MS SQL Server Last Inserted ID - sql

In my database all tables are using a common table for Sequence(ID_Table).
TABLE_ID has two fields (Common_ID, Table_Name).
If I insert any record in the table, I have to first insert a record in Table_ID(Auto-increment, Table_name) then use that Auto-increment value in my Other Table.
For example, I want to insert in Table_Products which has fields ID(Common_ID), Product_Name, Product_ID(Auto Increment)
I want to do something like this:
INSERT INTO TABLE_ID (Table_NAME), Values (Table_Products)
Get the Inserted ID and use it in Table_Products:
INSERT INTO Table_Products (ID, Product_Name, Product_ID(Auto Increment)
VALUES (ID from TABLE_ID, SomeProduct, Increment)

Try this one -
DECLARE #ID BIGINT
INSERT INTO dbo.TABLE_ID (Table_NAME)
SELECT 'Table_Products'
SELECT #ID = SCOPE_IDENTITY()
INSERT INTO dbo.Table_Products (ID, Product_Name)
SELECT #ID, 'SomeProduct'

You can use an insert statement with the output clause to generate a new Common_ID. Using insert ... select, you can specify that ID in an insert operation:
declare #Common_ID as table(ID int)
insert Table_ID
(Table_Name)
output inserted.Common_ID into #Common_ID
values ('Table_Products')
insert Table_Products
(ID, Product_Name)
select ID
, 'Some Product'
from #Common_ID

Use SCOPE_IDENTITY() after ur insert statementto get the last inserted id.
DECLARE #Product_Id int
INSERT INTO TABLE_ID (Table_NAME) VALUES (Table_Products);
SELECT #Product_Id=SCOPE_IDENTITY();
Insert INTO Table_Products (ID, Product_Name)
VALUES (ID from TABLE_ID, 'SomeProduct')

Dear friend you have to select id of last record inserted
and then pass it in another table so bellow code will help you very well
Insert INTO TABLE_ID (Table_NAME), Values (Table_Products)
DECLARE #ID int;
set #ID = SCOPE_IDENTITY();
Insert INTO Table_Products (ID, Product_Name)
Values (#ID, SomeProduct)
this code will solve your problem i define #ID for your last record id and then insert it in your other table

For MySql use select LAST_INSERT_ID();

All the other answers so far declare intermediary variables for SCOPE_IDENTITY(), but it could be simpler:
INSERT INTO dbo.TABLE_ID (Table_NAME) VALUES 'Table_Products';
INSERT INTO dbo.Table_Products (ID, Product_Name) VALUES (SCOPE_IDENTITY(),'SomeProduct');

You could be also more table-specific using IDENT_CURRENT()
Insert INTO TABLE_ID (Table_NAME), Values (Table_Products)
select #NewID=IDENT_CURRENT('TABLE_ID')
Insert INTO Table_Products (ID, Product_Name, Product_ID
Values (#NewID, SomeProduct, Increment)

Related

Insert multiple rows using triggers using three tables

ALTER TRIGGER tr_ItemAccessInsert
ON [dbo].[tbl_InventoryGroup]
AFTER INSERT
AS
BEGIN
DECLARE #ID decimal(18,3), #InventoryID decimal(18,3)
SELECT #ID = [ItemID] FROM [dbo].[tbl_ItemMain]
SELECT #InventoryID = [GroupID] FROM inserted
INSERT INTO tbl_ItemInventoryAccess ([ItemID], [InventoryID], [Value])
VALUES (#ID, #InventoryID, '0.11')
END
this is my query for trigger
i have 10 item in tbl_itemmain so i want to insert all the 10 itemsid in the tbl_inventoryacess please help me with that
You would just use insert . . . select:
insert into tbl_ItemInventoryAccess ([ItemID], [InventoryID], [Value])
select i.??, i.GroupID, '0.11'
from inserted i;
It is unclear how ItemId is determined. I imagine that a table called tbl_ItemMain has more than one row. Perhaps you can just use i.ItemId.
if i am using like
Alter trigger tr_ItemAccessInsert
on [dbo].[tbl_InventoryGroup]
After insert
as begin
Declare #ID decimal(18,3),#InventoryID decimal(18,3)
select #InventoryID=[GroupID] from inserted
insert into tbl_ItemInventoryAccess([ItemID],[InventoryID],[Value]) values((select itemid from tbl_ItemMain) ,#inventoryid,'0')
end
getting an error subquery returned more than one value

