Using a LEFT OUTER JOIN WHERE then updating same data - sql

Question

I have two databases running on MSSQL 2005, SOURCE and DESTINATION, which have the same structure and tables in them.
I'm trying to update data from s to d.
In this example, I'm trying to copy data from s to d using a join and only bringing across entries which aren't already in d.
I'm then trying to update the same records just inserted with vales thus:
INSERT DESTINATION.ITEM_REPLENISH_VENDOR ([ITEM_CODE],[VEND_CODE],[PRIMARY_VENDOR],[PURCHASE_MEASURE],[STD_COST],[LAST_COST],[EOQ],[VENDOR_PART_NO],[LEAD_TIME],[COST])
SELECT s.[ITEM_CODE],s.[VEND_CODE],s.[PRIMARY_VENDOR],s.[PURCHASE_MEASURE],s.[STD_COST],s.[LAST_COST],s.[EOQ],s.[VENDOR_PART_NO],s.[LEAD_TIME], s.[COST] FROM SOURCE.dbo.ITEM_REPLENISH_VENDOR s
LEFT OUTER JOIN DESTINATION.dbo.ITEM_REPLENISH_VENDOR d ON (d.ITEM_CODE = s.ITEM_CODE)
WHERE d.ITEM_CODE IS NULL
UPDATE DESTINATION.dbo.ITEM_REPLENISH_VENDOR
SET VEND_CODE='100004', PRIMARY_VENDOR='T',STD_COST='0',LAST_COST='0',COST='0'
WHERE
My issue is once I reach the second WHERE I don't know how to refer to the data I've just updated. This script is going to run either every day at a set time and I don't want to overwrite that whole column with those values, just the entries that have been inserted on this execution.

Answer 1

It looks like you want the output clause This will let you stash away the inserted values.
-- item_code needs to have the same type as the source table
declare #inserted table (item_code int not null primary key);
insert destination.item_replenish_vendor (
[item_code], [vend_code], [primary_vendor],
[purchase_measure], [std_cost], [last_cost],
[eoq], [vendor_part_no], [lead_time],[cost]
) -- save inserted values
output
inserted.item_code into #inserted
select
s.[item_code], s.[vend_code], s.[primary_vendor],
s.[purchase_measure], s.[std_cost], s.[last_cost],
s.[eoq], s.[vendor_part_no], s.[lead_time], s.[cost]
from
source.dbo.item_replenish_vendor s
left outer join
destination.dbo.item_replenish_vendor d
on d.item_code = s.item_code
where
d.item_code is null;
update
d
set
vend_code = '100004',
primary_vendor = 'T',
std_cost = '0',
last_cost = '0,
cost = '0'
from
destination.dbo.item_replenish_vendor d
inner join
#inserted i
on d.item_code = i.item_code;
In this case, you could just put constant values in the insert statement, instead of doing things in two steps...

Answer 2

In the example you have:
UPDATE DESTINATION.dbo.ITEM_REPLENISH_VENDOR
SET VEND_CODE='100004', PRIMARY_VENDOR='T',STD_COST='0',LAST_COST='0',COST='0'
If your VEND_CODE, PRIMARY_VENDOR, STD_COST, LAST_COST, COST are always going to be a static value, you could just put them into the first query.
INSERT DESTINATION.ITEM_REPLENISH_VENDOR ([ITEM_CODE],[VEND_CODE],[PRIMARY_VENDOR],[PURCHASE_MEASURE],[STD_COST],[LAST_COST],[EOQ],[VENDOR_PART_NO],[LEAD_TIME],[COST])
SELECT s.[ITEM_CODE],'100004','T',s.[PURCHASE_MEASURE],'0','0',s.[EOQ],s.[VENDOR_PART_NO],s.[LEAD_TIME], '0'
FROM SOURCE.dbo.ITEM_REPLENISH_VENDOR s
LEFT OUTER JOIN DESTINATION.dbo.ITEM_REPLENISH_VENDOR d ON (d.ITEM_CODE = s.ITEM_CODE)
WHERE d.ITEM_CODE IS NULL
but if they do need to be calculated after insert, then I agree with Laurence's approach.