The dates are currently displayed as: ddmmmyyyy (12DEC2013)
I've been playing around with this formula:
DECLARE #Date char(8)
set #Date='12312009'
SELECT CONVERT(datetime,RIGHT(#Date,4)+LEFT(#Date,2)+SUBSTRING(#Date,3,2))
but I didn't have any success, can someone help me out with this. Additionally all my dates are in a column called TERMDT and I'd like to put all the new date values in a new column formatted as such.
Just give convert() an appropriate 3rd argument (the format):
SELECT CONVERT(datetime,
RIGHT(d, 4) + LEFT(d,2) + SUBSTRING(d, 3, 2),
112)
from (select '12312009' as d) t
Related
I am trying to convert this into a period format, so e.g. 2018_05 (YYYY_MM). currently the data is in DD/MM/YYYY format.
I tried a cast code but it returns me YYYY_DD.
SELECT
CASE WHEN RESERVED_FIELD_4 IS NULL THEN NULL
ELSE cast(year(RESERVED_FIELD_4) as Nvarchar (4))
+'_'+right('00'+cast(month(RESERVED_FIELD_4) as Nvarchar (2)),2)
END AS [DATAFEED_PERIOD]
I expect/want to see YYYY_MM.
Assuming RESERVED_FIELD_4 is a string type (char/nchar/varchar/nvarchar) the simplest solution would be to use substring:
CASE
WHEN RESERVED_FIELD_4 IS NULL THEN NULL
ELSE SUBSTRING(RESERVED_FIELD_4, 7, 4) + '_'+ SUBSTRING(RESERVED_FIELD_4, 4, 2)
END AS [DATAFEED_PERIOD]
If it's a date/datetime/datetime2 data type, the simplest solution would be to use format:
FORMAT(RESERVED_FIELD_4, 'yyyy_MM')
But for better performance you can use convert and stuff:
SELECT STUFF(CONVERT(char(6), RESERVED_FIELD_4, 112), 5, 0, '_')
In case your format is actually d/m/y the simplest option is to convert to date and than back to string:
SELECT STUFF(CONVERT(char(6), CONVERT(Date, RESERVED_FIELD_4, 103), 112), 5, 0, '_')
This is the common problem of storing a date with a VARCHAR column. You are guessing that the stored pattern is DD/MM/YYYY but the SQL engine doesn't know that and is currently assuming the MM/DD/YYYY pattern.
Please check these results:
-- MM/DD/YYYY
SELECT
DAY ('05/01/2019'), -- 1
MONTH('05/01/2019') -- 5
-- DD/MM/YYYY
SELECT
DAY ('25/05/2019'), -- Conversion failed when converting date and/or time from character string
MONTH('25/05/2019') -- Conversion failed when converting date and/or time from character string.
To display what you want correctly use string functions:
SELECT
RIGHT(RESERVED_FIELD_4, 4) + '_' + SUBSTRING(RESERVED_FIELD_4, 4, 2)
But you should actually fix the values on your VARCHAR column, cast them to DATE and store the values as DATE.
ALTER TABLE YourTable ADD ReservedField4Date DATE
UPDATE YourTable SET
ReservedField4Date = CONVERT(DATE,
RIGHT(RESERVED_FIELD_4, 4) -- Year
+ '-' + SUBSTRING(RESERVED_FIELD_4, 4, 2) -- Month
+ '-' + LEFT(RESERVED_FIELD_4, 2)) -- Day
ALTER TABLE YourTable DROP COLUMN RESERVED_FIELD_4
EXEC sp_rename 'SchemaName.YourTable.ReservedField4Date', 'RESERVED_FIELD_4', 'COLUMN'
Beware that changing the column type might affect other queries that assume this is a VARCHAR column.
If your data is in DD/MM/YYYY format, then it is being stored as a string. Hence, string functions come to mind:
select right(RESERVED_FIELD_4) + '_' + substrint(RESERVED_FIELD_4, 4, 2)
In SQL-SERVER you can use 'format'
format(dy,#your_date) as day_of_year
month(#your_date) as month
Try this:
Select concat(month(#your_date),'_'year(#your_date)) as your_period
this is a reference
Why not just do conversations ? :
SELECT REPLACE(CONVERT(VARCHAR(7), CONVERT(date, RESERVED_FIELD_4, 101), 102), '.', '_')
This assumes RESERVED_FIELD_4 is date type.
