I'd like to insert these values in the following fashion:
insert into table (name, action-id) values ('user', select action from actions where name='user2');
The result being:
Inserts along the line of, ('user', 1) ('user', 2) ('user', 3)
I'm noticing this isn't correct sql.
How would I go about accomplishing this?
note)
select action from actions where name='user2'
would return: (1, 2, 3)
You can do it with a loop:
BEGIN
FOR x IN (select action from actions where name='user2') LOOP
insert into table (name, action-id) values ('user', x.action)
END LOOP;
END;
or you could use the INSERT/SELECT syntax:
INSERT INTO table (name, action-id)
SELECT 'user', action
FROM actions WHERE name='user2';
Add the fixed value as a column in your query, and use insert-select instead of insert-values:
insert into table (name, action-id)
select 'user', action from actions where name='user2';
Or can be done by procedure
Create that procedure and run it
create or replace procedure set_action
as
cursor c1 is
select * from user;
person c1%rowtype;
username varchar(8);
begin
username:='user';
for person in c1 loop
insert into table(name,action-id)
values (username,person.action);
end loop;
end;
It can be run by execute set_action;
Example:
create table testing(col1 varchar2(10), col2 varchar2(10));
create table testing2(col1 varchar2(10), col2 varchar2(10));
create table testing3(col1 varchar2(10), col2 int);
insert into testing2 (col1, col2) values ('test2_col1', 'test2_col2');
insert into testing3(col1, col2) values ('steve', 1);
insert into testing3(col1, col2) values ('brad', 2);
insert into testing3(col1, col2) values ('chad', 3);
insert into testing3(col1, col2) values ('nick', 1);
insert into testing(col1, col2)
(select col1 ,(select col2 from testing2) from testing3); -- inserts 4 rows
And finally:
select * from testing;
steve test2_col2
brad test2_col2
chad test2_col2
nick test2_col2
Related
I have a table having one of the columns that stores SQL query.
create table test1
(
name varchar(20),
stmt varchar(500)
);
insert into test1 (name, stmt)
values ('first', 'select id from data where id = 1;')
Data table is like:
create table data
(
id number,
subject varchar(500)
);
insert into data (id, subject) values (1, 'test subject1');
insert into data (id, subject) values (2, 'test subject2');
insert into data (id, subject) values (3, 'test subject2');
Now every time on insert in test1, I need to execute the query that gets inserted in stmt column of test1 and insert queried data to result table:
create table result
(
id number,
subject varchar(500)
);
For that I am writing a trigger that gets executed on every insert in test1 like as follows:
create or replace TRIGGER "TEST_AFTER_INSERT"
BEFORE INSERT or UPDATE ON test1
FOR EACH ROW
DECLARE
sql_stmt VARCHAR2(500);
BEGIN
select stmt into sql_stmt from data where name = :NEW.name;
insert into result(id, subject)
select id,subject from data where id in ('stmt');
END;
Could you please let me know how to achieve this, above trigger is throwing error that I am not able to understand.
You can use a dynamic query in your trigger as follows:
CREATE OR REPLACE TRIGGER "TEST_AFTER_INSERT" AFTER -- CHANGED IT TO AFTER AS NAME SUGGESTS
INSERT OR UPDATE ON TEST1
FOR EACH ROW -- REMOVED DECLARE SECTION
BEGIN
EXECUTE IMMEDIATE 'INSERT INTO result
SELECT ID, SUBJECT FROM DATA WHERE ID IN ('
|| RTRIM(:NEW.STMT, ';')
|| ')';
-- SINGLE QUERY TO INSERT THE DATA
-- USED RTRIM AS STMT HAS ; AT THE END
END;
Cheers!!
Consider direct insertion :
CREATE OR REPLACE TRIGGER "TEST_AFTER_INSERT"
BEFORE INSERT or UPDATE ON test1
FOR EACH ROW
DECLARE
BEGIN
insert into result(id, subject)
select id, subject from data where name = :NEW.name;
END;
I am working with ORACLE SQL Developer and I created a table with an id as PK, another FK, id_columnx and a column1 and inserted data into them. Then I added another 2 columns, column 2 and column 3 and when I try to insert data into these new added columns, I get the error:
ORA-01400: cannot insert NULL.
I have to mention that I don't have any triggers on the table and i DO have values in the INSERT statement. There seems to be a conflict with the PK id, but I don't understand why.
