Is there a way to explicitly position/orient an axis using dimple.js? I know that the first x-axis is added to the bottom and the second is added to the top, so I can get the desired outcome like this:
var xAxis = myChart.addMeasureAxis("x", "dur");
xAxis.hidden = true;
xAxis = myChart.addMeasureAxis("x", "dur");
...but that seems a little hacked.
I don't think there's any way around that. Here's the relevant code : https://github.com/PMSI-AlignAlytics/dimple/blob/master/src/objects/chart/methods/draw.js#L123
Because firstX is local to the draw function there isn't a way you could override it within the context of the loop.
You could possibly duplicate the logic used to position the top axis : https://github.com/PMSI-AlignAlytics/dimple/blob/master/src/objects/chart/methods/draw.js#L226
And then only add one axis (which would be positioned at the bottom), then manually move your axis after the drawing, like :
chart.draw();
chart.axes[0].shapes.attr('transform', ...);
But you would need to do this after every draw or else they'll be repositioned. The hack you have seems easiest.
You could open an enhancement ticket for this though : https://github.com/PMSI-AlignAlytics/dimple/issues?q=is%3Aissue+label%3Aenhancement+is%3Aopen
Related
I have a chart with a legend whose symbol I replaced per the example in the docs. It looks like this:
var marker = chart.legend.markers.template;
marker.disposeChildren();
let dollar = marker.createChild(am4core.Image);
dollar.width = 40;
dollar.height = 40;
dollar.verticalCenter = "top";
dollar.horizontalCenter = "left";
dollar.strokeWidth = 2;
dollar.strokeOpacity = 1;
dollar.adapter.add("href", function (href: any, target: any) {
return `http://host.com?id=${target.dataItem.dataContext.dummyData.value`;
});
And this works, my images are displayed, little faces :) - I would like to add a border around the image of the same color of the series so that you can identify the marker in the legend with the series. But I can't find the right set of settings to make this a thing.
Is this possible?
EDIT -
So, I tried the following chage to the above and got a decent result. It's a bit hacky, so there might be a better way. If not, I guess this works.
//marker.disposeChildren(); <= don't do this
marker.width = "50px";
marker.height = "50px";
Basically the original marker remains and is behind the image. The marker has to be made larger so that it sticks out and creates a pseudo border.
I'm going to answer this one myself, since I have a working solution and no one lese answered :)
The edit above does what it is needed. Doesn't see like a great solution, a border around an image should be doable. But this gets us what we want.
Solution:
Make the marker bigger than the image
Place the image above the marker
In this case, we do not remove child elements of the marker, like the sample code on amchart4 shows, since you need it.
I'm using Builder v1.80.06
I can vary the position of a polygon every repeat easily enough
e.g. I have a Positions list
positions=[[1,1],[1.1,0.9],...]
and in the 'Position field' have :
$positions[0]
and then change it's value in a code block on each repeat.
BUT I want to vary the size in a similar manner with a $sizes list but get an error.
Looking at the generated code, the problem is at the object creation stage. the code generated is:
for a hard coded polygon (ie ok)
polygon_1 = visual.Rect(win=win, name='polygon_1',
width=[1.5, .2][0], height=[1.5, .2][1],
ori=0, pos=[0, -0.6],
lineWidth=1, lineColor=[1,1,1], lineColorSpace=u'rgb',
fillColor=[0,1,0], fillColorSpace=u'rgb',
opacity=1,interpolate=True)
for one populated by a variable (not working):
polygon_2= visual.Rect(win=win, name='polygon_2',
width=1.0[0], height=1.0[1],
ori=0, pos=[0,0],
lineWidth=1, lineColor=[1,1,1], lineColorSpace=u'rgb',
fillColor=[1,0,0], fillColorSpace=u'rgb',
opacity=1,interpolate=True)
It complains (rightly) that 1.0[0] makes no sense on the width and height parameters
Even though I have my sizes list instantiated in a code block right at the beginning of the experiment instead of reading $sizes[0] a default float value of 1.0 is used.
Any other suggestions for how to vary the polygon size dynamically at runtime using builder?
I could just take the generated code and drop it into coder I suppose and fix the problem but I want to hand this over to a researcher so would like for them to be able to maintain it.
thanks,
If you set size to be a tuple/list with a pair values [1.2,1.5] or [1,1] does that not fix it?
When you change attributes at runtime, just change the attribute of an existing stimulus instead of instantiating a full new stimulus. The latter is quite heavy on ressources, causing unreliable timing. So do
stim = visual.Rect(win) # instantiation, ressource heavy
stim.attribute = newValue # change attribute. lighter.
I can think of two ways you could do it in a pretty neat way. The first is to set width and height explicitly instead of the size attribute, but using a size-like value. So (removing all parameters not of interest):
polygon_2 = visual.Rect(win)
# Unpack the x,y-sizes to the stimulus .width and .height attributes
newSize = (1.5, 0.2)
polygon_2.width, polygon_2.height = newSize
The second, if the size attribute is really important to use, is to use the Polygin with edges=4 to make it a rectangle:
polygon_2 = visual.Polygon(win=win, edges=4, size=(1.5, 0.2))
# Setting size
polygon_2.size = (0.8, 0.4)
Do try Jon's suggestion first. But the idea with visual.Rect and visual.Circleis to use substitute Polygon's size and vertices for something more relevant. So size can do unexpected things if width/height etc. are not 1.
