SQL first so I can reference it lower:
SELECT ID,
SUM(length(substr(DATA_STRING, instr(DATA_STRING,'P')+1)))
FROM DATA P, PLC PP
WHERE P.ID = PP.ID
AND instr(DATA_STRING, 'F') = 0
GROUP BY ID
The function above looks for the P in each data string and counts up how many characters are in the string.
So my problem is thus, I have two conditions that can occur, one where the data string could contain the P as in above, or when it contains a F. I need to be able to check for both and then sum up the total. The issue with the above is that I sum in a 0 if that condition when the string has an F occurs.
I almost need the equivalent of SUMIF in Excel so that I could say if when I search for P it's 0, then look for the F and add in that length and vice versa.
Please let me know if you have suggestions!
length(substr(DATA_STRING, instr(DATA_STRING,'P')+1))? This is doing a lot of work.
From what I can tell, you want sum of the number of characters after a 'P' or 'F' in the string. If so:
SELECT ID,
SUM(CASE WHEN data_string like '%P%'
THEN len(DATA_STRING) - (instr(DATA_STRING, 'P') + 1) ELSE 0
END) as Num_P,
SUM(CASE WHEN data_string like '%F%'
THEN len(DATA_STRING) - (instr(DATA_STRING, 'F') + 1) ELSE 0
END) as Num_F
FROM DATA P JOIN
PLC PP
ON P.ID = PP.ID
GROUP BY ID;
I also fixed the join syntax to use explicit joins.
Related
I'm a bit stuck in my coding here... I have this extense and complex code, but I'm actually failling by the end of it. I'm getting the SQL Error [42804]: ERROR: argument of CASE/WHEN must be type boolean, not type character varying
The thing, is: when "bairro" matches a row from "SUB_COUNTRY_DB", get psd.name, else get z.name. Any tips on how I could accomplish this?
select distinct
aa.mes,
--aa.modalidade,
--to_date(aa.created_date, 'yyyy-mm-dd') data_captacao,
ucl.ja_comprou_lf as comprou_lf,
case when bairro in (select sub_country from sub_country_DB)
then psd.name
else z.name
end loja,
count (distinct aa.customer_uid) qtde_socios,
count (distinct aa.assinatura_uid) qtde_assinaturas
from assinaturas_ativas aa
left join ultima_compra_loja_fisica ucl on (aa.customer_uid = ucl.customer_uid
and aa.mes = ucl.mes)
left join zip_code z on (aa.customer_uid = z.customer_uid
and aa.mes = z.mes)
left join SUB_COUNTRY_DB psd
on (psd.district = aa.bairro)
group by 1,2,3--,4
Try variants like:
moving condition to an inner query
CASE WHEN EXISTS (SELECT DISTINCT sub_country FROM sub_country_DB WHERE sub_country = barrio)
ANY (PostgreSQL only)
CASE WHEN bairro = ANY(ARRAY_AGG(select sub_country from sub_country_DB))
i want to have only one value in the result of the query which is the first value, or the last value, i tried many things but i coudnt resolve it, the query is too long but i picked for you only the part where i am stucked.
select eccev.extra_data , c.id,
case when (eccev.extra_data::json->'tns')::VARCHAR = 'false'
then 'NON'
else case when coalesce((eccev.extra_data::json->'tns')::VARCHAR, '') = '' then 'EMPTY VALUE' else 'OUI'
end end as tns
from endorsement_contract_covered_element_version eccev, endorsement_contract_covered_element ecce, endorsement_contract ec, contract c, endorsement e, party_party pp
WHERE ec.endorsement = e.id
and e.applicant = pp.id
and c.subscriber = pp.id
AND eccev.covered_element_endorsement = ecce.id
and ecce.contract_endorsement = ec.id
and c.contract_number = 'CT20200909112'
with this query i have the result
{"qualite":"non_etu","tns":false} 199479 NON
{"qualite":"non_etu","tns":false} 199479 NON
{"qualite":"non_etu","tns":false} 199479 NON
i want to have only the first or the last row so i dont have repetition on the other rows, i saw that we can use first_value(X over (XX)) but i couldnt make it.
if u guys can help me, i would be gratefull
Thanks
you can try this
select distinct on (eccev.extra_data , c.id) eccev.extra_data , c.id, case when ...
but your query seems not optimized as you cross join 6 tables all together ...
Elon Reeve Musk FRS is an entrepreneur and business magnate. He is the founder, CEO, and Chief Engineer at SpaceX; early-stage investor, CEO, and Product Architect of Tesla, Inc.; founder of The Boring Company; and co-founder of Neuralink and OpenAI.