I have a date saved in an nvarchar type and I want to split the day, month and year into separate nvarchar variables (that means three variables). The date looks as follows: exposure_date ='2018-12-04' and the format is yyyy-dd-mm
any help please?
My whole project is stuck on this.
The "correct" answer here is to fix your datatype. When storing data always choose an appropriate data type for the data you're storing. For a date (with no time part) then the correct datatype is date. if you're storing numerical data, then use a numerical datatype, such as int or decimal. (n)varchar is not a one size fits all datatype and using it to store data that has a data type designed for it is almost always a bad choice. I'm storing the data as an (n)varchar because I need it in a specific format is never an excuse; have your presentation layer handle to display format, not your RDBMS.
The first step, therefore would be to change your string representation yyyy-dd-MM of a date to the ISO format yyyyMMdd by doing:
UPDATE YourTable
SET exposure_date = LEFT(exposure_date,4) + RIGHT(exposure_date,2) + SUBSTRING(exposure_date,6,2);
Now you have a unambiguous representation, you can change the data type of your column without concerns of incorrect implicit casts or error:
ALTER YourTable ALTER COLUMN exposure_date date;
Then, finally, you can treat your data as what it is, a date, and use the DATEPART function:
SELECT DATEPART(YEAR,exposure_date) AS Exposure_Year,
DATEPART(MONTH,exposure_date) AS Exposure_Month,
DATEPART(DAY,exposure_date) AS Exposure_Day
FROM YourTable;
You can also try the following
Declare #myDate date
select #myDate= Cast(substring('2011-29-12', 1, 4)
+ '-' + substring('2011-29-12', 9, 2)
+ '-' + substring('2011-29-12', 6, 2)
as Date) --YYYY-MM-DD
Select #myDate as DateTime,
datename(day,#myDate) as Date,
month(#myDate) as Month,
datename(year,#myDate) as Year,
Datename(weekday,#myDate) as DayName
The output is as shown below
DateTime Date Month Year DayName
--------------------------------------------
2011-29-12 29 12 2011 Thursday
You can find the live demo here
You can try below -
select concat(cast(year(cast('2018-12-04' as date)) as varchar(4)),'-',
cast(month(cast('2018-12-04' as date)) as varchar(2)), '-',
cast(day(cast('2018-12-04' as date)) as varchar(2)))
from tablename
If you have fixed format, then you could use this simple query with substring method:
select substring(dt, 1, 4) + '-' +
substring(dt, 9, 2) + '-' +
substring(dt, 6, 2) [YYYY-MM-DD]
from (values ('2018-31-12')) tbl(dt)
Let's go directly to the main issue, which is you are using the wrong datatype to store dates, you should store them as DATE, the datatypes are there for a reason and you need to choose a proper one for your column.
So, you need to ALTER your table and change the column datatype to DATE instead of NVARCHAR datatype.
ALTER <Table Name Here>
ALTER COLUMN <Column Name Here> DATE;
Then all things will easy, you just run the following query to get the desired output
SELECT YEAR(<Column Name Here>) TheYear,
MONTH(<Column Name Here>) TheMonth,
DAY(<Column Name Here>) TheDay
FROM <Table Name Here>
Which is the right and the best solution.
You can also (if you are not going to alter your table) do as
CREATE TABLE Dates(
StrDate NVARCHAR(10)
);
INSERT INTO Dates VALUES
(N'2018-12-04'),
(N'Invalid');
SELECT LEFT(StrDate, 4) StrYear,
SUBSTRING(StrDate, 6, 2) StrMonth,
RIGHT(StrDate, 2) StrDay
FROM Dates;
OR
SELECT YEAR(StrDate) StrYear,
MONTH(StrDate) StrMonth,
DAY(StrDate) StrDay
FROM (
SELECT TRY_CAST(StrDate AS DATE) StrDate
FROM Dates
)T
We have the following solution:
select
substring(convert(varchar(20),convert(datetime,getdate())),5,2)
+ ' ' +
left(convert(varchar(20),convert(datetime,getdate())),3)
What is the elegant way of achieving this format?
