SQL - Condition which Matches two rows - sql

Question

I am trying to extract the data from SQL developer which matches two row conditions. Both the rows has one unique value ( ID ) and table name is abc.tcd
ID = Type = GL code = amount
1 = Debit = 0701 = 10000
1 = credit = 0601 = 10000
1 = Credit= 0501 = 1000
1 = Debit= 0401 = 1000
2 = Debit = 0701 = 9000
2 = credit = 0801 = 9000
3 = Debit = 0701 = 6000
3 = credit = 0601 = 6000
Condition 1 :
GL code = '0701' having Type = 'Debit'
condition 2 :
GL code = '0601' having Type = 'Credit'
Expected output :
ID Type GL code amount
1 = Debit = 0701 = 10000
1 = credit = 0601 = 10000
1 = Credit = 0501 = 1000
1 = Debit = 0401 = 1000
3 = Debit = 0701 = 6000
3 = credit = 0601 = 6000
Output should display all the rows based on ID

Answer 1

If I understand the question correctly, you want to extract all the rows for some ID where two different rows fulfill two different conditions. you could use a couple of in operators:
SELECT *
FROM mytable
WHERE id IN (SELECT id
FROM my_table
WHERE GLCode = '0701' AND Type = 'Debit')
AND id IN (SELECT id
FROM my_table
WHERE GLCode = '0601' AND Type = 'Credit')
Of course, this can be easily translated to use the exists operator:
SELECT *
FROM mytable a
WHERE EXISTS (SELECT *
FROM my_table b
WHERE a.id = b.id AND b.GLCode = '0701' AND b.Type = 'Debit')
AND EXISTS (SELECT *
FROM my_table c
WHERE a.id = c.id AND c.GLCode = '0601' AND c.Type = 'Credit')
A more elegant way might be to have all the conditions in a single query with ors and count how many of them are fulfilled:
SELECT *
FROM mytable
WHERE id IN (SELECT id
FROM my_table
WHERE (GLCode = '0701' AND Type = 'Debit') OR
(GLCode = '0601' AND Type = 'Credit')
GROUP BY id
HAVING COUNT(*) = 2)

Answer 2

Another alternative:
SELECT * FROM MyTable
INNER JOIN
(
SELECT ID
FROM MyTable
WHERE (GLCode = '0701' AND Type = 'Debit') OR (GLCode = '0601' AND Type = 'Credit')
GROUP BY ID
HAVING COUNT(DISTINCT GLCode) = 2 AND COUNT(DISTINCT Type) = 2
) X
ON MyTable.ID = x.ID;
SqlFiddle here
Basically "find the ids having two distinct rows meeting the criteria". We then return all rows with this ID
Edit
Your real query would look like:
SELECT *
FROM tbaadm.ctd
INNER JOIN
(SELECT Tran_id
FROM tbaadm.ctd
WHERE ((GL_SUB_HEAD_CODE = '06106' AND PART_TRAN_TYPE = 'C')
OR (GL_SUB_HEAD_CODE = '29101' AND PART_TRAN_TYPE = 'D'))
AND (tran_date >= '01-12-2014' AND tran_date < '30-12-2014')
GROUP BY Tran_id
HAVING COUNT(DISTINCT GL_SUB_HEAD_CODE) = 2 AND COUNT(DISTINCT PART_TRAN_TYPE) = 2
) X
ON tbaadm.ctd = x.Tran_id;
The parenthesis around the ANDs are obviously redundant due to operator precedence, but might help with readability?
Also, note with Date range checking that it is convention to include start date but exclude end date, viz x >= start and x < end