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Sql query to create a calculated field
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Closed 8 years ago.
I have this sql query:
SELECT DISTINCT
[Card NO],
[User Name],
(
SELECT
MIN(DateTime) AS [Enter Time],
MAX(DateTime) AS [Exit Time],
MAX(DateTime) - MIN(DateTime) AS [Inside Hours]
FROM
ExcelData
)
FROM
ExcelData
GROUP BY
[Card NO], [User Name], DateTime
Table Schema: CardNO | UserName | DateTime
I tried to execute it but with no success. I says that it is an invalid query.
Can anyone find what is wrong in this query?
This would not resolve your possible Problems with reserved keywords and column names, but should be a valid query. You were using a select query as column Name.
SELECT
[Card NO],
[User Name],
MIN(DateTime) AS [Enter Time],
MAX(DateTime) AS [Exit Time],
MAX(DateTime) - MIN(DateTime) AS [Inside Hours]
FROM
ExcelData
GROUP BY
[Card NO], [User Name]
You are grouping by DateTime, which is a reserved keyword, and you don't select a column DateTime. You do select aggregates over DateTime, which means you shouldn't group on it. #irene got the right answer.
Related
I have a query that's supposed to grab only the value for the last day of the month from all my existing records (so the last day of multiple months). I'm unable to get the value I'm needing for ONLY the last day, due to using a SUM() clause. This is adding all the values for the whole month together. Can I get only the value for the last day another way? Is there something I'm missing?
Code so far:
SELECT
ID,
[Customer Name],
Year([ValDate]) & IIf(Len(Month([ValDate]))>1,Month([ValDate]),"0" & Month([ValDate])) AS BalMonth,
Sum(Value) AS LastValue
FROM
Archive
GROUP BY
ID,
[Customer Name],
Year([ValDate]),
Month([ValDate])
ORDER BY
ID,
Year(ValDate) & Month(ValDate)
Other Code tested:
SELECT
ID,
[Customer Name],
YEAR([ValDate]) & MONTH([ValDate]) & MAX(DAY([BalDate])) AS LastDayofMonth
FROM
Archive
GROUP BY
ID ,
[Customer Name],
YEAR([ValDate]),
MONTH([ValDate])
ORDER BY
ID,
[Customer Name],
YEAR([ValDate]),
MONTH([ValDate])
The second section of code didn't work as it produces the dates in YYYYMMDD format. This makes it so it doesn't allow proper ordering of the dates. Instead, the dates are being ordered as 1 , 10 , 11 , 12 , 2 , 3 , 4 , etc.
If anything is unclear I'll try my best to clarify, just let me know!
Try something like:
SELECT
ID,
[Customer Name],
[ValDate] AS LastDayofMonth,
Sum([FieldToSum]) As Total
FROM
Archive
GROUP BY
ID,
[Customer Name],
[ValDate]
HAVING
[ValDate] = DateSerial(Year([ValDate]), Month([ValDate]) + 1, 0)
Edit:
To have a formatted date output, try this:
SELECT
ID,
[Customer Name],
Format([ValDate], "yyyymmdd") AS LastDayofMonth,
Sum([FieldToSum]) As Total
FROM
Archive
WHERE
[ValDate] = DateSerial(Year([ValDate]), Month([ValDate]) + 1, 0)
GROUP BY
ID,
[Customer Name],
Format([ValDate], "yyyymmdd")
Good day,
I have an SQL code that return to me all quantities that I received over time, but I want to display only the latest one
SELECT * FROM
(SELECT DISTINCT
[dbo].[ttcibd001110].[t_cmnf] AS [Manufacturer],
[dbo].[ttcibd001110].[t_item] AS [Item code],
[dbo].[ttcibd001110].[t_dsca] AS [Description],
[dbo].[ttcibd001110].[t_seak] AS [Search key 1],
[dbo].[twhinr110110].[t_trdt] AS [Transaction date],
[dbo].[twhinr110110].[t_cwar] AS [Warehouse],
[dbo].[twhinr110110].[t_qstk] AS [Quantity Inventory Unit]
FROM [dbo].[twhinr110110] LEFT JOIN [dbo].[ttcibd001110]
ON [dbo].[twhinr110110].[t_item]=[dbo].[ttcibd001110].[t_item]
WHERE [dbo].[twhinr110110].[t_koor]='2' AND [dbo].[ttcibd001110].[t_cmnf]='ManufacturerX') AS tabel
WHERE ltrim(tabel.[Item code])='1000045'
Now, from this selection I want to select only the line with the latest Transaction date, but I am stuck.
Can somebody help me in this way?
Thank you!
Change your beginning to
SELECT TOP 1
and after where use
ORDER BY [Transaction date] DESC
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In the following view,instead of specifying the actual dates in the where condition,I want sql server to recognize June and May as the latest month and the (latest month-1) as the view gets refreshed on a monthly basis and so does latest month and (latest month -1).
PS:- The latest Report month is June in the table
SELECT (A.[First Name])
,A.[Last Name]
,A.[Report Month]
FROM (
(
SELECT DISTINCT [First Name]
,[Last Name]
,[Report Month]
,[Bill To Code]
,[Region]
,[Area]
FROM dbo.Data
WHERE (
[Report Month] BETWEEN '2015-06-01'
AND '2015-06-30'
AND [FTE Status] = 'Inactive'
)
) A INNER JOIN (
SELECT DISTINCT [First Name]
,[Last Name]
,[Report Month]
,[Bill To Code]
,[Region]
,[Area]
FROM dbo.Data
WHERE (
[Report Month] BETWEEN '2015-05-01'
AND '2015-05-31'
AND [FTE Status] = 'Active'
)
) B ON A.[First Name] = B.[First Name]
AND A.[Last Name] = B.[Last Name]
)
Thank you,just learnt how to format better in SO.Thanks to Sean.Learning from my mistakes guys..:)
Hence i should write some function so that sql server reads the start
and end date of the latest month in the data set.