Referencing inserted ID in multiple insert transactions in Postgres

I need to build a SQL query that must be able to insert data in a first table, grab the inserted ID and then use it as foreign key in the following tables.
WITH inserted AS (
INSERT INTO firstTable (name) VALUES ('somename') RETURNING id
)
SELECT * FROM inserted; -- this has the inserted id
INSERT INTO secondTable (name, foreign_id) VALUES ('someexternalname', ???)
So how do I reference the id in inserted in the secondTable insert?
You have completed this 80% percent, the complete SQL is:
with inserted as (
insert into first_table(name) values ('somename') returning id
)
insert into second_table(name, foreign_id) select 'someexternalname',id from inserted
You can do this:
WITH inserted AS (
INSERT INTO firstTable (name) VALUES ('somename') RETURNING id
)
INSERT INTO secondTable (name, foreign_id)
SELECT
'someexternalname',
id
FROM inserted;
You can try this:
INSERT INTO secondTable (name, foreign_id) VALUES ('someexternalname', (SELECT
MAX (id) FROM firstTable))

Insert a table variable into a temp table with multiple columns (ID, Number, etc.)

I need to insert multiple Table variables into one temp table.
One of the table variables is:
DECLARE ##TempTable_Number TABLE (Number bigint)
insert into ##TempTable_Number (Number) values ('000000000000');
insert into ##TempTable_Number (Number) values ('100000000000');
This works for inserting just one table variable
select * into ##GlobalTempTable_1 from ##TempTable_Number
I have a couple more table variables like
DECLARE ##TempTable_ID TABLE (Number int)
insert into ##TempTable_ID (ID) values ('1');
insert into ##TempTable_ID (ID) values ('12');
etc...
I tried this to insert data from multiple table variables into one TempTable:
Select * into ####GlobalTempTable_1 From ##TempTable_ID, ##TempTable_Number;
The query goes to a continuous loop...
EDIT:
One of the table variables is:
DECLARE ##TempTable_Number TABLE (Number bigint, ID int)
insert into ##gvTempTable (Number) values ('21212321332332');
insert into ##gvTempTable (Number) values ('100000000000');
insert into ##gvTempTable (ID) values ('1');
insert into ##gvTempTable (ID) values ('12');
select * into ##GlobalTempTable from ##gvTempTable;
select * from ##GlobalTempTable;
This returns a kind of a cartesian product
Use UNION ALL:
SELECT ID
INTO ##GlobalTempTable_1
FROM ##TempTable_ID
UNION ALL
SELECT Number
FROM ##TempTable_Number;
LiveDemo
Select * into ####GlobalTempTable_1 From ##TempTable_ID, ##TempTable_Number;
The query goes to a continuous loop...
It is probably not loop but very long query. Keep in mind that you do Cartesian product.
So your query is the same as:
SELECT *
INTO ##GlobalTempTable_1
FROM ##TempTable_ID
CROSS JOIN ##TempTable_Number;
And the result is NxM records where N is number of records in first table and M in the second.
Try like this,
DECLARE #TempTable TABLE (
ID INT
,Number BIGINT
)
INSERT INTO #TempTable (Number)
VALUES ('21212321332332');
INSERT INTO #TempTable (Number)
VALUES ('100000000000');
INSERT INTO #TempTable (ID)
VALUES ('1');
INSERT INTO #TempTable (ID)
VALUES ('12');
--select * into #GlobalTempTable from ##gvTempTable;
--select * from ##GlobalTempTable;
SELECT *
FROM #TempTable
SELECT A.ID
,B.Number
FROM (
SELECT ID
,ROW_NUMBER() OVER (
ORDER BY ID
) TempId
FROM #TempTable
WHERE id IS NOT NULL
) A
INNER JOIN (
SELECT number
,ROW_NUMBER() OVER (
ORDER BY id
) TempId
FROM #TempTable
WHERE number IS NOT NULL
) B ON A.TempId = B.TempId

