SQL Date Calculation formatting - sql

It's been a while since I posted. I have an issue regarding date calculations.
I am trying to find the difference between two dates as in start time and finish time.
I have been able to find the difference in days so for instance if I have the dates:
start = 12/11/2014 12:05:05
finish = 13/11/2014 09:44:19
then the query gives me -0.90224537......
However, I need the answer in the form of hours, minutes, seconds for wage purposes. What is the best way of doing this?
My query so far is:
select
time_sheet.time_sheet_id,
time_sheet.start_date_time - time_sheet.finish_date_time,
employee_case.case, employee_case.employee
from
time_sheet
inner join
employee_case on time_sheet.employee_case = employee_case.employee_case_id
where
employee_case.case = 1;
P.S. I am using an Oracle database :)


date - date yields the difference in days. So you can use the standard time conversion to convert it to hours,minutes and seconds as below:
select
time_sheet.time_sheet_id,
(time_sheet.finish_date_time - time_sheet.start_date_time)||' days'||(time_sheet.finish_date_time - time_sheet.start_date_time)*24||' hours '||(time_sheet.finish_date_time - time_sheet.start_date_time)*24*60||' minutes '||(time_sheet.finish_date_time - time_sheet.start_date_time)*24*60*60||' seconds ' ,
employee_case.case, employee_case.employee
from
time_sheet
inner join
employee_case on time_sheet.employee_case = employee_case.employee_case_id
where
employee_case.case = 1;
Also, you would need finish_date_time as the minuend and start_date_time as the subtrahend to avoid negative values.


Thanks for the help toddlermenot but i have decided to go another way I have found. For anybody else who has the same issue I have done the following:
select
time_sheet.time_sheet_id,
to_number( to_char(to_date('1','J') +
(time_sheet.finish_date_time - time_sheet.start_date_time), 'J') - 1) days,
to_char(to_date('00:00:00','HH24:MI:SS') +
(time_sheet.finish_date_time - time_sheet.start_date_time), 'HH24:MI:SS') time,
employee_case.case, employee_case.employee
from
time_sheet
inner join
employee_case on time_sheet.employee_case = employee_case.employee_case_id
where
employee_case.case = 1;
This seems to do exactly what I need. It does the days in a serperate field to the hours minutes and seconds but for my purposes this is acceptable

Related

Get data when date is equal to or greater than 90 days ago

I wonder if anyone here can help with a BigQuery piece I am working on.
I'm trying to pull the date, email and last interaction time from a dataset when the last interaction time is equal to or greater than 90 days ago.
I have the following query:
SELECT
date,
user_email,
DATE_FROM_UNIX_DATE(gmail.last_interaction_time) AS Last_Interaction_Date,
DATE_ADD(CURRENT_DATE(), INTERVAL -90 DAY) AS Days_ago
FROM
`bqadminreporting.adminlogtracking.usage`
WHERE
'Last_Interaction_Date' >= 'Days_ago'
However, I run into the following error:
DATE value is out of allowed range: from 0001-01-01 to 9999-12-31
As far as I can see, it makes sense - so not entirely sure why its throwing out an error?

Looks like you have some inconsistent values (data) in filed gmail.last_interaction_time, which you need to handle to avoid error.
Moreover above query will not work as per your expected WHERE conditions, you should use following query to get expected output.
SELECT * FROM
(SELECT
date,
user_email,
DATE_FROM_UNIX_DATE(gmail.last_interaction_time) AS Last_Interaction_Date,
DATE_ADD(CURRENT_DATE(), INTERVAL -90 DAY) AS Days_ago
FROM
`bqadminreporting.adminlogtracking.usage`)
WHERE
Last_Interaction_Date >= Days_ago

Presumably, your problem is DATE_FROM_UNIX_DATE(). Without sample data, it is not really possible to determine what the issue is.
However, you don't need to convert to a date to do this. You can do all the work in the Unix seconds space:
select u.*
from `bqadminreporting.adminlogtracking.usage` u
where gmail.last_interaction_time >= unix_seconds(timestamp(current_date)) - 90 * 60 * 60 * 24
Note that I suspect that the issue is that last_interaction_time is really measured in milliseconds or microseconds or some other unit. This will prevent your error, but it might not do what you want.

