SQL select where startdate is today's date - sql

I am trying to write a query where the clause is when the start date for an employee is todays date.
select * from tbl_employees
where Startdate = getdate()
The issue is that Startdate is '2014-12-09 00:00:00.000'
and the function getdate is coming back with the date and time like '2014-12-09 08:25:16.013'
How can I write a query that only consider's the date?

You want just the date portion. The easy way is:
select *
from tbl_employees
where cast(Startdate as date) = cast(getdate() as date);
However, if you want to use an index, it is best not to have the column in a function call. So, this is better:
where (StartDate >= cast(getdate() as date) and StartDate < cast(getdate() + 1 as date))

select * from tbl_employees
where CONVERT(VARCHAR(10),Startdate,110) = CONVERT(VARCHAR(10),GETDATE(),110)

You can use to compare only DATE section not time..some thing like
IF CAST(DateField1 AS DATE) = CAST(DateField2 AS DATE)
OR
CONVERT(VARCHAR(10), GETDATE(), 112)

SELECT CONVERT (date, SYSDATETIME())
,CONVERT (date, SYSDATETIMEOFFSET())
,CONVERT (date, SYSUTCDATETIME())
,CONVERT (date, CURRENT_TIMESTAMP)
,CONVERT (date, GETDATE())
,CONVERT (date, GETUTCDATE());
/* Returned
SYSDATETIME() 2007-05-03
SYSDATETIMEOFFSET()2007-05-03
SYSUTCDATETIME() 2007-05-04
CURRENT_TIMESTAMP 2007-05-03
GETDATE() 2007-05-03
GETUTCDATE() 2007-05-04
*/
From: http://msdn.microsoft.com/en-us/library/ms188751.aspx
So using any of these will give you just the date

Related

SQL Check Current time is between two DATETIME columns

I need to check whether the current time is between two datetime column values.
And I only need to check the time is between the range and I don't want to check the date.
I know how to check a date is exists between a daterange like below
SELECT
*
FROM
Table1 T
WHERE
CAST(GETDATE() AS DATE) BETWEEN T.StartDate AND T.EndDate
We have stored start date and end date as folllows..
StartDate - 1900-01-01 08:00:00.000
EndDate - 1900-01-01 19:00:00.000
Is there something similar to this to check whether the time is exists in a date range?
if you only want to check time
SELECT *
FROM Table1 T
WHERE CAST(GETDATE() AS TIME) BETWEEN cast(T.StartDate as TIME) AND cast(T.EndDate as TIME)
Something like this I guess
declare #d1 datetime ='20171220 10:00'
, #d2 datetime = '20171220 12:00'
, #t time ='11:00';
select 'Yes' where #t between cast(#d1 as time) and cast(#d2 as time);
It worked when I tried like below
SELECT *
FROM Table1 T
WHERE CAST(GETDATE() AS TIME) BETWEEN CAST(T.StartDate AS TIME) AND CAST(T.EndDateAS TIME)
CONVERT() to TIME and then back to DATETIME and compare
WHERE CONVERT(DATETIME, CONVERT(TIME, GETDATE()))
BETWEEN T.StartDate AND T.EndDate

SQL Server Date comparison throws error

Please help on this, how independent query works but comparison is failing for below code,I am trying to compare only dates not time so tried the query like this.
SELECT CAST(getdate() AS DATE)---'2/9/2017 12:00:00 AM'
SELECT CAST('2017/01/15' AS DATE)----'1/15/2017 12:00:00 AM'
SELECT CAST(getdate() AS DATE) > CAST('2017/01/15' AS DATE); -- Error SQLSTATE 42000
You need to put this condition into context. For instance like this
SELECT case when CAST(getdate() AS DATE) > CAST('2017/01/15' AS DATE)
then 1
else 0
end
Try something like this:
DECLARE #nowDate DATE
SELECT #nowDate = CAST(getdate() AS DATE)
DECLARE #otherDate DATE
SELECT #otherDate = CAST('2017/01/15' AS DATE)
SELECT DATEDIFF(DAY, #nowDate, #otherDate)
SELECT CAST(getdate() AS DATE)---'2/9/2017 12:00:00 AM'
SELECT CAST('2017/01/15' AS DATE)----'1/15/2017 12:00:00 AM'
SELECT IIF(CAST(getdate() AS DATE) > CAST('2017/01/15' AS DATE),1,0); --good, you must use iif (or case when ) for predicates
You cannot compare in SELECT, you can use below code to determinate if date is greater or not than current date, or it is today.
DECLARE #DATE NVARCHAR(20) = '2017/01/15'
IF (CAST(getdate() AS DATE) > CAST(#DATE AS DATE))
PRINT 'Selected date is in past'
ELSE IF (CAST(getdate() AS DATE) = CAST(#DATE AS DATE))
PRINT 'Selected date is today'
ELSE
PRINT 'Selected date is in future'
You can try DATEDIFF() to find out difference between 2 dates.
select DATEDIFF( DAY,(CAST('2017/01/15' AS DATE)) ,(CAST(getdate() AS DATE)))