You say you need to read the start and end date, but if what you really need is just to get all the data that is in the latest month in your table, then this will do it:
select *
from dbo.Data
where DATEDIFF(month,[Report Month],(SELECT MAX([Report Month] FROM dbo.Data))=0
and [FTE Status]='Active'
Despite your rather vague question, I think this is what you are looking for.
This will return the first and last day for the max date in YourTable.
;with cte as (
select convert(date,left(convert(varchar,Max(Report_Month),112),6) + '01') startDate,
month(Max(Report_Month)) n
from YourTable
union all
select dateadd(month,n,convert(date,convert(varchar,year(startDate)) + '0101')) startDate,
(n+1) n
from cte
where n < month(startDate)
)
select startdate, dateadd(day,-1,dateadd(month,1,startdate)) enddate
from cte
How about:
SELECT MAX(MONTH(Report_Month))
FROM YourTable
GROUP BY YEAR(Report_Month)
HAVING YEAR(Report_Month) = MAX(YEAR(Report_Month))
We have a table which will capture the swipe record of each employee. I am trying to write a query to fetch the list of distinct employee record by the first swipe for today.
We are saving the swipe date info in datetime column. Here is my query its throwing exception.
select distinct
[employee number], [Employee First Name]
,[Employee Last Name]
,min([DateTime])
,[Card Number]
,[Reader Name]
,[Status]
,[Location]
from
[Interface].[dbo].[VwEmpSwipeDetail]
group by
[employee number]
where
[datetime] = CURDATE();
Getting error:
Column 'Interface.dbo.VwEmpSwipeDetail.Employee First Name' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
Any help please?
Thanks in advance.
The error says it all:
...Employee First Name' is invalid in the select list because it is not contained
in either an aggregate function or the GROUP BY clause
Saying that, there are other columns that need attention too.
Either reduce the columns returned to only those needed or include the columns in your GROUP BY clause or add aggregate functions (MIN/MAX). Also, your WHERE clause should be placed before the GROUP BY.
Try:
select distinct [employee number]
,[Employee First Name]
,[Employee Last Name]
,min([DateTime])
,[Card Number]
,min([Reader Name])
from [Interface].[dbo].[VwEmpSwipeDetail]
where CAST([datetime] AS DATE)=CAST(GETDATE() AS DATE)
group by [employee number], [Employee First Name], [Employee Last Name], [Card Number]
I've removed status and location as this is likely to return non-distinct values. In order to return this data, you may need a subquery (or CTE) that first gets the unique IDs of the SwipeDetails table, and from this list you can join on to the other data, something like:
SELECT [employee number],[Employee First Name],[Employee Last Name].. -- other columns
FROM [YOUR_TABLE]
WHERE SwipeDetailID IN (SELECT MIN(SwipeDetailsId) as SwipeId
FROM SwipeDetailTable
WHERE CAST([datetime] AS DATE)=CAST(GETDATE() AS DATE)
GROUP BY [employee number])
Please Try Below Query :
select distinct [employee number],[Employee First Name]
,[Employee Last Name]
,min([DateTime])
,[Card Number]
,[Reader Name]
,[Status]
,[Location] from [Interface].[dbo].[VwEmpSwipeDetail] group by [employee number],[Employee First Name]
,[Employee Last Name]
,[Card Number]
,[Reader Name]
,[Status]
,[Location] having [datetime]=GetDate();
First find the first timestamp for each employee on the given day (CURDATE), then join back to the main table to get all the details:
WITH x AS (
SELECT [employee number], MIN([datetime] AS minDate
FROM [Interface].[dbo].[VwEmpSwipeDetail]
WHERE CAST([datetime] AS DATE) = CURDATE()
GROUP BY [employee number]
)
select [employee number]
,[Employee First Name]
,[Employee Last Name]
,[DateTime]
,[Card Number]
,[Reader Name]
,[Status]
,[Location]
from [Interface].[dbo].[VwEmpSwipeDetail] y
JOIN x ON (x.[employee number] = y.[employee number] AND x.[minDate] =Y.[datetime]
This should not be marked as mysql as this would not happen in mysql.
sql-server does not know which of the grouped [Employee First Name] values to return so you need to add an aggregate (even if you only actually expect one result). min/max will both work in that case. The same would apply to all the other rows where they are not in the GROUP BY or have an aggregate function (EG min) around them.
i need to select two columns.1. calculate sum of one column and display it 2.display column as it is. so i tried below code
SELECT Sum(CONVERT(FLOAT, Replace(total, Char(0), ''))) AS Total,
[product name]
FROM tb_sales_entry_each_product
GROUP BY [sales date]
error message
Column 'tb_sales_entry_each_product.Product Name' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
where i made error.thanks
just need to group
select SUM(CONVERT(float, REPLACE(Total, CHAR(0), ''))) as Total, [Product Name]
from tb_sales_entry_each_product group by [Sales Date], [product name]
When ever you do a numercial count sum etc, any other columns need to be grouped.
thats all your missing
Try this:
select SUM(CONVERT(float, REPLACE(Total, CHAR(0), ''))) as Total,
[Product Name] ,[Sales Date]
from tb_sales_entry_each_product
group by [Sales Date],[Product Name]