You can do it this way:
declare #date as date = getdate()
select replace(convert(varchar(6), #date, 6), ' ', '-')
-- returns '11-Apr'
Format 6 is dd mon yy and you take the first 6 characters by converting to varchar(6). You just need to replace space with dash at the end.
You can use the dateName function:
select right(N'0' + dateName(DD, getDate()), 2) + N'-' + dateName(M, getDate())
If you really want the mmm part to only have the tree-letter abbreviation of the month, you're stuck with parsing the appropriate conversion type, for example
select left(convert(nvarchar, getDate(), 7), 3)
The problem is that dateName doesn't have an option to get you the abbreviated month, and the abbreviation isn't always just the first three letters (for example, in czech, two months start with Čer). On the other hand, convert 7 always starts with the abbreviation. Now, even with this, I assume that the abbreviation is always three letters long, so it isn't necessarily 100% reliable (you could search for space instead), but I'm not aware of any better option in MS SQL.
DECLARE #t datetime = getdate()
SELECT CONVERT(VARCHAR(24),LEFT(#t,6),113)
Try this...
SELECT LEFT(CONVERT(NVARCHAR(10), GETDATE(), 6), 6)
How can we convert date format to YYMM(ex:1208) for the given date 25/08/2012.
Use convert with style 12 and pick the first four characters.
select convert(char(4), getdate(), 12)
try this:
declare #date date='08/25/2012'
select CONVERT(varchar(4),#date,12)
You did not specify the datatype for the value 25/08/2012.
declare #dt char(10)
set #dt = '25/08/2012'
select right(#dt, 2) + substring(#dt, 4, 2)
If you don't like remembering the string convert formulas, you can also use:
declare #date date=CURRENT_TIMESTAMP
select right(CAST(year(#date) as varchar(4)), 2) + RIGHT('0'+cast(month(#date) as varchar(2)), 2)
It is a bit more cumbersome, but saves a trip to the help pages.
I need to convert date format in SQL
The current format is yyyy/mm/dd-hh:mm:ss:sss and I need to convert it to yyyy-mm-dd hh:mm:ss CST
I don't really know SQL but did some research and found that I can use instr to find the string and replace it, however, no matter what I try,there is always something off :(
Could anyone here help me with it? thanks in advance.
By the way, it's in oracle sql developer so syntax are different from previous answer. Thanks again
If your current column is stored as a varchar (which it looks like it is based on your example) you can convert it the following way to a datetime.
declare #date varchar(25)
set #date = '2012/02/16-09:40:30:000'
select Convert(datetime, Left(#date, 4) + '-' +
substring(#date, 6, 2) + '-' +
substring(#date, 9, 2) + ' ' +
substring(#date, 12, 8)) As NewDate
And the result would be 2012-02-16 09:40:30.000
There are lots of sites that have details on converting datetime:
http://www.sql-server-helper.com/tips/date-formats.aspx
http://anubhavg.wordpress.com/2009/06/11/how-to-format-datetime-date-in-sql-server-2005/
If the date is stored as a datetime, then you can get your format by doing:
SELECT convert(varchar, getdate(), 120)
thank you so much for your guys help! I got this sorted out by other user's help, the command is,
update b
set first= to_char(substr(FIRST,1,4)||'-'||substr(FIRST, 6, 2)||'-'||substr(FIRST, 9, 2)||' '||substr(FIRST, 12, 8))
Thanks :)
Mylie
The CONVERT() function is normally used for this. The third parameter lets you specify the required date formatting.
If the date is already in a string, then convert it first into a date type and then convert it back to a string in the required format.
http://msdn.microsoft.com/en-us/library/ms187928.aspx
If you're using SQL Server and it's a date field you can do:
convert(varchar,getdate(),120)
Replacing getdate() with the column name
If the date is stored as a DATETIME, then you can convert it to a string in the format you want by doing the following:
SELECT CONVERT(VARCHAR(19),YourColumn,120)
FROM YourTable
CAST AND CONVERT
declare #ds varchar(23)='2012/02/16 12:57:03:002'; --your current format
select convert(varchar(30),cast(#ds as datetime),120)+' CST' --new format you specified