Your inner select returns a table. That can't be used as parameter to match a WHERE IN condition. Instead try using an INNER JOIN
sum(decode(
select sum(dou.noukn)
from dou
join v_kzeiritsu on
dou.zeiritsu = v_kzeiritsu.zeiritsu
)) as noukn2;
Just move your sum logic inside select as follows:
(SELECT SUM(DOU$2.NOUKN)
FROM SDNISHI.V_KZEIRITSU V
WHERE DOU$2.ZEIRITSU = V.ZEIRITSU) AS NOUKN2
In case If it gives aggregation error then use sum(above query) AS NOUKN2
Your code is very strange. For instance, it seems to assume that V_KZEIRITSU has one row. But, you can move this to the FROM clause:
SELECT SUM(CASE WHEN DOU.ZEIRITSU = K.ZEIRITSU THEN DOU.NOUKN ELSE 0 END) AS NOUKN2
FROM DOU LEFT JOIN
V_KZEIRITSU K
ON 1=1 -- in case the table is really empty
A slightly more reasonable version would be:
SELECT SUM(DOU.NOUKN) AS NOUKN2
FROM DOU LEFT JOIN
V_KZEIRITSU K
ON DOU.ZEIRITSU = K.ZEIRITSU -- in case the table is really empty
It seems rather unlikely to me that this is what you really intend. If not, I would suggest that you ask a new question with appropriate same data, desired results, and explanation of the results. A non-working query should not be expected to provide the same level of information.
I'd say that it is, actually, as simple as
select sum(dou.noukn)
from dou
where dou.zeiritsu in (select zeiritsu from v_kzeiritsu)
(I'm not sure what dou is (table? alias?), but I hope you do.)
After you edited the question, I'm editing the answer. I marked with "--> this" two lines that - in my opinion - might help. As previously, the whole sum(case ...) as noukn2 is replaced by a simple sum(dou$2.noukn).
Note that - in Oracle - you can't use as keyword for table alias. For example:
no: from employees as e
yes: from employees e
Here's your query:
SELECT DOU$2.CUSTCD AS CUSTCD,
DOU$2.CHUNO AS CHUNO,
DOU$2.LINNO AS LINNO,
DOU$2.SHIPDAYYM AS SHIPDAYYM,
SUM (DOU$2.NOUKN) AS NOUKN,
SUM (DOU$2.ZEIKN) AS ZEIKN,
SUM (dou$2.noukn) AS noukn2 --> this
FROM SDNISHI.T_HCHUMON_DOUSOU DOU$2
INNER JOIN SDNISHI.SY_KANRI KNR ON KNR.SHIPDAYYM = DOU$2.SHIPDAYYM
INNER JOIN SDNISHI.T_HCHUMON_MEI MEI
ON MEI.CUSTCD = DOU$2.CUSTCD
AND MEI.CHUNO = DOU$2.CHUNO
AND MEI.LINNO = DOU$2.LINNO
AND MEI.SHIPDAYYM = DOU$2.SHIPDAYYM
AND MEI.USEDNGKBN = '0'
AND MEI.CANCELKBN = '0'
LEFT OUTER JOIN SDNISHI.T_HCHUMON_HD HD
ON HD.CUSTCD = MEI.CUSTCD
AND HD.CHUNO = MEI.CHUNO
AND HD.LINNO = MEI.LINNO
AND HD.USEDNGKBN = '0'
AND HD.CANCELKBN = '0'
AND isnull (HD.CANKBN, '00') = '00'
JOIN v_keziritsu vk ON vk.zeiritsu = dou$2.zeiritsu --> this
WHERE DOU$2.USEDNGKBN = '0'
AND DOU$2.CANCELKBN = '0'
AND ( ( MEI.CHGDELKBN = '1'
AND MEI.HDOUSOUKBN = '02'
AND ( MEI.CHUSU > 0
OR MEI.BCHUSU > 0))
OR ( MEI.CHGDELKBN != '1'
AND HD.HDOUSOUKBN = '02'
AND ( MEI.CHKBTNFGA = '1'
AND HD.CHUSU > 0)
OR ( MEI.CHKBTNFGB = '1'
AND HD.BCHUSU > 0)))
GROUP BY DOU$2.CUSTCD,
DOU$2.CHUNO,
DOU$2.LINNO,
DOU$2.SHIPDAYYM
I have a cs cart database and I am trying to select all the attributes for all the products, the problem is that for each separate attribute for a product, my query creates a new row, I want to to have a single row for each products that has all the attributes into columns.