I've got the following node set as follow.
box.physicsBody.allowsRotation = YES;
No mater what force applies to this box, I want it to never fall down or rotate more than a certain angle, just like a tree or a spring that might bend all the way down but has a tendency to go back to it's initial angle or position.
Is there a any trick or method to that?
I was thinking maybe joining an invisible un-rotatable physics body under the box and use a joint spring method for that which I have no Idea how that works!
Or, maybe there be a trick to play with the pivot. Any idea?
In the update: method you will have to continuously check the desired node's properties. In your case it is going to be the zRotation property of your node.
Add this code in your update: method:
if(yourNode.zRotation > 0.5)
yourNode.zRotation = 0.5;
if(yourNode.zRotation < -0.5)
yourNode.zRotation = -0.5;
Change the 0.5 value to your desired value or replace it with a static const float.
I’m trying to put together what seems to be a simple case of two NSTextFields with dynamic width and fixed spacing in between. I cannot figure out an effective way to do so though.
I’m looking to get something like this:
The blue boxes are the NSTextFields. When more text is entered into one, it should grow and thus make the other one shrink, maintaining the lead space, trailing space and the spacing in between the fields. The first one should take the priority if both of the fields have too much text. Each field will also clearly have a maximum and a minimum possible width it can reach.
How would I go around handling this, preferably utilising IB autolayout as much as possible?
It seems to me that all of constraints you mentioned directly translate into interface builder --
First view has width >= something.
First view has width <= something
Same for Second view.
Space between views is fixed.
Second view wants to be as small as possible (have its width at 0) but this has lower lower priority than the previous constraints and lower priority than inner content size constraints.
The code I had to add to my view controller, after applying the constraints as per the ilya’s answer:
In controlTextDidChange (_controlWidthConstraint refers to the fixed width constraint of the input; it’s probably 0 by default for the second input):
// Get the new width that fits
float oldWidth = textControl.frame.size.width;
[input sizeToFit];
float controlWidth = textControl.frame.size.width;
// Don’t let the sizeToFit method modify the frame though
NSRect controlRect = textControl.frame;
controlRect.size.width = oldWidth;
textControl.frame = controlRect;
_controlWidthConstraint.constant = controlWidth;
The key lies in invalidating the intrinsicContentSize for the text field when text is input.
You can check a sample project here, to get you on the right track.
I have a Zedgraph textobj which I want to place always in the same x, y position (ASP.NET image). I noticed that the text doesn't always show in the same starting x position. It shifts depending on the text's length. I tried to have the text to have the same length by padding it with spaces. It helped a little but the result is not always consistent. I am using PaneFraction for coordType.
What's the proper method to have a piece of text to always show in the same x position. I am using textobj as a title because the native title property always shows up centered and I need my title be left aligned to the graph.
No, it does not depend on text lenght, however...
It depends on various other things:
Horizontal and vertical align of the text box (see: Location )
Current size of the pane. The font size is scaled dynamically to fit the changing size of the chart.
Counting proper positions to have TextObj (or any other object) always at the same place is quite hard. So you need avoid as much as you can any numbers/fractions in your location coordinates. ZedGraph sometimes calculates the true position in quite odd way then.
You haven't provided any code, so it's hard to tell if and where you made the mistake (if any). But, if I were you, I would do something like that:
TextObj fakeTitle = new TextObj("some title\n ", 0.0, 0.0); // I'm using \n to have additional line - this would give me some space, margin.
fakeTitle.Location.CoordinateFrame = CoordType.ChartFraction;
fakeTitle.Location.AlignH = AlignH.Left; // Left align - that's what you need
fakeTitle.Location.AlignV = AlignV.Bottom; // Bottom - it means, that left bottom corner of your object would be located at the left top corner of the chart (point (0,0))
fakeTitle.FontSpec.Border.IsVisible = false; // Disable the border
fakeTitle.FontSpec.Fill.IsVisible = false; // ... and the fill. You don't need it.
zg1.MasterPane[0].GraphObjList.Add(fakeTitle);
I'm using ChartFraction coordinates instead of PaneFraction (as drharris suggests) coordinates to have the title nicely aligned with the left border of the chart. Otherwise it would be flushed totally to the left side (no margin etc...) - it looks better this way.
But make sure you didn't set too big font size - it could be clipped at the top
Are you using this constructor?
TextObj(text, x, y, coordType, alignH, alignV)
If not, then be sure you're setting alignH to AlignH.Left and alignV to AlignV.Top. Then X and Y should be 0, 0. PaneFraction for the coordType should be the correct option here, unless I'm missing your intent.
Alternatively, you can simply download Zedgraph code, edit it to Left-align the title (or even better, provide an option for this, which should have been done originally), and then use it in production. Beauty of open source.