In my continuous integration testing for my emacs package fsharp-mode, I am adding byte-compilation to the tests, in order to have immediate feedback. I am roughly using:
emasc -batch batch-byte-compile *.el
This returns non-zero if there is an error, but not if it is just a warning. I would like to be alerted also if there are any warnings, as this may include calls to undefined functions (which has happened before thanks to a typo).
So: how can I obtain a non-zero return code in case of compilation warnings?
You can set byte-compile-error-on-warn to a non-nil value, as in:
$ emacs -Q --batch \
--eval '(setq byte-compile-error-on-warn t)' \
-f batch-byte-compile *.el
The byte compiler now stops at the first warning, though, so you should make this setting optional in your Makefile, and only use it in your CI setup.
If you need more sophisticated control than that, you have to write your own post-processor, e.g. a Python script that parses the output of the byte compiler and adjusts the exit code and/or output accordingly, or write your own batch-byte-compile variant that does more sophisticated processing.
Related
I am writing a macro to check for cython on the system my program is about to be compiled.
i can use AC_PATH_PROG all right to find cython when it is in the path, but if the user want to specifiy it in the configure line like this:
./configure CYTHON=/home/user/cythonFoo
I just can't find the right way to check for it.
This is not working, it always pass the test whatever the value of CYTHON is:
AC_PATH_PROG( CYTHON, $CYTHON,"" )
This is kinda working, but not really usable, because it would require me to extract filename and filepath beforehand:
AC_PATH_PROG( CYTHON, cythonFoo,"", /home/user/ )
So i've wrote my own test, but i think there may be a standard way to do it
AC_MSG_CHECKING([Checking Cython path $CYTHON is correct])
AS_IF($CYTHON -V > /dev/null 2>&1, , CYTHON="")
if test -z $CYTHON; then
AC_MSG_RESULT([ no ])
else
AC_MSG_RESULT([ yes ])
fi
You're observing the expected behavior of AC_PATH_PROG. If the user sets CYTHON, AC_PATH_PROG is going to treat it as the cython to use, even if it's bogus. As the first line of the linked page states
If you need to check the behavior of a program as well as find out whether it is present, you have to write your own test for it
So what you've done is the "standard way".
This is slightly different from Can a Makefile execute code ONLY when an error has occurred?.
I'd like a rule or special target that is made whenever an error occurs (independent of the given target; without changing the rule for every target as the other answer seems to imply with the || operator).
In dmake there is special target .ERROR that is executed whenever an error condition is detected. Is there a similar thing with GNU make?
(I'm still using GNU make 3.81, but I didn't find anything in the documentation of the new GNU make 4.0 either)
Gnu doesn't support it explicitly, but there's ways to hack almost anything. Make returns 1 if any of the makes fail. This means that you could, on the command line, rerun make with your error rule if the first make failed:
make || make error_targ
Of course, I'll assume you just want to put the added complexity within the makefile itself. If this is the case, you can create a recursive make file:
all:
$(MAKE) normal_targ || $(MAKE) error_targ
normal_targ:
... normal make rules ...
error_targ:
... other make rules ...
This will cause the makefile to try to build normal_targ, and iff it fails, it will run error_targ. It makes it a bit harder to read the makefile for the inexperienced, but it puts all the logic in one place.
I'm just switch to zsh and now adapting the alias in which was printing some text (in color) along with a command.
I have been trying to use the $fg array var, but there is a side effect, all the command is printed before being executed.
The same occur if i'm just testing a echo with a color code in the terminal:
echo $fg_bold[blue] "test"
]2;echo "test" test #the test is in the right color
Why the command print itself before to do what it's supposed to do ? (I precise this doesn't happen when just printing whithout any wariable command)
Have I to set a specific option to zsh, use echo with a special parameter to get ride of that?
Execute the command first (keep its output somewhere), and then issue echo. The easiest way I can think of doing that would be:
echo $fg[red] `ls`
Edit: Ok, so your trouble is some trash before the actual output of echo. You have some funny configuration that is causing you trouble.
What to do (other than inspecting your configuration):
start a shell with zsh -f (it will skip any configuration), and then re-try the echo command: autoload colors; colors; echo $fg_bold[red] foo (this should show you that the problem is in your configuration).
