Getting average of product sales each day and calculate number of days that have positive sales - sql

Question

I have this table TARGETSALE that have the following columns
SELECT DATE, WEEK, BRANCH, PROD, TARGETREACH
FROM TARGETSALE
WHERE BRANCH = 1
AND WEEK BETWEEN 52 AND 53;
DATE WEEK BRANCH PROD TARGETREACH
-------------------------------------------------------------------
01/09/2014 52 1 1 50
02/09/2014 52 1 1 -10
03/09/2014 52 1 1 50
04/09/2014 52 1 1 50
05/09/2014 52 1 1 40
06/09/2014 52 1 1 -10
07/09/2014 53 1 1 -5
08/09/2014 53 1 1 0
09/09/2014 53 1 1 10
10/09/2014 53 1 1 20
11/09/2014 53 1 1 30
12/09/2014 53 1 1 40
13/09/2014 53 1 1 0
01/09/2014 52 1 2 20
02/09/2014 52 1 2 0
03/09/2014 52 1 2 0
04/09/2014 52 1 2 10
05/09/2014 52 1 2 20
06/09/2014 52 1 2 10
07/09/2014 53 1 2 -10
08/09/2014 53 1 2 10
09/09/2014 53 1 2 -10
10/09/2014 53 1 2 20
11/09/2014 53 1 2 20
12/09/2014 53 1 2 40
13/09/2014 53 1 2 0
01/09/2014 52 1 3 30
02/09/2014 52 1 3 30
03/09/2014 52 1 3 5
04/09/2014 52 1 3 0
05/09/2014 52 1 3 10
06/09/2014 52 1 3 -10
07/09/2014 53 1 3 -10
08/09/2014 53 1 3 -10
09/09/2014 53 1 3 20
10/09/2014 53 1 3 10
11/09/2014 53 1 3 40
12/09/2014 53 1 3 10
13/09/2014 53 1 3 10
"targetsales" shows how much over the target the sales is, where negative means how far below the target the sales was. How can I do the following:
1. I need to get the average for all the product for each day. Something like this:
DATE BRANCH AVERAGE_SALES_OF_ALL_PRODUCT
01/09/2014 1 33.33
02/09/2014 1 -1.67
...and so on
And then I need to have another query that shows how many days within those two weeks that there's positive average sales. Something like this:
BRANCH 2WEEKS_SINCE DAYS_WITH_POSITIVE_AVERAGE_SALES
1 53 9
Above just an example not a real result.
Sorry, hope this not too confusing. Thank you so much.

Answer 1

In Oracle, the date type might still have a time component. If you do not know if this is there, then use trunc() to remove it:
select trunc(date), branch, avg(targetreach)
from targetsale
group by truncdate, branch
order by 1, 2;
For the second query, you want to use case:
select branch, count(distinct case when targetreach > 0 then date end) as DaysWithPositiveSales
from targetsales
group by branch;
If you know there is one row per date per branch -- and the time component of the date is empty -- then the distinct is not necessary.

Answer 2

1)
SELECT TRUNC(DATE, 'DD'), BRANCH, SUM(TARGETREACH)
FROM TARGETSALE WHERE BRANCH = 1 AND WEEK BETWEEN 52 AND 53
GROUP BY TRUNC(DATE, 'DD'), BRANCH;
2)
SELECT BRANCH, SUM(DECODE(ABS(TARGETREACH), 1, 1, 0)
FROM TARGETSALE WHERE BRANCH = 1 AND WEEK BETWEEN 52 AND 53
GROUP BY BRANCH;