I am having trouble with the below PDO code, which is throwing this error:
Uncaught exception 'PDOException' with message 'SQLSTATE[HY093]: Invalid parameter number'
I know that the $theID variable is working just fine, grabbing the variable and storing it as I have used it elsewhere on the page. The problem lies somewhere in my PDO code...
// get the ID
$theID = ( isset( $_GET['ID'] ) ) ? $_GET['ID'] : false;
$sql ="SELECT count(*) from writing
LEFT JOIN stories on writing.SID = stories.SID
LEFT JOIN wp_users ON writing.ID = wp_users.ID
WHERE (wp_users.ID != :theID) AND (writing.approved = :approved) AND (stories.ID =
:theID)";
$stmt = $dbh->prepare($sql);
$stmt->bindParam(':theID', $theID, PDO::PARAM_INT);
$stmt->bindParam(':approved', $m = Y, PDO::PARAM_STR);
$stmt->execute();
I figured it out. Problem was I was using the same named paramter :theID more than once. I changed it to :theID1 and :theID2 and had two seperate bindParam statements for each and it worked.
Related
I have a query, and I want to get the last ID inserted. The field ID is the primary key and auto incrementing.
I know that I have to use this statement:
LAST_INSERT_ID()
That statement works with a query like this:
$query = "INSERT INTO `cell-place` (ID) VALUES (LAST_INSERT_ID())";
But if I want to get the ID using this statement:
$ID = LAST_INSERT_ID();
I get this error:
Fatal error: Call to undefined function LAST_INSERT_ID()
What am I doing wrong?
That's because that's an SQL function, not PHP. You can use PDO::lastInsertId().
Like:
$stmt = $db->prepare("...");
$stmt->execute();
$id = $db->lastInsertId();
If you want to do it with SQL instead of the PDO API, you would do it like a normal select query:
$stmt = $db->query("SELECT LAST_INSERT_ID()");
$lastId = $stmt->fetchColumn();
lastInsertId() only work after the INSERT query.
Correct:
$stmt = $this->conn->prepare("INSERT INTO users(userName,userEmail,userPass)
VALUES(?,?,?);");
$sonuc = $stmt->execute([$username,$email,$pass]);
$LAST_ID = $this->conn->lastInsertId();
Incorrect:
$stmt = $this->conn->prepare("SELECT * FROM users");
$sonuc = $stmt->execute();
$LAST_ID = $this->conn->lastInsertId(); //always return string(1)=0
You can get the id of the last transaction by running lastInsertId() method on the connection object($conn).
Like this $lid = $conn->lastInsertId();
Please check out the docs https://www.php.net/manual/en/language.oop5.basic.php
I'm attempting to join two tables while using codeigniter. I've done this same SQL query writing regular SQL. When I attempt to do the same in codeigniter, I keep getting errors. I'm not quite sure what I'm doing wrong. What do you guys think I'm doing wrong?
My function in model_data.php
function getJoinInformation($year,$make,$model)
{
//$this->db->distinct();
// here is where I need to conduct averages but lets just work on extracting info.
// from the database and join tables.
$this->db->select('*');
$this->db->from('tbl_car_description');
$this->db->join('tbl_car_description', 'd.id = p.cardescription_id');
$this->db->where('d.year', $year);
$this->db->where('d.make', $make);
$this->db->where('d.model', $model);
$result = $this->db->get();
/*
$query = $this->db->get_where('tbl_car_description',
array(
'year' => $year,
'make' => $make,
'model' => $model
)
);
if($query->num_rows()) return $query->result();
return null;
*/
}
My error message
A Database Error Occurred
Error Number: 1066
Not unique table/alias: 'tbl_car_description'
SELECT * FROM (`tbl_car_description`) JOIN `tbl_car_description` ON `d`.`id` = `p`.`cardescription_id` WHERE `d`.`year` = '2006' AND `d`.`make` = 'Subaru' AND `d`.`model` = 'Baja'
Filename: C:\wamp\www\_states\system\database\DB_driver.php
Line Number: 330
Here is the code written in SQL and it's working great. I want to do the something in codeigniter but I'm confused as to how. Any help would be much appreciated. Thanks everyone.
$sql_2 = mysql_query("SELECT ROUND(AVG(p.value),1) AS AvgPrice, ROUND(AVG(p.mileage),1) AS AvgMileage
FROM tbl_car_description d, tbl_car_prices p
WHERE (d.id = p.cardescription_id)
AND (d.year = '".$year."')
AND (d.make = '".$make."')
AND (d.model = '".$model."')
AND (p.approve = '1')");
Your CI query references the same table twice, which I assume is a typo. However, you only need include your table alias with the table name in your Active Record call:
//$this->db->distinct();
$this->db->select('*');
$this->db->from('tbl_car_description d');
$this->db->join('tbl_car_prices p', 'd.id = p.cardescription_id');
$this->db->where('d.year', $year);
$this->db->where('d.make', $make);
$this->db->where('d.model', $model);
$result = $this->db->get();
Couple issues: You need to include your table aliases and your join should have the name of the second table ...