Date inside current timestamp - IBM DB2

I have a column (ROW_UPDATE_TIME) in a table where it stores the timestamp when an update happens in this table.
I'd like to know how to check rows that the timestamp is today.
This is what I'm using now, but it's not a pretty solution I think:
SELECT
*
FROM
TABLE
WHERE
ROW_UPDATE_TIME BETWEEN (CURRENT TIMESTAMP - 1 DAY) AND (CURRENT TIMESTAMP + 1 DAY);
Is there a better solution, example: ROW_UPDATE_TIME = CURRENT DATE, or something like that?

Found it:
SELECT
*
FROM
TABLE
WHERE
DATE(ROW_UPDATE_TIME) = CURRENT DATE;

The first version you have provided will not return you the results you expect, because you will get in the result timestamps from today or tomorrow, depends on the hour you run it.
Use the query below to get the results from today:
SELECT
*
FROM
table
WHERE
row_update_time
BETWEEN TIMESTAMP(CURRENT_DATE,'00:00:00')
AND TIMESTAMP(CURRENT_DATE,'23:59:59')
Avoid applying a function to a column you compare in the where clause(DATE(row_update_time) = CURRENT_DATE) . That will cause the optimizer to run the function against each row, just to allocate the data you need. It could slow down the query dramatically. Try to run explain against the two versions and you will see what I mean.

How to show rows where date is equal to every 7 days from a specific day

I'd like to show every row where date_added equals '2015-02-18' and every seven days after, so '2015-02-25' and '2015-03-04' etc..
here's what I have so far
select * from table
where ((to_char(date_added, 'j')) /
((select to_char(d,'j') from (select date '2015-02-18' d from dual)))) = 1
That gets me the first desired date, however I'm stuck as to how to express it to show the next 7 days as a step additive function.
Any help is appreciated. Thank you.

One way to do this is with mod():
select *
from table
where mod(date_added - date '2015-02-18', 7) = 0;
Note: this assumes that the dates have no time component. If they do, then use trunc() to get rid of it.

I like Gordon's "mod()" solution but he's missing part of the requested solution.
In this case, I have a "calendar" table that includes a series of dates:
http://www.perpendulum.com/2012/06/calendar-table-script-for-oracle/
select *
from calendar
where date_time_start >= to_date('01-Jan-2013')
and mod(trunc(date_time_start) - to_date('01-Jan-2013'), 7) = 0;
Per the original question, you want records where the dates are equal to a given date and every seven days thereafter.

How to get a SUM of a DATEDIFF but provide cut-off at 24 hours IF a single day is specified

This is actually my first question on stackoverflow, so I sincerely apologize if I am confusing or unclear.
That being said, here is my issue:
I work at a car manufacturing company and we have recently implemented the ability to track when our machines are idle. This is done by assessing the start and end time of the event called "idle_start."
Right now, I am trying to get the SUM of how long a machine is idle. Now, I figured this out BUT, some of the idle_times are LONGER than 24 hours.
So, when I specify that I only want to see the idle_time sums of ONE particular day, the sum is also counting the idle time past 24 hours.
I want to provide the option of CUTTING OFF at that 24 hours. Is this possible?
Here is the query:
{code}
SELECT r.`name` 'Producer'
, m.`name` 'Manufacturer'
-- , timediff(re.time_end, re.time_start) 'Idle Time Length'
, SEC_TO_TIME(SUM((TIME_TO_SEC(TIMEDIFF(re.time_end, re.time_start))))) 'Total Time'
, (SUM((TIME_TO_SEC(TIMEDIFF(re.time_end, re.time_start)))))/3600 'Total Time in Hours'
, (((SUM((TIME_TO_SEC(TIMEDIFF(re.time_end, re.time_start)))))/3600))/((IF(r.resource_status_id = 2, COUNT(r.resource_id), NULL))*24) 'Percent Machine is Idle divided by Machine Hours'
FROM resource_event re
JOIN resource_event_type ret
ON re.resource_event_type_id = ret.resource_event_type_id
JOIN resource_event_type reep
ON ret.parent_resource_event_type_id = reep.resource_event_type_id
JOIN resource r
ON r.`resource_id` = re.`resource_id`
JOIN manufacturer m
ON m.`manufacturer_id` = r.`manufacturer_id`
WHERE re.`resource_event_type_id` = 19
AND ret.`parent_resource_event_type_id` = 3
AND DATE_FORMAT(re.time_start, '%Y-%m-%d') >= '2013-08-12'
AND DATE_FORMAT(re.time_start, '%Y-%m-%d') <= '2013-08-18'
-- AND re.`resource_id` = 8
AND "Idle Time Length" IS NOT NULL
AND r.manufacturer_id = 13
AND r.resource_status_id = 2
GROUP BY 1, 2
Feel free to ignore the dash marks up top. And please tell me if I can be more specific as to figure this out easier and provide less headaches for those willing to help me out.
Thank you so much!