Most likely your configuration defines a precmd function that gets executed before every command (which is failing in some way). Try which precmd. If that is not defined, try echo $precmd_functions (precmd_functions is an array of functions that get executed before every command). Knowing which is the code being executed would help you search for it in your configuration (which I assume you just took from someone else).
If I had to guess, I'd say you are using oh-my-zsh without knowing exactly what you turned on (which is an endless source of troubles like this).
I don't replicate your issue, which I think indicates that it's either an option (that I've set), or it's a zsh version issue:
$ echo $fg_bold[red] test
test
Because I can't replicate it, I'm sure there's an option to stop it happening for you. I do not know what that option is (I'm using heavily modified oh-my-zsh, and still haven't finished learning what all the zsh options do or are).
My suggestions:
You could try using print:
$ print $fg_bold[red] test
test
The print builtin has many more options than echo (see man zshbuiltins).
You should also:
Check what version zsh you're using.
Check what options (setopt) are enabled.
Check your ~/.zshrc (and other loaded files) to see what, if any, options and functions are being run.
This question may suggest checking what TERM you're using, but reading your question it sounds like you're only seeing this behaviour (echoing of the command after entry) when you're using aliases...?
I was originally trying to run an executable (tftpd32.exe) from Expect with the following command, but for some unknown reason it would hanged the entire script:
exec c:/tftpd32.351/tftpd32.exe
So, decided to call a batch file that will start the executable.
I tried to call the batch file with the following command, but get an error message stating windows cannot find the file.
exec c:/tftpd32.351/start_tftp.bat
I also tried the following, but it does not start the executable:
spwan cmd.exe /c c:/tftpd32.351/start_tftp.bat
The batch file contains this and it run ok when I double click on it:
start tftpd32.exe
Any help would be very much appreciated.
Thanks
The right way to run that program from Tcl is to do:
set tftpd "c:/tftpd32.351/tftpd32.exe"
exec {*}[auto_execok start] "" [file nativename $tftpd]
Note that you should always have that extra empty argument when using start (due to the weird way that start works; it has an optional string in quotes that specifies the window title to create, but it tends to misinterpret the first quoted string as that even if that leaves it with no mandatory arguments) and you need to use the native system name of the executable to run, hence the file nativename.
If you've got an older version of Tcl inside your expect program (8.4 or before) you'd do this instead:
set tftpd "c:/tftpd32.351/tftpd32.exe"
eval exec [auto_execok start] [list "" [file nativename $tftpd]]
The list command in that weird eval exec construction adds some necessary quoting that you'd have trouble generating otherwise. Use it exactly as above or you'll get very strange errors. (Or upgrade to something where you don't need nearly as much code gymnastics; the {*} syntax was added for a good reason!)
It seems as if a script with #! prefix can have the interpreter name and ONLY one argument. Thus:
#!/bin/ls -l
works, but
#!/usr/bin/env ls -l
doesn't
Do you agree? Any thoughts?
Francesc
Different Unixes interpret #! differently. Here's a comprehensive-looking writeup: http://www.in-ulm.de/~mascheck/various/shebang/
It seems that the lowest common denominator across platforms is "the interpreter (which must not itself be a script) and no more than one argument".
Originally, we only had one shell on Unix. When you asked to run a command, the shell would attempt to invoke one of the exec() system calls on it. It the command was an executable, the exec would succeed and the command would run. If the exec() failed, the shell would not give up, instead it would try to interpret the command file as if it were a shell script.
Then unix got more shells and the situation became confused. Most folks would write scripts in one shell and type commands in another. And each shell had differing rules for feeding scripts to an interpreter.
This is when the “#! /” trick was invented. The idea was to let the kernel’s exec () system calls succeed with shell scripts. When the kernel tries to exec () a file, it looks at the first 4 bytes which represent an integer called a magic number. This tells the kernel if it should try to run the file or not. So “#! /” was added to magic numbers that the kernel knows and it was extended to actually be able to run shell scripts by itself. But some people could not type “#! /”, they kept leaving the space out. So the kernel was expended a bit again to allow “#!/” to work as a special 3 byte magic number.