So here is the code:
create table mytable(id INT PRIMARY KEY, name varchar2(30));
insert into mytable values (1, 'Mary');
insert into mytable values (2, 'John');
insert into mytable values (3, 'Bill');
alter table mytable
add email VARCHAR2(30);
alter table mytable
add addess VARCHAR2(30);
insert into mytable (email, addess)
values ('mary#gmail.com', 'Street X');
And here is the error I get:
Error starting at line : 12 in command -
insert into mytable (email, addess)
values ('mary#gmail.com', 'Street X')
Error report -
ORA-01400: cannot insert NULL into ("ZAMFIRESCUA_49"."MYTABLE"."ID")
INSERT is for inserting new rows, UPDATE is for altering data in the current rows. As mentioned in the comments, it looks like you want to be updating Mary's row with her email/address:
UPDATE mytable
SET email = 'mary#gmail.com',
address = 'Street X'
WHERE ID = 1 --Mary's ID for example, replace with the ID of the row you want to update
You could also use a subquery to find the right ID so you don't have to always look it up:
UPDATE mytable
SET email = 'mary#gmail.com',
address = 'Street X'
WHERE ID = (SELECT ID FROM mytable WHERE name = 'Mary')
Edit:
I was thinking there were two tables while writing this answer, you could always just use the name field as your filter:
UPDATE mytable
SET email = 'mary#gmail.com',
address = 'Street X'
WHERE name = 'Mary'
You're missing a PK value in your last INSERT after the ALTER statements. Try this:
create table mytable(id INT PRIMARY KEY, name varchar2(30));
insert into mytable values (1, 'Mary');
insert into mytable values (2, 'John');
insert into mytable values (3, 'Bill');
alter table mytable add email VARCHAR2(30);
alter table mytable add addess VARCHAR2(30);
insert into mytable (id, email, addess) values (4, 'mary#gmail.com', 'Street X');
I am trying to insert into 3 tables from one single select statement. Here is what I am trying to do:
insert into dbo.temp1 (name, location, city)
select name, location, city from mytable.
I want to be able to insert into 3 tables once I run the select statement like inserting into temp1, temp2 and temp3.
How can I do this? Thanks.
You can do it maximum for 2 tables with using output:
insert into dbo.temp1 (name, location, city)
output inserted.name, inserted.location, inserted.city into temp2
select name, location, city from mytable
You can't do this in one step*
What you can do is to insert the initial query into a #temp table (or a #table variable) as a staging area, and then insert into the tables from there. Wrap the steps in a transaction to retain ACID:
BEGIN TRAN
select name, location, city
into #TEMP
from mytable;
insert into temp1(name, location, city)
select name, location, city
from #TEMP;
-- Same for temp2 and temp3.
COMMIT TRAN
* Excluding hacks such as a view with an Instead-of Trigger.
The staging table is important from a concurrency point of view, as repeating the original query 3 times may result in different results if there are interim concurrent changes to the source table.
You can.
With a trick.
Create a view, then create an 'instead of' trigger for insert on that view where you insert the stuff into your tables. If you now insert into your view, you finally insert data in 3 tables. Here's a demo
-- 1. create 3 test tables
create table t1( id int, f1 varchar(20))
create table t2( id int, f2 varchar(20))
create table t3( id int, f3 varchar(20))
go
-- 2. create the view
create view Tt as
select t1.ID, t1.f1, t2.f2,t3.f3
from t1
join t2 on t1.ID=t2.ID
join t3 on t1.ID=t3.id
go
-- 3. create the trigger
create trigger Tr_Test on Tt INSTEAD OF INSERT
AS
BEGIN
SET NOCOUNT ON;
insert into t1 select id,f1 from inserted
insert into t2 select id,f2 from inserted
insert into t3 select id,f3 from inserted
END
GO
-- 4. now do your insert with a single select
insert into tt
select 1,'A','B','C'
-- 5. and watch the 3 tables
select * from t1
select * from t2
select * from t3
voilá, one insert, 3 tables got modified. Wwe don't count the hidden trigger, do we ;-)
There is no way to insert into X tables with one query (Ok it its with insert and output to table).
So you have to write 3 queries.
Or you can generate SQL statments with dynamic queries.
I don't believe you can insert into multiple tables in one statement. You can definitely do it in one transaction, however.
BEGIN TRANSACTION
INSERT INTO dbo.temp1 (name, location, city)
SELECT name, location, city
FROM myTable
INSERT INTO dbo.temp2 (name, location, city)
SELECT name, location, city
FROM myTable2
COMMIT TRANSACTION
You can insert into multiple tables with one select statement using a TRIGGER.
CREATE TRIGGER TEMP2_TEMP3_INSERT ON TEMP1
AFTER INSERT AS
BEGIN
/* create your insert statements for TEMP2 and TEMP3 here
referencing the data from the first insert */
END;
GO
MySQL doesn't support multi-table insertion in a single INSERT statement. Oracle is the only one I'm aware of that does, oddly...
