I want a SQL query to follow the conditions of a WHERE statement, except those that are subqueries. In the example below, I'd like to get all entries from the past week, but I want the subqueries to ignore that outer WHERE clause, but I'm not sure of how it will behave.
For example:
SELECT
ProductID,
SUM(CASE WHEN from_source = 'button' THEN 1 ELSE 0 END) 'Used Button',
(SELECT COUNT(*) FROM tracking WHERE from_source = 'button') 'Used Button to date'
FROM tracking
WHERE date_entered > (GETDATE() - 7)
GROUP BY ProductID
Expected output, where the second column is calculating based on outer WHERE, and subquery is not looking at the outer WHERE:
ProductID | Used Button | Used Button to date
123 | 5 | 102
456 | 8 | 175
You could write the query just using conditional aggregation:
select sum(case when date_entered > (GETDATE() - 7) then 1 else 0
end) as UsedButton,
count(*) as UsedButtonToDate
from tracking
where from_source = 'button';
This seems like a simpler approach.
By the way, you shouldn't use single quotes for column aliases. Either name the columns with something that doesn't have to be escaped (as above) or use square braces.
Related
SELECT
SELECT pp.id, TO_CHAR(pp.created_dt::date, 'dd.mm.yyyy') AS "Date", CAST(pp.created_dt AS time(0)) AS "Time",
au.username AS "User", ss.name AS "Service", pp.amount, REPLACE(pp.status, 'SUCCESS', ' ') AS "Status",
pp.account AS "Props", pp.external_id AS "External", COALESCE(pp.external_status, null, 'indefined') AS "External status"
FROM payment AS pp
INNER JOIN auth_user AS au ON au.id = pp.creator_id
INNER JOIN services_service AS ss ON ss.id = pp.service_id
WHERE pp.created_dt::date = (CURRENT_DATE - INTERVAL '1' day)::date
AND ss.name = 'Some Name' AND pp.status = 'SUCCESS'
id | Date | Time | Service |amount | Status |
------+-----------+-----------+------------+-------+--------+---
9 | 2021.11.1 | 12:20:01 | some serv | 100 | stat |
10 | 2021.12.1 | 12:20:01 | some serv | 89 | stat |
------+-----------+-----------+------------+-------+--------+-----
Total | | | | 189 | |
I have a SELECT like this. I need to get something like the one shown above. That is, I need to get the total of one column. I've tried a lot of things already, but nothing works out for me.
If I understand correctly you want a result where extra row with aggregated value is appended after result of original query. You can achieve it multiple ways:
1. (recommended) the simplest way is probably to union your original query with helper query:
with t(id,other_column1,other_column2,amount) as (values
(9,'some serv','stat',100),
(10,'some serv','stat',89)
)
select t.id::text, t.other_column1, t.other_column2, t.amount from t
union all
select 'Total', null, null, sum(amount) from t
2. you can also use group by rollup clause whose purpose is exactly this. Your case makes it harder since your query contains many columns uninvolved in aggregation. Hence it is better to compute aggregation aside and join unimportant data later:
with t(id,other_column1,other_column2,amount) as (values
(9,'some serv','stat',100),
(10,'some serv','stat',89)
)
select case when t.id is null then 'Total' else t.id::text end as id
, t.other_column1
, t.other_column2
, case when t.id is null then ext.sum else t.amount end as amount
from (
select t.id, sum(amount) as sum
from t
group by rollup(t.id)
) ext
left join t on ext.id = t.id
order by ext.id
3. For completeness I just show you what should be done to avoid join. In that case group by clause would have to use all columns except amount (to preserve original rows) plus the aggregation (to get the sum row) hence the grouping sets clause with 2 sets is handy. (The rollup clause is special case of grouping sets after all.) The obvious drawback is repeating case grouping... expression for each column uninvolved in aggregation.
with t(id,other_column1,other_column2,amount) as (values
(9,'some serv','stat',100),
(10,'some serv2','stat',89)
)
select case grouping(t.id) when 0 then t.id::text else 'Total' end as id
, case grouping(t.id) when 0 then t.other_column1 end as other_column1
, case grouping(t.id) when 0 then t.other_column2 end as other_column2
, sum(t.amount) as amount
from t
group by grouping sets((t.id, t.other_column1, t.other_column2), ())
order by t.id
See example (db fiddle):
(To be frank, I can hardly imagine any purpose other than plain reporting where a column mixes id of number type with label Total of text type.)
My goal is something like following table:
Key | Count since date X | Count total
1 | 4 | 28
With two simple selects I could gain this values: (the key of the table consists of 3 columns [t$ncmp, t$trav, t$seqn])
1. SELECT COUNT(*) FROM db.table WHERE t$date >= sysdate-2 GROUP BY t$ncmp, t$trav, t$seqn
2. SELECT COUNT(*) FROM db.table GROUP BY t$ncmp, t$trav, t$seqn
How can I join these statements?
What I tried:
SELECT n.t$trav, COUNT(n.t$trav), m.total FROM db.table n
LEFT JOIN (SELECT t$ncmp, t$trav, t$seqn, COUNT(*) as total FROM db.table
GROUP BY t$ncmp, t$trav, t$seqn) m
ON (n.t$ncmp = m.t$ncmp AND n.t$trav = m.t$trav AND n.t$seqn = m.t$seqn)
WHERE n.t$date >= sysdate-2
GROUP BY n.t$ncmp, n.t$trav, n.t$seqn
I tried different variantes, but always got errors like 'group by is missing' or 'unknown qualifier'.