You'll want a conditional SUM, using CASE.
Not sure of syntax for your db exactly, but something like:
, SUM (CASE WHEN TIME_TO_SEC(TIMEDIFF(re.time_end, re.time_start))/3600 > 24 THEN 0
ELSE TIME_TO_SEC(TIMEDIFF(re.time_end, re.time_start))/3600
END)'Total Time in Hours'

This is not an attempt to answer your question. It's being presented as an answer rather than a comment for better formatting and readability.
You have this
AND DATE_FORMAT(re.time_start, '%Y-%m-%d') >= '2013-08-12'
AND DATE_FORMAT(re.time_start, '%Y-%m-%d') <= '2013-08-18'
in your where clause. Using functions like this make your query take longer to execute, especially on indexed fields. Something like this would run quicker.
AND re.time_start >= a date value goes here
AND re.time_start <= another date value goes here

Do you want to cut off when start/end are before/after your time range?
You can use a case to adjust it based on your timeframe, e.g. for time_start
case
when re.time_start < timestamp '2013-08-12 00:00:00'
then timestamp '2013-08-12 00:00:00'
else re.time_start
end
similar for time_end and then use those CASEs within your TIMEDIFF.
Btw, your where-condition for a given date range should be:
where time_start < timestamp '2013-08-19 00:00:00'
and time_end >= timestamp '2013-08-12 00:00:00'
This will return all idle times between 2013-08-12 and 2013-08-18

Calculating working days including holidays between dates without a calendar table in oracle SQL