Getdate() functionality returns partial day in select query

I have a query -
SELECT * FROM TABLE WHERE Date >= DATEADD (day, -7, -getdate()) AND Date <= getdate();
This would return all records for each day except day 7. If I ran this query on a Sunday at 17:00 it would only produce results going back to Monday 17:00. How could I include results from Monday 08:00.
Try it like this:
SELECT *
FROM SomeWhere
WHERE [Date] > DATEADD(HOUR,8,DATEADD(DAY, -7, CAST(CAST(GETDATE() AS DATE) AS DATETIME))) --7 days back, 8 o'clock
AND [Date] <= GETDATE(); --now
That's because you are comparing date+time, not only date.
If you want to include all days, you can trunc the time-portion from getdate(): you can accomplish that with a conversion to date:
SELECT * FROM TABLE
WHERE Date >= DATEADD (day, -7, -convert(date, getdate())
AND Date <= convert(date, getdate());
If you want to start from 8 in the morning, the best is to add again 8 hours to getdate.
declare #t datetime = dateadd(HH, 8, convert(datetime, convert(date, getdate())))
SELECT * FROM TABLE
WHERE Date >= DATEADD (day, -7, -#t) AND Date <= #t;
NOTE: with the conversion convert(date, getdate()) you get a datatype date and you cannot add hours directly to it; you must re-convert it to datetime.
Sounds like you want to remove the time. Correct? If so then do the following.
SELECT * FROM TABLE WHERE Date >= (DATEADD (day, -7, -getdate()) AND Date DATEADD(dd, DATEDIFF(dd, 0, getdate()), 0))

TSQL SELECT previous date's records

I want to select all records from a table Log where the DateAndTime field values (of type datetime) are for the day before today, whatever day it is.
So if today is 2011-06-08, I want to select all rows where DateAndTime is greater than or equal to 2011-06-07 00:00:00 and also less than 2011-06-08 00:00:00.
I'm guessing the potential pitfall here would be it's behaviour on the 1st day of the month, as obviously a date like 2011-06-00 is invalid, and should be 2011-05-31.
For SQL Server 2008 you can use this.
select *
from [log]
where cast(DateAndTime as date) = cast(getdate()-1 as date)
Pre 2008 you can use this
select *
from [log]
where DateAndTime >= dateadd(d, datediff(d, 0, getdate())-1, 0) and
DateAndTime < dateadd(d, datediff(d, 0, getdate()), 0)
Related on DBA: Cast to date is sargable but is it a good idea?
SELECT * FROM Log
WHERE DateAndTime >= DATEADD(DAY,-1, CAST(GETDATE() AS DATE))
AND DateAndTime < CAST(CAST(GETDATE() AS DATE) AS DATETIME)
This example assumes SQL Server:
select *
from log
where convert(varchar(8), DateAndTime , 112) = convert(varchar(8), getdate()-1, 112)
Essentially, convert the date to yyyymmdd (the 112 parameter) and then check it is equal to yesterday's date (getdate()-1), also converted to yyyymmdd.
Assuming SQL Server
declare #today date
set #today = GETDATE()
select * from Log where DateAndTime between DATEADD(dd, -1, #today ) and #today
It should include conditional operator and not between .
Otherwise it includes today's records as well.
Declare #today date
Set #today = GETDATE()
Select YourcolumnNames from log
Where DateAndTime >= DATEADD(dd, -1, #today ) and DateAndTime < DATEADD(dd, -1, #today )
Moreover, you should mention the column name and * should be avoided in the select statement. This can improve the performance

Compare current date with stored datetime using month an year only

Using SQL Server 2005 I have a field that contains a datetime value.
What I am trying to do is create 2 queries:
Compare to see if stored datetime is of the same month+year as current date
Compare to see if stored datetime is of the same year as current date
There is probably a simple solution but I keep hitting brick walls using various samples I can find, any thoughts?
Thanks in advance.
Compare the parts of the date:
WHERE YEAR( columnName ) = YEAR( getDate() )
While the other answers will work, they all suffer from the same problem: they apply a transformation to the column and therefore will never utilize an index on that column.
To search the date without a transformation, you need a couple built-in functions and some math. Example below:
--create a table to hold our example values
create table #DateSearch
(
TheDate datetime not null
)
insert into #DateSearch (TheDate)
--today
select getdate()
union all
--a month in advance
select dateadd(month, 1, getdate())
union all
--a year in advance
select dateadd(year, 1, getdate())
go
--declare variables to make things a little easier to see
declare #StartDate datetime, #EndDate datetime
--search for "same month+year as current date"
select #StartDate = dateadd(month, datediff(month, 0, getdate()), 0), #EndDate = dateadd(month, datediff(month, 0, getdate()) + 1, 0)
select #StartDate [StartDate], #EndDate [EndDate], TheDate from #DateSearch
where TheDate >= #StartDate and TheDate < #EndDate
--search for "same year as current date"
select #StartDate = dateadd(year, datediff(year, 0, getdate()), 0), #EndDate = dateadd(year, datediff(year, 0, getdate()) + 1, 0)
select #StartDate [StartDate], #EndDate [EndDate], TheDate from #DateSearch
where TheDate >= #StartDate and TheDate < #EndDate
What the statement does to avoid the transformations, is find all values greater-than or equal-to the beginning of the current time period (month or year) AND all values less-than the beginning of the next (invalid) time period. This solves our index problem and also mitigates any issues related to 3ms rounding in the DATETIME type.
SELECT * FROM atable
WHERE
YEAR( adate ) = YEAR( GETDATE() )
AND
MONTH( adate ) = MONTH( GETDATE() )
It sounds to me like DATEDIFF is exactly what you need:
-- #1 same month and year
SELECT *
FROM your_table
WHERE DATEDIFF(month, your_column, GETDATE()) = 0
-- #2 same year
SELECT *
FROM your_table
WHERE DATEDIFF(year, your_column, GETDATE()) = 0
The datepart function lets you pull the bits you need:
declare #d1 as datetime
declare #d2 as datetime
if datepart(yy, #d1) = datepart(yy, #d2) and datepart(mm, #d1) = datepart(mm, #d2) begin
print 'same'
end
You can use something like this
a)
select *
from table
where MONTH(field) = MONTH(GetDATE())
and YEAR(field) = YEAR(GetDATE())
b)
select *
from table
where YEAR(field) = YEAR(GetDATE())