS (SELECT 1 FROM SALARY s2
WHERE s2.DEPARTMENT = s1.DEPARTMENT AND
s2.JOB = 'MANAGER' AND
s2.SALARY >= s1.SALARY);
The objective of the query is get a count of employees absent under each manager.
Attendance (Dates when employees are present)
id date
1 16/05/2020
2 16/05/2020
1 17/05/2020
2 18/05/2020
3 18/05/2020
Employee
id manager_id
1 2
2 3
3 NA
The desired output should be in this format:
Date manager_id Number_of_absent_employees
16/05/2020 NA 1
17/05/2020 3 1
17/05/2020 NA 1
18/05/2020 2 1
I have tried writing code but partially understood it, intuition being calculating total number of actual employees under each manager and subtracting it from number of employees present on given day. Please help me in completing this query, many thanks!
with t1 as /* for counting total employees under each manager */
(
select employee.manager_id,count(*) as totalc
from employee as e
inner join employee on e.employee_id=employee.employee_id
group by employee.manager_id
)
,t2 as /* for counting total employees present each day */
(
select Attendence.date, employee.manager_id,count(*) as present
from employee
Left join Attendence on employee.employee_id=Attendence.employee_id
group by Attendence.date, employee.manager_id
)
select * from t2
Left join t1 on t2.manager_id=t1.manager_id
order by date
Cross join the distinct dates from Attendance to Employee and left join Attendance to filter out the matching rows.
The remaining rows are the absences so then you need to aggregate:
select d.date, e.manager_id,
count(*) Number_of_absent_employees
from (select distinct date from Attendance) d
cross join Employee e
left join Attendance a on a.date = d.date and a.id = e.id
where a.id is null
group by d.date, e.manager_id
See the demo.
Results:
| date | manager_id | Number_of_absent_employees |
| ---------- | ---------- | -------------------------- |
| 16/05/2020 | NA | 1 |
| 17/05/2020 | 3 | 1 |
| 17/05/2020 | NA | 1 |
| 18/05/2020 | 2 | 1 |
Try this query. In first cte just simplify your code. And in the last query calculate absent employees.
--in this CTE just simplify counting
with t1 as /* for counting total employees under each manager */
(
select employee.manager_id,count(*) as totalc
from employee
group by manager_id
)
,t2 as
(
select Attendence.date, employee.manager_id,count(*) as present
from employee
Left join Attendence on employee.employee_id=Attendence.employee_id
group by Attendence.date, employee.manager_id
)
select t2.date,t2.manager_id, (t1.totalc-t2.present) as employees_absent from t2
Left join t1 on t2.manager_id=t1.manager_id
order by date
Select ec.manager_id, date, (total_employees - employee_attended) as employees_absent from
(Select manager_id, count(id) as total_employees
from employee
group by manager_id) ec,
(Select distinct e.manager_id, a.date, count(a.id) over (partition by e.manager_id, a.date) as employee_attended
from Employee e, attendence, a
where e.id = a.id(+)) ea
where ec.manager_id = ea.manager_id (+)
I guess this should work