Okay, so I've done quite a lot of reading on the possibility of emulating the networkdays function of excel in sql, and have come to the conclusion that by far the easiest solution is to have a calendar table which will flag working days or non working days. However, due to circumstances out of my control, we don't have access to such a luxury and it's unlikely that we will any time in the near future.
Currently I have managed to bodge together what is undoubtedly a horrible ineffecient query in SQL that does work - the catch is, it will only work for a single client record at a time.
SELECT O_ASSESSMENTS.ASM_ID,
O_ASSESSMENTS.ASM_START_DATE,
O_ASSESSMENTS.ASM_END_DATE,
sum(CASE
When TO_CHAR(O_ASSESSMENTS.ASM_START_DATE + rownum -1,'Day')
= 'Sunday ' THEN 0
When TO_CHAR(O_ASSESSMENTS.ASM_START_DATE + rownum -1,'Day')
= 'Saturday ' THEN 0
WHEN O_ASSESSMENTS.ASM_START_DATE + rownum - 1
IN ('03-01-2000','21-04-2000','24-04-2000','01-05-2000','29-05-2000','28-08-2000','25-12-2000','26-12-2000','01-01-2001','13-04-2001','16-04-2001','07-05-2001','28-05-2001','27-08-2001','25-12-2001','26-12-2001','01-01-2002','29-03-2002','01-04-2002','06-04-2002','03-06-2002','04-06-2002','26-08-2002','25-12-2002','26-12-2002','01-01-2003','18-04-2003','21-04-2003','05-05-2003','26-05-2003','25-08-2003','25-12-2003','26-12-2003','01-01-2004','09-04-2004','12-04-2004','03-05-2004','31-05-2004','30-08-2004','25-12-2004','26-12-2004','27-12-2004','28-12-2004','01-01-2005','03-01-2005','25-03-2005','28-03-2005','02-05-2005','30-05-2005','29-08-2005','27-12-2005','28-12-2005','02-01-2006','14-04-2006','17-04-2006','01-05-2006','29-05-2006','28-08-2006','25-12-2006','26-12-2006','02-01-2007','06-04-2007','09-04-2007','07-05-2007','28-05-2007','27-08-2007','25-12-2007','26-12-2007','01-01-2008','21-03-2008','24-03-2008','05-05-2008','26-05-2008','25-08-2008','25-12-2008','26-12-2008','01-01-2009','10-04-2009','13-04-2009','04-05-2009','25-05-2009','31-08-2009','25-12-2009','28-12-2009','01-01-2010','02-04-2010','05-04-2010','03-05-2010','31-05-2010','30-08-2010','24-12-2010','27-12-2010','28-12-2010','31-12-2010','03-01-2011','22-04-2011','25-04-2011','29-04-2011','02-05-2011','30-05-2011','29-08-2011','26-12-2011','27-12-2011')
THEN 0
ELSE 1
END)-1 AS Week_Day
From O_ASSESSMENTS,
ALL_OBJECTS
WHERE O_ASSESSMENTS.ASM_QSA_ID IN ('TYPE1')
AND O_ASSESSMENTS.ASM_END_DATE >= '01/01/2012'
AND O_ASSESSMENTS.ASM_ID = 'A00000'
AND ROWNUM <= O_ASSESSMENTS.ASM_END_DATE-O_ASSESSMENTS.ASM_START_DATE+1
GROUP BY
O_ASSESSMENTS.ASM_ID,
O_ASSESSMENTS.ASM_START_DATE,
O_ASSESSMENTS.ASM_END_DATE
Basically, I'm wondering if a) I should stop wasting my time on this or b) is it possible to get this to work for multiple clients? Any pointers appreciated thanks!
Edit: Further clarification - I already work out timescales using excel, but it would be ideal if we could do it in the report as the report in question is something that we would like end users to be able to run without any further manipulation.
Edit:
MarkBannister's answer works perfectly albeit slowly (though I had expected as much given it's not the preferred solution) - the challenge now lies in me integrating this into an existing report!
with
calendar_cte as (select
to_date('01-01-2000')+level-1 calendar_date,
case when to_char(to_date('01-01-2000')+level-1, 'day') in ('sunday ','saturday ') then 0 when to_date('01-01-2000')+level-1 in ('03-01-2000','21-04-2000','24-04-2000','01-05-2000','29-05-2000','28-08-2000','25-12-2000','26-12-2000','01-01-2001','13-04-2001','16-04-2001','07-05-2001','28-05-2001','27-08-2001','25-12-2001','26-12-2001','01-01-2002','29-03-2002','01-04-2002','06-04-2002','03-06-2002','04-06-2002','26-08-2002','25-12-2002','26-12-2002','01-01-2003','18-04-2003','21-04-2003','05-05-2003','26-05-2003','25-08-2003','25-12-2003','26-12-2003','01-01-2004','09-04-2004','12-04-2004','03-05-2004','31-05-2004','30-08-2004','25-12-2004','26-12-2004','27-12-2004','28-12-2004','01-01-2005','03-01-2005','25-03-2005','28-03-2005','02-05-2005','30-05-2005','29-08-2005','27-12-2005','28-12-2005','02-01-2006','14-04-2006','17-04-2006','01-05-2006','29-05-2006','28-08-2006','25-12-2006','26-12-2006','02-01-2007','06-04-2007','09-04-2007','07-05-2007','28-05-2007','27-08-2007','25-12-2007','26-12-2007','01-01-2008','21-03-2008','24-03-2008','05-05-2008','26-05-2008','25-08-2008','25-12-2008','26-12-2008','01-01-2009','10-04-2009','13-04-2009','04-05-2009','25-05-2009','31-08-2009','25-12-2009','28-12-2009','01-01-2010','02-04-2010','05-04-2010','03-05-2010','31-05-2010','30-08-2010','24-12-2010','27-12-2010','28-12-2010','31-12-2010','03-01-2011','22-04-2011','25-04-2011','29-04-2011','02-05-2011','30-05-2011','29-08-2011','26-12-2011','27-12-2011','01-01-2012','02-01-2012') then 0 else 1 end working_day
from dual
connect by level <= 1825 + sysdate - to_date('01-01-2000') )
SELECT
a.ASM_ID,
a.ASM_START_DATE,
a.ASM_END_DATE,
sum(c.working_day)-1 AS Week_Day
From
O_ASSESSMENTS a
join calendar_cte c
on c.calendar_date between a.ASM_START_DATE and a.ASM_END_DATE
WHERE a.ASM_QSA_ID IN ('TYPE1')
and a.ASM_END_DATE >= '01/01/2012'
GROUP BY
a.ASM_ID,
a.ASM_START_DATE,
a.ASM_END_DATE

