Linktext in selenium webdriver - selenium

Is it possible to use linkText locator in this code
I used driver.findElement(By.linkText("welcome")).click();
But it didn't work.
Please help....
<div class="back-to">
<a class="button blue" href="javascript:history.back()">welcome</a>
</div>


The linkText should work in this case. Or else try the below alternatives(and please provide sufficient implicit timeout to give selenium sufficent time to detect the element):
1. Using xpath, to click on the element 'a' with exact innerHTML/text as 'welcome':
driver.findElement(By.xpath("//a[.='welcome']")).click();
2- Using JavascriptExecutor to click on the element with exact innerHTML/text as 'welcome':
((JavascriptExecutor)driver).executeScript("arguments[0].click();", driver.findElement(By.xpath("//a[.='welcome']")));
3- Using partialLinkText to click on the link with partial text 'welcome'
driver.findElement(By.partialLinkText("welcome")).click();


This Should be enough:
driver.find_element_by_xpath('//a[#class="button blue"]').click();

Related

Finding Xpath Selenium

I have the following element:
<div class="PickList visible"
widgetid="Palette" id="Palette">
<span class="stuff">
<span class="stuff"><span class="lbl">A-B</span><span class="no">1111</span>
</span>
<span class="stuffSelect"><span class="lblSelect">C</span><span
class="plu">2222</span></span>
The xpath that I am using is:
Driver.driver.findElement(By.xpath("//*[#id="Palette"]//span//span[2]//span[contains(text(),'C')]"));
It's still not able to pickup the letter 'C'.
Any suggestions appreciated. Thanks.

you can try below xpath to track from div.
driver.findElement("//*[#id='Palette']/span[2][#class='stuffSelect']/span[1][contains(text(), 'C')]");

xpath you are using is incorrect. I am providing you with the correct xpath or you can directly fetch it using the className as well.
Updated xpath as per the discussion:
WebElement selectedCharacter = driver.findElement(By.xpath("//div[#id='Palette']//span[#class='lblSelect']"));
selectedCharacter.getText();
By using className:
WebElement selectedCharacter = driver.findElement(By.className("lblSelect"));
selectedCharacter.getText();

Please try the below Xpath.It will print you 'C'
driver.findElement(By.xpath("(//div[#id='Palette']//span[1]//span[2]/span)[1]")).getText()

Here is the xpath. Consider the class visible in your xpath or css. As this denotes that this div might be not visible sometimes. So always be sure to use the visible if you have it as part of the class.
CSS
div.PickList.visible span.lblSelect
xpath
//div[#class='PickList visible']//span[#class='lblSelect']

find specific element for button using selenium for web scraping

I am inspecting one button element from a web page using chrome driver and selenium. And the html code for the particular button is:
<div class="label text-left text-link link-blue text-
uppercase">Financial Statement Analysis <span class="count">(2)</span>
</div>
I have tried different element options like find element by name, xpath, link text etc. But none of them unable to locate the element.
What will be the element to locate the button. ?

try Xpath :
//span[contains(#class,'count') and text() = '(2)']

You can try with this css selector :
div.label.text-left.text-link.link-blue.text-.uppercase

To locate the element with text as Financial Statement Analysis (2) you can use the following solution:
Java Solution:
WebElement elem = driver.findElement(By.xpath("//div[#class='label text-left text-link link-blue text-uppercase'][contains(.,'Financial Statement Analysis')]"));

Best way to locate link with protractor

<a href="someCoolLinkText.com">
<h3 class="main-header">
COOL LINK
</h3>
</a>
What is best way to find and click on this link?