However, you CAN use a transaction and have both of them be contained within one transaction.
MySQL:
START TRANSACTION;
INSERT INTO table1 VALUES ('1','2','3');
INSERT INTO table2 VALUES ('1','2','3');
COMMIT;
SQL Server:
BEGIN TRAN;
INSERT INTO table1 VALUES ('1','2','3');
INSERT INTO table2 VALUES ('1','2','3');
COMMIT;
SQL Server with error catching/rollback:
BEGIN TRANSACTION [Tran1]
BEGIN TRY
INSERT INTO table1 VALUES ('1','2','3')
INSERT INTO table2 VALUES ('1','2','3')
COMMIT TRANSACTION [Tran1]
END TRY
BEGIN CATCH
ROLLBACK TRANSACTION [Tran1]
END CATCH
GO
In my database all tables are using a common table for Sequence(ID_Table).
TABLE_ID has two fields (Common_ID, Table_Name).
If I insert any record in the table, I have to first insert a record in Table_ID(Auto-increment, Table_name) then use that Auto-increment value in my Other Table.
For example, I want to insert in Table_Products which has fields ID(Common_ID), Product_Name, Product_ID(Auto Increment)
I want to do something like this:
INSERT INTO TABLE_ID (Table_NAME), Values (Table_Products)
Get the Inserted ID and use it in Table_Products:
INSERT INTO Table_Products (ID, Product_Name, Product_ID(Auto Increment)
VALUES (ID from TABLE_ID, SomeProduct, Increment)
Try this one -
DECLARE #ID BIGINT
INSERT INTO dbo.TABLE_ID (Table_NAME)
SELECT 'Table_Products'
SELECT #ID = SCOPE_IDENTITY()
INSERT INTO dbo.Table_Products (ID, Product_Name)
SELECT #ID, 'SomeProduct'
You can use an insert statement with the output clause to generate a new Common_ID. Using insert ... select, you can specify that ID in an insert operation:
declare #Common_ID as table(ID int)
insert Table_ID
(Table_Name)
output inserted.Common_ID into #Common_ID
values ('Table_Products')
insert Table_Products
(ID, Product_Name)
select ID
, 'Some Product'
from #Common_ID
Use SCOPE_IDENTITY() after ur insert statementto get the last inserted id.
DECLARE #Product_Id int
INSERT INTO TABLE_ID (Table_NAME) VALUES (Table_Products);
SELECT #Product_Id=SCOPE_IDENTITY();
Insert INTO Table_Products (ID, Product_Name)
VALUES (ID from TABLE_ID, 'SomeProduct')
Dear friend you have to select id of last record inserted
and then pass it in another table so bellow code will help you very well
Insert INTO TABLE_ID (Table_NAME), Values (Table_Products)
DECLARE #ID int;
set #ID = SCOPE_IDENTITY();
Insert INTO Table_Products (ID, Product_Name)
Values (#ID, SomeProduct)
this code will solve your problem i define #ID for your last record id and then insert it in your other table
For MySql use select LAST_INSERT_ID();
All the other answers so far declare intermediary variables for SCOPE_IDENTITY(), but it could be simpler:
INSERT INTO dbo.TABLE_ID (Table_NAME) VALUES 'Table_Products';
INSERT INTO dbo.Table_Products (ID, Product_Name) VALUES (SCOPE_IDENTITY(),'SomeProduct');
You could be also more table-specific using IDENT_CURRENT()
Insert INTO TABLE_ID (Table_NAME), Values (Table_Products)
select #NewID=IDENT_CURRENT('TABLE_ID')
Insert INTO Table_Products (ID, Product_Name, Product_ID
Values (#NewID, SomeProduct, Increment)
When use a bunch of INSERT statements as below it takes forever :
INSERT INTO my_table ( col1, col2, id_col) VALUES ('val1', 'val1', (select max(my_table_ID) from my_table)+1);
If I run one by one and commit then it works fine. What is the reason?
I know sequence should be used in production. But I am writing this to insert few rows in toad.
may be
INSERT INTO my_table ( col1, col2, id_col)
VALUES ('val1', 'val1', (select max(my_table_ID)+1 from my_table));
or in pl/sql block
declare
v_max number(10);
begin
select max(my_table_id) + 1 into v_max
from my_table;
insert into my_table ( col1, col2, id_col)
values ('val1', 'val1', v_max);
end;
/
but, i don't know you task...
may be used sequence + trigger before insert?