Insert New data into multiple tables with Foreign Key simultaneously in One query in sql server

I have two tables:
tblDepartment:
Id Name
and
tblEmployee:
Id FullName Dept_ID
Dept_ID is a foreign key for tblDepartment
I want to insert a new record into both tables.
I tried this:
declare #id int
insert dbo.tblDepartment
select Name='Name1'
select id = scope_Identity()
insert dbo.tblEmployee
select FullName = 'Name1'
select Dept_Id=#id
select Id=#id
However, this is not working. I searched through other posts, but they contain solutions for inserting existing data from one table into another, not creating a new record. How can I do this in one query?
You need to use variables properly along with column lists for inserts. Assuming you are using SQL Server:
declare #id int ;
insert dbo.tblDepartment(Name)
select 'Name1';
select #id = scope_Identity();
insert dbo.tblEmployee(FullName, Dept_Id)
select 'Name1', #id;
Also, scope_identity() is okay for learning about such id's. The safe way to really get this information is to use the output clause.
declare #id int
insert dbo.tblDepartment(Name)
select 'Name1'
-- Don't insert any other statements before next line...
select #id=scope_Identity()
insert dbo.tblEmployee(Fullname, Dept_ID)
select 'Name1', #id

Help with T-SQL script: Insert record, then use identity of that insert on another statement?

Just as a preface, I'm not very knowledgeable on T-SQL syntax.
I'd like to create a simple SQL script that will make 3 insert statements.
Insert A
Insert B
Insert C
Insert A statement's identity or "ID" would be needed in insert B statement.
And both the identities Inserts A & B would be needed in Insert C statement.
Pseudo code would look something like:
INSERT INTO tableA
VALUES ('blah', 'blah')
INSERT INTO tableB
VALUES (IDENTITY_FROM_A_INSERT, 'foo')
INSERT INTO tableC
VALUES (IDENTITY_FROM_A_INSERT, IDENTITY_FROM_B_INSERT)
How would I go about writing this script?
Use SCOPE_IDENTITY() after each insert in order to get the identity of the inserted row (in the current session).
I have used two variables to capture the two identities and then insert them into the third table:
DECLARE #Id1 INT
DECLARE #Id2 INT
INSERT INTO tableA VALUES ('blah', 'blah')
SET #Id1 = SELECT SCOPE_IDENTITY()
INSERT INTO tableB VALUES (IDENTITY_FROM_A_INSERT, 'foo')
SET #Id2 = SELECT SCOPE_IDENTITY()
INSERT INTO tableC VALUES (#Id1, #Id2)
scope_identity() is perfect for integer identifiers on single-record insertions (+1 to the other answer btw). However, if you find yourself using a guid/uniqueidentifier (newsequentialid(), newid(), etc) or inserting multiple records at once, you'll need something a little different:
declare #id uniqueidentifier;
-- Table variable for storing your newly inserted identifiers:
declare #NewlyInsertedIds table
(
[Id] uniqueidentifier
);
insert [MyTable]
(
[Blah1]
,[Blah2]
)
-- in the output clause you can access the inserted/deleted pseudo tables:
ouptut inserted.[Id]
into #NewlyInsertedIDs
(
[Id]
)
values
(
'Blah'
,'Blah'
);
select
#id = [Id]
from #NewlyInsertedIds;
Check out the OUTPUT Clause for more information.