Try to locate required node by its link text:
element(by.linkText('COOL LINK')).click()
Note that you should use text exactly as it appears on page, but not as it appears in HTML source code
Update
You can try to use ExpectedCondition to wait for link appearance in DOM:
var EC = protractor.ExpectedConditions;
browser.wait(EC.elementToBeClickable(element(by.linkText('COOL LINK'))), 5000).click();

You can use this xpath :- //h3[text()='COOL LINK']

The text COOL LINK is within <h3> tag so you can use xpath as :
//a[#href='someCoolLinkText.com']/h3[#class='main-header' and contains(.,'COOL LINK')]

Selenium click anchor link with class attribute

Can anyone help how to click the below link using selenium
<a class=”btn btn-primary btn-large” href="target-URL">Submit</a>
I tried using below options
linkText
partialLinkText
CssSelector
contains - logic which checks the URL text

You can try:
driver.findElement(By.xpath("//a[contains#class,'btn '] and contains(#class, 'btn-large') and contains(text(), 'Submit')")).click()

Give full xpath
driver.findElement(By.xpath("html/body/a").click();
Can try with tag name
driver.findElement(By.tagName("a").click();

Try with below xpath:
driver.findElement(By.xpath("//a[#href='target-URL']").click();

In theory, this is just:
driver.findElment(By.linkText("Submit")).click();
But, I'm pretty sure you've already tried that. Check if the element is in iframe/frame. If yes, you need to switch to it and only then find the link element:
driver.switchTo().frame("frame_name_or_id");
To switch back in the main context, use defaultContent():
driver.switchTo().defaultContent();

how to locate element with selenium webdriver for below html

I have an issue clicking on the below HTML:
<div id="P7d2205a39cb24114b60b80b3c14cc45b_1_26iT0C0x0" style="word-wrap:break-word;white-space:pre-wrap;font-weight:500;" class="Ab73b430b430a49ebb0a0e8a49c8d71af3"><a tabindex="1" style="cursor:pointer;" onclick="var rp=$get('ctl00_ContentPlaceHolder1_ReportViewer1_ctl10_ReportControl');if(rp&&rp.control)rp.control.InvokeReportAction('Toggle','26iT0C0x0');return false;" onkeypress="if(event.keyCode == 13 || event.which == 13){var rp=$get('ctl00_ContentPlaceHolder1_ReportViewer1_ctl10_ReportControl');if(rp&&rp.control)rp.control.InvokeReportAction('Toggle','26iT0C0x0');}return false;"><img border="0" src="/Reserved.ReportViewerWebControl.axd?OpType=Resource&Version=10.0.30319.1&Name=Microsoft.ReportingServices.Rendering.HtmlRenderer.RendererResources.TogglePlus.gif" alt="+"></a> 2013</div>
I have used the below script to click anchor inside a div tag. For the above html code it is not fixed only end part of id example "26iT0C0x0" is fixed. The script that I have used is:
WebElement e1=wait.until(ExpectedConditions.elementToBeClickable(By.xpath("//div[ends-with(#id,'26iT0C0x0')]/a")));
e1.click();

You can use the 'contains' method within an xpath lookup:
driver.findElement(By.xpath("//div[contains(#id,'26iT0C0x0')]")

I would recommend you to consider CSS selector alternative as CSS working faster, than xpath.
So 'contains' in attribute in CSS stands for '*=', for example
if we want to find attribute by 'CSS' ending in this: <htmlTag A="blablaCSS" > we need do the following:
String CSSselector="htmlTag[A*=CSS]";
and you get this element searched.
So considering your example CSS selector be like:
String cssSearched="div[id*=26iT0C0x0] a";
also try to click not on link - a
but on parent div as well:
String cssSearched="div[id*=26iT0C0x0]";
driver.findElement(By.cssSelector(cssSearched));
hope this works for you.

As Mark Rwolands already mentioned: the xpath-Function 'ends-with()' isn't supported in Selenium 2.
Also, if you maybe consider to use chromeDriver in the future, I would recommend clicking the image, not the anchor, see:
https://sites.google.com/a/chromium.org/chromedriver/help/clicking-issues
edit:
Also your IDs are looking generated. I wouldn't count on them for a stable test-environment.