$this->db->from('tbl_car_description AS d');
$this->db->join('tbl_car_prices AS p', 'd.id = p.cardescription_id');
i have one one issue in fetch image and text from database by module what to do for this issue and i add my table name and field name #__home_service_item this is my table name in that table two field one is image and image_name than i have one error for that question i display my error
Warning: Invalid argument supplied for foreach() in C:\wamp\www\Joomla_2.5.8-Stable-Full_Package\modules\mod_home\tmpl\default.php on line 40
please give me any clue for that problem i also add my code
<?php
defined('_JEXEC') or die('Restricted access');
$items = $params->get('items', 1);
$db =& JFactory::getDBO();
$query = "SELECT id
FROM #__home_service_item
WHERE published = '1'
ORDER BY id DESC";
$db->setQuery( $query, 0 , $items );
$rows = $db->loadObjectList();
foreach($rows as $row)
{
echo 'ID: '.$row->id.' </br>';
}
?>
please give one clue
do print_r($rows) and see if any records are returning from the database. I think that you have a problem with your query. If there are no results returning try enclosing your foreach statement with in a try catch or ignore warnings.
Also try to set $db->setQuery($query); instead of $db->setQuery( $query, 0 , $items );
If you just need one row result use $db->loadResult();
Whenever I tried to execute this sql query in a function module in drupal I am not able to get the results but when I try to execute this in MySQL I can view the result. My code looks like this :
function _get_subject_sub_category() {
$options = array();
$sql = "SELECT father.Subject_Code, child.Subject_Category
FROM {subjects} as child
INNER JOIN {subjects} as father ON (child.Parent_Category = father.Subject_Code
AND child.Level =2 )";
$result = db_query($sql);
foreach ($result as $row) {
$options[$row->father.Subject_Code] = $row->child.Subject_Category;
}
return $options;
}
The error I encountered is in the line $options[$row->father.Subject_Code] = $row->child.Subject_Category;`.
Any help will be highly appreciated.
Try changing this line:
$options[$row->father.Subject_Code] = $row->child.Subject_Category;
To this:
$options[$row->Subject_Code] = $row->Subject_Category;
The name of the table is not in the result. If you need to avoid confusion, you can use alias in your SQL query.
I don't know drupal and don't use php, but I would say :
remove
father. in $row->father.Subject_Code
and
child. in $row->child.Subject_Category
as father and child are just db aliases.
I am using codeIgniter..
I want to update a table column is_close when id=$ticket_id of my table= tbl_tickets.
I am doing this :-
$data=array(
'is_close'=>1
);
$this->db->where('id',$title_id);
$this->db->update('tbl_tickets',$data);
and I have also done this :-
$sql = "UPDATE tbl_tickets SET is_close={1} WHERE id='$title_id'";
$this->db->query($sql);
both are not working,i.e., my table is not updating the value to 1 and also no error is being shown in the broswer. :(
Edited: Included my model part :
function setClosePost($title_id){
$sql = "UPDATE tbl_tickets SET is_close=0 WHERE id='$title_id'";
$this->db->query($sql);
// $data=array(
// 'is_close'=>1
// );
// $this->db->where('id',$title_id);
// $this->db->update('tbl_tickets',$data);
}
My controller :-
function closePost(){
$this->load->model('helpdesk_model');
$this->helpdesk_model->setClosePost($this->input->post('title_id'));
}
first of all use a get method to check if ticket_id is exist or not.
another thing is always use return in your functions in models so you can check them by if(function_name){...}else{...}
then if your get method returned data correctly try
Model Method
public function set_closed($ticket_id){
$this->db->set(array(
'is_close'=>1
)); // pass fields in array
$this->db->where('id',$ticket_id);
$this->db->update('tbl_tickets'); // table name
return true;
}
then check that in your controller
if($this->Ticket_model->set_closed($ticket_id) == true){
echo 'ticket set to closed correctly';
}else{
echo 'there is some error on updating database'.$this->db->error(); // to checkout db error .
}
First, check $title_id before passing:
var_dump($title_id);
Then, try do "select a row with this id" before updating and after.
$query = $this->db->get_where('tbl_tickets', array('id' => $id));
foreach ($query->result() as $row)
{
var_dump($row->is_close);
}
$data=array(
'is_close'=>1
);
$this->db->where('id',$title_id);
$this->db->update('tbl_tickets',$data);
$query = $this->db->get_where('tbl_tickets', array('id' => $id));
foreach ($query->result() as $row)
{
var_dump($row->is_close);
}
Then, give your table structure.
Just try like this
$sql = "UPDATE tbl_tickets SET is_close='1' WHERE id=".$title_id;
$this->db->query($sql);
just try like this
**function edit($close,$id) {
$sql = "UPDATE tbl_tickets SET is_close= ? WHERE id = ? ";
$this->db->query($sql, array($close,$id));
}**
To handle this type of errors, i mean if reflection is not happen in database, then use below steps to resolve this type of error.
1) use $this->db->last_query() function to print query, using this we can make sure our variable have correct value (should not null or undefined), using that we can make sure also SQL query is valid or not.
2) If SQL query is valid then open phpmyadmin & fire same query into phpmyadmin, it will return error if query columns or table names are invalid.
Use this way, its best way to cross check our SQL queries issues.
I hope it will work.
Thanks
You are trying to update integer(INT) type value, just cross check with your column datatype if that is varchar then you have to put value in a single or double quote.
Like this
$data=array('is_close'=> '1');