Now this at least executes, but total is always 2.
T$TRAV COUNT(N.T$TRAV) TOTAL
4 2 2
29 3 2
51 1 2
62 2 2
16 1 2
....
If it matter, I will run this as an OPENQUERY from MSSQLSERVER to Oracle-DB.
I'd try
GROUP BY n.t$trav, m.total
You typically GROUP BY the same columns as you SELECT - except those who are arguments to set functions.
My goal is something like following table:
If so, you seem to want conditional aggregation:
select key, count(*) as total,
sum(case when datecol >= date 'xxxx-xx-xx' then 1 else 0 end) as total_since_x
from t
group by key;
I'm not sure how this relates to your sample queries. I simply don't see the relationship between that code and your question.
I have a query that returns two amounts. I would like to sum them together, while leaving one as it is returned by the query.
For example:
DESC | sum(AMOUNT)
A | -61149025.940000
B | -9696.910000
B needs to be the sum of B and A and replace the current value. A stays as is on the result of the query.
My SQL is similar to this:
Select SQ.DESC, SUM(SQ.AMOUNT)
FROM (subquery) SQ
GROUP by SQ.DESC
My return results would be
DESC | sum(AMOUNT)
A | -61149025.940000
B | -61158722.850000
I have not been able to logically make sense of this
If you want "B" to be the total of all the values, you can use window functions:
Select SQ.DESC,
(CASE WHEN SQ.DESC = 'A' THEN SUM(SQ.AMOUNT)
WHEN SQ.DESC = 'B' THEN SUM(SUM(SQ.AMOUNT)) OVER ()
END) as SUM_AMOUNT
FROM (subquery) SQ
GROUP by SQ.DESC
Note: Even if Teradata allows DESC as a column name, it is a poor choice because DESC is a SQL keyword (think ORDER BY).
I should probably be able to figure this out from other questions/answers I've read here, but I just can't get anything to work today. Any help is really appreciated.
I have two queries, counting the instances of "GOOD" feedback, and "BAD" feedback from a single table. I just want to join them so that I can see something like below
ID | GOOD | BAD
121 | 0 | 7
123 | 5 | 0
287 | 32 | 8
I'm running numerous queries from VBA, if that matters, and the 0's can just be null. I can clean that stuff up in VBA.
Query 1:
select ID, count(*)
from HLFULL
where DEPT= 'HLAK'
and feedback = 'GOOD'
group by ID
Query 2:
select ID, count(*)
from HLFULL
where DEPT= 'HLAK'
and feedback = 'BAD'
group by ID
I've tried UNION, UNION ALL, JOIN, INNER JOIN, OUTER JOIN, aggregations, etc.
You can do conditional aggregation like this:
select ID,
count(case when feedback = 'GOOD' then 1 end) as Good,
count(case when feedback = 'BAD' then 1 end) as Bad
from HLFULL
where DEPT = 'HLAK'
and feedback in ('GOOD', 'BAD')
group by ID
You should be able to get the result using conditional aggregation. This type of query uses a CASE expression along with your aggregate function to get multiple columns:
select ID,
count(case when feedback = 'GOOD' then Id end) as Good,
count(case when feedback = 'BAD' then Id end) as Bad
from HLFULL
where DEPT= 'HLAK'
group by ID
I have the following SQL Code which is not giving me my desired results.
SELECT
POLICIES.CLIENTS_ID,
POLICIES.CLIENTCODE,
COUNT(POLICIES.POLICIES_ID) as [Total Policies],
(
SELECT
COUNT(POLICIES.POLICIES_ID)
FROM
POLICIES
WHERE
POLICIES.COVCODE = 'AUT'
) as [Auto Policies]
FROM
POLICIES
LEFT JOIN CLIENTS
ON CLIENTS.CLIENTS_ID = POLICIES.CLIENTS_ID
WHERE
POLICIES.CNR IS NULL
GROUP BY
POLICIES.CLIENTS_ID,
POLICIES.CLIENTCODE
ORDER BY
POLICIES.CLIENTS_ID
I get a result like this:
ID CODE Total Auto
3 ABCDE1 1 999999
4 ABCDE2 1 999999
5 ABCDE3 2 999999
6 ABCDE4 2 999999
I would like for the last column to COUNT the total auto policies that exists for that clientid rather than all of the auto policies that exist. I believe I need a nested select statement that somehow groups all like results on the clientid, but it ends up returning more than 1 row and throws the error.
If I add:
GROUP BY
POLICIES.CLIENTS_ID
I get:
Subquery returned more than 1 value. This is not permitted when the....
Any help would be appreciated greatly!
Thank you
You can use a CASE statement to do this. Instead of your subquery in the SELECT clause use:
SUM(CASE WHEN POLICIES.COVCODE = 'AUT' THEN 1 ELSE 0 END) as [AUTO POLICIES]
As Martin Smith pointed out. If client_id has multiple client_codes then this will give you the count of records for each combination of client_id/client_code. If client_id is 1:1 with client_code then this will give you a count of records for each distinct client_id, which I suspect is the case from your example and question.
Unrelated: You have a LEFT JOIN to your Clients table, but you don't use your Clients table anywhere int he query. Consider removing it if you don't need to select or filter by any its fields, since it's just unused overhead.
What if you modify the inner query for getting count to something like
SUM(CASE WHEN POLICIES.COVCODE = 'AUT' THEN 1 ELSE 0 END) as [Auto Policies]