There are a few ways to do this. Perhaps the simplest might be to create a CTE that produces a virtual calendar table, based on Oracle's connect by syntax, and then join it to the Assesments table, like so:
with calendar_cte as (
select to_date('01-01-2000')+level-1 calendar_date,
case when to_char(to_date('01-01-2000')+level-1, 'Day')
in ('Sunday ','Saturday ') then 0
when to_date('01-01-2000')+level-1
in ('03-01-2000','21-04-2000','24-04-2000','01-05-2000','29-05-2000','28-08-2000','25-12-2000','26-12-2000','01-01-2001','13-04-2001','16-04-2001','07-05-2001','28-05-2001','27-08-2001','25-12-2001','26-12-2001','01-01-2002','29-03-2002','01-04-2002','06-04-2002','03-06-2002','04-06-2002','26-08-2002','25-12-2002','26-12-2002','01-01-2003','18-04-2003','21-04-2003','05-05-2003','26-05-2003','25-08-2003','25-12-2003','26-12-2003','01-01-2004','09-04-2004','12-04-2004','03-05-2004','31-05-2004','30-08-2004','25-12-2004','26-12-2004','27-12-2004','28-12-2004','01-01-2005','03-01-2005','25-03-2005','28-03-2005','02-05-2005','30-05-2005','29-08-2005','27-12-2005','28-12-2005','02-01-2006','14-04-2006','17-04-2006','01-05-2006','29-05-2006','28-08-2006','25-12-2006','26-12-2006','02-01-2007','06-04-2007','09-04-2007','07-05-2007','28-05-2007','27-08-2007','25-12-2007','26-12-2007','01-01-2008','21-03-2008','24-03-2008','05-05-2008','26-05-2008','25-08-2008','25-12-2008','26-12-2008','01-01-2009','10-04-2009','13-04-2009','04-05-2009','25-05-2009','31-08-2009','25-12-2009','28-12-2009','01-01-2010','02-04-2010','05-04-2010','03-05-2010','31-05-2010','30-08-2010','24-12-2010','27-12-2010','28-12-2010','31-12-2010','03-01-2011','22-04-2011','25-04-2011','29-04-2011','02-05-2011','30-05-2011','29-08-2011','26-12-2011','27-12-2011')
then 0
else 1
end working_day
from dual
connect by level <= 36525 + sysdate - to_date('01-01-2000') )
SELECT a.ASM_ID,
a.ASM_START_DATE,
a.ASM_END_DATE,
sum(c.working_day) AS Week_Day
From O_ASSESSMENTS a
join calendar_cte c
on c.calendar_date between a.ASM_START_DATE and a.ASM_END_DATE
WHERE a.ASM_QSA_ID IN ('TYPE1') and
a.ASM_END_DATE >= '01/01/2012' -- and a.ASM_ID = 'A00000'
GROUP BY
a.ASM_ID,
a.ASM_START_DATE,
a.ASM_END_DATE
This will produce a virtual table populated with dates from 01 January 2000 to 10 years after the current date, with all weekends marked as non-working days and all days specified in the second in clause (ie. up to 27 December 2011) also marked as non-working days.
The drawback of this method (or any method where the holiday dates are hardcoded into the query) is that each time new holiday dates are defined, every single query that uses this approach will have to have those dates added.

If you can't use a calendar table in Oracle, you might be better off exporting to Excel. Brute force always works.
Networkdays() "returns the number of whole working days between start_date and end_date. Working days exclude weekends and any dates identified in holidays."
Excluding weekends seems fairly straightforward. Every 7-day period will contain two weekend days. You'll just need to take some care with the leftover days.
Holidays are a different story. You have to either store them or pass them as an argument. If you could store them, you'd store them in a calendar table, and your problem would be over. But you can't do that.
So you're looking at passing them as an argument. Off the top of my head--and I haven't had any tea yet this morning--I'd consider a common table expression or a wrapper for a stored procedure.