This is my query right now:
SELECT a.product_id, b.variant, c.description, d.product_code
FROM cscart_product_features_values a
LEFT JOIN cscart_product_feature_variant_descriptions b ON a.variant_id = b.variant_id
LEFT JOIN cscart_product_features_descriptions c ON a.feature_id = c.feature_id
LEFT JOIN cscart_products d ON a.product_id = d.product_id
After I run the query, I get the following result:
product_id;"variant";"description";"product_code"
38;"1st";"Grade Level";"750"
38;"Math";"Subject Area";"750"
38;"Evan-Moor";"Publisher";"750"
etc next product
What I want is this:
product_id;"product_code";"Grade Level";"Subject Area";"Publisher"
38;"750";"1st";"Math";"Evan-Moor"
etc next product
We only have 3 type of attributes: Grade Level, Subject Area and Publisher.
Any ideas how to improve my query and achieve this? I would be happy even with concatenating all 3 attributes in one column, delimited by ",".
This is a generic SQL solution using GROUP BY and MAX(case expression) to achieve the transformation of 3 rows into a single row with the 3 columns.
SELECT
v.product_id
, p.product_code
, MAX(CASE WHEN fd.description = 'Grade Level' THEN vd.variant END) AS GradeLevel
, MAX(CASE WHEN fd.description = 'Subject Area' THEN vd.variant END) AS SubjectArea
, MAX(CASE WHEN fd.description = 'Publisher' THEN vd.variant END) AS Publisher
FROM cscart_products p
LEFT JOIN cscart_product_features_values v ON p.product_id = v.product_id
LEFT JOIN cscart_product_feature_variant_descriptions vd ON v.variant_id = vd.variant_id
LEFT JOIN cscart_product_features_descriptions fd ON v.feature_id = fd.feature_id
GROUP BY
v.product_id
, p.product_code
This approach should work on just about any SQL database.
Note also that I have changed the order of tables because I presume there has to be a row in cscart_products, but there might not be related rows in the other tables.
I have also changed the aliases, personally I do not care for aliaes based on the order of use in a query (e.g. I just changed the order so I had to change all references). I have use 'p' = product, 'v' = variant, 'vd' = variant description & 'fd' = feature description' - with such a convention for aliases I can re-arrange the query without changing every reference.
I'm trying to get a count of all speakers who are active regarding that item as well as the total of speakers who correlate to a certain item. The first LEFT JOIN for the total speakers works, but the other for ONLY the active speakers regarding that item doesn't, any help is appreciated. The SQLFiddle is here
http://sqlfiddle.com/#!3/b579d/1
But when I try to add in the portion where you would get the number of active speakers
(LEFT JOIN (SELECT COUNT (tbl_SpeakerCard_Log.SpeakerName)
WHERE tbl_Speaker_Log.Spoken = 0)
ON tbl_AgendaList.AID = tbl_SpeakerCard_Log.AID)
under the previous LEFT JOIN I get an error. I'm 100% sure the query is wrong in some form, but I'm not sure how to approach it.
*NOTE: Spoken/Active are interchangeable, I just use different wording to clarify what I'm looking for.
EDIT: This is the desired output
http://imgur.com/yP1FKxg
You can use conditional aggregation to do this:
SELECT
AgendaList.AID,
AgendaList.Item,
COUNT(SpeakerList.SPID) as SpeakerTotal,
SUM(CASE WHEN SpeakerList.Spoken = 0 THEN 1 ELSE 0 END) as ActiveSpeakers
FROM AgendaList
LEFT JOIN SpeakerLIST ON AgendaList.AID = SpeakerList.AID
GROUP BY AgendaList.AID, AgendaList.Item;
Sample SQL Fiddle
Or you could use count instead of sum (which might be clearer):
COUNT(CASE WHEN Spoken = 0 THEN Spoken END) as ActiveSpeakers
SQL FIDDLE
WITH sTotal AS (
SELECT AgendaList.AID, AgendaList.Item, COUNT( SpeakerList.SPID) as SpeakerTotal
FROM AgendaList
LEFT JOIN SpeakerLIST ON AgendaList.AID = SpeakerList.AID
GROUP BY AgendaList.AID, AgendaList.Item
),
sActive AS (
SELECT AgendaList.AID, AgendaList.Item, COUNT( SpeakerList.SPID) as SpeakerActive
FROM AgendaList
LEFT JOIN SpeakerLIST ON AgendaList.AID = SpeakerList.AID
WHERE SpeakerLIST.Spoken = 0
GROUP BY AgendaList.AID, AgendaList.Item
)
SELECT sTotal.*, sActive.SpeakerActive
FROM sTotal left join
sActive on sTotal.AID = sActive.AID